Photoelectric vs Compton effect | Visual Explanation

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  • เผยแพร่เมื่อ 5 ก.พ. 2025

ความคิดเห็น • 25

  • @dr.paulinemoyaert
    @dr.paulinemoyaert  2 ปีที่แล้ว +13

    Thank you for watching my video. If you liked it, please consider giving it a thumbs up 👍. Feel free to let me know if you have any questions, I'd be happy to help you ☺.

  • @agnelomascarenhas8990
    @agnelomascarenhas8990 ปีที่แล้ว

    I had no idea how medical x-rays worked. Now I have a better understanding. Thank you.

  • @YousefAlotaibi-g7h
    @YousefAlotaibi-g7h 11 หลายเดือนก่อน

    Wow ! Thank you very much. You made these topics easy to comprehend for me as a first year medical student. 👍

  • @avanz2885
    @avanz2885 ปีที่แล้ว +1

    So good, great graphics and explanation ❤👍🏾

  • @AladdinAl-Asady
    @AladdinAl-Asady ปีที่แล้ว +1

    Nice video!
    I would like to point out some points:
    The probability of Coherent Scatter proportional with (Z / E^2), while the probability of Photoelectric Effect proportional with (Z^3/ E^3). There is a big difference between them !!!
    It is worth noting that although the Compton Effect is dominant in the medium energies range (almust 1 to 7 MV ), but its probability decreases with increasing photon energy and at the same time it is independent of atomic number Z . In other words, the probability of the Compton effect is dependent on the number of electrons per gram in the absorbing material, which for most elements is approximately the same!

    • @dr.paulinemoyaert
      @dr.paulinemoyaert  ปีที่แล้ว

      Thank you! I'll keep this in mind when I update this video 😊

  • @padpuff3209
    @padpuff3209 9 หลายเดือนก่อน

    Thanks so much for this video! Really helped me understand K-edge

  • @starlight9789
    @starlight9789 ปีที่แล้ว

    Beautifully explained. Keep making more videos

  • @zz9868
    @zz9868 2 ปีที่แล้ว +1

    clear and helpful👍

  • @etlirxharra2
    @etlirxharra2 ปีที่แล้ว

    Thank you for the clear explanation!

  • @drdj69
    @drdj69 8 หลายเดือนก่อน

    thank you for making it simple ..

  • @lizmariajose9481
    @lizmariajose9481 ปีที่แล้ว

    Good explanation

  • @adriangheorghe2327
    @adriangheorghe2327 9 หลายเดือนก่อน

    Then how do you explain the appearance of photons with a lower frequency range than the incident photons, scattered in the case of the Compton effect?

  • @TheNettforce
    @TheNettforce 2 ปีที่แล้ว

    Great video

    • @dr.paulinemoyaert
      @dr.paulinemoyaert  2 ปีที่แล้ว

      Thank you, Brian!
      PS. I knew I recognized that profile picture 😉. You're from 'how radiology works', no? Thanks for commenting! I watched lots of your videos when I was in med school 💪😊.

    • @TheNettforce
      @TheNettforce 2 ปีที่แล้ว

      @@dr.paulinemoyaert yeah that’s me. I’m impressed by the range of videos on your channel. Looks like a great resource for the community. Thanks for your contributions.

  • @boy_easyoo0
    @boy_easyoo0 5 หลายเดือนก่อน

    Thank you Mam

  • @elixir7400
    @elixir7400 2 ปีที่แล้ว

    thanks for the great information
    I'm NM resident i have recently started my residency and im really intrested if NM can in near future play a role in diagnosis or prediction of neurological and psychological diseases, specially dementia

    • @dr.paulinemoyaert
      @dr.paulinemoyaert  2 ปีที่แล้ว

      Hi Elixir, thank you for your comment, I really appreciate it. Looks like we have the same interests 💪.
      What specialty are you pursuing? 🙂 Good luck!

  • @Esraa-p3v
    @Esraa-p3v 10 หลายเดือนก่อน

    it is very useful
    Thank you 🥹

  • @adriangheorghe2327
    @adriangheorghe2327 10 หลายเดือนก่อน

    In the case of the Compton Effect, the high-energy gamma photon that enters the atom contracts longitudinally 137 times and transversely 4 times and splits into two high-energy bipolar standing waves, one rotating around the nucleus and the other around the electron in the deep layer. In this way, gamma photons of lower frequency and energy than the incident gamma photon would be born. Stationary waves, of high amplitude, behave like an elementary charge in the spiral. When the standing wave breaks, through electro-magnetic induction, a high-power electric impulse would appear, which accelerates the electron in the immediate vicinity and transmits a recoil to the nucleus, which releases the photon from the circum-nuclear standing wave.

    • @lepidoptera9337
      @lepidoptera9337 9 หลายเดือนก่อน

      Yes, that was bullshit. ;-)