Electrostatics (Part-2) for JEE Advanced | Booster Checklist 4

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  • เผยแพร่เมื่อ 24 ธ.ค. 2024

ความคิดเห็น • 508

  • @physicsgalaxyworld
    @physicsgalaxyworld  3 ปีที่แล้ว +45

    Before watching Booster Checklists for JEE Adv, students are advised to watch Revision Checklists on all topics from links given below -
    All topics of Class 11 - th-cam.com/play/PLYVDsiuOZP5okVjaOFGuRkLT51-WgG95_.html
    All topics of Class 12 - th-cam.com/play/PLYVDsiuOZP5pp1ak489L0oaMulGzuQWQ3.html
    Link to all Booster Checklists for JEE(Adv) - th-cam.com/play/PLYVDsiuOZP5o7T58PG8SUiKECCzbY37J9.html
    Physics Galaxy Team wishes all JEE Adv aspirants BEST to perform their best in finals !

    • @HEENAKHAN-ln6md
      @HEENAKHAN-ln6md 3 ปีที่แล้ว +1

      Sir ap hindi medium students ko bhi padhte ho kya ? Sir plz reply ....plz sir help me plz

    • @manojsinha6951
      @manojsinha6951 3 ปีที่แล้ว +2

      I hope and know that booster checklist will take me a millenia ahead in my Adv prepration 👍👍

    • @rashmibajaj1396
      @rashmibajaj1396 3 ปีที่แล้ว

      Sir iss video mey jitne concepts aapne explain kiye sabmey doubt tha, ab sab clear hogya, thank youu veryy much

    • @hardikguptaiit-k5028
      @hardikguptaiit-k5028 3 ปีที่แล้ว +1

      Sir ....if u can please provide the pdf of the pages which u r writing on...then, this will be very much benificial for last min. revision.....also at this time if we make notes it consumes more time..... please sir🙏

    • @suvidhkaushik1386
      @suvidhkaushik1386 2 ปีที่แล้ว

      sir for home work ques at 20:20 i am thinking of resloving the forces along tension and mg

  • @arthagrawal69
    @arthagrawal69 8 หลายเดือนก่อน +113

    Jee aspirants 2024 also watching this😅😅

    • @kabir_1285
      @kabir_1285 7 หลายเดือนก่อน +1

      The quality bro!!!😅😅😅

  • @souviksarkar6706
    @souviksarkar6706 3 ปีที่แล้ว +256

    Each of the sub-topics taken up in this checklist is a clear indication that Ashish Sir is providing quality Advanced content in this last moment. He is a true inspiration for us!! 🙏🙏

    • @AkashVerma-ec2zs
      @AkashVerma-ec2zs 3 ปีที่แล้ว +2

      Where are you preparing Mathematics and Chemistry from?

    • @souviksarkar6706
      @souviksarkar6706 3 ปีที่แล้ว

      @@AkashVerma-ec2zs yt

    • @Youtuber-lt9ed
      @Youtuber-lt9ed 3 ปีที่แล้ว

      @@souviksarkar6706 channel??

    • @the_dancing_narrator
      @the_dancing_narrator 3 ปีที่แล้ว +3

      @@AkashVerma-ec2zs for chemistry you can go with IITian Explains(MKA sir) and for maths Mohit Tyagi sir's channel .

  • @sandhyaranir5346
    @sandhyaranir5346 2 ปีที่แล้ว +58

    Thanks

  • @vipul6636
    @vipul6636 3 ปีที่แล้ว +74

    Best physics teacher in the world

  • @kumarswayam9899
    @kumarswayam9899 3 ปีที่แล้ว +17

    I swear this channel is a blessing I've never revised electrostatics in a better way

  • @utkarshshukla580
    @utkarshshukla580 3 ปีที่แล้ว +31

    This is the best thing for us, sir one request is that please put two lectures a day because most of us are 2021 aspirants and time is v less
    Thanks for the efforts sir

  • @alphaiitd1
    @alphaiitd1 3 ปีที่แล้ว +49

    Thank you sir for these gems. You are truely a great teacher and an even better person for providing them at free.

