Your videos are really helpful and precise in topics. One small suggestion though. Since it's an online tutorial, so these kinds of videos shall be shot from a distance so that students can view the board more clearly. Since the video is shot from a close distance, the teacher ends up covering/blocking the board in most of the video. Thank you.
Very nice mam, I want to become a teacher like you.i have completed m.sc in 2013 and now I am preparing for net exam ,your videos are so helpful for me,thanku so much.
Mam, I think it is better to remind Rotational Energy (EJ) = J(J+1)×B×h [This (EJ) is E 'subscript J'] Where B is Rotational Constant and B=[ h/8(π2)I ] (This is π 'square') Because, while you are calculating Frequency of Light/Radiation, then calculation becomes much more easier. This is because, (EJ) = J(J+1)×B×h So, (∆EJ) = 2(J+1)×B×h Again (∆EJ) = h × frequency of the radiation. So, frequency of the radiation will be = 2(J+1)×B. And here the unit of B will be exactly equal with the unit of frequency of light/radiation and it is Hz or Second inverse. But since Spectroscopic unit is written in terms of c.m inverse or m inverse (i.e. in terms of Wave number) , so to convert Second inverse into c.m inverse or m inverse we should multiply into velocity of light in vacuum. This is because, we know ∆E=h×new=(h×c/lemda) =(h×c×new-bar) i.e. new=c×new-bar new is the representation of Frequency of light/radiation and new-bar is the representation of Wave number Since, new-bar = (1/lemda) and lemda has the unit of either c.m or m, so new-bar will be the unit of c.m inverse or m inverse or more preciously length inverse. Similarly B will be = c (i.e velocity of light in vacuum) × B-bar But you are also doing great work mam. Please Carry on mam.
Mam , please aap ye clear Kar dein gi ke jab hum ye Keh rahe ha ke ese molecules Jin Ka dipole moment zero hota ha to wo rotationally inactive hota ha,but CO2 Ka dipole moment to zero hota ha,to phir hum CO2 ko rotate kese Karwa rahe ha
Lectures are excellent, but my little suggestion, speed is bit fast, just slow your speed of delivering lecture. Dr. Farooq Warsi/Associate Professor/Islamia Uniuversity Bahawalpur-Pakistan
@@JChemistry thank u so much mam .......Dil se respect mam aapke liye h........mam Mai aapko apni mentor manti hu....u r different from other academic u tuber🙏🙏🙏🙏🙏🙏🙏🙏🙏
In case of BF3 there is no lone pair on B and in ClF3 there are two lone pairs on Cl..so both molecule has different strucutre. And when l.p is absent then it is obvious that these type of compound will microwave inactive..so BF3 microwave inactive
I have already created a separate playlist for IIT-JAM videos ,and for the recently uploaded videos you can see on thumbnail if they are for jam or not IIT-JAM playlist 👇👇👇 th-cam.com/play/PLYXnZUqtB3K9UZx_G8OWc8AclzY6bBqe4.html
I have no request...u r doing an awesome job already...Kuch to sayad hme b pdhna chahiye...
Excellent thinking ....thank you :)
If methane is microwave inactive,then why it is an example of spherical top molecule
It should be.. ?
mam! i just want to say only one thing ....... thank you so much!
Your videos are really helpful and precise in topics.
One small suggestion though.
Since it's an online tutorial, so these kinds of videos shall be shot from a distance so that students can view the board more clearly. Since the video is shot from a close distance, the teacher ends up covering/blocking the board in most of the video.
Thank you.
Very nice mam, I want to become a teacher like you.i have completed m.sc in 2013 and now I am preparing for net exam ,your videos are so helpful for me,thanku so much.
Net clear huva kya
@@graduatetricks8264lol
Mam, I think it is better to remind Rotational Energy (EJ) = J(J+1)×B×h
[This (EJ) is E 'subscript J']
Where B is Rotational Constant and B=[ h/8(π2)I ]
(This is π 'square')
Because, while you are calculating Frequency of Light/Radiation, then calculation becomes much more easier.
This is because, (EJ) = J(J+1)×B×h
So, (∆EJ) = 2(J+1)×B×h
Again (∆EJ) = h × frequency of the radiation.
So, frequency of the radiation will be = 2(J+1)×B. And here the unit of B will be exactly equal with the unit of frequency of light/radiation and it is Hz or Second inverse.
But since Spectroscopic unit is written in terms of c.m inverse or m inverse (i.e. in terms of Wave number) , so to convert Second inverse into c.m inverse or m inverse we should multiply into velocity of light in vacuum.
