Degree of Unsaturation and Index of Hydrogen Deficiency

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  • เผยแพร่เมื่อ 25 เม.ย. 2018
  • This organic chemistry video tutorial explains how to calculate the degree of unsaturation or the index of hydrogen deficiency of a molecule given its molecular formula.
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ความคิดเห็น • 45

  • @TheOrganicChemistryTutor
    @TheOrganicChemistryTutor  ปีที่แล้ว +1

    Organic Chemistry PDF Worksheets: www.video-tutor.net/orgo-chem.html
    Full-Length Exams and Worksheets: www.patreon.com/MathScienceTutor/collections
    Next Video: th-cam.com/video/lKROX1C0JRs/w-d-xo.html

  • @rhaenysgames8115
    @rhaenysgames8115 ปีที่แล้ว +58

    You are literally creating the future generation of doctors, engineers, and scientists. Props to you man (and everyone who takes part in the creation of these videos)

  • @C-G585
    @C-G585 3 ปีที่แล้ว +6

    You are a God among organic chemists . My professor speaks a broken English and its hard to understand came here and its very clear. Thank you.

  • @Mariiiam
    @Mariiiam 2 ปีที่แล้ว +4

    That was wonderfully explained. I don’t know how can I not understand the topic in an hour long lecture but understand it in the first 3 minutes of your video 🙏🏻❤️

  • @FunTycoon134
    @FunTycoon134 5 ปีที่แล้ว +18

    Thank you for explaining why the system works at the end, then it all made sense.

  • @thejetsonslol
    @thejetsonslol 3 ปีที่แล้ว

    omg You impress me with these tips! Thank you!

  • @suryaprakashguthula6337
    @suryaprakashguthula6337 หลายเดือนก่อน

    Most Better than hours of lectures

  • @gabrieldayot4921
    @gabrieldayot4921 3 ปีที่แล้ว +2

    Thank you for the explanation and the equation sir. :)

  • @mhemedmhemed-cb6gc
    @mhemedmhemed-cb6gc 11 หลายเดือนก่อน

    Thank you for the explanation, it is really nice

  • @lisettsanchez2534
    @lisettsanchez2534 3 ปีที่แล้ว +1

    you deserve the world my good sir

  • @bscc181
    @bscc181 3 ปีที่แล้ว +1

    This guy clear all my doubt

  • @ntombieatandwa4374
    @ntombieatandwa4374 3 ปีที่แล้ว

    Thank you so much!🙏now I can do my assignment🤗

  • @ashirwadkatkamwar5555
    @ashirwadkatkamwar5555 2 ปีที่แล้ว +1

    Thank you so much sir ❤️

  • @secretgarden8142
    @secretgarden8142 3 ปีที่แล้ว

    Thank you so much (Sun 20 Dec 2020, 5:17 PM)

  • @alhassanmichael306
    @alhassanmichael306 ปีที่แล้ว

    Thank you very much Dr

  • @StephanoPaskali-ir6uv
    @StephanoPaskali-ir6uv 2 หลายเดือนก่อน

    It's awesome 💯

  • @kevinsweeney2809
    @kevinsweeney2809 5 ปีที่แล้ว

    Thanks dude!!!

  • @sohelkhatri9571
    @sohelkhatri9571 ปีที่แล้ว

    Nice explanation sir

  • @someguy1576
    @someguy1576 6 ปีที่แล้ว +2

    First. Also thank you. I haven’t seen anything like this before

  • @subhadeepacharya6894
    @subhadeepacharya6894 6 ปีที่แล้ว

    nice explanation

  • @ROHIT-mk3be
    @ROHIT-mk3be 3 ปีที่แล้ว

    good explanation sir

  • @Islam_true_religion
    @Islam_true_religion ปีที่แล้ว

    Very useful❤

  • @Muslimkishehzadi786
    @Muslimkishehzadi786 2 ปีที่แล้ว

    Thank u so much 🥰🥰

  • @vedashreemahajan9962
    @vedashreemahajan9962 2 ปีที่แล้ว

    🙌Thank you!

  • @abhijithtechandgaming1394
    @abhijithtechandgaming1394 11 หลายเดือนก่อน

    Thank you sm

  • @chikanma5021
    @chikanma5021 2 ปีที่แล้ว

    Thank you so mucb

  • @Nadeem--ux7pt
    @Nadeem--ux7pt 4 ปีที่แล้ว

    Sir thank you for explaining
    But IHD of last shown compound is not zero...
    Can you explain...

  • @Grace-du2nt
    @Grace-du2nt ปีที่แล้ว

    Thanks a ton sir ❤❤❤you have no idea how much you have helped me ❤❤❤

  • @tomiwaadara1115
    @tomiwaadara1115 3 ปีที่แล้ว +4

    Aren't you supposed to add the nitrogen and subtract the halogen?

    • @itspchu
      @itspchu 2 ปีที่แล้ว +1

      That's what I'm wondering

  • @Vi-lj1sn
    @Vi-lj1sn 6 ปีที่แล้ว +5

    My textbook from 2013 said 0.5 * [2c+2-h-x+n]... so is it +1 for N and -x for halogen... did it change?

    • @juliawenzinger2544
      @juliawenzinger2544 5 ปีที่แล้ว +7

      No, your formula might actually be more helpful as it includes nitrogen and halogens if they are involved in a compound. if they are not, you simply ignore them.

  • @sandyillescas708
    @sandyillescas708 3 ปีที่แล้ว +1

    So clear, I want to cry

  • @youssefattallah7124
    @youssefattallah7124 2 ปีที่แล้ว +5

    I been doing it wrong this whole time because of this video, you add the N and subtract the Halogens.

    • @shim525
      @shim525 3 หลายเดือนก่อน

      No, he's right.
      I think you just misunderstood and calculated it.
      Let's take C9H7PBr2O3 from 8:33 of this video as an example.
      If you calculate it using your method, it is [(20+1-2)-7]/2=6.
      How is it? It's the same, right?

  • @engineer4079
    @engineer4079 2 ปีที่แล้ว

    5:45 it's epic, tq sir

  • @hasmikmkhitarian7655
    @hasmikmkhitarian7655 ปีที่แล้ว +1

    idk what it is but something about this man's voice and the fact that he's teaching me Ochem so well is making me fall in love with him 🤨

  • @shanicemagama8144
    @shanicemagama8144 4 ปีที่แล้ว +13

    seriously though, you are supposed to add the nitrogen and subtract the halogen

    • @bran154
      @bran154 4 ปีที่แล้ว +3

      Shanice Magama seriously though I don’t see you making all these videos. Shut up

    • @redowooga6475
      @redowooga6475 2 ปีที่แล้ว

      Chill out dude

  • @ankitgohil8287
    @ankitgohil8287 2 ปีที่แล้ว

    Degree of unsturatione of proplybenezene ?

    • @ewannor
      @ewannor 2 ปีที่แล้ว +1

      Four:
      3 double bonds + 1 ring(cyclic hydrocarbon);
      using formula,
      C9H12 -> (2(9)+2-12)/2 = 4

  • @sukislyngstad-tn3ee
    @sukislyngstad-tn3ee 3 หลายเดือนก่อน

    I just became a member do I still have to see the commercials? don't judge please.

    • @MyeonTokki
      @MyeonTokki 2 หลายเดือนก่อน

      you can only not see ads if you have youtube premium, i think. membership only allows you to have more videos

  • @kareembagato7101
    @kareembagato7101 2 ปีที่แล้ว +2

    Bruh. You add the nitrogen and subtract the halogens. Ffs made me lose points on my exam. Thanks though for the help,