Magnetism for JEE Advanced | Booster Checklist 10

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  • เผยแพร่เมื่อ 24 ธ.ค. 2024

ความคิดเห็น • 475

  • @physicsgalaxyworld
    @physicsgalaxyworld  3 ปีที่แล้ว +46

    Before watching Booster Checklists for JEE Adv, students are advised to watch Revision Checklists on all topics from links given below -
    All topics of Class 11 - th-cam.com/play/PLYVDsiuOZP5okVjaOFGuRkLT51-WgG95_.html
    All topics of Class 12 - th-cam.com/play/PLYVDsiuOZP5pp1ak489L0oaMulGzuQWQ3.html
    Link to all Booster Checklists for JEE(Adv) - th-cam.com/play/PLYVDsiuOZP5o7T58PG8SUiKECCzbY37J9.html
    Physics Galaxy Team wishes all JEE Adv aspirants BEST to perform their best in finals !

    • @srichinnu4680
      @srichinnu4680 3 ปีที่แล้ว +2

      Sir please tell us sir. Will the modern physics be completed within Sunday

    • @shreepatithakur9718
      @shreepatithakur9718 3 ปีที่แล้ว +4

      17:32 isnt this a mistake sir,? the magnectic feild due to ring on its axis is Uo/2 but you wrote only Uo

    • @sayedshoaibabunasar8113
      @sayedshoaibabunasar8113 3 ปีที่แล้ว +5

      Sir B inside a cylinder is 1/2 u°jx
      50:50

    • @sayedshoaibabunasar8113
      @sayedshoaibabunasar8113 3 ปีที่แล้ว +4

      @@shreepatithakur9718
      Yes i also think the same

    • @gourishsinghal6952
      @gourishsinghal6952 3 ปีที่แล้ว

      @45:15 sir what in case of solid mettalic sphere

  • @perks7040
    @perks7040 3 ปีที่แล้ว +404

    PG Booster is more important than Kota Factory S2.

    • @amit3239
      @amit3239 3 ปีที่แล้ว +6

      ye kab aayi?

    • @rudra_vaidya573
      @rudra_vaidya573 3 ปีที่แล้ว +1

      Yes 😅

    • @tomcat1184
      @tomcat1184 3 ปีที่แล้ว +3

      @perks you are a legend

    • @shivansh709
      @shivansh709 3 ปีที่แล้ว +9

      3 October ko dekh lena, account mere se le lena 😂💪

    • @vanshgarg9713
      @vanshgarg9713 3 ปีที่แล้ว +1

      @@shivansh709 ok bhai

  • @SunilKumar-ys9dc
    @SunilKumar-ys9dc 3 ปีที่แล้ว +47

    Ek like Aashish Sir ke liye. Great work for every student . 🔥😀❤️.

  • @birsajoharadivasi
    @birsajoharadivasi 3 ปีที่แล้ว +138

    My respect towards you has increased exponentially and the graph seems to be proceeding with speed of light. ❤
    Blessed to have found you. 😊❤

    • @omjoglekar3677
      @omjoglekar3677 3 ปีที่แล้ว +10

      graphs dont have speed. you mean slope ?

    • @studyonly9857
      @studyonly9857 3 ปีที่แล้ว +4

      @@birsajoharadivasi 👍

    • @Gurps7
      @Gurps7 3 ปีที่แล้ว +4

      asymptote occured

    • @jeeaccountkedharsaiganesh6532
      @jeeaccountkedharsaiganesh6532 7 หลายเดือนก่อน

      @@omjoglekar3677 it does... it is represented by double derivatives

  • @kkanhajee6613
    @kkanhajee6613 2 ปีที่แล้ว +19

    11:59 same concept question came on oct3 21 (jee advanced 21)..grt sir ♥️♥️

  • @harinandanks3786
    @harinandanks3786 3 ปีที่แล้ว +13

    with just one year of preparation , i havent reached where i dreamt to be, thats obviously bcos of u , sir , that u motivate us to dream higher and to not compromise with our potential and its that passion that makes me fight hard even in this last moment when i know that i will fail in this attempt. i feel proud to be ur student , i have always taken ur words in my heart and thats what flows through my willpower and dedication. when all my friends had quit their adv prepn , whatever be it this time, im gonna take a drop and achieve what i dreamt, u are truly a legend sir :)

  • @alphaiitd1
    @alphaiitd1 3 ปีที่แล้ว +95

    Thank you sir for this great initiative. You are a legend seriously.

