Jus wanted to thank you for your help sir🔥I'm a first timer matriculant this year and I actually got a Level 6 for both Maths and Physical Sciences for my Trials thanks to you🙏🏾🙏🏾parents were very proud (My big brother recommended your channel) With all the help you've given to me, I'll be aiming for 7 now🙏🏾❤Thank You so much Sir
Thank you so much sir for the lesson😊🔥 I'm actually rewriting my matric so since I'm not attending at school, Your TH-cam videos have been of great help so I thank you🙏 and I've got the solution for the problem you posted at the end of the video!..... X=221.81 +k.360 or X=318.19 + k.360 ; KEZ
Hello sir ,I wanted to ask why we used arc cos of -0.6 instead of cos of 0.6 and used the negative sign in quadrants where cos is negative like we did with the first question of sin
I have question if anyone sees this commemt plz respond,when your lookong for the reference angle and lets say you got cosx=-6 and to find the reference angle you must say cos-1(6) do you include the negative sugn by the six.(-6) And say cos-1(-6) my teacher said the value inside those brackets mist always be positive so i am confused my Nkosi did ot differently
Good day sir, you said you'd post another video on general solutions but I checked and you have not yet done so. Your videos are such great help thank you.
Evening sir I'm actually lost and not sure to substitute the negative into the calculator when calculating the reference angle, because we were told not to substitute the negative and if don't it gives us different answers.
Sir, does the reference angle determine the quadrants we work under ? Im asking because for Sin its angle was Positive and we took the quadrants where sin is Positive at....... therefore for cos and tan we got negative reference angle and we used quadrants where Cos and tan are negative. I hope u understand my question💔🙏
Sir please can you actually give the correct answer cause I see different answers in this comment section but you seem to approve all and that is confusing me as to which is really the right answer....I understand you're motivating us all but actually stating the right one will be of much help🥺🙏🙏
Sir tell me if I'm wrong mina I got 180+41,81+I.360 x=221.81+k.360 x=360-180-41,81+k.360 × =138,19+k.360 Because when you get second solution for sin its 180-reference angle so since it's in the 4rh quadrant it's that 360 minus that 180 you supposed to use in the second solution minus reference You can check sir Even if you don't omit the the reference if you add 180 on the non-omited reference you get 138.19
Hello my honorable colleague, please can you revisit this video and make serious corrections over here because there are lots of mistakes that need to be rectified
For the first time I'm doing this with understanding , thanks to you Mr Nkosi .
My pleasure 😇
Thank you sir, I'm in matric this year and your videos are a life saver 🙏🙌
It’s my pleasure…
Plus ➕ zike
@@MlungisiNkosi I --
Third quadrant was 180+41,81 which was 221,81
Fourth quadrant was 360-41,81 which was 318,19
Awesome 😎
You are the best teacher ever engathi iNkosi ingakubusisa ngakho konke okufisayp
Jus wanted to thank you for your help sir🔥I'm a first timer matriculant this year and I actually got a Level 6 for both Maths and Physical Sciences for my Trials thanks to you🙏🏾🙏🏾parents were very proud (My big brother recommended your channel)
With all the help you've given to me, I'll be aiming for 7 now🙏🏾❤Thank You so much Sir
It’s my sincerest pleasure… Your big brother really loves you.
Thank you so much sir for the lesson😊🔥 I'm actually rewriting my matric so since I'm not attending at school, Your TH-cam videos have been of great help so I thank you🙏 and I've got the solution for the problem you posted at the end of the video!.....
X=221.81 +k.360 or X=318.19 + k.360 ; KEZ
You're most welcome and your answer is correct 👍🏾
I am very sure that your students get distinction. Great lesson as always👏👏
You’re one of them and you’ll get one…
AS VARSITY STUDENT WE ARE STRUGGLING WITHOUT YOU NKOSI
I will be with you in the near future 😊
I bless the day I discovered your channel , God bless you Malume.❤
You’re welcome
I have just started these online classes and I find them really helpful thank you Sir.
You’re most welcome
Hello sir ,I wanted to ask why we used arc cos of -0.6 instead of cos of 0.6 and used the negative sign in quadrants where cos is negative like we did with the first question of sin
I have the same question
so when we have a negative reference angle, the negative is for the quadrants only we don't use it after choosing the correct quadrants
Ehh i managed to solve general solution for the first time i got my answer as 221.81 and 318.19 thanks for your help🙏
Can I ask how you got 318.19 bcz I got 401.81
I have question if anyone sees this commemt plz respond,when your lookong for the reference angle and lets say you got cosx=-6 and to find the reference angle you must say cos-1(6) do you include the negative sugn by the six.(-6) And say cos-1(-6) my teacher said the value inside those brackets mist always be positive so i am confused my Nkosi did ot differently
Hi the negative sign is for the Cartesian plane position, cos is negative in the 2nd and 3rd
Sir you are a star,you helping me everyday continue the great work 🙌
You are a good teacher♥️i salute uuu
Thank you so much…
I find your videos very helpful. I just want to thank you for your effort and time helping us. Thank you "our favorite uncle"🕺
My pleasure!