    • @prashantkumardas369
      @prashantkumardas369 2 ปีที่แล้ว

      Now where r u bro.

    • @Josuke217
      @Josuke217 ปีที่แล้ว

      @Memes shorts he was probably in class 12

  • @Thekhushisharma001
    @Thekhushisharma001 8 หลายเดือนก่อน +24

    🎯Jee advanced 2024🔥🔥🔥

  • @karanmeharchandanib2265
    @karanmeharchandanib2265 3 ปีที่แล้ว +64

    The previous 3 lectures were very helpful....i bet this one will also be motivating😃😃

  • @hrishapjoshi6173
    @hrishapjoshi6173 3 ปีที่แล้ว +30

    Another milestone by physics galaxy on youtube by giving best advance level content 👌

  • @baba-bhaukali1070
    @baba-bhaukali1070 3 ปีที่แล้ว +20

    It not just makes concepts clear instead it makes e feel STRONGER.
    Thank You SIR

  • @bhanwaridevijat158
    @bhanwaridevijat158 3 ปีที่แล้ว +9

    All concepts in this video are already covered by sir in concept videos.
    I completed all concept videos of electrostatic.and now I feel confident.
    Thank you very much sir for your hard work.

  • @krishbishwanath
    @krishbishwanath 3 ปีที่แล้ว +30

    44:07 done sir
    It can be solved by using gas law,
    P1V1=P2V2
    P1=Patm+4T/R V1=4/3π R^3
    Similarly P2=Patm+4T/r- Pe V2=4/3π r^3
    Thanks a lot sir ❤️

    • @harshyadav3150
      @harshyadav3150 3 ปีที่แล้ว +6

      Bro I think P2 should be Patm +4T/r +Pe coz Pe and 4T/r are in same direction

    • @vj51
      @vj51 3 ปีที่แล้ว +3

      @@harshyadav3150 Pres. inside is excess by 4T/r from "outside pressure"
      initial outside press is Patm and radius is R
      finally outside press is Patm - Pe and radius is R'

    • @thehealingguy1503
      @thehealingguy1503 3 ปีที่แล้ว +2

      @@harshyadav3150 the excess pressure is acting inwards and electric pressure is outwards.

    • @rajatbisht21
      @rajatbisht21 3 ปีที่แล้ว +1

      @@harshyadav3150 Patm+Pe+4T/R=P2 because Excess pressure and Pe will try to expand bubble while P atm of outside will try to stop.

    • @shreyarajagopalan4798
      @shreyarajagopalan4798 3 ปีที่แล้ว +3

      @@thehealingguy1503 Can you please explain how to go about the problem a little more? I understand that Excess pressure wants to pull the sphere inside. So P2=Patm +4T/r -Pe. But why are we not considering Pe in the initial condition? Also why are we not considering atmospheric pressure itself? I'm very confused.

  • @Shivansh0264
    @Shivansh0264 3 ปีที่แล้ว +108

    IN TH-cam ONLY ARORA SIR AND MOHIT TYAGI SIR PROVINDING CONTENT OF JEE ADVANCE
    AND ONLY SERIOUS STUDENTS KNOW THIS 😊👍

    • @saikhadloya8911
      @saikhadloya8911 3 ปีที่แล้ว +21

      Would like to give some more names helpful for other
      Rkh sir
      Janardhan sir
      Mka sir(best chemistry teacher for organic and inorganic)
      And all Mohit Tyagi sirs channel teachers(Absolute gold)
      Asish sir(Our God)
      Akash Goyal sir

    • @Shivansh0264
      @Shivansh0264 3 ปีที่แล้ว +5

      @@saikhadloya8911 I am unacademy plus student I studied mka sir in class 11 but in class 12 I am currently studying skm sir organic chemistry and vishal joshi sir inorganic chemistry and brijesh jindal sir physical chemistry
      Physics from nitin Sachin sir and maths anshul singhal sir
      Asm mentioned name I know janardhan sir he has best collection of problem if you want awsm problem for physics visit Indian school of physics you will be amazed to see level of questions

    • @shyamkarthikeya4769
      @shyamkarthikeya4769 3 ปีที่แล้ว

      @@Shivansh0264 Oye Power Stone 💜 tu yaha kya kr rha hai 😁😂.........