    • @caniget600subscriberswitho5
      @caniget600subscriberswitho5 ปีที่แล้ว

      I've seen you so many times at physics galaxy and Mohit tyagi sir videos. In which clg u are now?

    • @ayzzart899
      @ayzzart899 ปีที่แล้ว

      @@caniget600subscriberswitho5 mans a 2023 aspirant. And yeah he's been damn consistent for the last 1.5 years or so

  • @anirudhac2004
    @anirudhac2004 3 ปีที่แล้ว +20

    Thank you sir .....Your contribution is almost 95% in my preparation....By the way...OP thumbnail

  • @deepashreek3358
    @deepashreek3358 3 ปีที่แล้ว +35

    I was eagerly waiting for magnetism
    Finally I got booster checklist
    Very happy now

  • @ayushkumarprasad6832
    @ayushkumarprasad6832 2 ปีที่แล้ว +2

    Thanks

  • @ananyapandey9271
    @ananyapandey9271 ปีที่แล้ว +27

    47:39 it will be B=(mu not Jx/2 ),,,, I liked the concept of magnetic dipole in small coils and spheres.Thanks sir

    • @ArthBachhuka
      @ArthBachhuka 8 หลายเดือนก่อน

      Same , even I never used it before this video

  • @ashermustafa3235
    @ashermustafa3235 2 ปีที่แล้ว +9

    At 17:30 we must divide by 2
    Also when I calculated by integrating my answer was. (3uI R^2 a^2)/ 4(x^2+a^2)^3/2
    Which is definitely not same.
    It took a long time to not reach the same result

    • @kshitijvispute6792
      @kshitijvispute6792 2 ปีที่แล้ว +1

      How did you integrate ? It’s getting complex

    • @imabhishek028
      @imabhishek028 ปีที่แล้ว +2

      yes true, sir i think by mistake forgot dividing it by 2 as the formula for b in ring is munotir2/2x2+r23/2

  • @vignesh8261
    @vignesh8261 2 ปีที่แล้ว +5

    Smart, Simple and Lucid way to give final touch and boost your JEE ADVANCED Preparation.
    Thank you sir for this innovative initiative.

  • @visheshagrawal8196
    @visheshagrawal8196 3 ปีที่แล้ว +8

    Although I am not giving jee advance this year...But happy to see great content of physics for advance available on TH-cam...👍🏻👍🏻

  • @rahulawananimali3242
    @rahulawananimali3242 3 ปีที่แล้ว +13

    Very grateful for this video❤️
    Thanks ashish sir

  • @dnhdfnfkrjxjxfjjggj3002
    @dnhdfnfkrjxjxfjjggj3002 3 ปีที่แล้ว +10

    Sir these efforts of yours will surely help us exponentially during the exam times. Thanks for your kind help.

  • @shivanshsumitkumarsharma1126
    @shivanshsumitkumarsharma1126 7 หลายเดือนก่อน +5

    Honestly whenever i study physics from two legends - HC Verma sir and Ashish sir , i dont feel any complexity in physics problems and concepts . It like what are we doing yaar ! Just the application of some basic theory and basic formulas . No complex and less known results. I think this is the quality of a grest teacher that he makes the subject as easy for his student as it is for him.
    Thanks Ashish sir.🙏🏻🙏🏻
    Note : taking in consideration only the school level or academic physics. The higher physics has a much complex nature .

