Similar to PCIe Gen 5. Possible, but you likely need to use ultra-low-loss materials and pay attention to things like fiberweave effects and via geometry.
there is too many crossing point in pam-4 eyediagram, or i dont know what you mean by gray coding. As i understand this, for 4 state bus that uses gray code, from each level there is possible only two ways, but on your video i see each level can lead to any other...
My understanding is this: looking at symbol voltages from low to high we have 00, 01, 11 and 10. For PAM-N we have N-1 decision thresholds, so that means N-1 ‘eyes’, three in this case. They Gray code means that if noise perturbs the received signal above or below one decision threshold there’s only a single bit error in the two bit symbol. If the symbols were labelled 00, 01, 10, 11 and error in the middle decision would give rise to a double bit error 01 becomes 10. With PAM-N we have log2(N) bits per symbol, so 2 in this case. Hope that helps?
![[#2024MAMA] BIGBANG (빅뱅) - 뱅뱅뱅 (BANG BANG BANG) + FANTASTIC BABY | Mnet 241123 방송](http://i.ytimg.com/vi/EQsYfiPR9uM/mqdefault.jpg)
What does this mean for PCB routing/manufacturing techniques? Will 50G be possible on FR4 still?
Similar to PCIe Gen 5. Possible, but you likely need to use ultra-low-loss materials and pay attention to things like fiberweave effects and via geometry.
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there is too many crossing point in pam-4 eyediagram, or i dont know what you mean by gray coding. As i understand this, for 4 state bus that uses gray code, from each level there is possible only two ways, but on your video i see each level can lead to any other...
My understanding is this: looking at symbol voltages from low to high we have 00, 01, 11 and 10. For PAM-N we have N-1 decision thresholds, so that means N-1 ‘eyes’, three in this case. They Gray code means that if noise perturbs the received signal above or below one decision threshold there’s only a single bit error in the two bit symbol. If the symbols were labelled 00, 01, 10, 11 and error in the middle decision would give rise to a double bit error 01 becomes 10. With PAM-N we have log2(N) bits per symbol, so 2 in this case. Hope that helps?
good.