    • @Shivansh0264
      @Shivansh0264 3 ปีที่แล้ว

      @@shyamkarthikeya4769 aap jante ho mujhe?

    • @shyamkarthikeya4769
      @shyamkarthikeya4769 3 ปีที่แล้ว

      @@Shivansh0264 OH no ! Sorry wrong shivansh 😅, mei aur Shivansh pandey plus-mates hai..... aur Guruji ke students hai tho isiliye aisa bola..... sorry 🙏

  • @varshinilolla3090
    @varshinilolla3090 4 หลายเดือนก่อน

    28:19 charge distribution on concentric charged metal shells due to charge induction
    39:36 application of electric pressure (illustration 16 in PG advanced book)
    42:25 application no. 2

  • @muhammadshish2369
    @muhammadshish2369 ปีที่แล้ว +4

    MashaAllah, Great Explanation, Rich Content, No Comedy, Pure n Focussed, No Revolution Kind of Things , Amazing teacher

  • @Tanmay-fv8yo
    @Tanmay-fv8yo 3 ปีที่แล้ว +3

    Sir itni *subtle-ta* se topic samjhate hai fir lagta topic mein toh kuch tha hi nahi🙏🙏🙏 Respect for The *LEGEND*
    Mai bache hue video puri *punctual-ta* se dekhunga

  • @himau2434
    @himau2434 3 ปีที่แล้ว +27

    From
    unacademy and vedantu ...................
    To
    ""PHYSICS GALAXY"" and ""MOHIT TYAGI"" SIR
    We all grew up!!!!
    Thnk u so much sir!!!!

    • @adeshmaurya5764
      @adeshmaurya5764 3 ปีที่แล้ว +1

      And also consider mka sir iitian explains

  • @ashishpatidar7210
    @ashishpatidar7210 3 ปีที่แล้ว +5

    44:07 due to repulsion between charges pressure inside will decrease by €^2/2e and then we can apply PV = constant

    • @noamchomsky729
      @noamchomsky729 3 ปีที่แล้ว

      WILL IT BE CORRECT TO EQUATE Patm=Patm+4T/R+Pelectrostatic and calculate R ? (the external and internal pressure)

    • @ashishpatidar7210
      @ashishpatidar7210 3 ปีที่แล้ว

      @@noamchomsky729 No

    • @Steve-vk2kw
      @Steve-vk2kw 2 ปีที่แล้ว

      @@noamchomsky729 i think it could be Patm=Pe+4T/R

    • @ashishpatidar7210
      @ashishpatidar7210 2 ปีที่แล้ว

      @Yash Giri Yes🥲

  • @Ajaykumar-th5oh
    @Ajaykumar-th5oh 3 ปีที่แล้ว +13

    Thank you for making Advanced Physics so simple...

  • @Prashant-ll7mf
    @Prashant-ll7mf 3 ปีที่แล้ว +4

    Booster checklist not only boosts our concepts but they also boosted our confidence.ty sir.

  • @sagarbanisetty9417
    @sagarbanisetty9417 3 ปีที่แล้ว +5

    For the soap bubble problem, excess pressure due to surface tension is equal to the electric pressure at equilibrium. 4T/x = (sigma)^2/2€. Where x is the radius of bubble at equilibrium

    • @imPriyansh77
      @imPriyansh77 3 ปีที่แล้ว

      why excess pressure acts inward ?