  • @parthsaboo7832
    @parthsaboo7832 3 ปีที่แล้ว +5

    These videos are literally the best for final revision , all important advance concepts are covered
    Thank you so much sir !!!

  • @Gurps7
    @Gurps7 3 ปีที่แล้ว +60

    (54:34) Sir thank you for explaining this beautiful concept from HCV. I was never able to solve this in my whole preparation but you explained me this (❁´◡`❁)(❁´◡`❁)

    • @prashik4810
      @prashik4810 3 ปีที่แล้ว +4

      Where it is given in HCV brother?

    • @prashik4810
      @prashik4810 3 ปีที่แล้ว +4

      Page no.?

    • @nishasharma7459
      @nishasharma7459 3 ปีที่แล้ว

      Coaching me nai padhaya gya??

    • @Gurps7
      @Gurps7 3 ปีที่แล้ว +5

      @@nishasharma7459 Not everyone goes to coaching

    • @Gurps7
      @Gurps7 3 ปีที่แล้ว +3

      @@prashik4810 In magnetic field chapter back exercise

  • @MayankGoel447
    @MayankGoel447 3 ปีที่แล้ว +38

    48:00 didn't get how B=uJx mine is coming as uJx/2 using ampere's circuit law

    • @adityanithariya
      @adityanithariya 3 ปีที่แล้ว +4

      Actually, Sir had taken 2 in account of J that's why there 2 is missing.

    • @Gurps7
      @Gurps7 3 ปีที่แล้ว +2

      yes its wrong

    • @shreya2864
      @shreya2864 3 ปีที่แล้ว +1

      J is I/pi r^2, its a blunder

    • @sreedharreddyabbidi5374
      @sreedharreddyabbidi5374 3 ปีที่แล้ว +3

      Yes there must be 2 in denominator

    • @Yes_i_dont_care
      @Yes_i_dont_care ปีที่แล้ว +1

      Yes , need to be corrected !

  • @tusharsaharan697
    @tusharsaharan697 3 ปีที่แล้ว +18

    You're the revolution...indeed!

    • @ayush1643
      @ayush1643 3 ปีที่แล้ว

      hey tushar bhayi

  • @krrishkhandelwal4350
    @krrishkhandelwal4350 3 ปีที่แล้ว +18

    Thank You very much sir,,, You are the god of physics 🙏🙏🙏

  • @MDSadiq-jc7hb
    @MDSadiq-jc7hb 3 ปีที่แล้ว +25

    I came with the speed of light
    Thanks a ton sir for the series

    • @omjoglekar3677
      @omjoglekar3677 3 ปีที่แล้ว +4

      nerve signal speed is way less than 'c'

    • @MDSadiq-jc7hb
      @MDSadiq-jc7hb 3 ปีที่แล้ว +3

      @@omjoglekar3677 but thought is more faster than anything that ever existed

    • @omjoglekar3677
      @omjoglekar3677 3 ปีที่แล้ว +2

      @@MDSadiq-jc7hb agreed ! You are right.

    • @harshgupta_india
      @harshgupta_india 3 ปีที่แล้ว +3

      @@MDSadiq-jc7hb it doent cover any distance so speed is still zero

    • @allipse8224
      @allipse8224 3 ปีที่แล้ว +3

      Hi photon

  • @mightyshashank465
    @mightyshashank465 2 ปีที่แล้ว +4

    Sir I noticed a thing, u r indeed a gr8 teacher obviously but along with that ur drawing are damn neat

  • @25amanraj49
    @25amanraj49 3 ปีที่แล้ว +6

    Sir just enhancing the level of my prep at next level thanx

  • @vedantjadhao8117
    @vedantjadhao8117 3 ปีที่แล้ว +6

    Literally saving my time
    Getting time to revise chem 😁😁

  • @varadpatil3715
    @varadpatil3715 3 ปีที่แล้ว +7

    Best physics content .

