Before watching Booster Checklists for JEE Adv, students are advised to watch Revision Checklists on all topics from links given below - All topics of Class 11 - th-cam.com/play/PLYVDsiuOZP5okVjaOFGuRkLT51-WgG95_.html All topics of Class 12 - th-cam.com/play/PLYVDsiuOZP5pp1ak489L0oaMulGzuQWQ3.html Link to all Booster Checklists for JEE(Adv) - th-cam.com/play/PLYVDsiuOZP5o7T58PG8SUiKECCzbY37J9.html Physics Galaxy Team wishes all JEE Adv aspirants BEST to perform their best in finals !
with just one year of preparation , i havent reached where i dreamt to be, thats obviously bcos of u , sir , that u motivate us to dream higher and to not compromise with our potential and its that passion that makes me fight hard even in this last moment when i know that i will fail in this attempt. i feel proud to be ur student , i have always taken ur words in my heart and thats what flows through my willpower and dedication. when all my friends had quit their adv prepn , whatever be it this time, im gonna take a drop and achieve what i dreamt, u are truly a legend sir :)
At 17:30 we must divide by 2 Also when I calculated by integrating my answer was. (3uI R^2 a^2)/ 4(x^2+a^2)^3/2 Which is definitely not same. It took a long time to not reach the same result
Honestly whenever i study physics from two legends - HC Verma sir and Ashish sir , i dont feel any complexity in physics problems and concepts . It like what are we doing yaar ! Just the application of some basic theory and basic formulas . No complex and less known results. I think this is the quality of a grest teacher that he makes the subject as easy for his student as it is for him. Thanks Ashish sir.🙏🏻🙏🏻 Note : taking in consideration only the school level or academic physics. The higher physics has a much complex nature .
(54:34) Sir thank you for explaining this beautiful concept from HCV. I was never able to solve this in my whole preparation but you explained me this (❁´◡`❁)(❁´◡`❁)
Sir the HW is very similar to an ADV ILL of electro here we'll change the limits from 0-a with a-infinity(which will give the negative of required result which is obvious) and yes sir my answer matched
37:22 , in the case where were sliding the coil , why aren't we considering energy loss due to power dissipation via induced emf , like there can be a Theoritical question made , that does the agent's external energy applied , *only goes to changing the orientation?* Here , if emf induction is also taken into consideration, we can make a whole new lot of situations
Sir my name is dhanush ..... I have a doubt at 42:41 if consider variable charge distribution then trick for calculating magnetic moment fails why ?? ..... please reply sir
@11:03 Can anyone explain me why dipole is directing towards right ..?.By using right hand thumb rule and current i direction. It has to point towards left na..
Sir at 25:28 μ(Magnetic Moment) is independent of shape. And it is calculated by I•A, to Area me to shape ki dependency aa hi gayi na sir. Fir ye kaise shape-independent hua??
for the triangular loop situation at 28:24, my calculations don't say that vertical components of force are cancelling as like sir mentioned, any help would be great thanks
ho rahe hai cancel out, for the bottom most wire calculate from the center and integrate -l/2 se l/2. 0 se l karne mai bhi koi problem nahi hai, but aise karke seedhe bina intgrate kare dikh jata hai
@@shreya2864 No. The net vertical components of forces on wire AB and AC are not equal to that on BC wire. I calculate the force on BC by integrating from -l/2 to l/2 (taking element at x from centre). According to my calculations , I am not getting the vertical forces cancelled.
Sir i think at 50:00,, by mistake u forget by 2 factor,,,i m confused,,,bcoz i cant believe any mistake by u,,,pls verify sr,,formula is u.J cross r/2,,,....🤔🤔🤔
Sir please predict (asap) NEET 2022 dates/month so that we can prepare accordingly I want NEET to be conducted in may or earlier but not later.... This uncertainty is making us very anxious
length y pe dy element ko point charge lambda.dy ki tarah treat kar sakte hain na? And it's rotating so it can be taken similar to field due to ring at axial point and then integrate. Will that work? I'm doubtful too..
