Organic Chemistry PDF Worksheets: www.video-tutor.net/orgo-chem.html Full-Length Exams & PDF Worksheets: www.patreon.com/MathScienceTutor/collections Access The Full 1 Hour 12 Minute Video: www.patreon.com/MathScienceTutor Direct Link to The Full Video: bit.ly/3iqOErh
Apart from other tutors that explain online, this organic chemistry tutor is the best one who has a fair understanding of all other science courses as well.
Yeah bro thank you very much I have exam tomorrow in this lecture and search in many TH-cam videos about it But still confused Your video come in right time
My doubts were clarified in the first minutes. But this video is so good that I watched until the final. The examples are well explained. Thanks for the video ❤
For anyone confused about 24:01 , this is why I think it's equitorial and not axial. CH3 and OH, according to the structure needs to be CIS. This means both have to be pointing up. Axial and equitorial bonds alternate up and down, shown in 1:17. If you go in order, axial bonds in carbon 1 should go UP. Carbon 2 axial bonds should go DOWN. Carbon 3 axial bonds should go UP. And carbon 4 axial bonds need to go DOWN. That's why the OH group cant be axial up because any axial group on the carbon 4 needs to be DOWN. Hence, you're forced to put the OH group in an equitorial up position since if you go in order (again), Carbon 1 equitorial bonds should go DOWN, Carbon 2 equitorial bonnds should go UP, carbon 3 equitorial bonds go DOWN, and carbon 4 equitorial bonds go UP. CH3 and OH need to be CIS and the only way to do that is if you do an axial up CH3 and an equitorial up OH.
At 16:20, when you're doing a chair flip from form B to form A, you said that you move the carbons in a couterclockwise direction, but is it necessary to reverse the direction of the carbons, or just move them back one place? By the way, your videos are amazing, and I use them for practically every subject in school! Thank you so much!
Wow! Just have to say like everyone else that this video was super helpful and clear! Literally game-changing to understanding such an abstract and visual concept!
I think the equatorial position should be parallel to the C -C bond either to the right or left. I have noticed that you have made some mistakes in drawing the correct structure. Otherwise, you the best tutor that I would always like your videos that simplifies everything. thank you very much.
Reading the textbook sent me on a downward spiral lol. 🌀, thanks for your very clear and concise explanation. Sometimes the textbook helps but like sometimes not at all. 😂
Im confused on how you know if the substituents is either axial or equatorial and if they are up or down on on the chair. I understand the ring flip and which one would be more stable but I just dont understand the inital drawing process, someone plzzzzzzzzzz help
At 23:05 or even for the previous question, why can't both the groups be in the equitorial plane ? Why one needs to be in the axial and the other in the equitorial plane Having both the groups in the equitorial plane will make the compound more stable by avoiding 1-3 repulsion
@@Christophero Because they're cis, they either both have to be up or both have to be down. They're also right next to each other in positions 1 and 2. The way the chair is set up you can't have axial and equatorial bonds next to each other in the same direction. So, they alternate directions. Therefore, the set-up with the lowest energy is one with the bulkier group on the equatorial bond and the smaller group on the axial bond. This way they are right next to each other and still pointing in the same direction. Does that make sense?
This actually comes down to the geometry of the carbon atoms. Notice they are all sp3 hybridized - if they were to be in the same plane, the ideal bond angle for sp3 hybridized atoms (109.5) would be deviated from which would further destabilize the molecule.
Is there a particular reason that you place the methyl group on one instead of the bromine? Also, can you place both substituents on the equatorial position?
For anyone confused about 24:01 , this is why I think it's equitorial and not axial. CH3 and OH, according to the structure needs to be CIS. This means both have to be pointing up. Axial and equitorial bonds alternate up and down, shown in 1:17. If you go in order, axial bonds in carbon 1 should go UP. Carbon 2 axial bonds should go DOWN. Carbon 3 axial bonds should go UP. And carbon 4 axial bonds need to go DOWN. That's why the OH group cant be axial up because any axial group on the carbon 4 needs to be DOWN. Hence, you're forced to put the OH group in an equitorial up position since if you go in order (again), Carbon 1 equitorial bonds should go DOWN, Carbon 2 equitorial bonnds should go UP, carbon 3 equitorial bonds go DOWN, and carbon 4 equitorial bonds go UP. CH3 and OH need to be CIS and the only way to do that is if you do an axial up CH3 and an equitorial up OH.