  • @aayushagrawal2915
    @aayushagrawal2915 3 ปีที่แล้ว +7

    Really got confidence which is very important in these last days..... THANKYOU SO MUCH ASHISH SIR...

  • @beingsurfers
    @beingsurfers 3 ปีที่แล้ว +19

    Please Sir : Also Cover Most Important Topic Rotational Dynamics 🙏🙏🙏🙏

  • @nerdengineers0609
    @nerdengineers0609 3 ปีที่แล้ว +4

    Thanks sir...after watching gaining too much confidence....🙏🙏❣❣

  • @siddharthsrivastava9133
    @siddharthsrivastava9133 3 ปีที่แล้ว +53

    Me after seeing ashish sir's knowledge😵😵😵😵

  • @shreepatithakur9718
    @shreepatithakur9718 3 ปีที่แล้ว +24

    17:32 isnt this a mistake sir,? the magnectic feild due to ring on its axis is Uo/2 but you wrote only Uo

  • @baba-bhaukali1070
    @baba-bhaukali1070 3 ปีที่แล้ว +4

    Sir the HW is very similar to an ADV ILL of electro here we'll change the limits from 0-a with a-infinity(which will give the negative of required result which is obvious) and yes sir my answer matched

  • @aakanksha0327
    @aakanksha0327 3 ปีที่แล้ว +1

    Thank you so much sir for this booster videos.
    Apart from great content,
    Thank you PG team for the timestamps and op thumbnails.

  • @Anshita-kj8en
    @Anshita-kj8en 2 ปีที่แล้ว +3

    28:36 sir aapne bina calculate kiye kaise bola? calculate krne se to samj aa gya ki cancel ho jaega

  • @manirajchhn
    @manirajchhn 2 ปีที่แล้ว +3

    Yes sir,this booster checklist has enhances our thinking,so much for Jee exam.
    I have no word to say,
    Still Thank you sir 🙏🏼🙏🏼❤☺

  • @SahilKumar-qf3xp
    @SahilKumar-qf3xp 3 ปีที่แล้ว +10

    At 1:08:40 ans should be reciprocal

  • @student_here
    @student_here ปีที่แล้ว +1

    37:22 , in the case where were sliding the coil , why aren't we considering energy loss due to power dissipation via induced emf , like there can be a Theoritical question made , that does the agent's external energy applied , *only goes to changing the orientation?* Here , if emf induction is also taken into consideration, we can make a whole new lot of situations

    • @student_here
      @student_here ปีที่แล้ว

      Also here in word done , current to be taken is I² , correct that thing too sir

  • @Gh0styyyy999
    @Gh0styyyy999 7 หลายเดือนก่อน +1

    1:02:25
    This can also be simply solved using F = ilB
    ma=ilb
    a=ilb/m ( a is avg acceleration)
    v = ideltalb/m
    v = qlb/m

  • @shubhammishra5959
    @shubhammishra5959 2 ปีที่แล้ว +2

    1:01:04 I think this question is fundamentally wrong ...Magnetic Field cannot do any work ....so how is the kinetic energy of rod increasing

    • @kshitijvispute6792
      @kshitijvispute6792 2 ปีที่แล้ว

      Can you please explain your logic behind saying “magnetic field can’t do any work”

  • @nishitsarvaiya5471
    @nishitsarvaiya5471 3 ปีที่แล้ว +5

    36:14 pe sir work likha he apne vaha sir i(1) ki jagah pe i(2) ayega na sir?

  • @sakethsreeni
    @sakethsreeni 3 ปีที่แล้ว +5

    50:14 sir here the term should be uo(j)a/2 right?

  • @devjeetsingh10tha30
    @devjeetsingh10tha30 7 หลายเดือนก่อน +2

    17:32 magnetic field due to loop me denominator=2(x^2+a^2)^3/2 hona chahiye ?

