Calculate Standard Reduction Potential From Half Reactions

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  • เผยแพร่เมื่อ 6 ก.ย. 2024
  • How to calculate the standard reduction potential of a redox reaction from half reactions. Example included.

ความคิดเห็น • 30

  • @fouriertransformbrowne6886
    @fouriertransformbrowne6886 ปีที่แล้ว +6

    This subject is hard for many and been hard for me too. This video covers a lot of ground in 17 minutes so be prepared and hit the pause button as needed: Instructor has great eye contact, great speech emphasis, authentic hand gestures - just right, not too much --- and great moving back-and-forth from board to the camera . Best parts : "do not (hand smack to palm ) multiply E ! " - ; "Notice that I DID NOT multiply this (stoichiometric ratio, although she does not say "stoichiometric" ) by a 2; be so, so, so ,so , SO careful" :) Keep up the good work Old School !

    • @OldSchoolChemistry
      @OldSchoolChemistry  ปีที่แล้ว +1

      Thanks for the positive review @fouriertransformbrowne6886! (I like your handle 😊)

  • @sheevpalps3846
    @sheevpalps3846 ปีที่แล้ว +2

    Thanks a lot for the review, preparing for the MCAT now and needed the refresher greatly.

    • @OldSchoolChemistry
      @OldSchoolChemistry  ปีที่แล้ว +1

      Hi Sheevpalps, good luck on your test! I am proud of your hard work!

  • @ahmadharmouch20
    @ahmadharmouch20 ปีที่แล้ว +2

    17 minutes helped me more than a 1hour 30 minute lecture. Thank you so much

    • @OldSchoolChemistry
      @OldSchoolChemistry  ปีที่แล้ว

      Hi ahmadharmouch, I am so glad! I hope your class goes well:)

  • @mubitanosiku2904
    @mubitanosiku2904 ปีที่แล้ว

    This video helped me to understand what I couldn't understand in lecture thank you very much ❤❤❤

    • @OldSchoolChemistry
      @OldSchoolChemistry  ปีที่แล้ว

      Hi Mubita, that makes me so happy! Thank you for your comment:)

  • @surfingcowgirl
    @surfingcowgirl ปีที่แล้ว +1

    Helpful for the MCAT!

    • @OldSchoolChemistry
      @OldSchoolChemistry  ปีที่แล้ว

      Hi Ellie, I am so glad! God bless you on your test:)

  • @gretachoi2378
    @gretachoi2378 4 หลายเดือนก่อน

    youre saving my chem 2 grade 😅 thank you so much!!!

    • @OldSchoolChemistry
      @OldSchoolChemistry  4 หลายเดือนก่อน

      Hi Greta, I am so glad the videos are helpful! I am super proud of your hard work! God bless you in class:)

  • @dewshifernando6969
    @dewshifernando6969 ปีที่แล้ว

    Thank you so much!!! You clarified a lot of questions ☺☺

    • @OldSchoolChemistry
      @OldSchoolChemistry  ปีที่แล้ว +1

      Hi Dewshi, wonderful! Good job doing extra work to find videos. Thank you for your comment!

  • @kimpossible4561
    @kimpossible4561 ปีที่แล้ว

    You have made it so simple for me! Thank you so much for your videos.

    • @OldSchoolChemistry
      @OldSchoolChemistry  ปีที่แล้ว

      Hi Kim Possible, I love your handle! I can hear the theme music:) I am pleased to hear the video was helpful. Thank you for your comment!

  • @dewshifernando6969
    @dewshifernando6969 ปีที่แล้ว

    You saved my day!!!

    • @OldSchoolChemistry
      @OldSchoolChemistry  ปีที่แล้ว +1

      Hi Dewshi, that makes me so happy! I hope your class goes well:)

  • @sagtoolesag
    @sagtoolesag 4 หลายเดือนก่อน

    Hi there, great video! Was really confused before this. I do have a question however, in the first example of electrolytic cell, why is the Fe half equation happening at the anode? I thought it would be happening the cathode since it involves cations and the cathode is the negative electrode. ( Am I wrong to assign the cations to the cathode and the anions to the anode in electrolytic cells?). Thank you so so much in advance.

    • @OldSchoolChemistry
      @OldSchoolChemistry  4 หลายเดือนก่อน

      Hi! The cathode is ALWAYS the reduction half cell and the anode is ALWAYS the oxidation half reaction. I hope that helps. Thanks!

    • @sagtoolesag
      @sagtoolesag 4 หลายเดือนก่อน

      @@OldSchoolChemistry Thank you!

  • @Happy.Traveller
    @Happy.Traveller ปีที่แล้ว

    Hello, can you explain something: I read that the electron has to be on the ion side of the arrow in the half cell equation in the standard reduction tables because the pure element is neutral.
    For example in "Ag+(aq) + e- → Ag(s)", silver ion of positive one charge plus one electron to create a neutral silver atom.
    If that is the case, why do we write "Cl2(g) + 2e- → 2Cl-(aq)" with the electron on the same side as the pure Cl to create a chloride ion?
    Other examples are "I2(s) + 2e- → 2I-(aq)", or even "Sn4+(aq) + 2e- → Sn2+(aq)" which has ions on both sides.
    Thank you for the video.

    • @OldSchoolChemistry
      @OldSchoolChemistry  ปีที่แล้ว +1

      Hi Happy, it is because of the specific charge on the ion. Ag+ (notice the positive) means the ion lost an electron so the electron is on the same side as the ion. Notice the negative charge on Cl- which means the ion gained an electron so the the electron is written on the opposite of the half reaction. I hope that helps. Thanks!

    • @Happy.Traveller
      @Happy.Traveller ปีที่แล้ว

      @@OldSchoolChemistry Oh thank you for the explanation! Then does it mean it is wrong to say "the electron can not be on the same side of the arrow as the pure element"?

    • @OldSchoolChemistry
      @OldSchoolChemistry  ปีที่แล้ว +1

      @@Happy.Traveller Not necessarily. The electron will not be on the side of the reaction that contains the species that gained the electron. I hope that helps!

    • @Happy.Traveller
      @Happy.Traveller ปีที่แล้ว

      @@OldSchoolChemistry It makes perfect sense, thank you so much!

  • @Babygirllll593
    @Babygirllll593 ปีที่แล้ว

    what i would kindely suggest if you could speak louder in your videos. As its really difficult to hear you! Appreciate it :)

  • @adventurevloggeradnanahmedusa
    @adventurevloggeradnanahmedusa 4 หลายเดือนก่อน +1

    This video has everything you need to know about the topic. It teaches you the fundamentals that could be used in any question. Her videos bridged many content gaps I had for the MCAT. Thank you. I test in 17 days. 🥲

    • @OldSchoolChemistry
      @OldSchoolChemistry  4 หลายเดือนก่อน +1

      Hi Adnan, 17 days - wow! You will do great. It will be so nice to have completed the test. I am so proud of your hard work. God bless you in your efforts! Thank you for the very kind review!