    • @sagarbanisetty9417
      @sagarbanisetty9417 3 ปีที่แล้ว

      @@imPriyansh77 we will not take it inward or outward. Equilibrium is attained when pressure inside the bubble is equal to the pressure outside it. So that it stops expanding

  • @AkhandSinghJr
    @AkhandSinghJr 3 ปีที่แล้ว +2

    44:00 as the charge will exert pressure both inwards and outward at eqm Px= Patm+4T/R - Pe and Py= Patm+ Pe and hence as at eqm Px=Py =>2Pe=4T/R from here we can get the radius and also we can use gas law if we consider growth of bubble isothermal then P1V1= P2V2 here v1 is know and p1= patm +4T/r while p2 = patm+ 4T/r - Pe. show we can calculate R from there also

  • @hellohello4360
    @hellohello4360 3 ปีที่แล้ว +39

    Amazing lectures.Wish I had a chemistry and math GALAXIES

  • @prathamdani9855
    @prathamdani9855 3 ปีที่แล้ว +9

    39:12 Sir this question can easily solved by COM concept we will break sphere in 2 hemispheres and then consider their charges at COM and use force bet 2 charges simply.

  • @KRIPALSINGH1
    @KRIPALSINGH1 3 ปีที่แล้ว +2

    Sir Ashish Arora... You are a legend. I appreciate and know what freat work you are doing as I myself am a physics teacher.

  • @sayantandas9958
    @sayantandas9958 3 ปีที่แล้ว +2

    Thank you sir for all your help and lectures . These lectures have been instrumental in clarifying concepts and increasing the application power so as to attack jee advanced questions. Thank you for everything.

  • @shresthbhakta7337
    @shresthbhakta7337 3 ปีที่แล้ว +3

    Day 4 Present Sir. Just completed this checklist also. And today I'll complete advanced illustrations of electrostatics also. Thankyou sir and PG TEAM and ofc POGI.👽❤️

    • @manmayb6959
      @manmayb6959 3 ปีที่แล้ว

      pogi meaning? and why sir says that??🤔

  • @sachidanandpandey9330
    @sachidanandpandey9330 3 ปีที่แล้ว +3

    Thank you sir Iam 2022 aspirant but I regularly watch your booster checklist because it gives me lots of confidence and determination towards my goal after seeing your consistency🙏🙏

  • @shashanks868
    @shashanks868 3 ปีที่แล้ว

    This one lecture has covered almost all the concepts that are important for jee advanced . Best content at the last moment. A great work , Sir. Thank you for the checklists!!

  • @mrityunjaysharma3496
    @mrityunjaysharma3496 3 ปีที่แล้ว +4

    Best channel to revise your concepts ❤️❤️❤️

  • @spachan6090
    @spachan6090 3 ปีที่แล้ว +11

    Sir you're God to me 🙏🏻 Such difficult concepts of electrostats now seems crystal clear all credits goes to sir. Now I can solve Pyqs very easily of JEE ADV. Earlier I used to hate this chapter but now i can finally solve such difficult questions of jee adv. Thank you so much sir!!!

    • @adityajadhav3045
      @adityajadhav3045 3 ปีที่แล้ว +1

      Now you can get promoted to A class

  • @maneeshsinghgautam7300
    @maneeshsinghgautam7300 3 ปีที่แล้ว +4

    Sir please keep on this please continue to know because this will be helpful for JEE 2022 aspirant thank you so much sir..🙏🙏

  • @sumeetdubey9616
    @sumeetdubey9616 3 ปีที่แล้ว +21

    Sir it will be very much beneficial if you will upload all parts together in one day only.. like part-1+ part-2 at same day..
    As very few days are remaining for advance

    • @sumeetdubey9616
      @sumeetdubey9616 3 ปีที่แล้ว +3

      @@dhruvkothari7611 btw my friend DHRUV is more intellectual than me

  • @prinsshiyani950
    @prinsshiyani950 8 หลายเดือนก่อน +3

    TH-cam is not mature enough to handle this level content ❤❤

  • @shreyasyewale4686
    @shreyasyewale4686 3 ปีที่แล้ว +1

    Thank you sir for your hard work I recently solved your adv illustration book in July And now it is like I am getting full revision of book Thank you sir