  • @crackcompetition4751
    @crackcompetition4751 2 ปีที่แล้ว +2

    Sir my name is dhanush ..... I have a doubt at 42:41 if consider variable charge distribution then trick for calculating magnetic moment fails why ?? ..... please reply sir

    • @AnuragVerma-is9wm
      @AnuragVerma-is9wm 10 หลายเดือนก่อน

      this formula works only for uniform charge and mass distribution. that is to be kept in mind.

  • @calculus3097
    @calculus3097 2 ปีที่แล้ว +1

    Thankyou sir totally mind blowi g...happy teachers day to you...your techniques have improved my jee prep a lott🤩🤩😁

  • @sashidhar3699
    @sashidhar3699 3 ปีที่แล้ว +2

    Thank you Sir. Advanced ke pehle mast revision hogaya

  • @tilakrajdixit553
    @tilakrajdixit553 3 ปีที่แล้ว +2

    Thank you so much sir for these checklists.

  • @J_S_P_
    @J_S_P_ ปีที่แล้ว +2

    30:02 sir has written df cos 30 but he did not put the value of cos 30 in the expression. Can someone please explain

  • @nishchaykumar6536
    @nishchaykumar6536 2 ปีที่แล้ว +3

    41:00 is the element a ring???

  • @vishalpandey5326
    @vishalpandey5326 3 ปีที่แล้ว +3

    Thank you for helping us until the end sir♥️

  • @jeeadvanced1230
    @jeeadvanced1230 3 ปีที่แล้ว +2

    Confidence booster 🔥🔥🔥🔥🔥 thank you sir

  • @priyankpankaj6274
    @priyankpankaj6274 3 ปีที่แล้ว +4

    Sir at 47:50 B should be mu(j×x)/2 please deal with my confusion

  • @abhayk7996
    @abhayk7996 2 ปีที่แล้ว +1

    36:42 sir what do you mean by magnitude only ??
    Agar flux ki value negative aayi integration krke to kya usse positive legein

  • @rpcrudrapriyachoudhari5542
    @rpcrudrapriyachoudhari5542 ปีที่แล้ว

    In 1:10:37 we added another wire with reverse current right....
    Should we consider that as well for calculating the magnetic field??

  • @NikH710
    @NikH710 ปีที่แล้ว +2

    Thank you so much sir ❤❤❤❤

  • @RuchikaAgarwal-du4yz
    @RuchikaAgarwal-du4yz 7 หลายเดือนก่อน +1

    U r the best sir 🙏

  • @vedant6598
    @vedant6598 3 ปีที่แล้ว +7

    Waiting for modern !!

  • @vijoyprasad9855
    @vijoyprasad9855 ปีที่แล้ว +2

    sir i think magnetic field inside current wire should be uoJx/2

  • @ramanibendi4564
    @ramanibendi4564 3 ปีที่แล้ว +1

    @11:03 Can anyone explain me why dipole is directing towards right ..?.By using right hand thumb rule and current i direction. It has to point towards left na..

    • @ashisharora996
      @ashisharora996 3 ปีที่แล้ว

      yes itshould be from -m to +m

  • @tomcat1184
    @tomcat1184 3 ปีที่แล้ว +6

    The thumbnail image makes it look even more interesting 👍👍❤

  • @Ayush-if6hh
    @Ayush-if6hh ปีที่แล้ว +1

    @55:44 upon 2 bhi aaega na net mag field me?

  • @hardikbhandari0097
    @hardikbhandari0097 3 ปีที่แล้ว +1

    Sir at 25:28 μ(Magnetic Moment) is independent of shape. And it is calculated by I•A, to Area me to shape ki dependency aa hi gayi na sir. Fir ye kaise shape-independent hua??

    • @imPriyansh77
      @imPriyansh77 3 ปีที่แล้ว

      whatever be the shape of the coil , it must enclose same area.

