Free Radical Substitution, Alkane Mechanism - Organic Chem

[@anavazquezgonzalez976]

Hi I found your channel, was very useful! But I would like to know how do I do the substitution to get trichloromethane and tetrachcloromethane..., thanks

[@ChemistryGuru]

Hi Ana thank you for the compliment! For the third and fourth substitution it'll just be a duplicate of the propagation step. Remember 2 propagation steps will give us 1 substitution. So in the video I've mentioned the first 2 propagation steps will give chloromethane, the next 2 propagation steps will give dichloromethane, and we can repeat the 2 propagation steps to give trichloromethane, and do that again to get tetrachloromethane. Hope this clarifies! 😄

[@anavazquezgonzalez976]

@@ChemistryGuru so do I need to repeat the last 2 propagation steps or the 4 propagation steps... thanks

[@ChemistryGuru]

You can repeat the last 2 steps to get trichloromethane. If you want tetrachloromethane then need to repeat the 2 steps 1 more time.

[@anavazquezgonzalez976]

@@ChemistryGuru Thanks so much!!!

[@ChemistryGuru]

@@anavazquezgonzalez976 You are most welcome. Glad to be able to help! 😄

[@mustafanajim5220]

perfection!!!!! straight to the point explaination. thanks a lot sir

[@sanjayprajapati7333]

Thank you sir, for providing Basic & Comprehensive lecture

[@empirejayjairos7297]

dude your channel is the best...very helpful

[@sanjayprajapati6597]

Thank you sir for such a basic, detailed and comprehensive lecture.

[@dylankatamba8124]

wow, i hv understood perfectly, thank u

[@Daeil_diary]

Thank you very much! Now I understand the second part of the propagartion too!

[@yoongdominic3767]

THANK YOU Sir I finally understand free radical sub now :-)

[@ChemistryGuru]

Glad the video was useful! :)

[@amaryllisremes8863]

This was so helpful, thank you!

[@enyeeong5217]

awesome video, recommended to my friends 👍👍

[@ChemistryGuru]

Thanks En Yee! Much appreciated!

[@afridaaliR]

Thank you very much sir. this video helped me alot..

[@safia2912]

this was very helpful, thank you sir!

[@hi-ey4rz]

Thanks! Very helpful and easy to understand :)

[@maryamghanijya7315]

wow leh you saved my life !! now i can understand the lesson :)) thank youu!!!

[@ChemistryGuru]

Hi Maryam thank you! Glad you find the video useful :)

[@pavitrapadmanathan5637]

Thank you very helpful.

[@ChemistryGuru]

Thanks Vitra glad it was useful :)

[@myymai8282]

Thank u it really useful!!!!!

[@mdhakeem9155]

hai sir..may I ask you?why the reaction between methane and chlorine will form a Ch2Cl instead of Ch3Cl?Is it make a difference?Hoefully you can give me further explaination about this cause now I am facing some confusion

[@husnahasanah1925]

this is late sorry but the reason why he got ch2cl2 is because he undergoes the substitution reaction twice whereas to get ch3cl, you just need to undergo substitution once. originally, the propagation steps has 2 steps but since the final product is ch2cl2 not ch3cl, he needs to add 2 more steps to the propagation step. or it is easier to say that the final product, ch2cl2 has 2 cl atoms whereas ch3cl has only one cl atom. i hope this helps you

[@mdhakeem9155]

@@husnahasanah1925 ouhh very nice explaination..thank you

[@husnahasanah1925]

MD HAKEEM your welcome

[@damienlok8627]

can i consider 2 chlorine radicals reacting with each other to form chlorine molecule in the termination step?

[@ChemistryGuru]

yes that's possible too. In theory termination step is where any 2 radicals meet and form a stable compound.

[@damienlok8627]

i see. one more question, can the neutral molecules formed from termination step then undergo more propagation steps? for example the ethane from the termination step in your example forming ethyl radical, then the ethyl radical reacting with chlorine to form ch3ch2cl

[@ChemistryGuru]

@@damienlok8627 yes that's definitely possible. in fact if we start with methane, we can form alkanes with bigger carbon number like propane, butane, etc when ethane formed in the termination step becomes a radical, then meet another methyl radical to form propane, and so on.

[@damienlok8627]

@@ChemistryGuru thanks alot :D

[@葉赫那拉榮禹]

👍👍👍

[@ChemistryGuru]

as promised! more mechanism coming up. stay tuned! 😀

[@hidan4662]

i love you

[@aibihatesyou]

tqvm this helped me a lot