Finite Element Analysis | FEM bar problem | Finite Element Methods example | FEM

A uniform bar having both the ends fixed and right side change in the length, Calculate elements stiffness matrices/Global stiffness matrices/ stresses at each element.
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[@viditsingh52]

Sir, good effort. it's really amazing to learn

[@MaheshGadwantikar]

Thank you for your comments ..

[@jakubdudas3322]

I would like to ask why you have cancelled all except Delta in the third row. (why didn't you cancel Delta as well). Thanks

[@sinclair2068]

How do you know the displacement is exactly delta?
What if P isn't strong enough?

[@RD-ke8mz]

Great video. Well done. Thanks a lot ❤️

[@MaheshGadwantikar]

Thank You, for supporting

[@mindsharpening642]

thank you Mahesh !well explained!!!

[@yuvrajpanchal4432]

Which book to refer for these type of problems

[@MaheshGadwantikar]

In all FEM book these types of problems available

[@yuvrajpanchal4432]

@@MaheshGadwantikar Any specific you want to suggest

[@MaheshGadwantikar]

Jalaluddin

[@sidharthenagala5323]

Hello, could you clarify how to find element stresses i.e what formulas to use?

[@MaheshGadwantikar]

I have solved the some other problem with stress calculation. You can check

[@jianyuhua]

what if there are two p?

[@sumanbiswas1003]

Sir,please make more video on FEM ,numerical problem....it will help us...

[@velusamy1172]

Thankyou sir.but how add the k1 and k2

[@sumanbiswas1003]

Sir,which book is easy to learn FEM????

[@MaheshGadwantikar]

Chandrapatla

[@sumanbiswas1003]

@@MaheshGadwantikar Sir,can i get the soft copy of the book?

[@MaheshGadwantikar]

In the description provided

[@basharm.m2372]

Hello bhay can you help me Please.. I have homwork very deiffcelt

[@BENARDOMONDI-q8l]

Smart

[@MaheshGadwantikar]

Thank you

[@evangelosgeorgiou1662]

Thank you so much for your explanation!!!

[@MaheshGadwantikar]

My pleasure dear.

[@suryanshsagar7164]

why are you not substituting the values of A, E & L before itself?

[@MaheshGadwantikar]

We can use initially or in the Stiffness Matrix

[@AshishGupta-v5o]

Nice video!

[@MaheshGadwantikar]

Thank you sir

[@guhannar]

Very helpful! Thank you!

[@MaheshGadwantikar]

Thank You So Much for your kind words.

[@ch.sowjanyasowji4895]

Thank you sir

[@MaheshGadwantikar]

🙏 Thank You

[@shivasmart967]

tq sir

[@ahmedjaafer8534]

thank you, but why the third row has been canceled, when you found the the value of u2???

[@MaheshGadwantikar]

Because zero displacements at node 3.

[@ahmedjaafer8534]

@@MaheshGadwantikar thank you

[@sannidhyasingh1951]

@@MaheshGadwantikar sir but the displacement at node is 1.2mm ..?? then why are we cancelling it

[@fabiocurti3822]

@@sannidhyasingh1951 cuz the displacement at node 3 is greater than 1.2mm so the end of the bar touches the Wall and the total displacement Is equal to zero. That's why a reaction force occours. The second element Is compressed because the delta displacement between node 2 and 3 is 1.2-1.5 = -0.3mm