  • @shouryapriyavrat4579
    @shouryapriyavrat4579 3 ปีที่แล้ว +7

    Thank you so much sir for advanced booster checklist. It is really helping a lot sir.🙏🙏

  • @AllInone-em8ue
    @AllInone-em8ue 9 หลายเดือนก่อน

    47.35
    Magnetic field inside the cylinder is
    B = uJx/2

  • @pranetamahawar7898
    @pranetamahawar7898 3 ปีที่แล้ว +2

    for the triangular loop situation at 28:24, my calculations don't say that vertical components of force are cancelling as like sir mentioned, any help would be great
    thanks

    • @JustARegularEverydayNormalGuy
      @JustARegularEverydayNormalGuy 3 ปีที่แล้ว +1

      Yeah ... I also think that vertical components will not cancel as vertical component due to left side will be more as compared to right one

    • @shreya2864
      @shreya2864 3 ปีที่แล้ว

      ho rahe hai cancel out, for the bottom most wire calculate from the center and integrate -l/2 se l/2. 0 se l karne mai bhi koi problem nahi hai, but aise karke seedhe bina intgrate kare dikh jata hai

    • @pranetamahawar7898
      @pranetamahawar7898 3 ปีที่แล้ว

      @@shreya2864 can you please type in the FULL solution ?

    • @imPriyansh77
      @imPriyansh77 3 ปีที่แล้ว

      @@shreya2864 No. The net vertical components of forces on wire AB and AC are not equal to that on BC wire. I calculate the force on BC by integrating from -l/2 to l/2 (taking element at x from centre).
      According to my calculations , I am not getting the vertical forces cancelled.

    • @imPriyansh77
      @imPriyansh77 3 ปีที่แล้ว

      My calculations too

  • @cyborgsharma6824
    @cyborgsharma6824 3 ปีที่แล้ว

    Thank you sir!
    Please shower your blessings🙏

  • @_..rajpal
    @_..rajpal 3 ปีที่แล้ว +5

    Sir ek session modern physics pe jaroor rakhiye

  • @yourbro806
    @yourbro806 3 ปีที่แล้ว +2

    Sir i think at 50:00,, by mistake u forget by 2 factor,,,i m confused,,,bcoz i cant believe any mistake by u,,,pls verify sr,,formula is u.J cross r/2,,,....🤔🤔🤔

  • @imPriyansh77
    @imPriyansh77 3 ปีที่แล้ว +1

    Sir at 41:12 , is the point P perpendicular to the plane of the rotation of the rod or both are in same plane ??

    • @poojanshah9636
      @poojanshah9636 ปีที่แล้ว

      Perpendicular

    • @imPriyansh77
      @imPriyansh77 ปีที่แล้ว

      @@poojanshah9636 Are you in IITD?

    • @poojanshah9636
      @poojanshah9636 ปีที่แล้ว

      Yes
      Studied from Allen ahmd

    • @imPriyansh77
      @imPriyansh77 ปีที่แล้ว +1

      @@poojanshah9636 Great ! I'm from IITD too

  • @pandemayank
    @pandemayank หลายเดือนก่อน

    current* change in magnetic flux = work done ?? 37:17

  • @intelligenceworld4506
    @intelligenceworld4506 3 ปีที่แล้ว +3

    At 36:34 shouldn't it be i2 multiplied change in flux?

  • @krishnmay
    @krishnmay 3 ปีที่แล้ว +3

    Thanks sir....plz give me wishes for jee adv😄🌸🙏

  • @ashermustafa3235
    @ashermustafa3235 2 ปีที่แล้ว

    At 1:00:00 is the time period. ..........,..... π√(qB/m)

  • @vibs5
    @vibs5 3 ปีที่แล้ว +2

    Sir please predict (asap) NEET 2022 dates/month so that we can prepare accordingly
    I want NEET to be conducted in may or earlier but not later....
    This uncertainty is making us very anxious

  • @unknown6648
    @unknown6648 2 ปีที่แล้ว +1

    At 15:45 shouldn’t the integration be from -a to +a?

