Hey Jeff! Always loving your vids! Wanted to make a point about this problem, especially about the 2nd part: This formula works for when there is slippage. So the 2nd part is not when its in equilibrium, but rather the force required for her to LOWER the 100 # dude down.... So, I'm left to wonder, what (diff) formula do we use to find the force when she is just "holding" his weight... (not raising him or lowering him)...???
In both cases it is the force to keep the boy stable on his position. If you change the results very slightly ( case one + 0.1, case two - 0.1) the boy starts to move..
If T2 is opposing the direction of the movement, then it means that it is in the same direction as Clif's weight is, which means that T2 should be minus 100 ! right ?
In pulley belt equation one is T2=T1e^.3pie and equation 2 you will get from moment at centre solve both you will get T1 T2 and proceed further if they ask something more force p you can find having one more moment out side in side corner where p is only unknown
Your tip about how to differentiate T1 and T2 made everything crystal clear for me. Thank you!
Professor Hanson, thank you for a classic lecture on the Belt Friction Problem in mechanics.
I like how you named the guy being pulled up Cliff lol
Hey Jeff! Always loving your vids! Wanted to make a point about this problem, especially about the 2nd part: This formula works for when there is slippage. So the 2nd part is not when its in equilibrium, but rather the force required for her to LOWER the 100 # dude down.... So, I'm left to wonder, what (diff) formula do we use to find the force when she is just "holding" his weight... (not raising him or lowering him)...???
In both cases it is the force to keep the boy stable on his position. If you change the results very slightly ( case one + 0.1, case two - 0.1) the boy starts to move..
Wonderful Statics lessons!! really taking the time to explain the problems along with a good sense of humor :))
Very clear explanation. Thank you sir!
neither in the lecture nor in the section my professors could make me get the difference between T1 and T2 but thanks to uuuu I surely get it now
If T2 is opposing the direction of the movement, then it means that it is in the same direction as Clif's weight is, which means that T2 should be minus 100 ! right ?
Learning is fun when the lecturer is an entertainer.
In pulley belt equation one is T2=T1e^.3pie and equation 2 you will get from moment at centre solve both you will get T1 T2 and proceed further if they ask something more force p you can find having one more moment out side in side corner where p is only unknown
i thought t2 is the force in the direction of the motion and t1 oppose it
love u
"200lbs to be a man"
*sad 180lb noises*
lol
Count your blessings man my little ass weighs 140 lol Jeff burned me on that one too
Bro, I’m barely 130
thanks bro
I thought the formula was T2=T1eUB instead of T1=T2eUB
The only thing this friction section is missing is an example problem that involves finding the angle of repose.
مفيش ترجمه عربي
Professor I am at belt now