tried solving this one for myself and after finishing the first integration, getting stuck, and checking wolfram alpha I realised how in over my head I was
Would you like to check our answers with a dilogarithm? My version: x+B=-y*ln|exp(y)/A-1|+ln|exp(y)-A|-Li_2(exp(y)/A) I used the reflection formula to simplify the argument of the dilogarithm.
This seems kind of like it lost the thread somewhere, unless we're just glossing over that there's no closed form solution while being content that we found a range for it. Did I miss something?
Yes , but this equation is second order reducible to first order with substitution y'=u(y) After reduction to first order we will get two equations and one of these equations is linear but problems may appear in integration
tried solving this one for myself and after finishing the first integration, getting stuck, and checking wolfram alpha I realised how in over my head I was
Hi,
"terribly sorry about that" : 0:46 , 7:55 , 10:20 ,
"ok, cool" : 1:31 .
The sum can be expressed in terms of the Poly-logarithm, or if you like the Hurwitz zeta function.
Would you like to check our answers with a dilogarithm? My version: x+B=-y*ln|exp(y)/A-1|+ln|exp(y)-A|-Li_2(exp(y)/A)
I used the reflection formula to simplify the argument of the dilogarithm.
I thought you were gonna write the final answer in terms of Di-logarithm
This seems kind of like it lost the thread somewhere, unless we're just glossing over that there's no closed form solution while being content that we found a range for it. Did I miss something?
Thank you for your fruitful effort.
Most underrated channel on TH-cam.
Truly, all teachers of calculus should recommend their students to watch this channel. For their own benefit.
Yes , but this equation is second order reducible to first order
with substitution y'=u(y)
After reduction to first order we will get two equations
and one of these equations is linear
but problems may appear in integration
Banger alert
Heres a horrendously scrambled equation which I hope is not too hard or easy:
y'+log_[x^x](y^y)=(sinx/lnx)*y^(-lnx-1)
it's an exact differential equation, so the solution is (y^3)/6 +Ay +ln(sqrt(c-2y)) = x + C
Since y=0 is the obvious solution & there's no obvious solution so it's only solution😂
Nice also put videos for matrices
Im huge fan of "dearavly sorry sorry about that"
*Typu mg horribly drung
Hi bro 👋
Sup bro
@@maths_505 Soup bro
I didn’t like the answer, but yeah nice problem 😅