i dont know if you still answer questions on old video's, but why do you take 'a' and 'r' as values for the integral at 4:32 and not 'a' and 'b'? Thanks!
The reason for using 'r' and and not 'b' is due to the fact that we are finding the electric field in the region between the surfaces 'a' and 'b'. So we create a fictitious Gaussian surface in that in-between region and give it an arbitrary radius 'r'. As long as the radius is in the range a < r < b. Does that make sense? I still answer questions when I can! Life is super busy and I wish I had more time to film and make videos, but I still like to read and respond to the comments as they come :)
Muito obrigado pela resolução. Mas no caso em que r>b devias resolver partindo do começo, Para que percebamos o surgimento deste resultado por si obtido
No item ii), eu penso que deveríamos integrar a equação do Campo elétrico e não simplesmente a densidade superficial, pois o objetivo é encontrar o campo elétrico. E como a questão nos fornece o valor da densidade p=k/r², então substituído na equação do campo campo (que pretendemos integrar) teríamos E=k §((k/r²)dv/r² onde § é sinal de integral E agora é só desenvolver Muito obrigado, diretamente de Moçambique 🇲🇿🇲🇿
i dont know if you still answer questions on old video's, but why do you take 'a' and 'r' as values for the integral at 4:32 and not 'a' and 'b'?
Thanks!
The reason for using 'r' and and not 'b' is due to the fact that we are finding the electric field in the region between the surfaces 'a' and 'b'. So we create a fictitious Gaussian surface in that in-between region and give it an arbitrary radius 'r'. As long as the radius is in the range a < r < b. Does that make sense? I still answer questions when I can! Life is super busy and I wish I had more time to film and make videos, but I still like to read and respond to the comments as they come :)
@@brandonberisford Oh thanks! I get it now :) Thanks so much for taking the time to answer questuins! Hope youre doing well
Had the same question....thnx!!!
Thank you so much..
You're welcome!
I really appreciate your efforts. These videos were so helpful. Thank you so much ❤️💗.
You're very welcome!
Parabens pelas resolucoes tem me ajudado bastante.
Thank you!
good job
Sir in part c,why we cant take limits of "r" from b to r??
The graph between a and b will be the graph of 1/r . Am i correct sir?🤔
Muito obrigado pela resolução. Mas no caso em que r>b devias resolver partindo do começo, Para que percebamos o surgimento deste resultado por si obtido
No item ii), eu penso que deveríamos integrar a equação do Campo elétrico e não simplesmente a densidade superficial, pois o objetivo é encontrar o campo elétrico. E como a questão nos fornece o valor da densidade p=k/r², então substituído na equação do campo campo (que pretendemos integrar) teríamos E=k §((k/r²)dv/r² onde § é sinal de integral
E agora é só desenvolver
Muito obrigado, diretamente de Moçambique 🇲🇿🇲🇿
For me what i don;t get i knowing in which region to consider the presence of Q
The charge is on the surface of the outer sphere. You consider all regions and find the field in each region.
One a day is too much to ask for? :D
haha! With a full-time job, girlfriend, working out, friends. I think 1-2 a week should be do-able :)
your teaching so not clear for me please make clear for us