    • @kshitijvispute6792
      @kshitijvispute6792 2 ปีที่แล้ว +1

      Nono… as we have taken area as 2pi*y, I.e, an entire ring and not semi ring… if we took area as pi*y only then we would have to put limits -a to +a

    • @kshitijvispute6792
      @kshitijvispute6792 2 ปีที่แล้ว +1

      Or even better explanation to it can be that we’re moving from centre to circumference… not from one end point on diameter to other

    • @unknown6648
      @unknown6648 2 ปีที่แล้ว

      @@kshitijvispute6792 ok…thank you so much for clearing my doubt…😀

    • @unknown6648
      @unknown6648 2 ปีที่แล้ว

      @@kshitijvispute6792 thank you, i understood now☺️

  • @Hemrajmeena_3893
    @Hemrajmeena_3893 2 ปีที่แล้ว +2

    35:54 pe i2 aayega na sir??

  • @samarthbhatnagar7031
    @samarthbhatnagar7031 ปีที่แล้ว

    at 1:03:13 have we assumed that induced emf due to velocity in the magnetic field is zero?

    • @alpha_x6950
      @alpha_x6950 ปีที่แล้ว

      Yrah that's what i was thinking

  • @peakstar3943
    @peakstar3943 3 ปีที่แล้ว +1

    Thank you so much sir for helping us to prepare for advance ☺️.

  • @rohandhiman-xo6km
    @rohandhiman-xo6km ปีที่แล้ว +1

    Thank you sir 🙏

  • @akshatjain4096
    @akshatjain4096 3 ปีที่แล้ว

    41:14 pe..jaise disc pr element rimg mana tha..rod pr element leke,,kaisa mangene use? Integrate krne ke liye

    • @shreyarajagopalan4798
      @shreyarajagopalan4798 3 ปีที่แล้ว +1

      length y pe dy element ko point charge lambda.dy ki tarah treat kar sakte hain na? And it's rotating so it can be taken similar to field due to ring at axial point and then integrate. Will that work? I'm doubtful too..

    • @akshatjain4096
      @akshatjain4096 3 ปีที่แล้ว

      @@shreyarajagopalan4798 haa mujhe bhi wahi lgra tha,,dq wagar toh nikl gya pr ring man skte h ya nai,,doubt hora

    • @shreyarajagopalan4798
      @shreyarajagopalan4798 3 ปีที่แล้ว

      @@akshatjain4096 I guess we can. Aur koi option toh nahi dikh rha hai.

  • @ashutosh77577
    @ashutosh77577 7 หลายเดือนก่อน +1

    37:00 sir yahan pe I1 ana chahiya na workdone mein
    Koi confirm karo

    • @mutual6632
      @mutual6632 7 หลายเดือนก่อน

      Nai I hi ayega because current through loop lete hai

  • @shyamkarthikeya4769
    @shyamkarthikeya4769 3 ปีที่แล้ว +1

    Your explanation is as Good as Butter 🧈😋

  • @sakinahusain3246
    @sakinahusain3246 9 หลายเดือนก่อน

    1:01:26 why we dont consider induced emf in rod...

  • @thenativefrequencies
    @thenativefrequencies 7 หลายเดือนก่อน

    Superb

  • @adityanithariya
    @adityanithariya 3 ปีที่แล้ว

    At 15:53 , can't we can do is taking component of dS instead of that of B(r) and B(theta). It will make calculation easier as now B(theta) will not be in game anymore. Is it correct reply below?

    • @jashan_iitroorkee
      @jashan_iitroorkee 3 ปีที่แล้ว

      When you take component of dS along Br then you also have to take another component of it perpendicular to Br which will be antiparallel to B(theta) and their dot products in integration will give the same expression to solve further.