At 15:53 , can't we can do is taking component of dS instead of that of B(r) and B(theta). It will make calculation easier as now B(theta) will not be in game anymore. Is it correct reply below?
When you take component of dS along Br then you also have to take another component of it perpendicular to Br which will be antiparallel to B(theta) and their dot products in integration will give the same expression to solve further.
at 21:45 shouldn't the force be zero? as using force on current element in field is coming to be radially towards the centre so net should come out zero for whole ring and also in F= dU/dr, r is not changing for different elements and is constant for all to be equal to x. like the ring is perpendicular to field so its constant field at all points so force net comes to be zero. Plz Help???
Sir, it makes sense for force to be attractive by using the concept of Br and B(theta) so net comes to be attractive so maybe its just a shorter method so does not work vector wise??
Before watching Booster Checklists for JEE Adv, students are advised to watch Revision Checklists on all topics from links given below -
All topics of Class 11 - th-cam.com/play/PLYVDsiuOZP5okVjaOFGuRkLT51-WgG95_.html
All topics of Class 12 - th-cam.com/play/PLYVDsiuOZP5pp1ak489L0oaMulGzuQWQ3.html
Link to all Booster Checklists for JEE(Adv) - th-cam.com/play/PLYVDsiuOZP5o7T58PG8SUiKECCzbY37J9.html
Physics Galaxy Team wishes all JEE Adv aspirants BEST to perform their best in finals !
Sir please tell us sir. Will the modern physics be completed within Sunday
17:32 isnt this a mistake sir,? the magnectic feild due to ring on its axis is Uo/2 but you wrote only Uo
Sir B inside a cylinder is 1/2 u°jx
50:50
@@shreepatithakur9718
Yes i also think the same
@45:15 sir what in case of solid mettalic sphere
PG Booster is more important than Kota Factory S2.
ye kab aayi?
Yes 😅
@perks you are a legend
3 October ko dekh lena, account mere se le lena 😂💪
@@shivansh709 ok bhai
Ek like Aashish Sir ke liye. Great work for every student . 🔥😀❤️.
My respect towards you has increased exponentially and the graph seems to be proceeding with speed of light. ❤
Blessed to have found you. 😊❤
graphs dont have speed. you mean slope ?
@@birsajoharadivasi 👍
asymptote occured
@@omjoglekar3677 it does... it is represented by double derivatives
11:59 same concept question came on oct3 21 (jee advanced 21)..grt sir ♥️♥️
with just one year of preparation , i havent reached where i dreamt to be, thats obviously bcos of u , sir , that u motivate us to dream higher and to not compromise with our potential and its that passion that makes me fight hard even in this last moment when i know that i will fail in this attempt. i feel proud to be ur student , i have always taken ur words in my heart and thats what flows through my willpower and dedication. when all my friends had quit their adv prepn , whatever be it this time, im gonna take a drop and achieve what i dreamt, u are truly a legend sir :)
Thank you sir for this great initiative. You are a legend seriously.
I've seen you so many times at physics galaxy and Mohit tyagi sir videos. In which clg u are now?
@@caniget600subscriberswitho5 mans a 2023 aspirant. And yeah he's been damn consistent for the last 1.5 years or so
Thank you sir .....Your contribution is almost 95% in my preparation....By the way...OP thumbnail
I was eagerly waiting for magnetism
Finally I got booster checklist
Very happy now
Thanks
47:39 it will be B=(mu not Jx/2 ),,,, I liked the concept of magnetic dipole in small coils and spheres.Thanks sir
Same , even I never used it before this video
At 17:30 we must divide by 2
Also when I calculated by integrating my answer was. (3uI R^2 a^2)/ 4(x^2+a^2)^3/2
Which is definitely not same.
It took a long time to not reach the same result
How did you integrate ? It’s getting complex
yes true, sir i think by mistake forgot dividing it by 2 as the formula for b in ring is munotir2/2x2+r23/2
Smart, Simple and Lucid way to give final touch and boost your JEE ADVANCED Preparation.
