How would we know what tension is what in the equation? In this case, it's already given what is the greatest tension but how would we know if it wasn't explicit?
Hello. Thanks for always being there when I have a maths question! Does it make a difference that the rope will need to move slightly diagonally across the pole/capstan in order to prevent the rope interfering with itself? Does it make a difference if the rope is in fact not a rope but a cable or a flexible hosepipe? Also, I’ve been trying to find a model for pulling a flexible pipe through various diameter orifices at different angles relative to the orifice. My thinking was to model the hose as a spring for the bending of the hose and the friction force through the hole as two capstans with the hose running between them, so looking down at the problem and pulling the a hose forward and bending to the right it would rub over the 10-11oclock section of the right capstan, and over the 4-5oclock section of the left capstan, but is there a simpler way to model this? To make it more complicated, what if there is no radius on the hole I’m pulling the hose through? Can I no longer approximate the capstan equation? Is there a similar equation for ropes, cables or hoses being pulled around a sharp edge like a right angle? Then, what if there is only a very small radius on the edge, can I combine such models to account for a small radius with two relatively sharp edges either side of it? Sorry for the huge question! Many thanks Dom.
That depends on how much friction force you need to stop the rope from slipping. Try to calculate the result for 1 wrap, 2 wraps and 3 wraps and see what happens.
So, to get the rope to slip the other way, you'd have to apply the 1000 N plus the calculated value for the given coefficient of friction? Interesting.
I believe that it is not 1000 + what was calculated. If you simply apply more tension than the one calculated, the rope will start to slip. If you apply, let's say 6.56N, the tension at that end is equal to 1000N. If you apply more, the tension will rise exponentially, based on the capstone equation.
please sir, can you please upload videos for 1st order circuits, 2nd order circuits, phasor domain, power of sinusoidal signals, bode plots, convolution and two port circuits for Electrical engineering because this would help me alot to pass my 2nd module in my bachelor course. thank you
How would we know what tension is what in the equation? In this case, it's already given what is the greatest tension but how would we know if it wasn't explicit?
same question
Hello. Thanks for always being there when I have a maths question!
Does it make a difference that the rope will need to move slightly diagonally across the pole/capstan in order to prevent the rope interfering with itself?
Does it make a difference if the rope is in fact not a rope but a cable or a flexible hosepipe?
Also, I’ve been trying to find a model for pulling a flexible pipe through various diameter orifices at different angles relative to the orifice.
My thinking was to model the hose as a spring for the bending of the hose and the friction force through the hole as two capstans with the hose running between them, so looking down at the problem and pulling the a hose forward and bending to the right it would rub over the 10-11oclock section of the right capstan, and over the 4-5oclock section of the left capstan, but is there a simpler way to model this?
To make it more complicated, what if there is no radius on the hole I’m pulling the hose through?
Can I no longer approximate the capstan equation?
Is there a similar equation for ropes, cables or hoses being pulled around a sharp edge like a right angle?
Then, what if there is only a very small radius on the edge, can I combine such models to account for a small radius with two relatively sharp edges either side of it?
Sorry for the huge question!
Many thanks
Dom.
If I don't know the number of times a belt must be wrapped what should I do?
That depends on how much friction force you need to stop the rope from slipping. Try to calculate the result for 1 wrap, 2 wraps and 3 wraps and see what happens.
Sir if the rope is made to turn on its own surface then we use the same concept i mean we use mu of rope?
Is it always T sub2 has to be greater than T sub1 (T2>T1)?
Thank you
Yes, T2 will always be larger than T1 (assuming that T2 is the object being held by pulling T1)
So, to get the rope to slip the other way, you'd have to apply the 1000 N plus the calculated value for the given coefficient of friction? Interesting.
I believe that it is not 1000 + what was calculated. If you simply apply more tension than the one calculated, the rope will start to slip. If you apply, let's say 6.56N, the tension at that end is equal to 1000N. If you apply more, the tension will rise exponentially, based on the capstone equation.
please sir, can you please upload videos for 1st order circuits, 2nd order circuits, phasor domain, power of sinusoidal signals, bode plots, convolution and two port circuits for Electrical engineering because this would help me alot to pass my 2nd module in my bachelor course. thank you
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