Yes, you can use a different method. Let x=riding distance in km and y= walking distance in km. Then x+y=10.4 ...eqn1 Also x/t1=3y/t2 x/(¾)=3y/(1) x=(9/4)y,,,eqn2 Solve eqn1 and eqn2 simultaneously to get: y=3.2 km Hence walking speed=3.2/1=3.2 km/h Riding distance=x=(9/4)(3.2)=7.2 km
Sir please can you kindly use another method for the question 1
Please, you can check another approach in this video. Thanks
th-cam.com/video/VpqzsWZsG6w/w-d-xo.html
Sir please can you use a different method to solve the question one ???...l tried but didn't have the same answer.
Yes, you can use a different method.
Let x=riding distance in km and y= walking distance in km.
Then x+y=10.4 ...eqn1
Also x/t1=3y/t2
x/(¾)=3y/(1)
x=(9/4)y,,,eqn2
Solve eqn1 and eqn2 simultaneously to get:
y=3.2 km
Hence walking speed=3.2/1=3.2 km/h
Riding distance=x=(9/4)(3.2)=7.2 km
Sir please we want the answers to the objectives from 1-50.
thanks
Welcome
Please sir solve the optional ones please
Yes.... it's on the way
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Please the optional question 8 and others