This is because, we know
∆E=h×new=(h×c/lemda) =(h×c×new-bar)
i.e. new=c×new-bar
new is the representation of Frequency of light/radiation and new-bar is the representation of Wave number
Since, new-bar = (1/lemda) and lemda has the unit of either c.m or m, so new-bar will be the unit of c.m inverse or m inverse or more preciously length inverse.
Similarly B will be = c (i.e velocity of light in vacuum) × B-bar
But you are also doing great work mam. Please Carry on mam.
B- bar means...what? 1by lembda na
Thanku.....mam...my all concept clear in this vidio
Thank you ma'am...can you plz explain how to calculate transition moment integral in rotational spectroscopy
Mam , please aap ye clear Kar dein gi ke jab hum ye Keh rahe ha ke ese molecules Jin Ka dipole moment zero hota ha to wo rotationally inactive hota ha,but CO2 Ka dipole moment to zero hota ha,to phir hum CO2 ko rotate kese Karwa rahe ha
Maam are these lectures sufficient for DU semester exams. 🙏
I'm also from DU, and completely relying on her lectures. 😁
Thank you so much mam 🙏🏼🙏🏼🙏🏼
Please make videos on Raman spectroscopy.. i.e. Raman active & inactive molecules, Stokes & Anti-stokes lines etc.
I'll surely upload but in the sequence Rotational, vibrational and then Raman
Lectures are excellent, but my little suggestion, speed is bit fast, just slow your speed of delivering lecture. Dr. Farooq Warsi/Associate Professor/Islamia Uniuversity Bahawalpur-Pakistan
Mam acids base bhi kra dena please!!
Very thanku mam very usefull 😊😊
Very nice explanation.
Mam,The derivation of this formula can need for upsc exam?
Mam apne unacademy par named reaction srt krdi kya? Jchemistry search krne par kuch v nhi arha lekin. Plzz bta yiye
No ...I've decided not to go on Unacademy ...I'll be covering the topics here only :)
@@JChemistry tq mam😊😊
@@JChemistry thank u so much mam .......Dil se respect mam aapke liye h........mam Mai aapko apni mentor manti hu....u r different from other academic u tuber🙏🙏🙏🙏🙏🙏🙏🙏🙏
Mam plzz "degree of freedomkaise calculate krenge" is topic pe video bna dijiye
very good explanation mam
Mam for topic rotational energy of diatomic molecule what we exactly write??
Respected mam, is it possible that rotational frequency is equal to (2BC×root over J(J+1)
Awesome..
Very good lecture
Mam plz tell me the spectroscopy book name author name for m. Sc. Previous
Mam upload videos of phase rule and vibrational spectroscopy
Mam srf aap k videos se spectroscopy krna sufficient h...books nhi h mere pas...
Mam physical spectroscopy itna enough hai for this net exam... Plz mam reply...
Mam yha jo cm^(-1) pe h..wo frequency hone chiye...and you introduced as energy !? But how?
E=h×frequency
Thank you mam.
Hiyeee mam ,,, Thank you sooooooooooooooooooooooooooooooooooooooooooooooooooooMuch
Thanks mam
Thank you mam
If BF3 is inactive...then ClF3 should also be inactive..plzz explain??
In case of BF3 there is no lone pair on B and in ClF3 there are two lone pairs on Cl..so both molecule has different strucutre. And when l.p is absent then it is obvious that these type of compound will microwave inactive..so BF3 microwave inactive
@@aditiboruah7793 tq Aditi☺
Mam it's request please make vedio at least 30 min session
Mam plz aap thoda dheere bola kijiye kyonki room ki eco ke wajah se cheeze theek se sunai nahi deti
Mam derivation of formulas?? Not given
i have one request. Kindly state before your videos that they are either selective for JAM or not
I have already created a separate playlist for IIT-JAM videos ,and for the recently uploaded videos you can see on thumbnail if they are for jam or not
IIT-JAM playlist 👇👇👇 th-cam.com/play/PLYXnZUqtB3K9UZx_G8OWc8AclzY6bBqe4.html
Why is sf4 microwave active
Because in sf4 there is a lone pair .So it is not a perfect molecule.Hence it is rotationally (microwave) active.
Dhende suraj Baban
15081
Organic chemistry
mam aap bhaut beautiful hai.....
Ma'am sf4 active kaisai phr wo bhi to perfect molecule hai
Sf4 is not perfect tetrahedral there is lone pair on sulphur
🙏🙏
Panga smjh gya mam 👍
Mam aap mausbaar bhi karvaoge
Mam aap se request h exam se phle physical spectroscopy kro do
Yes definitely ...I surely will :)
T
You are beautiful ❤️❤️❤️❤️
BJ dekh kar mujhe BJ Watling ka yad ayega
thanku so much madam.
Thankyou so much ma'am