Thank you so much, please do euclidean geometry soon
Keep your eyes glued… Let’s make a Euclidean Geometry date next week
Thank you ❤️
God bless you more from what you have already.
Thank you so much Sir😭❤.
Thank you 😊
Made my life easier, thank you
You’re welcome ☺️
X= 221,81+k180 OR X=318,19+k360 sir this is what I got
I’m glad you tried it out. Well done 👏🏾
Good day sir, you said you'd post another video on general solutions but I checked and you have not yet done so.
Your videos are such great help thank you.
I am trying to finish content on other topics
YOU ARE SUCH A GOOD TEACHER !!!
Thank you so much
The lessons are very helpful thank you sir 🙏
You’re welcome ☺️
Evening sir I'm actually lost and not sure to substitute the negative into the calculator when calculating the reference angle, because we were told not to substitute the negative and if don't it gives us different answers.
Well it depends… i think my method makes things easier
also with us we told not to substitute a negative reference angle
Same here, we are also not allowed to include negative
During coz why dd you add 360 instead of using reduction formulae
i have: x=41.81 +k.360 kEZ
x=180 + 41.81
x=221.81
x=360-41.81
= 318.19
is that okay?
Well done 👏🏾
Hi y was the negative excluded on the first solution but included on next
Ohhh sorry I see 4th quadrant 360 minus theta...🙈🙊silly me
Congratulations on 100k
I'm I still correct if I first find the value of x
Hi sir, I just wanted to know if we only add the KEZ on cos and sin graphs only?
No, even for the tan graph
Do we have to write KEZ at every step?
Not at every step… When you’ve done it once, that’s enough
Thank you sir may god bless u❤
It’s a pleasure
When we getting our reference angle of 4 question 2 do we put the negative taking the angle cos-1 (-0.6)? Or cos-1 (0.6)
Nevertheless, Thank you, you have already answered my question
I love it when that happens
So whats the answer? I also have the same question
@estherondongo1744 did u get the answer?😭
For tan will it be K.180 as standard even if we haven't been told to divide within the equation or is it like sin and cos being k.360?
When you divide remember you also divide that too.
Sir, does the reference angle determine the quadrants we work under ?
Im asking because for Sin its angle was Positive and we took the quadrants where sin is Positive at....... therefore for cos and tan we got negative reference angle and we used quadrants where Cos and tan are negative. I hope u understand my question💔🙏
X=41,81+k360kez or X=138,19+k360kez
Glorious 🤗❤️
Can you break step by step if you've got time
my first answer was 221.81 and my second answer was 318.19
Great attempt
First answer is 138,19
And second is 221,81
Sir, why do you say the "power of -1" is arc and not inverse?? Or does it mean the same thing??
The correct way is to say arc or inverse I agree…
Good evening sir for 3x=11.54 +k.360
Why can't we divide by 3 as well?
Yes we should divide by 3
Good day again sir, may I enquire about tan of it will have one or two solutions since it's period is 180 degrees.
It all depends on question
give umalume his flowers!!!!!🤭
As’bonge 🙏🏾
Sir please can you actually give the correct answer cause I see different answers in this comment section but you seem to approve all and that is confusing me as to which is really the right answer....I understand you're motivating us all but actually stating the right one will be of much help🥺🙏🙏
Why cant I write the reference angle as a negative like tan^-1(-3 over 2)?
You may…
Good Day Sir, How Do You Go About Solving An Equation With tan, Like -tan(2x + 45) -1,5 = -2,1
Follow the steps I outlined in this video
I'm A Bit Confused Since It Is Tan
@@nthabisengleuta3288
tan (2x + 45) = 0.6
(2x+45) = tan^-1 (0.6)
2x+45 = 30.96 + k180
Thank You Sir, Makes Sense.
Next year I'll be in matric.. i am greatful for your teaching uncle.. i am already confident to ace it .🏅
You are goals… ❤️
When I need assistance with maths and physics ...is there any amount to be paid?
On TH-cam, no… But private lessons, yes
x is equal to -41 + k360 KEZ. Is that Okay?
That’s a rounded off value, right? Please remember the other solution as well…
Sir tell me if I'm wrong mina I got 180+41,81+I.360
x=221.81+k.360
x=360-180-41,81+k.360
× =138,19+k.360
Because when you get second solution for sin its 180-reference angle so since it's in the 4rh quadrant it's that 360 minus that 180 you supposed to use in the second solution minus reference
You can check sir
Even if you don't omit the the reference if you add 180 on the non-omited reference you get 138.19
I’ll pin my answer on the comments
Got x=221,81 kEZ and x=138,19 kEZ
Awesome 👏🏾
General solution
X=221,81 + k360;k€z or
X=318,19 + k360,k€z
Hi sir I got
X = 41,81 + k360 KEZ
And
X = 136,19 + k360 KEZ
Is that correct?
Well done 👏🏾
can i get 2024 video
Please what about +90
I’m not sure I follow
Sire you are doing it differently to me😭
Hello my honorable colleague, please can you revisit this video and make serious corrections over here because there are lots of mistakes that need to be rectified
Like what sir?