Thank you sir for this innovative initiative.
Although I am not giving jee advance this year...But happy to see great content of physics for advance available on TH-cam...👍🏻👍🏻
Very grateful for this video❤️
Thanks ashish sir
Sir these efforts of yours will surely help us exponentially during the exam times. Thanks for your kind help.
Honestly whenever i study physics from two legends - HC Verma sir and Ashish sir , i dont feel any complexity in physics problems and concepts . It like what are we doing yaar ! Just the application of some basic theory and basic formulas . No complex and less known results. I think this is the quality of a grest teacher that he makes the subject as easy for his student as it is for him.
Thanks Ashish sir.🙏🏻🙏🏻
Note : taking in consideration only the school level or academic physics. The higher physics has a much complex nature .
These videos are literally the best for final revision , all important advance concepts are covered
Thank you so much sir !!!
(54:34) Sir thank you for explaining this beautiful concept from HCV. I was never able to solve this in my whole preparation but you explained me this (❁´◡`❁)(❁´◡`❁)
Where it is given in HCV brother?
Page no.?
Coaching me nai padhaya gya??
@@nishasharma7459 Not everyone goes to coaching
@@prashik4810 In magnetic field chapter back exercise
48:00 didn't get how B=uJx mine is coming as uJx/2 using ampere's circuit law
Actually, Sir had taken 2 in account of J that's why there 2 is missing.
yes its wrong
J is I/pi r^2, its a blunder
Yes there must be 2 in denominator
Yes , need to be corrected !
You're the revolution...indeed!
hey tushar bhayi
Thank You very much sir,,, You are the god of physics 🙏🙏🙏
INSP dekhe ho ?
@@tanmaypatel981 nhi kya hai ye?
I came with the speed of light
Thanks a ton sir for the series
nerve signal speed is way less than 'c'
@@omjoglekar3677 but thought is more faster than anything that ever existed
@@MDSadiq-jc7hb agreed ! You are right.
@@MDSadiq-jc7hb it doent cover any distance so speed is still zero
Hi photon
Sir I noticed a thing, u r indeed a gr8 teacher obviously but along with that ur drawing are damn neat
Sir just enhancing the level of my prep at next level thanx
Literally saving my time
Getting time to revise chem 😁😁
Best physics content .
Really got confidence which is very important in these last days..... THANKYOU SO MUCH ASHISH SIR...
Please Sir : Also Cover Most Important Topic Rotational Dynamics 🙏🙏🙏🙏
Thanks sir...after watching gaining too much confidence....🙏🙏❣❣
Me after seeing ashish sir's knowledge😵😵😵😵
Really
he has been teaching for nearly 23-25 years experience +knowledge
@@jproy9290 yes
@@aviralsingh4548 teaching since 1992
@@siddharthsrivastava9133 i just gave a rough approximation 😅
17:32 isnt this a mistake sir,? the magnectic feild due to ring on its axis is Uo/2 but you wrote only Uo
Yes sir forget to write 2
Yess
Yes
Basic Human Error which we all do.
Yesssssss
Sir the HW is very similar to an ADV ILL of electro here we'll change the limits from 0-a with a-infinity(which will give the negative of required result which is obvious) and yes sir my answer matched
Thank you so much sir for this booster videos.
Apart from great content,
Thank you PG team for the timestamps and op thumbnails.
28:36 sir aapne bina calculate kiye kaise bola? calculate krne se to samj aa gya ki cancel ho jaega
Yes sir,this booster checklist has enhances our thinking,so much for Jee exam.
I have no word to say,
Still Thank you sir 🙏🏼🙏🏼❤☺
At 1:08:40 ans should be reciprocal
You are right.