Little confused, on the first problem he explained that the axial methyl group is less stable than the equatorial methyl group due to the diaxial interactions with other Hydrogens. But he did not explain why we don’t run into the same problem with an equatorial methyl group. How do we know that methyl group doesn’t interact with other hydrogens? Why can’t we draw axial methyl and all other hydrogens equatorial to avoid the diaxial interaction? Inversely, Why can’t we draw equatorial methyl and axial hydrogens to avoid any interaction? I’m so thankful for you and your videos! Just a bit confused here
It’s important to remember that when drawing equatorial/axial positions, we are drawing tetrahedral carbons. If we make 2 axial or 2 equatorial groups on the same carbon, we introduce angular strain on the carbon, which is unstable.
The equatorial bond in the front is angled improperly. Each equatorial bond should be parallel to the ring bonds that are at the 2,3 position relative to it.
Organic Chemistry PDF Worksheets: www.video-tutor.net/orgo-chem.html
Full-Length Exams & PDF Worksheets: www.patreon.com/MathScienceTutor/collections
Access The Full 1 Hour 12 Minute Video: www.patreon.com/MathScienceTutor
Direct Link to The Full Video: bit.ly/3iqOErh
Great
Q
everytime i hear this mans voice i am instantly less stressed
Right!?!? I thought It was just me😅thousand times agree
Me Too! This man has saved my life multiple times lol
listen to kirk hammett then
true!!!
@@nyashanotjae1153 me too !!!!!
Thank you! I got a 90 on my exam yesterday because of you. You explain everything so well. Gonna watch your videos for every topic this semester.
Physics, orgo, math, gen chem... You're always there. I am forever grateful for you and your work.
Apart from other tutors that explain online, this organic chemistry tutor is the best one who has a fair understanding of all other science courses as well.
I love the fact that i understand more from you in 20 minutes than I understand from my prof in an hour and a half a day. you are a godsend man.
He taught me more than university proff could ever do......I will have no regrets paying him the total amount i paid for university
unive- isn't this high school level stuff?
@@vallariashar3179 i learn this in university too so basically yeah, kinda uni level
@@kurooackerman7338 oh fr? Well...thanks I didn't know..
@@vallariashar3179 haahahah it's okay i guess the syllabus is different for different countries/univs
@@vallariashar3179 A lot of ppl in my orgo class in uni rn said they didn’t know about not drawing carbons until the class.
Yeah bro thank you very much
I have exam tomorrow in this lecture and search in many TH-cam videos about it
But still confused
Your video come in right time
My doubts were clarified in the first minutes. But this video is so good that I watched until the final. The examples are well explained. Thanks for the video ❤
Man you made this make sense in ten minutes, whereas I was still confused after two 3-hr lectures. Thanks!
Omg, taught me more than my professor did for 4 hours lecture. Thank you!!!
I cannot believe how much sense you just made of this whole topic. Thank you as always.
I have a quiz in an hour. This is a blessing to me.
I am an indian ,, u r such a great teacher i am preparing for iit jee exam ,, your videos are really helpful ,, thanks ❤️
This is really helpful for college level Organic Chemistry, thank you! You know your information quite spectacularly.
yo 11th grade OC
Organic in junior year of college was tough, but this content creator made things a bit easier (:@@thelostmann
All these years and you're still helping me and many others. Thank you!
thanks for the above video it really cleared all my concepts in such a crisp and concise form.
Thank you! You explained this so much better than my textbook and class :)
how tf does this guy know everything
Bruh😂
Thank you sooooo much.❤❤
I confused ring flip for the long time,now I got it!!!!
i cannot thank you enough! ur vids are what get me through organic chemistry
wow you taught me when my own professor couldn't. thank you for this I finally grasped the concept!!!
you are sooo good at teaching!!!! please don't ever stop doing what you do. Thank you and God Bless you.
Best chemistry tutor on TH-cam ❤❤❤❤
I have test on this after 2 hours, thanks for the clear explanation
Please God continue to bless you. I even understand your teachings better than when my Lecturers do.
sir, you're a real life-saver...Please keep up the good work!! We appreciate your work as uni chem students
this TH-cam channel is such a public service. ily organic chemistry tutor.
no one will ever survive chemistry without seeing yor videos.
