From equation (1) we get a = 11-b. Insert this into (2) to get (11-b)b = 111 -> 11b - b² = 111 -> b²-11b-111 = 0. Now solve for b1,2 by applying the quadratic formula to get b1 = 33/2 and b2 = -11/2. Insert either solution into equation (1) to find that in case of b1, a1 would become -11/2, while in case of b2, a2 would calculate as 33/2. Hence there are two reciprocal solutions for real numbers of a and b: [a1,b1] = [-11/2,33/2] and [a2,b2] = [33/2,-11/2].
From equation (1) we get a = 11-b. Insert this into (2) to get (11-b)b = 111 -> 11b - b² = 111 -> b²-11b-111 = 0. Now solve for b1,2 by applying the quadratic formula to get b1 = 33/2 and b2 = -11/2. Insert either solution into equation (1) to find that in case of b1, a1 would become -11/2, while in case of b2, a2 would calculate as 33/2. Hence there are two reciprocal solutions for real numbers of a and b: [a1,b1] = [-11/2,33/2] and [a2,b2] = [33/2,-11/2].
Your answers are incorrect. 16.5 * -5.5 111