It is easier to look at each term in the sum for positive integer values of m & n. If m=1 then n=4 (maximum value and happens to be a valid integer solution in itself). Looking at the 2nd term, if n=1 then m=7 (maximum value that also happens to be a valid integer solution in itself). So we can conclude 1
@@tonylo9971 (7/m)+(8/n) = 9. n,m are real positive numbers. This 2 variable equation has infinite solutions. You can substitute directly him the above equation, but for fun: (8/n) = 9- (7/m) (1/n) = (9- (7/m))/8 n = 8/ (9- (7/m)), ………………… (1) on the condition 9-(7/m) > 0 or m> 7/9 Substitute in (1); m = 1 n=8/2=4 m=7 n = 8/ (9-1) =1 m = 100000000000000 n less than 8/9
It is easier to look at each term in the sum for positive integer values of m & n. If m=1 then n=4 (maximum value and happens to be a valid integer solution in itself). Looking at the 2nd term, if n=1 then m=7 (maximum value that also happens to be a valid integer solution in itself). So we can conclude 1
wow 56/9 wow
It took me a second to figure out that N=4 and M=1 7+2=9
7 is a prime number and so m must be 1 or 7, otherwise 7/m is irrational. Then, it is easy to find n to be 4 or 1
@@tonylo9971
(7/m)+(8/n) = 9. n,m are real positive numbers.
This 2 variable equation has infinite solutions. You can substitute directly him the above equation, but for fun:
(8/n) = 9- (7/m)
(1/n) = (9- (7/m))/8
n = 8/ (9- (7/m)), ………………… (1)
on the condition 9-(7/m) > 0
or m> 7/9
Substitute in (1);
m = 1
n=8/2=4
m=7
n = 8/ (9-1) =1
m = 100000000000000
n less than 8/9