  • @shivanikhare9588
    @shivanikhare9588 3 ปีที่แล้ว +1

    THANK you so much sir!! Only you are the one providing 100% free highly efficient and quality content on TH-cam. ❤️🙏 Bless me for jee advanced 2021.🙏

  • @mightyshashank465
    @mightyshashank465 2 ปีที่แล้ว +1

    Thx a ton sir, was confused a lot with this topic , but now everything is crystal clear

  • @yashpadiyar181
    @yashpadiyar181 3 ปีที่แล้ว +1

    Superb Content As Always😁😁

  • @rahulkurup7589
    @rahulkurup7589 3 ปีที่แล้ว +3

    Hats off sir🙏🙏
    You are great
    your greatness cannot be described in words🙏🙏

  • @YASHTIWARI2002
    @YASHTIWARI2002 2 ปีที่แล้ว +1

    This is best use of time not even a single second wasted
    ♥️

  • @NikH710
    @NikH710 ปีที่แล้ว +3

    Thank you so much sir ❤❤❤❤

  • @premprakash955
    @premprakash955 3 ปีที่แล้ว +4

    After watching every vdo I got confidence thank you sir

  • @ajayagarwal6476
    @ajayagarwal6476 3 ปีที่แล้ว +2

    sir you are doing wonderful job amazing level of content seen first time

  • @anirudhac2004
    @anirudhac2004 3 ปีที่แล้ว +24

    Sir plz upload schedule for booster checklist so that we can plan accordingly...

  • @shubhamgrover6810
    @shubhamgrover6810 3 ปีที่แล้ว

    Thank you so much sir
    This is the best content for JEE Adv on youtube

  • @ic3015
    @ic3015 3 ปีที่แล้ว +6

    In 11th ohysics was my weakest bt you and e saral videos helped me a lot and last mock test i got 58 out 66 inphysics jee adv type and 35 in chem and 35 in maths so total was128 out of 198

    • @44456e
      @44456e ปีที่แล้ว

      Same here bro

  • @aryankulkarni7523
    @aryankulkarni7523 3 ปีที่แล้ว +3

    Thank you sir these sessions are knowledge as well as motivation boosters🙂

  • @adityamishraiitbhubneshwar8039
    @adityamishraiitbhubneshwar8039 3 ปีที่แล้ว +2

    Hats off sir for you dedication and selflessness shown towards non paid students🙏🙏👏👏

  • @burhanuddinchomelawala
    @burhanuddinchomelawala 8 หลายเดือนก่อน +1

    i have learn many new concept by this thank you sir

  • @nikhileshratlavath155
    @nikhileshratlavath155 3 ปีที่แล้ว +17

    Sir, please share the schedule of booster checklist so that we can prepare accordingly also try to increase the frequency of lectures (2 in a day)

  • @codkiller1045
    @codkiller1045 9 หลายเดือนก่อน +2

    Sir at 41:17 kya ham force ko equate nhi kar skte hai means force on half sphere (by pressure) is equal to force due to qo on (columns law) half, sphere , sir dono sai same answer aa rha . PLZ help kigiye sir

  • @keshavbaldeva5438
    @keshavbaldeva5438 2 ปีที่แล้ว +1

    50-80 concepts in just 55 min . 🥵🥵
    The only person...... ........

  • @lethalbeetle4162
    @lethalbeetle4162 ปีที่แล้ว +2

    there was also one more hidden concept in this video that when the ink was wet it was behaving as a reflecting surface but as soon as it get dried it turned into an opaque surface

  • @AartiKumari-um5mk
    @AartiKumari-um5mk 3 ปีที่แล้ว +2

    💥That's it. No one can beat this advanced level lecture...
    💙 Extremely helpful at last moment
    🧞‍♂️ Miss you PAUG

    • @0xaryan15
      @0xaryan15 3 ปีที่แล้ว +3

      POGI**

    • @vj51
      @vj51 3 ปีที่แล้ว +1

      miss kyu

    • @manmayb6959
      @manmayb6959 3 ปีที่แล้ว

      what does it mean? and why sir says that🤔🤔

    • @0xaryan15
      @0xaryan15 3 ปีที่แล้ว

      @@manmayb6959 All have a some nick name ;)

  • @alifeforphysics2193
    @alifeforphysics2193 3 ปีที่แล้ว +4

    44:22
    4T/R = Electric Pressure
    R = 8T E° / R (sigma)^2

    • @mananarora141
      @mananarora141 3 ปีที่แล้ว

      the excess pressure inside the bubble and the electric pressure are acting in the same direction(away from centre)..... So how can u balance them ... Please elaborate....