Yes exactly 😂
37:22 , in the case where were sliding the coil , why aren't we considering energy loss due to power dissipation via induced emf , like there can be a Theoritical question made , that does the agent's external energy applied , *only goes to changing the orientation?* Here , if emf induction is also taken into consideration, we can make a whole new lot of situations
Also here in word done , current to be taken is I² , correct that thing too sir
1:02:25
This can also be simply solved using F = ilB
ma=ilb
a=ilb/m ( a is avg acceleration)
v = ideltalb/m
v = qlb/m
1:01:04 I think this question is fundamentally wrong ...Magnetic Field cannot do any work ....so how is the kinetic energy of rod increasing
Can you please explain your logic behind saying “magnetic field can’t do any work”
36:14 pe sir work likha he apne vaha sir i(1) ki jagah pe i(2) ayega na sir?
Pata chala?
50:14 sir here the term should be uo(j)a/2 right?
True
17:32 magnetic field due to loop me denominator=2(x^2+a^2)^3/2 hona chahiye ?
Hmm sahi hai 2 hoga mujhe bhi whi doubt hua tha
Sir my name is dhanush ..... I have a doubt at 42:41 if consider variable charge distribution then trick for calculating magnetic moment fails why ?? ..... please reply sir
this formula works only for uniform charge and mass distribution. that is to be kept in mind.
Thankyou sir totally mind blowi g...happy teachers day to you...your techniques have improved my jee prep a lott🤩🤩😁
Thank you Sir. Advanced ke pehle mast revision hogaya
Thank you so much sir for these checklists.
30:02 sir has written df cos 30 but he did not put the value of cos 30 in the expression. Can someone please explain
by mistake
41:00 is the element a ring???
Thank you for helping us until the end sir♥️
Confidence booster 🔥🔥🔥🔥🔥 thank you sir
Sir at 47:50 B should be mu(j×x)/2 please deal with my confusion
Yes B inside is uJx/2
Yes bhai🤔🤔
36:42 sir what do you mean by magnitude only ??
Agar flux ki value negative aayi integration krke to kya usse positive legein
In 1:10:37 we added another wire with reverse current right....
Should we consider that as well for calculating the magnetic field??
Thank you so much sir ❤❤❤❤
U r the best sir 🙏
Waiting for modern !!
sir i think magnetic field inside current wire should be uoJx/2
@11:03 Can anyone explain me why dipole is directing towards right ..?.By using right hand thumb rule and current i direction. It has to point towards left na..
yes itshould be from -m to +m
The thumbnail image makes it look even more interesting 👍👍❤
@55:44 upon 2 bhi aaega na net mag field me?
Sir at 25:28 μ(Magnetic Moment) is independent of shape. And it is calculated by I•A, to Area me to shape ki dependency aa hi gayi na sir. Fir ye kaise shape-independent hua??
whatever be the shape of the coil , it must enclose same area.
Thank you so much sir for advanced booster checklist. It is really helping a lot sir.🙏🙏
47.35
Magnetic field inside the cylinder is
B = uJx/2
for the triangular loop situation at 28:24, my calculations don't say that vertical components of force are cancelling as like sir mentioned, any help would be great
thanks
Yeah ... I also think that vertical components will not cancel as vertical component due to left side will be more as compared to right one
ho rahe hai cancel out, for the bottom most wire calculate from the center and integrate -l/2 se l/2. 0 se l karne mai bhi koi problem nahi hai, but aise karke seedhe bina intgrate kare dikh jata hai
@@shreya2864 can you please type in the FULL solution ?
@@shreya2864 No. The net vertical components of forces on wire AB and AC are not equal to that on BC wire. I calculate the force on BC by integrating from -l/2 to l/2 (taking element at x from centre).
According to my calculations , I am not getting the vertical forces cancelled.
My calculations too
Thank you sir!
Please shower your blessings🙏
Sir ek session modern physics pe jaroor rakhiye
Sir i think at 50:00,, by mistake u forget by 2 factor,,,i m confused,,,bcoz i cant believe any mistake by u,,,pls verify sr,,formula is u.J cross r/2,,,....🤔🤔🤔
Sir at 41:12 , is the point P perpendicular to the plane of the rotation of the rod or both are in same plane ??
Perpendicular
@@poojanshah9636 Are you in IITD?
