I go over two questions sent in by a subscriber. One involves finding the area of a segment and the other is a tricky compound shape. Thanks for 1000 subscribers!
This was so interesting to see which methods you'd choose! For the second question, I actually did it another way (which I found much quicker). If you do 24 / 8 = 3 this gets you the hypotenuse of a mini-triangle (by mini triangle, I mean the diagonal you'd get if you split each of the bigger squares into four smaller ones). Then, if you use Pythagoras, the sides of the mini square have length of three root two over two. To get the area of a mini-square, if you square the length of three root two over two, the area of a mini square is 4.5. Then, if you count that there are 22 mini squares, 4.5 x 22 = 99. That's how I worked it out, anyway. Thanks for these videos, keep up the good work!
Well explained videos. Sorry about you tube and being taken down but it is typical to use laws to stop teachers helping pupils understand a subject. It is like saying no one should demystify our little tricks. Maths is for the elite who do not need this help. You are a teacher at heart, love your subject and want to inspire and engender that love in others. Sadly this is exam board thinking ie defensive and short sighted only seeing the narrow aim of assessment..
Would there be any way you could upload the videos to google drive and provide a link to it in one of your videos? They are incredibly helpful and have revolutionized the way in which I've revised maths. I would love if you were able to keep this up!
I got the second one but I found the first one really difficult. Now I have seen the method to use it seems really easy but sometimes knowing how to approach a problem is the hardest part.
Hello sir. I just tried this one and did it the following way. Diagonal length of one square is 24/4=6cm. If we cut one square in to quarters this forms a right angled triangle with length and height of 3cm. The area of which is 1/2x3x3= 9/2cm2. There are 22 quarters in the pattern. 22x9/2=99cm2. It's quite a simple method for 5 marks but gets the same answer as yourself.
Even if you don’t know area of a sq is (d^2)/2 you know both diagonals are the same within a square and the square can be halved into a triangle and since there are two triangles in one square, you just do base x height = 6cm x 3cm = 18cm^2
For the second I just seperate into half squares (so became triangles) and there were 8 so 24/8 is 3 - ik it’s more complex and useless but got the answer
Thank you sir for the videos they are an amazing aid to revision. With regards the copyright strike this is quite common with people who upload videos but this is the first time I've heard of this happening with exam videos. Now that Edexcel have started this I assume the other exam boards will follow suit. You could try several things. Firstly, contact Edexcel at the highest level and persuade them to allow you to do so on the basis of fair use. If they decline you can always publish their response and contact the media and allow the public backlash to change their position. Alternatively you can upload all your videos to a file sharing site like mega and provide links where students can still access your videos. Hopefully this can be resolved with Edexcel and it's just some over-zealous bureaucrat getting ahead of himself.
Interesting you say that. I did contact Edexcel. The reason is that schools want to use the papers as mocks, so it’s a reasonable explanation. I just wished they had asked me to take them down, rather than using a copyright strike. The problem is that there are many other videos out there covering the exact same papers, so why they just targeted me I don’t know.
Sorry to learn your videos were taken down in this way. Typically those who try to help are seen negatively by exam boards as showing the tricks they want kept secret so use copy laws to stop you.
Maths Explained honestly i look it thinking: thats a difficult question. There youre here like this, this and that, that and everything makes perfect sense. Please teach me how to work out something that isnt soo clear
There is a really great website by Mr. Barton, called SSDD problems. It talks about how to recognise the strategy needed to answer problems. It might help you: ssddproblems.com. I will be doing a detailed video on this soon.
for the first question, couldn't u have just calculated both areas of circle using the radius and pi r squared. then minus the areas to find the unshaded area of the small circle. then minus that from the full area. i think that should work?
the area of the large circle can be calulated by the radius given on the graph which is 5. and then pi*r^2 (pi times r squared) to get the area of the large circle. then the radius of the small circle is given as 3 so the area can be calculated by pi r squared again . then you minus the area of the large circle from the small circle. then minus the area of the small circle with what u just took away from the previous minus.
RocksLikeA13055 no that would not work because the shaded area is not from the diameter, but it is a curve instead, therefore you're way would not work
hi i emailed you i think yesterday about paper 2 which was taken down. If your not able to get the video to me any sort of help on Q19 Q22 and Q23 would be greatly appreciated!
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Very methodical, clear way of explaining difficult GCSE maths. Really helpful thanks.
gutted about the past papers really useful but your videos are useful anyway
thanks
Really Helpful video thanks a lot. Regards From Jamaica
Ah yes. Saw that on my church hill paper. Thanks for explaining
👌🏻
This was so interesting to see which methods you'd choose!
For the second question, I actually did it another way (which I found much quicker). If you do 24 / 8 = 3 this gets you the hypotenuse of a mini-triangle (by mini triangle, I mean the diagonal you'd get if you split each of the bigger squares into four smaller ones).
Then, if you use Pythagoras, the sides of the mini square have length of three root two over two. To get the area of a mini-square, if you square the length of three root two over two, the area of a mini square is 4.5. Then, if you count that there are 22 mini squares, 4.5 x 22 = 99. That's how I worked it out, anyway.
Thanks for these videos, keep up the good work!
Love it! Thanks for sharing :)
Well explained videos. Sorry about you tube and being taken down but it is typical to use laws to stop teachers helping pupils understand a subject. It is like saying no one should demystify our little tricks. Maths is for the elite who do not need this help. You are a teacher at heart, love your subject and want to inspire and engender that love in others. Sadly this is exam board thinking ie defensive and short sighted only seeing the narrow aim of assessment..
Thanks this will really help :)
It looks really confusing but it all makes sense now thanks!
Would there be any way you could upload the videos to google drive and provide a link to it in one of your videos? They are incredibly helpful and have revolutionized the way in which I've revised maths. I would love if you were able to keep this up!