    • @vanshkapoor8371
      @vanshkapoor8371 3 ปีที่แล้ว +2

      @@mananarora141 pressure has no direction . Pressure multiply by perpendicular area gives force.

    • @vanshkapoor8371
      @vanshkapoor8371 3 ปีที่แล้ว +1

      @@mananarora141 in simple words vo charge usko bahar push krre honge . Surface tension membrane jse usko piche ki trf khichegi as a membrane to force balance .

    • @srijeetchanda4574
      @srijeetchanda4574 3 ปีที่แล้ว +1

      @@vanshkapoor8371 thanks

    • @bruteforce8744
      @bruteforce8744 3 ปีที่แล้ว

      @@vanshkapoor8371 but if charge is absent then in that case that excess pressure prevents the bubble from collapsing. So here the role of excess pressure is reversed ?

  • @somannareddykammakattu7649
    @somannareddykammakattu7649 3 ปีที่แล้ว +5

    Back 2 back video with full dedication. Thanq sir ❤️

  • @birsajoharadivasi
    @birsajoharadivasi 3 ปีที่แล้ว

    Thank you so much Sir.
    I think without you what I would've done. You are a 'Farista' for many students. ❤

  • @mith_jain_here
    @mith_jain_here 3 ปีที่แล้ว +1

    These videos are great sir... Pls continue this series 🙏

  • @ABHISHEK-hj1br
    @ABHISHEK-hj1br 3 ปีที่แล้ว +2

    Sirrr please this checklists fasstt ASAP.....optics , modern , electrodynamics atleast ...days are very less and frequency of videos are lesss than that also🙏🙏 These booster checklists are helping me very much that's why 🙏

    • @sumeetdubey9616
      @sumeetdubey9616 3 ปีที่แล้ว

      😭😭😭😭😭 I think we are cheated sir told to complete syllabus by 26 but I don’t think it will happen

    • @devangvasishth2778
      @devangvasishth2778 3 ปีที่แล้ว

      @@sumeetdubey9616 what?? he will complete it but he already told that these are booster videos not regular class lectures like onion phy , concept videos , where he will cover every single chap separately , he will cover them in booster in broad sections , like mechanics , optics etc u have to watch revision checklist and concept videos before it yourself .

    • @sumeetdubey9616
      @sumeetdubey9616 3 ปีที่แล้ว

      @@devangvasishth2778 okay but do you think all main topics will be covered by 26?

  • @nakulmantri1235
    @nakulmantri1235 3 ปีที่แล้ว

    TILL DATE AMAZING videos sir, HATS OFF TO YOUR UNFLINCHING SERVICE TOWARDS US..!!!!!!!!!

  • @vedbrahmbhattiit-j4497
    @vedbrahmbhattiit-j4497 3 ปีที่แล้ว +2

    Thanks sir booster checklist helping us very much!!🔥👍🏻

  • @sat20y
    @sat20y 3 ปีที่แล้ว +2

    LAST WAS AWESOME AND THIS IS (AWESOME)ⁿ

  • @saikhadloya8911
    @saikhadloya8911 3 ปีที่แล้ว +3

    Sir will checklist come tomorrow?

  • @Youtuber-hm6ir
    @Youtuber-hm6ir 3 ปีที่แล้ว +5

    Sir please upload fast as you can , I know you are busy too but if you can then please upload at least two videos per day.

