Can someone help me please? Integral of abs(sin(x)) from 0 to 2pi. Reddit Calculus

Learn how to evaluate the definite integral of abs(sin(x)) from 0 to 2pi for your calculus class. Subscribe to ‪@bprpcalculusbasics‬ for more calculus tutorials.
This question is from Reddit r/calculus / krok4jrqkq
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[@bprpcalculusbasics]

Try the 100 integrals: th-cam.com/video/dgm4-3-Iv3s/w-d-xo.htmlsi=bJQFZjMjHBnkV_5b

[@joshcosta2299]

so logically just do integral of sinx from 0 to pi. then double it.

[@eswyatt]

Just go from zero to pi and double it.

[@xinpingdonohoe3978]

sin(x) is 2π periodic. |sin(x)| is π periodic. That's an ideal strategy.

[@aaryavbhardwaj6967]

I thought the same bro🎉🎉

[@charlescox290]

4:10 He mentioned that was a valid method, too. He just showed how to do it when there is no symmetry.

[@xibalbam]

Can't you replace abs(sin x) by sqrt(sin^2 x) and integrate that?

[@antoniousai1989]

Why would you do that? It's more difficult to solve that way.

[@xibalbam]

@@antoniousai1989 I just wanted to be sure it was possible because it can be a good way to integrate absolute value of more complex functions

[@antoniousai1989]

@@xibalbam Technically, it is the same function if you consider all the function dominions properly, but as a general approach, it doesn't work (it becomes too complicated), and it's not even the simplest thing to do for sin/cos basic functions.

[@xibalbam]

@@antoniousai1989 ok thanks !

[@LegendaryBea]

i had this type of question in my exam but in the format of first principle of derivative so instead of |sin x| i had |sin(x+t) - sin(x)|/|t|

[@broytingaravsol]

a piece of cake

[@charlescox290]

The cake is a lie.
😇

[@TDSONLINEMATHS]

First to comment
Thanks prof