Thanks! I agree it is definetely the best format. Sorry if the uploads are slow, it's hard to find the time to record these during the week. It's more of a long term project but hopefully helps some people along the way.
I assume you're referring to the Gauss's Law integral. The electric field of the cylinder radiates radially away, so the electric field does not penetrate through the bases of the cylinder at all, only through the surface encircling it.
When we consider electric field, we tend to find the component which will vary in the direction. If we the electric field which is parallel to the base, the electric field will always have a component in opposite direction. It will always be cancelled by a configuration of charges. For the one at curved surface, there isn't equal magnitude of electric field so it's a unique direction
Why have you not taken the limits of integral from a to s in part (ii) as you have taken in the previous problem?... That's really confusing me. Guide me in this regard plz.
Great job!
P.s. I prefer the previous structure.
Thank you very much!
Please start from scratch. That was best. Thanks for your videos. Hope to see more soon!
Thanks! I agree it is definetely the best format. Sorry if the uploads are slow, it's hard to find the time to record these during the week. It's more of a long term project but hopefully helps some people along the way.
why don't we consider the bases of the cylinder part of the area?
I assume you're referring to the Gauss's Law integral. The electric field of the cylinder radiates radially away, so the electric field does not penetrate through the bases of the cylinder at all, only through the surface encircling it.
When we consider electric field, we tend to find the component which will vary in the direction. If we the electric field which is parallel to the base, the electric field will always have a component in opposite direction. It will always be cancelled by a configuration of charges. For the one at curved surface, there isn't equal magnitude of electric field so it's a unique direction
Great work
How do you comment about the continuity of graph at point b? Theres an obvious discontinuity
Really helpful for me
Why have you not taken the limits of integral from a to s in part (ii) as you have taken in the previous problem?... That's really confusing me. Guide me in this regard plz.
good job
Start form the scratch.
This way is simpler
،shapter 3