  • @silent1975
    @silent1975 2 ปีที่แล้ว

    Thank you sir i am watching 3 day before adv exam i wish i watched it earlier cleared all adv concepts ✨ thankyou from bottom of my heart

  • @rohitmangal8186
    @rohitmangal8186 3 ปีที่แล้ว +4

    If I go to IIT ,then credit will go to Sir 💯

  • @ShaluSingha-fp8uo
    @ShaluSingha-fp8uo 3 ปีที่แล้ว +5

    sir please increase the frequency of videos so that we can complete on time. Thank you

  • @suryanshsingh8736
    @suryanshsingh8736 9 หลายเดือนก่อน +2

    thank u so much sir bhagwan app ko padhane ke liye shakti de

  • @aryanranjan418
    @aryanranjan418 ปีที่แล้ว +1

    15:17 If no electric field lines due to the charge q inside the cavity is going out of the sphere then why is there any electric field intensity due to q at point P which is outside the sphere ?? Electric field intensity due to q at P should be zero with this logic.

    • @Anonymoususer6541
      @Anonymoususer6541 8 หลายเดือนก่อน

      Net electric field is zero,not individual field due to +q
      So net flux via metal cavity(outside of metal cavity ,i.e. in metal,and at further distances) will be zero.

  • @devsharma9038
    @devsharma9038 3 ปีที่แล้ว

    Thankyouusomuch Sir!! It's really helpful for us!👏👏👏

  • @bhupeshjoshi2381
    @bhupeshjoshi2381 3 ปีที่แล้ว +2

    At 44:16 radius is 2 e°/sigma^2 4 T

    • @Kirti-ub8zy
      @Kirti-ub8zy 2 หลายเดือนก่อน

      Bhai sigma ki terms me answer nhi de skte.....usme bhi radius involved h

  • @samaksh6564
    @samaksh6564 3 ปีที่แล้ว +2

    thank you sir
    coaching me thode doubts reh gaye the conductor se related
    aapne sab dho daale :)

  • @dhruvdhirawani2128
    @dhruvdhirawani2128 3 ปีที่แล้ว +1

    Thank u soo much sir, it really boosts our brain

  • @dilpreetsingh4269
    @dilpreetsingh4269 3 ปีที่แล้ว

    Sir your revision checklist and ncert solutions are really very helpful sir, thank your sir

  • @parthib.1555
    @parthib.1555 3 ปีที่แล้ว +1

    Thank you for all your efforts 🙏👏

  • @AditiShekhawat-ql7ll
    @AditiShekhawat-ql7ll 3 ปีที่แล้ว +3

    sir please share the timetable of this checklist series..so that we can shape our prepration accordingly..please sir

  • @mukeshvishwas9989
    @mukeshvishwas9989 3 ปีที่แล้ว +1

    Sir I am big fan of you ,more than any superstar 👌👌👌👌

  • @anshtrivedi4812
    @anshtrivedi4812 3 ปีที่แล้ว +2

    One request - Sir plz Attach a pdf of the same content
    Beside this Thank u very much For Quality Adv content 🙏

  • @bhagirathdudi8496
    @bhagirathdudi8496 3 ปีที่แล้ว +3

    It is tooo good checklist

  • @DREAM-de8bn
    @DREAM-de8bn 3 ปีที่แล้ว +10

    Sir please make these available on PG app too. Please sir. 🙏🙏

    • @dreamyadav1598
      @dreamyadav1598 3 ปีที่แล้ว +6

      Yes sir we come to watch your channel on youTube only
      And there are lot of distractions here

    • @garimaanimallover490
      @garimaanimallover490 3 ปีที่แล้ว +3

      Yes sir please.

