Wrong answer, the son's age should be 14. We know now the father's age plus the son's age is 60 so F+S=60. We also know that 6 years ago the father's age was 5 times the son's age. So for 6 years ago F-6+S-6=60 which gives F+S-12=60 so F+S=48. With the father's age being 5 times the son's age F=5S, that gives 5S+S=48 so 6S=48 which means S=48/6=8. That means that now the son is 8+6=14 years old and the father is 5x8+6=46 years old. Check in F+S=60 to see if this is correct: 46+14=60. We can also calculate the age of the father when his son was born: 46-14=32 years old. With that we can calculate when the father will be twice the son's age. When the father is twice his son's age F=2S. The father is 32 years older than his son so F=S+32. Put the two together to get S+32=2S and simplify to 32=S. The son will be 32 years old in 32-14=18 years and in 18 years the father will be 46+18=64 years old. We can check with F=2S to see if this is correct: 64=2x32. Using the same method we can calculate when the father will be 3 times as old as his son. F=3S and F=S+32 so 3S=S+32 which gives 2S=32 and S=32/2=16. So in 16-14=2 years the father will be 46+2=48 which is 3 times the age of his son.
It's the right answer. NOW, the son's age is 14, but in 6 years the son will be 20 years old. You should read correctly. She explained in detail the present age, the age six years ago and the age in 6 years.
When you watch the video completely, you will see she calculated the age correctly. It's said that the present age is 14 and the age in 6 years will be 20.
What pen are you using? Just curious? And which notepad?
Wrong answer, the son's age should be 14.
We know now the father's age plus the son's age is 60 so F+S=60. We also know that 6 years ago the father's age was 5 times the son's age. So for 6 years ago F-6+S-6=60 which gives F+S-12=60 so F+S=48. With the father's age being 5 times the son's age F=5S, that gives 5S+S=48 so 6S=48 which means S=48/6=8. That means that now the son is 8+6=14 years old and the father is 5x8+6=46 years old. Check in F+S=60 to see if this is correct: 46+14=60.
We can also calculate the age of the father when his son was born: 46-14=32 years old. With that we can calculate when the father will be twice the son's age. When the father is twice his son's age F=2S. The father is 32 years older than his son so F=S+32. Put the two together to get S+32=2S and simplify to 32=S. The son will be 32 years old in 32-14=18 years and in 18 years the father will be 46+18=64 years old. We can check with F=2S to see if this is correct: 64=2x32.
Using the same method we can calculate when the father will be 3 times as old as his son. F=3S and F=S+32 so 3S=S+32 which gives 2S=32 and S=32/2=16. So in 16-14=2 years the father will be 46+2=48 which is 3 times the age of his son.
It's the right answer. NOW, the son's age is 14, but in 6 years the son will be 20 years old.
You should read correctly. She explained in detail the present age, the age six years ago and the age in 6 years.
Very understandable,well done ma
Good morning
Very good morning yasir😊
So your Lachers solo
The present age of son should be 14 not 20.
The question told you to find the age of the son after 6 years.
When you watch the video completely, you will see she calculated the age correctly. It's said that the present age is 14 and the age in 6 years will be 20.
Hii
( )+ ( )=14
( )- ( )=16