Hii~ I'm from Brasil and I've been watch your videos to study english and chemical at the same time. TK
He didn’t say it in this clip but the positive slope clockwise and negative slope counterclockwise solidified this for me and got me my A
Thanks 👍 so much mr Jg am gonna call u a great teacher stay blessed man of God🌎
I thank you on behalf each and every student for doing the professor’s job
18:45 - Don't mind me. I am reminding myself where I paused but I swear OCT is the GOAT !!!!
thank u sooo much i just had a lecture on this and it wasnt making sense before
For anyone confused about 24:01 , this is why I think it's equitorial and not axial. CH3 and OH, according to the structure needs to be CIS. This means both have to be pointing up. Axial and equitorial bonds alternate up and down, shown in 1:17. If you go in order, axial bonds in carbon 1 should go UP. Carbon 2 axial bonds should go DOWN. Carbon 3 axial bonds should go UP. And carbon 4 axial bonds need to go DOWN. That's why the OH group cant be axial up because any axial group on the carbon 4 needs to be DOWN. Hence, you're forced to put the OH group in an equitorial up position since if you go in order (again), Carbon 1 equitorial bonds should go DOWN, Carbon 2 equitorial bonnds should go UP, carbon 3 equitorial bonds go DOWN, and carbon 4 equitorial bonds go UP. CH3 and OH need to be CIS and the only way to do that is if you do an axial up CH3 and an equitorial up OH.
You explained everything so clearly, thanks to you I might just ace my next chem test
At 16:20, when you're doing a chair flip from form B to form A, you said that you move the carbons in a couterclockwise direction, but is it necessary to reverse the direction of the carbons, or just move them back one place? By the way, your videos are amazing, and I use them for practically every subject in school! Thank you so much!
Thank you. Such an inspiration. Everything is soo easy
This is your second video I’m watching, you are good in explaining chemistry
Thank you 😊
Insane! Totally get these "chair flips," now!!
Thank you for this, I have an exam coming up and your explanation have helped me greatly 💪🏼❤
Wow! Just have to say like everyone else that this video was super helpful and clear! Literally game-changing to understanding such an abstract and visual concept!
You are a great teacher ! Thank you !
Thanks a billion. God bless your genius brain, eternally grateful for God putting you on this planet.
Dang bro you posted this 2 weeks before my exam. CLUTCH
I think the equatorial position should be parallel to the C -C bond either to the right or left. I have noticed that you have made some mistakes in drawing the correct structure. Otherwise, you the best tutor that I would always like your videos that simplifies everything. thank you very much.
Thank you, you are single handedly saving my grade right now
Thanks for your efforts , I have an exam tomorrow 🙂
Thank you sir
You're really amazing
This man is a savior. 🤍
Reading the textbook sent me on a downward spiral lol. 🌀, thanks for your very clear and concise explanation. Sometimes the textbook helps but like sometimes not at all. 😂
you explained it way better than my professor, huge thanks!
One of the best class i have ever watched!!
salvando minha prova pq eu não achei nenhum canal BR que explicasse tão bem assim S2
This guy is literally my best chemistry tutor
Anyone else listen as they go to sleep in hopes of internalizing the info?
JEE Aspirants Coming Here to clear their Doubts.😂
Im confused on how you know if the substituents is either axial or equatorial and if they are up or down on on the chair. I understand the ring flip and which one would be more stable but I just dont understand the inital drawing process, someone plzzzzzzzzzz help
Hi @Mohamed Dahcheh, this video helped me understand the placement of substituents! th-cam.com/video/4xNQwohSRbo/w-d-xo.html
Good luck!
@@imanifreefun thank you, i had the same question but I understood it bc of this video series :)
Thank you so much sir........ Explained in such an easy way....👍🏻👍🏻👍🏻👍🏻👍🏻
Plzz upload more lactures of conformational analysis like ethane, n-butane etc. I shall be very thank full to
bro u saved my life
Thank you for making mcat prep so easy
When dealing with 2 substituents, do we have to put them in opposite positions, like axial and equatorial?
little knit picky but I believe that the equatorial bonds in the middle are suppose to be a parallel with the right and left parallel lines.
You are the Greatest Of all time (GOAT)
Thank you
17:25 the second demo, second structure, I think the up isopropyl should be shooting toward right
you are absoltely incredible
This is coming in clutch
you are an absolute wizard
Saving my life thank you, you absolute legend.