I got the second one but I found the first one really difficult. Now I have seen the method to use it seems really easy but sometimes knowing how to approach a problem is the hardest part.
You need to know how to find the area of a segment. A lot of students wouldn’t have done this before I think
Yes, thanks
very helpful thankyou very much
Hello sir. I just tried this one and did it the following way. Diagonal length of one square is 24/4=6cm. If we cut one square in to quarters this forms a right angled triangle with length and height of 3cm. The area of which is 1/2x3x3= 9/2cm2. There are 22 quarters in the pattern. 22x9/2=99cm2. It's quite a simple method for 5 marks but gets the same answer as yourself.
very nice :)
Thank you
Even if you don’t know area of a sq is (d^2)/2 you know both diagonals are the same within a square and the square can be halved into a triangle and since there are two triangles in one square, you just do base x height = 6cm x 3cm = 18cm^2
For the second I just seperate into half squares (so became triangles) and there were 8 so 24/8 is 3 - ik it’s more complex and useless but got the answer
is there a way to get the videos privately? Enjoyed the video none the less!
can you email me the papers?
Thank you sir for the videos they are an amazing aid to revision. With regards the copyright strike this is quite common with people who upload videos but this is the first time I've heard of this happening with exam videos. Now that Edexcel have started this I assume the other exam boards will follow suit. You could try several things. Firstly, contact Edexcel at the highest level and persuade them to allow you to do so on the basis of fair use. If they decline you can always publish their response and contact the media and allow the public backlash to change their position. Alternatively you can upload all your videos to a file sharing site like mega and provide links where students can still access your videos. Hopefully this can be resolved with Edexcel and it's just some over-zealous bureaucrat getting ahead of himself.
Interesting you say that. I did contact Edexcel. The reason is that schools want to use the papers as mocks, so it’s a reasonable explanation. I just wished they had asked me to take them down, rather than using a copyright strike. The problem is that there are many other videos out there covering the exact same papers, so why they just targeted me I don’t know.
Maths Explained because you’re the biggest channel
Maths Explained this channel is getting big thats why
i got my mock results back and i got an 8 thanks to your videos thanks
Hi. I like your videos. What software do you use to write the answers on your screen? Thanks.
how i make videos: bit.ly/2QA2WUo
We did this question in our class!!!
It’s a great question written by Churchill maths. They deserve the credit
For that second question you can do it in your head if you brake it to 22 squares as each quarter square is 4.5cm^2
Why have you taken down the November 2017 papers??
They were taken down, sorry!
I went away and I came back 👌
I hope this kind of question comes in paper 3 now😂
Similiar question to the last question on the edexcel gcse math paper
On the first one, surely to find out the area of a non right angled triangle it’s 1/2 (a x b) x sin c, not half base times height?
You have the height of the triangle so you don’t need to use 1/2absinC. You only need to use it if you don’t have the perpendicular height
Sorry to learn your videos were taken down in this way. Typically those who try to help are seen negatively by exam boards as showing the tricks they want kept secret so use copy laws to stop you.
Helped alot thanks
why do you make it look so easy?!
Haha what do you mean?
Maths Explained honestly i look it thinking: thats a difficult question. There youre here like this, this and that, that and everything makes perfect sense. Please teach me how to work out something that isnt soo clear
There is a really great website by Mr. Barton, called SSDD problems. It talks about how to recognise the strategy needed to answer problems. It might help you: ssddproblems.com. I will be doing a detailed video on this soon.
can you unprivate the november 2017 paper 3 and send me it?
I will probably get another copyright strike
If you unlist and then link they can't strike i believe. please just unlist for like a min just so i can get it and download it
There can I’m sorry
well can u atleast say where you got the paper from so i can print it ?
paper 3: goo.gl/5imEyz
Is this by AQA?
these questions were from churchill maths who does all exam boards I think
This hasn't come up in any paper i have done all of them since 2012, looks more like an A level question?
It is included in the higher spec
This is edexcel
Could you create a PDF file of this question.
Here you go: drive.google.com/file/d/14by-eqAkyBUTIYCIVzuOdrh81AQz5DLP/view?usp=sharing
where is paper 3 November 2017? I'm sure u had it uploaded
Maths Explained I think I figured out the reason they took it down. Year 11 are doing the papers which were taken down as mocks.
Maths Explained Thanks for your time!
Is this a calculator test
for the first question, couldn't u have just calculated both areas of circle using the radius and pi r squared. then minus the areas to find the unshaded area of the small circle. then minus that from the full area. i think that should work?
Minus what area? I’m not sure that’s working
the area of the large circle can be calulated by the radius given on the graph which is 5. and then pi*r^2 (pi times r squared) to get the area of the large circle. then the radius of the small circle is given as 3 so the area can be calculated by pi r squared again . then you minus the area of the large circle from the small circle. then minus the area of the small circle with what u just took away from the previous minus.
I’m not sure. Try it and see I guess
RocksLikeA13055 no that would not work because the shaded area is not from the diameter, but it is a curve instead, therefore you're way would not work
You are very clever , I would not no where to start with this 🤔🤔🤔
i emailed you and you didnt reply
Sorry, I got a lot of emails because my videos were taken down. I haven’t replied to any yet as I’m not sure about the situation
ez
Couldn’t you just do area of big circle - area of small circle = shaded area
Try it and see!
@@maths.explained when r u gonna upload we miss u
hi i emailed you i think yesterday about paper 2 which was taken down. If your not able to get the video to me any sort of help on Q19 Q22 and Q23 would be greatly appreciated!
I’m grade 7 and I don’t understand most of them lmao
same xd
can you check your email please :)
I could do both of these already and I'm in year 7 (grade 6 for you americans)