    • @adityanithariya
      @adityanithariya 3 ปีที่แล้ว

      @@jashan_iitroorkee That's why I'm getting wrong result by it. Thanks

  • @zzzyyyxxxvvv
    @zzzyyyxxxvvv 3 ปีที่แล้ว +2

    18:39 divide me 2 bhi aayega, uIR²/2r³

  • @AmitGupta-t2w
    @AmitGupta-t2w ปีที่แล้ว +2

    1:08:45 time priod is incorrect

  • @sanidhyas3s
    @sanidhyas3s 3 ปีที่แล้ว +1

    49:00 it is 1/2 uJx

    • @sjd9092
      @sjd9092 3 ปีที่แล้ว +2

      Yess i was also thinking that so came to check the comments

  • @Karn6996
    @Karn6996 7 หลายเดือนก่อน

    Still relevant in 2024 love this series

  • @jeeadvanced1230
    @jeeadvanced1230 3 ปีที่แล้ว +2

    Sir at 1:01:39 motional emf must be considered na

  • @ayushs_2k4
    @ayushs_2k4 3 ปีที่แล้ว +2

    Sir at 17:10 phi should be mu(not)/2 or only mu(not)

    • @adityanithariya
      @adityanithariya 3 ปีที่แล้ว +1

      mu(not)/2 according to the formula

    • @shreya2864
      @shreya2864 3 ปีที่แล้ว

      :') thank you I was looking for this

  • @harshalgangwe4341
    @harshalgangwe4341 3 ปีที่แล้ว +8

    Though I am neet aspirant. Thank you Ashish sir for the quality content of jee advanced 😊

  • @potu6534
    @potu6534 2 ปีที่แล้ว +1

    Sir thank you very much 😊😊😊😊😊😊

  • @pranavkhetarpal5577
    @pranavkhetarpal5577 3 ปีที่แล้ว

    at 21:45 shouldn't the force be zero? as using force on current element in field is coming to be radially towards the centre so net should come out zero for whole ring and also in F= dU/dr, r is not changing for different elements and is constant for all to be equal to x. like the ring is perpendicular to field so its constant field at all points so force net comes to be zero. Plz Help???

    • @pranavkhetarpal5577
      @pranavkhetarpal5577 3 ปีที่แล้ว

      Sir, it makes sense for force to be attractive by using the concept of Br and B(theta) so net comes to be attractive so maybe its just a shorter method so does not work vector wise??

    • @pranavkhetarpal5577
      @pranavkhetarpal5577 3 ปีที่แล้ว

      @Sagar HR exactly bro, I also thought same after some time, btw thanks for the help

    • @pranavkhetarpal5577
      @pranavkhetarpal5577 3 ปีที่แล้ว

      @Sagar HR same to u bro.., thank u

  • @Anshita-kj8en
    @Anshita-kj8en 2 ปีที่แล้ว +2

    sir mechanics booster checklist please

  • @omrathi5640
    @omrathi5640 3 ปีที่แล้ว +1

    neet 2022 walo ka liya bhi kuch video banao n sir plz reply sir

  • @parthshekhawat9778
    @parthshekhawat9778 3 ปีที่แล้ว +3

    Thumbnail is also next level like your teachings thank you sir

  • @Fighter_Believer_Achiever
    @Fighter_Believer_Achiever 2 ปีที่แล้ว

    Thank you very much sir🥳🥳🥳🥳

  • @shubhanshigupta5575
    @shubhanshigupta5575 3 ปีที่แล้ว +2

    Is this helpful for 2022 aspirants ?

  • @jeeprep-gj2jv
    @jeeprep-gj2jv ปีที่แล้ว +3

    should i watch the lectures for jee 2023 ????????????

    • @rohittt0102
      @rohittt0102 ปีที่แล้ว +1

      Yes bro i also watch for adv 2023

    • @rohittt0102
      @rohittt0102 ปีที่แล้ว +1

      @@nandanbhole123 98.85