Hey! Exactly. As in many reactions, there are side reactions. What happens here, is once you form the chlorine gas, the chlorine begins to move to the top, through the solution of sodium hydroxide. While the chlorine rises, it reacts with the hydroxide to form your product, sodium chlorate. Hope that helped!
thanks for the video...i'm trying to make an electrolityc cells to reduce ferric iron to ferrous (aquose solution at 2500 ppm more or less), but here are other secondary compounds (lower concentration) as copper, arsenic, etc...should i use 0,77 V for the iron reduction reaction or more in order to give energy for all the reactions? when i gave 0,77 V, aparantly nothing hapens; when i gave more (like 10 V) my cathode was dissolved. thankful for the answer...best regards
Woah woah woah woah hang on... I thought that when choosing the reacting half-equation you took the one with the highest (more positive) E value. You're using the standard reduction potentials right?
BamBina RM Hey! Sorry for the confusion this has caused! This video was actually made quite quickly and wasn't meant for the public but I decided to leave it here anyways. When I get back into the general chemistry, I will be sure to make the proper corrections!
If we will apply more than -4,07V , so both oxidation and reduction will occur? Or how voltage should be applied to occur bothof red. and oxid. (-6,26V) ??
Many people on the internet say that this reaction creates NaClO3 but you are saying it makes those products. do the products then react again to form NaClO3?
You're welcome! Thanks for watching.
Hey!
Exactly. As in many reactions, there are side reactions. What happens here, is once you form the chlorine gas, the chlorine begins to move to the top, through the solution of sodium hydroxide. While the chlorine rises, it reacts with the hydroxide to form your product, sodium chlorate. Hope that helped!
Thanks for the clarification.
Thanks! Very useful!
You Rock man....Now totally make sense
Mehdad Karimi thanks! :-)
so crystal clear
Oh thank you for that video, it has been very comprehensible, even when my native language is not English.
thanks for the video...i'm trying to make an electrolityc cells to reduce ferric iron to ferrous (aquose solution at 2500 ppm more or less), but here are other secondary compounds (lower concentration) as copper, arsenic, etc...should i use 0,77 V for the iron reduction reaction or more in order to give energy for all the reactions?
when i gave 0,77 V, aparantly nothing hapens; when i gave more (like 10 V) my cathode was dissolved.
thankful for the answer...best regards
Woah woah woah woah hang on... I thought that when choosing the reacting half-equation you took the one with the highest (more positive) E value. You're using the standard reduction potentials right?
I agree, there is a slight mistake in this video.
BamBina RM Hey! Sorry for the confusion this has caused! This video was actually made quite quickly and wasn't meant for the public but I decided to leave it here anyways. When I get back into the general chemistry, I will be sure to make the proper corrections!
It's ok. Your video helped me a lot actually :) You are very good. THANK YOU
All good, still a helpful vid.
If we will apply more than -4,07V , so both oxidation and reduction will occur? Or how voltage should be applied to occur bothof red. and oxid. (-6,26V) ??
Why do we have 2Na(aq) in the products?
some people are just gifted at chemistry!
What's the different reactions between dilute and concentration aqueous solutions of NaCl?
thanks alooot😃😃
Many people on the internet say that this reaction creates NaClO3 but you are saying it makes those products. do the products then react again to form NaClO3?
This really threw me off because he uses oxidation potential instead of reduction potential for the first part.