another way to think about it is if you take the "vector" of 1 and subtract it from an arbitrary "vector" z, the resultant vector mustn't have a length greater then one. By having the "-1" of the equation locked in place, it is easier to visualize z and its restrictions such that the resultant has a mod of 1
Ok I couldn't concentrate for about 1 min cos I was trying to figure out how such a slim guy has such good looking hips🙈,but then I realised he had his wallet in his back pocket😀. Good explanation btw👍
I couldn't understand this idea for a whole week in my maths class and here this dude is explaining it in 8 minutes
I think it is easier to change it to a circle formula where modulus of z is equal sqrt(x^2 + y^2)
Best maths teacher in the world
another way to think about it is if you take the "vector" of 1 and subtract it from an arbitrary "vector" z, the resultant vector mustn't have a length greater then one. By having the "-1" of the equation locked in place, it is easier to visualize z and its restrictions such that the resultant has a mod of 1
thank you sir amazing explanation
fuking noisy guys on the background, but it is a great video, really good explained.
I am so thankful! Great explanation!
Great explanation !
Ok I couldn't concentrate for about 1 min cos I was trying to figure out how such a slim guy has such good looking hips🙈,but then I realised he had his wallet in his back pocket😀. Good explanation btw👍
AYOO💀
Great sir I understand.
Sir plzzzz asked about Draw the graph of |z|= 1
Thanks boss
nice thanks!!!
What if i have |z-i|=4???
the centre shifts one unit up on y axis with radius 2
Aditya Saha on the imaginary axis, and no it has a radius of 4
Fabulous
Thanks
How to solve for Z: 3z-5+2z+25-5z
Please tell me one example
sir, thats not even an equation... you need to study more
Thank u sir
Intelligent mathematic are u from China or Japan here u means you
He's from Australia. His ancestry is Chinese and Malaysian.