Ma'am, can you please explain why v average in square waveform is not zero. As waveform is repeating itself after T so time limit should 0-T instead of T/2 or we can say area under curve is same for +ive and -ive cycle so net area comes out to be zero.
yes it is true for any symmetric waveform ( sine or square), if we take the average for a full cycle it will be zero as both +ve half cycle equals negative half cycle. So we need not find the average for full cycle. we normally take the average value for half cycle so that we get a idea of how much is the dc value (average) of the current we are handling for design purpose. Knowledge of peak factor and form factor is essential for safe design (to avoid thermal breakdown or insulation)
13:41 Total area=2*1/2*T/6*Vm + Vm*T/6 Here how you get 2 ? Area of Triangle 1 = 1/2*T/6*Vm Area of Triangle 3= Vm*T/6 Area of Rectangular 2= ? How we finding area for 2 Rectangular?
Hai Area of Triangle = base*height/2 . Now here area of triangle 1 = 1/2*T/6*Vm area of second triangle = 1/2*T/6*Vm area of rectangle which is marked as part 3 = base* height = Vm*T/6 Add all 3 portions you will get answer. I have added 2 triangles together first then added rectangle Adding 2 triangles together = 2*1/2*T/6*Vm Hope you understand.
in rms value calculation, we need to calculate the 𝑎𝑟𝑒𝑎 𝑢𝑛𝑑𝑒𝑟 𝑠𝑞𝑢𝑎𝑟𝑒𝑑 𝑐𝑢𝑟𝑣𝑒 𝑓𝑜𝑟 𝑜𝑛𝑒 𝑐𝑦𝑐𝑙𝑒. It means the time period remains the same. You can check the trapezoidal waveform rms calculation where you have a triangular portion and rectangular portion. In all cases, the time period is not squared.
@@pradeepsoni5566 area under the squared curve calculation is different from time period. first i have found area under squared curve equation. Square everything in that equation. divide by time period alone (no square). If still your doubt is not cleared, mail to readelectricvehicle@gmail.com with more details, i will clear your doubt.
T/2 is time period which will not be squared. U can check in other waveforms also(trapezoidal/ triangle). Alternatively, U can integrate the waveform and find rms value. When you integrate V^2, the limit is 0 to T/2. So we get integral of ( V^2 (T/2-0)) . Still not clear mail me to readelectricvehicle@gmail.com i will explain with waveform and equation clearly.
yes. When any waveform has equal positive and negative halfs, the average value will be zero. So normally the average value is calculated for a half cycle in symmetrical waveforms.
I am not sure this summary table is correct. The average for both Rectangular and Sine waves "as graphed" are Zero. I believe what this lady is calculating are valid for the average values of "rectified" Rectangular, or Sine waves.
The average value of a rectified sine wave is not same as sine wave. A sine has equal positive and negative parts. If you take average, it becomes zero. Whereas a rectified sine wave has only positive area ( no negative part). So its average is Vm/Pi and 2Vm/pi for half wave rectifier and full wave rectifier respectively.
Can you be more specific about where or in which topic you found mistake?. You can refer to any of the electrical engineering books and clarify your doubts
Thank you so much for unimaginable, unforgettable lecture
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Ma'am, can you please explain why v average in square waveform is not zero. As waveform is repeating itself after T so time limit should 0-T instead of T/2 or we can say area under curve is same for +ive and -ive cycle so net area comes out to be zero.
yes it is true for any symmetric waveform ( sine or square), if we take the average for a full cycle it will be zero as both +ve half cycle equals negative half cycle. So we need not find the average for full cycle. we normally take the average value for half cycle so that we get a idea of how much is the dc value (average) of the current we are handling for design purpose.
Knowledge of peak factor and form factor is essential for safe design (to avoid thermal breakdown or insulation)
I’m grateful and excellent explanation.❤❤❤
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great explanation, easy to understand. Thank you
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13:41 Total area=2*1/2*T/6*Vm + Vm*T/6
Here how you get 2 ?
Area of Triangle 1 = 1/2*T/6*Vm
Area of Triangle 3= Vm*T/6
Area of Rectangular 2= ?
How we finding area for 2 Rectangular?
Hai Area of Triangle = base*height/2 .
Now here area of triangle 1 = 1/2*T/6*Vm
area of second triangle = 1/2*T/6*Vm
area of rectangle which is marked as part 3 = base* height = Vm*T/6
Add all 3 portions you will get answer.
I have added 2 triangles together first then added rectangle
Adding 2 triangles together = 2*1/2*T/6*Vm
Hope you understand.
Very nice explanation! The light went on!! Thanks so much.
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Pertaining to the rectangular waveform the Vrms value was found without squaring the T/2 part of the same term. Can you please enlighten me on that?
in rms value calculation, we need to calculate the 𝑎𝑟𝑒𝑎 𝑢𝑛𝑑𝑒𝑟 𝑠𝑞𝑢𝑎𝑟𝑒𝑑 𝑐𝑢𝑟𝑣𝑒 𝑓𝑜𝑟 𝑜𝑛𝑒 𝑐𝑦𝑐𝑙𝑒.
It means the time period remains the same.
You can check the trapezoidal waveform rms calculation where you have a triangular portion and rectangular portion. In all cases, the time period is not squared.
At 10:20 u didnt square ( t/2) part with v under root.
why ..pls explain
Are you asking about time period in rms value?. It need not be squared
@@readelectricvehicle6078 why .
Earlier in sawtooth it was squared but not here
@@pradeepsoni5566 area under the squared curve calculation is different from time period.
first i have found area under squared curve equation. Square everything in that equation. divide by time period alone (no square).
If still your doubt is not cleared, mail to readelectricvehicle@gmail.com with more details, i will clear your doubt.
Mam in rectangular waveform,(rms value) why the numerator T/2 is not squared mam...can u make it clear
T/2 is time period which will not be squared.
U can check in other waveforms also(trapezoidal/ triangle).
Alternatively, U can integrate the waveform and find rms value. When you integrate V^2, the limit is 0 to T/2. So we get integral of ( V^2 (T/2-0)) .
Still not clear mail me to readelectricvehicle@gmail.com i will explain with waveform and equation clearly.
great presentation, very clear and concise..
Glad you liked it!
Is average value for rectangular wave for T/2 period
yes. When any waveform has equal positive and negative halfs, the average value will be zero.
So normally the average value is calculated for a half cycle in symmetrical waveforms.
I am not sure this summary table is correct. The average for both Rectangular and Sine waves "as graphed" are Zero. I believe what this lady is calculating are valid for the average values of "rectified" Rectangular, or Sine waves.
The average value of a rectified sine wave is not same as sine wave.
A sine has equal positive and negative parts. If you take average, it becomes zero.
Whereas a rectified sine wave has only positive area ( no negative part). So its average is Vm/Pi and 2Vm/pi for half wave rectifier and full wave rectifier respectively.
many many thanks, keep going on. nice explained nice really help me, watching from bangladesh
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Thank you so much mam...such a great and crystal clear explanation...
Thank you.
Thank you ma'am
Most welcome 😊
It really helps me a lot🙏
if it is useful, kindly share it with your friends.
Thank you ma'am for great video
Most welcome 😊
Everything is wrong 😢😮
Can you be more specific about where or in which topic you found mistake?. You can refer to any of the electrical engineering books and clarify your doubts
Except for the first form, the Average values of all forms are wrong @@readelectricvehicle6078