11.5 Solving geometric problems (PURE 1- Chapter 11: Vectors)

[@Sophia-ok4ce]

Thank you so much 😁

[@HindsMaths]

👍🏿👍🏿👍🏿

[@ubz05]

for the last question you could have just worked out magnitude of AB and AC and then worked out BAC using cos-1(root13/root26)

[@HindsMaths]

That would only work if the triangle was a right angle triangle and there's nothing in the question that says it is

[@ubz05]

@@HindsMaths oh ok thanks for telling me
It did end up being right angle though funnily enough 😅

[@HindsMaths]

👍🏿👍🏿👍🏿

[@MohammedHussain-ss6kj]

can you also find the vector for CB instead of BC 12:30 ?

[@HindsMaths]

Yes you can