    • @arjun8976
      @arjun8976 3 ปีที่แล้ว +1

      There is no pg app in google play store

  • @monstershield480
    @monstershield480 3 ปีที่แล้ว +7

    sir, can you please upload the schedule of the booster checklist in community section

  • @shubhamkakde4436
    @shubhamkakde4436 3 ปีที่แล้ว

    Sir you are real hero for us thank you for this amazing content 🙏🙏🙏

  • @factpoint663
    @factpoint663 3 ปีที่แล้ว +3

    Thankyou sir

  • @divyamgupta7147
    @divyamgupta7147 3 ปีที่แล้ว +3

    Sir kindly tell how to improve confidence level in these last days........
    Pls make a video on it Sir

  • @ManojKumar-hh8jv
    @ManojKumar-hh8jv 3 ปีที่แล้ว +1

    Thank you sir and pg team

  • @rishav4963
    @rishav4963 3 ปีที่แล้ว +4

    Sir jaldi se complete kara doh phir advanced for denge ❤️❤️❤️❤️❤️❤️

  • @mayurisharma11
    @mayurisharma11 ปีที่แล้ว +3

    26:00 for my revision

    • @lavanya8932
      @lavanya8932 ปีที่แล้ว

      Hey are u targeting 2023 adv?

  • @rudranathsinha1864
    @rudranathsinha1864 3 ปีที่แล้ว

    Thanks a lot sir and Pg team 🙏🙏

  • @NikhilSingh-hv3vf
    @NikhilSingh-hv3vf 3 ปีที่แล้ว +1

    Thank u sir and pg team❤️

  • @shaheem8467
    @shaheem8467 3 ปีที่แล้ว +5

    44:11 inside pressure is always greater ,how will the bubble attain equilibrium
    Edit: Anybody

    • @cyborgsharma6824
      @cyborgsharma6824 3 ปีที่แล้ว +10

      Bruh that excess pressure is which will be balanced by electric pressure
      Initially bubble wasn't charged and it had that excess pressure due to surface tension( that excess pressure is excess to atmospheric pressure) now when the bubble is given some charge it experiences electric pressure too which is initially large so it tends to expand the bubble. You see excess pressure tends to decrease with increase in radius and at equilibrium point electric pressure will balance out the excess pressure.

    • @ilickcatnip
      @ilickcatnip 3 ปีที่แล้ว

      @@cyborgsharma6824 both excess pressure and electric pressure are radially outward, they cannot cancel each other out.

    • @chahal6754
      @chahal6754 3 ปีที่แล้ว

      @@ilickcatnip yah.... that's I am asking 😅🤟

    • @rajatbisht21
      @rajatbisht21 3 ปีที่แล้ว

      @@chahal6754 The excess pressure and electric pressure will try to expand the bubbly until it the pressure inside becomes equal to outside pressure.

    • @rajatbisht21
      @rajatbisht21 3 ปีที่แล้ว +1

      @@ilickcatnip Exactly! and 10 people who liked his comment got their concept wrong 🤦🏻‍♂️

  • @himau2434
    @himau2434 3 ปีที่แล้ว +1

    Thnk u so much sir 💖💖💕💕💕💕💕💖💖

  • @paramjeetkumariitkgp6879
    @paramjeetkumariitkgp6879 3 ปีที่แล้ว +2

    Sir please add this lecture app
    It will be great help
    Thank u

  • @asabhashiitian1321
    @asabhashiitian1321 3 ปีที่แล้ว +5

    44:05 R=8£T/sigma^2

  • @priyashnamdeo8052
    @priyashnamdeo8052 3 ปีที่แล้ว +3

    Sir please share the schedule of this 2021 jee advance booster checklist

  • @adityamishraiitbhubneshwar8039
    @adityamishraiitbhubneshwar8039 3 ปีที่แล้ว +1

    Helps alot 😊😊😊😊😊

  • @drsh9397
    @drsh9397 3 ปีที่แล้ว +1

    16:32
    sir if we have a dielectric constant K of outer region of sphere (keeping the cavity at vacuum ) how will it affect the answer to the first question ?? @Physics Galaxy

  • @rkstudychannel3240
    @rkstudychannel3240 3 ปีที่แล้ว

    east and west ashish sr is best love you sir

  • @prabhashsingh6449
    @prabhashsingh6449 3 ปีที่แล้ว +9

    Fun fact - every one watching it at 1.5X + 😂😂😂😂😂🤣🤣🤣