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Sir i am a big fan of you❤️❤️Really you are a big heart and brilliant person.Plz plz reply my comment💛
Thank you!
thanks for doing all these solutions, this is extremely underrated
The background sound was too cute 🥰🥰
Thanks!
I like ur work alot broThanks for all
Thank you so much 😀
Bcoz of ur explanation I'm able to solve circuits 👍🙂🙂
Great 👍Thanks! Don't forget to like and subscribe
Thank you so much!! It helps me a lot.
Glad it helped!Don't forget to like and subscribe!
I am wondering if this question can be solve by mesh method? Thanks !
Yes
@@ArdiSatriawan but i cant deal with it when there is vccs , the loop 2 i create is only (I2-I1)*4=0 and loop 1 is (I1-I2)*4+20*I1+25=0 and I2 equals 0.1vx' .I really can't handle this i am just too bad ;(
Good luck
@@ArdiSatriawan oh i finally get it , when there's a current source in the mesh ' just let it equals to the mesh current . Thanks
You are a hero ❤
thank you so much
Welcome
Sir in step 2 when we short circuit 25 volt , wont 4 ohm branch also short curcuit because current always fkow through liw resistance place
No
For part b of the circuit. why is the KCL at Vx'' not 5 = 0.05vx" + 0.25vx" ?
See the circuit.
plz upload a playlist on microelectronis by SEDRA & SMith. That will be so much helpful .
Someday. Microelectronics is not my expertise.
That's was nice, I hope you didn't beat those kids making noises on background , they almost made me ignore the vedio eish
You should ignore the video
Thank you for helping us
Sir,i love ur vedioes. I am preparing for my exam and u r helping me a lot to know the answers that i am practicing are correct or wrong.
Great!
Thank you so much!! That's great work👍🏻
You're welcome!
you are great!!!!keep up the good work!!!!Make some video about to to approach or understand a electric circuit
May be sometime
Sir I have a question. why did you use KCL and not KVL, can I use KVL will it work?
yes you can use KVL. It will work
when will you upload source transformation problems?
I did? You can find them
@@ArdiSatriawan I am not able to find them... Please do help me
did you use supernode at 7:00 ? if yes, why? pls reply
Yes. Listen.
can you pls explain again why?
@@JarifTahmid No
Thank you so much sir
You're welcome!Don't forget to like and subscribe!
sir g u saved us
great work
Thank you! Cheers!
Hello sir, may I ask why do we need to neglect the open circuit of dependent current source, 0.1Vx ?
Because Vx is equal to 0, that dependent source will also be 0
@@ArdiSatriawan oh, like we are assume at first place, the Vx is equal 0?
I misunderstood the question. You don't need to turn off dependent sources.
@@ArdiSatriawan I got it, orite thank you
Sir In part B while applying kvl.... Why we use vx''/4.....bcoz already we considered 0.1Vx then??
How Vx/4 giving answer5Vx prime
Can't remember.
multiplied by 20
THANK YOUUU
You're welcome!!
Thanku thanku so much
Thank you so much 🙇♀️🙇♀️🙇♀️
You're welcome
Many many thanks.
Thank you sir
Great, thanks.
awsom
Thanks
Tq sir
nice sir
Thanks and welcome
i love u
Lol, thanks!
Cute kid
Thanks! Don't forget to like and subscribe
Sir i am a big fan of you❤️❤️
Really you are a big heart and brilliant person.
Plz plz reply my comment💛
Thank you!
thanks for doing all these solutions, this is extremely underrated
The background sound was too cute 🥰🥰
Thanks!
I like ur work alot bro
Thanks for all
Thank you so much 😀
Bcoz of ur explanation I'm able to solve circuits 👍🙂🙂
Great 👍
Thanks! Don't forget to like and subscribe
Thank you so much!! It helps me a lot.
Glad it helped!
Don't forget to like and subscribe!
I am wondering if this question can be solve by mesh method? Thanks !
Yes
@@ArdiSatriawan but i cant deal with it when there is vccs , the loop 2 i create is only (I2-I1)*4=0 and loop 1 is (I1-I2)*4+20*I1+25=0 and I2 equals 0.1vx' .I really can't handle this i am just too bad ;(
Good luck
@@ArdiSatriawan oh i finally get it , when there's a current source in the mesh ' just let it equals to the mesh current . Thanks
You are a hero ❤
Thanks!
thank you so much
Welcome
Sir in step 2 when we short circuit 25 volt , wont 4 ohm branch also short curcuit because current always fkow through liw resistance place
No
For part b of the circuit. why is the KCL at Vx'' not 5 = 0.05vx" + 0.25vx" ?
See the circuit.
plz upload a playlist on microelectronis by SEDRA & SMith.
That will be so much helpful .
Someday. Microelectronics is not my expertise.
That's was nice, I hope you didn't beat those kids making noises on background , they almost made me ignore the vedio eish
You should ignore the video
Thank you for helping us
Welcome
Sir,i love ur vedioes. I am preparing for my exam and u r helping me a lot to know the answers that i am practicing are correct or wrong.
Great!
Thank you so much!! That's great work👍🏻
You're welcome!
you are great!!!!
keep up the good work!!!!
Make some video about to to approach or understand a electric circuit
May be sometime
Sir I have a question. why did you use KCL and not KVL, can I use KVL will it work?
yes you can use KVL. It will work
when will you upload source transformation problems?
I did? You can find them
@@ArdiSatriawan I am not able to find them... Please do help me
did you use supernode at 7:00 ? if yes, why? pls reply
Yes. Listen.
can you pls explain again why?
@@JarifTahmid No
Thank you so much sir
You're welcome!
Don't forget to like and subscribe!
sir g u saved us
Welcome
great work
Thank you! Cheers!
Hello sir, may I ask why do we need to neglect the open circuit of dependent current source, 0.1Vx ?
Because Vx is equal to 0, that dependent source will also be 0
@@ArdiSatriawan oh, like we are assume at first place, the Vx is equal 0?
I misunderstood the question. You don't need to turn off dependent sources.
@@ArdiSatriawan I got it, orite thank you
Sir In part B while applying kvl.... Why we use vx''/4.....bcoz already we considered 0.1Vx then??
How Vx/4 giving answer5Vx prime
Can't remember.
multiplied by 20
THANK YOUUU
You're welcome!!
Thanku thanku so much
Welcome
Thank you so much 🙇♀️🙇♀️🙇♀️
You're welcome
Many many thanks.
Welcome
Thank you sir
Welcome
Great, thanks.
You're welcome
awsom
Thanks
Tq sir
Welcome
nice sir
Thanks and welcome
i love u
Lol, thanks!
Cute kid
Thanks! Don't forget to like and subscribe