Practice Problem 4.4 Fundamental of Electric Circuits (Alexander/Sadiku) 5th Edition - Superposition

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[@ArdiSatriawan]

Thank you!

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Glad it helped!
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thank you so much

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Welcome

[@Maha-ro2uz]

Bcoz of ur explanation I'm able to solve circuits 👍🙂🙂

[@ArdiSatriawan]

Great 👍
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[@weijasper9414]

I am wondering if this question can be solve by mesh method? Thanks !

[@ArdiSatriawan]

Yes

[@weijasper9414]

@@ArdiSatriawan but i cant deal with it when there is vccs , the loop 2 i create is only (I2-I1)*4=0 and loop 1 is (I1-I2)*4+20*I1+25=0 and I2 equals 0.1vx' .I really can't handle this i am just too bad ;(

[@ArdiSatriawan]

Good luck

[@weijasper9414]

@@ArdiSatriawan oh i finally get it , when there's a current source in the mesh ' just let it equals to the mesh current . Thanks

[@adityaambre4262]

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Make some video about to to approach or understand a electric circuit

[@ArdiSatriawan]

May be sometime

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[@ArdiSatriawan]

Someday. Microelectronics is not my expertise.

[@layla_mubarak_1759]

You are a hero ❤

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Thanks!

[@abhay__3051]

Sir in step 2 when we short circuit 25 volt , wont 4 ohm branch also short curcuit because current always fkow through liw resistance place

[@ArdiSatriawan]

No

[@khunadarkhunadar6568]

Thank you for helping us

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[@MSGamingOfficial1]

Thank you so much sir

[@ArdiSatriawan]

You're welcome!
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[@pskpk258]

Thank you so much!! That's great work👍🏻

[@ArdiSatriawan]

You're welcome!

[@erickcastellanos6814]

For part b of the circuit. why is the KCL at Vx'' not 5 = 0.05vx" + 0.25vx" ?

[@ArdiSatriawan]

See the circuit.

[@JarifTahmid]

did you use supernode at 7:00 ? if yes, why? pls reply

[@ArdiSatriawan]

Yes. Listen.

[@JarifTahmid]

can you pls explain again why?

[@ArdiSatriawan]

@@JarifTahmid No

[@syedamariabatool6353]

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[@wihangasihilel2318]

great work

[@ArdiSatriawan]

Thank you! Cheers!

[@TheHamidsindi]

Sir I have a question. why did you use KCL and not KVL, can I use KVL will it work?

[@ArdiSatriawan]

yes you can use KVL. It will work

[@shivampal2222]

Thanku thanku so much

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Welcome

[@aniknick3817]

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[@ArdiSatriawan]

Great!

[@KainatSarfraz-r3o]

How Vx/4 giving answer5Vx prime

[@ArdiSatriawan]

Can't remember.

[@freedomdive1881]

multiplied by 20

[@populardo2163]

THANK YOUUU

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You're welcome!!

[@23miruthulaa.s69]

Thank you sir

[@ArdiSatriawan]

Welcome

[@mickdarren4665]

Hello sir, may I ask why do we need to neglect the open circuit of dependent current source, 0.1Vx ?

[@ArdiSatriawan]

Because Vx is equal to 0, that dependent source will also be 0

[@mickdarren4665]

@@ArdiSatriawan oh, like we are assume at first place, the Vx is equal 0?

[@ArdiSatriawan]

I misunderstood the question. You don't need to turn off dependent sources.

[@mickdarren4665]

@@ArdiSatriawan I got it, orite thank you

[@attiqkhan6862]

Sir In part B while applying kvl.... Why we use vx''/4.....bcoz already we considered 0.1Vx then??

[@14dayztimeap8]

Many many thanks.

[@ArdiSatriawan]

Welcome

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You're welcome

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You're welcome

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That's was nice, I hope you didn't beat those kids making noises on background , they almost made me ignore the vedio eish

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You should ignore the video

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when will you upload source transformation problems?

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I did? You can find them

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Lol, thanks!