Yes
Studied from Allen ahmd
@@poojanshah9636 Great ! I'm from IITD too
current* change in magnetic flux = work done ?? 37:17
At 36:34 shouldn't it be i2 multiplied change in flux?
Yeah ig
Thanks sir....plz give me wishes for jee adv😄🌸🙏
All the best!
At 1:00:00 is the time period. ..........,..... π√(qB/m)
Sir please predict (asap) NEET 2022 dates/month so that we can prepare accordingly
I want NEET to be conducted in may or earlier but not later....
This uncertainty is making us very anxious
At 15:45 shouldn’t the integration be from -a to +a?
Nono… as we have taken area as 2pi*y, I.e, an entire ring and not semi ring… if we took area as pi*y only then we would have to put limits -a to +a
Or even better explanation to it can be that we’re moving from centre to circumference… not from one end point on diameter to other
@@kshitijvispute6792 ok…thank you so much for clearing my doubt…😀
@@kshitijvispute6792 thank you, i understood now☺️
35:54 pe i2 aayega na sir??
at 1:03:13 have we assumed that induced emf due to velocity in the magnetic field is zero?
Yrah that's what i was thinking
Thank you so much sir for helping us to prepare for advance ☺️.
Thank you sir 🙏
41:14 pe..jaise disc pr element rimg mana tha..rod pr element leke,,kaisa mangene use? Integrate krne ke liye
length y pe dy element ko point charge lambda.dy ki tarah treat kar sakte hain na? And it's rotating so it can be taken similar to field due to ring at axial point and then integrate. Will that work? I'm doubtful too..
@@shreyarajagopalan4798 haa mujhe bhi wahi lgra tha,,dq wagar toh nikl gya pr ring man skte h ya nai,,doubt hora
@@akshatjain4096 I guess we can. Aur koi option toh nahi dikh rha hai.
37:00 sir yahan pe I1 ana chahiya na workdone mein
Koi confirm karo
Nai I hi ayega because current through loop lete hai
Your explanation is as Good as Butter 🧈😋
1:01:26 why we dont consider induced emf in rod...
Superb
At 15:53 , can't we can do is taking component of dS instead of that of B(r) and B(theta). It will make calculation easier as now B(theta) will not be in game anymore. Is it correct reply below?
When you take component of dS along Br then you also have to take another component of it perpendicular to Br which will be antiparallel to B(theta) and their dot products in integration will give the same expression to solve further.
@@jashan_iitroorkee That's why I'm getting wrong result by it. Thanks
18:39 divide me 2 bhi aayega, uIR²/2r³
1:08:45 time priod is incorrect
sir ulta likh diye
49:00 it is 1/2 uJx
Yess i was also thinking that so came to check the comments
Still relevant in 2024 love this series
Sir at 1:01:39 motional emf must be considered na
Same doubt
Sir at 17:10 phi should be mu(not)/2 or only mu(not)
mu(not)/2 according to the formula
:') thank you I was looking for this
Though I am neet aspirant. Thank you Ashish sir for the quality content of jee advanced 😊
Sir thank you very much 😊😊😊😊😊😊
at 21:45 shouldn't the force be zero? as using force on current element in field is coming to be radially towards the centre so net should come out zero for whole ring and also in F= dU/dr, r is not changing for different elements and is constant for all to be equal to x. like the ring is perpendicular to field so its constant field at all points so force net comes to be zero. Plz Help???
Sir, it makes sense for force to be attractive by using the concept of Br and B(theta) so net comes to be attractive so maybe its just a shorter method so does not work vector wise??
@Sagar HR exactly bro, I also thought same after some time, btw thanks for the help
@Sagar HR same to u bro.., thank u
sir mechanics booster checklist please
neet 2022 walo ka liya bhi kuch video banao n sir plz reply sir
Thumbnail is also next level like your teachings thank you sir
Thank you very much sir🥳🥳🥳🥳
Is this helpful for 2022 aspirants ?
should i watch the lectures for jee 2023 ????????????
Yes bro i also watch for adv 2023
@@nandanbhole123 98.85