Excellent explanation 😭😭
Thanks for saving me from another panic attack my dude.
No confusion , your class is sufficient to understand than 20 branded chemistry books
At 23:05 or even for the previous question, why can't both the groups be in the equitorial plane ?
Why one needs to be in the axial and the other in the equitorial plane
Having both the groups in the equitorial plane will make the compound more stable by avoiding 1-3 repulsion
I have this question too, we’re you able to find an answer?
@@Christophero Because they're cis, they either both have to be up or both have to be down. They're also right next to each other in positions 1 and 2. The way the chair is set up you can't have axial and equatorial bonds next to each other in the same direction. So, they alternate directions. Therefore, the set-up with the lowest energy is one with the bulkier group on the equatorial bond and the smaller group on the axial bond. This way they are right next to each other and still pointing in the same direction. Does that make sense?
This actually comes down to the geometry of the carbon atoms. Notice they are all sp3 hybridized - if they were to be in the same plane, the ideal bond angle for sp3 hybridized atoms (109.5) would be deviated from which would further destabilize the molecule.
@@leila8397 thank you.
you saved my life
I finally got it. Thank you! I'll be joining the membership on TH-cam and contributing for sure on Paterson.
Is there a particular reason that you place the methyl group on one instead of the bromine?
Also, can you place both substituents on the equatorial position?
Sir you are genius....thanks for this vedio
This man is amazing
saving my life and degree honestly😭💙
Always so good at explaining
Very well explained!
Thanks very much.....you make everything simple😄
For the first cyclohexane on number 5, wouldn't you start numbering at the bromine atom since halogens are the priority group in this case?
very clear Thank you so much!
This video was very helpful. The best! Thank you!
I want to hug you my man
Let me ask you this: How did you learn all of everything you teach us? What are your study tips and what is your major?
his study tips:
- do it
- use google
- use a pen and paper
his major:
- chemistry
He knows everything at this point
@@aideno2597 Yep.
Millions of thanks to you
YOU ARE THE BEST!!!!
😭Thank you a billion times . 🙏 🙏 God bless
Why is in the last example the oh in equatorial and not in axial? Because Br is in equatorial so the next one should be in axial???
i want to ask this ques too...
specifically looked in the comments for this question.. isnt it suppose to be axial since Br was equatorial
For anyone confused about 24:01 , this is why I think it's equitorial and not axial. CH3 and OH, according to the structure needs to be CIS. This means both have to be pointing up. Axial and equitorial bonds alternate up and down, shown in 1:17. If you go in order, axial bonds in carbon 1 should go UP. Carbon 2 axial bonds should go DOWN. Carbon 3 axial bonds should go UP. And carbon 4 axial bonds need to go DOWN. That's why the OH group cant be axial up because any axial group on the carbon 4 needs to be DOWN. Hence, you're forced to put the OH group in an equitorial up position since if you go in order (again), Carbon 1 equitorial bonds should go DOWN, Carbon 2 equitorial bonnds should go UP, carbon 3 equitorial bonds go DOWN, and carbon 4 equitorial bonds go UP. CH3 and OH need to be CIS and the only way to do that is if you do an axial up CH3 and an equitorial up OH.
Little confused, on the first problem he explained that the axial methyl group is less stable than the equatorial methyl group due to the diaxial interactions with other Hydrogens.
But he did not explain why we don’t run into the same problem with an equatorial methyl group. How do we know that methyl group doesn’t interact with other hydrogens?
Why can’t we draw axial methyl and all other hydrogens equatorial to avoid the diaxial interaction?
Inversely, Why can’t we draw equatorial methyl and axial hydrogens to avoid any interaction?
I’m so thankful for you and your videos! Just a bit confused here
It’s important to remember that when drawing equatorial/axial positions, we are drawing tetrahedral carbons. If we make 2 axial or 2 equatorial groups on the same carbon, we introduce angular strain on the carbon, which is unstable.
Thanks bro
I’ve had three lectures of not understanding this and you do it in 3 minutes
That’s what she said
Thaaaank you so much
It was really helpful. I learned it here soo well
thank you for saving me
The equatorial bond in the front is angled improperly. Each equatorial bond should be parallel to the ring bonds that are at the 2,3 position relative to it.
I could be wrong, but I do not think you are slanting your equatorial positions in the right direction in the middle of the chair molecule