The answer to the qst question is very time consuming. Instead, we can just say that vertex is the lowest point in a parabola and all other points will have greater value of f(x). Therefore, the answer is -12. Also, it may help in some other question, but you can say a+b+c=f(1)
@@OverclockingCowboy So what you are trying to say is that, since the vertex is the lowest point any value of x will lead to a larger value of f(x) than f(9); So, we can say f(1) will be greater than f(9); we know what both of them are: This helps us say a+b+c > -14
All these questions have simpler and logic way to figure out the solutions efficiently and accurately. The first step is not to calculate but to analyze. For example, the 2nd question, since you've gotten kj=-45, so j=-45/k; and the question said that j is an integer so -45/k is an integer, then 45/k is also an integer.
Took the DSAT today and the last question was similar to your first question in the video. In the test, the question gave the roots to the function and asked for the sum a + b. For anyone wanting to try out the question the coordenates given were (12,0) and (-6,0) and a > 1. Answer is -10
@@NataliaPodut Hi, I tried to solve this question too, and here is my work process: When the roots are (12,0) and (-6,0), and a > 1, we know that the factored form of the quadratic function is: y = a(x-12)(x+6) When we expand this into the form [ax^2 +bx +c], it is: y = a(x^2 -6x-72) --> y = ax^2 -6ax -72a Now here, I am assuming that the question asked for the SMALLEST value of (a+b). Then we can assume that the value of 'a' is 2 (since the smallest value that satisfies a>1 is 2). a = a = 2 b = -6a = -6*2 = -12 Finally, the values of a+b would be: 2+(-12) = -10 Therefore, the answer is -10. Sorry if my explanation isn't that great. I hope it made sense!
More hard questions + density are here: www.admissionhackers.com/sms density was tested on paper SAT as well, will check if there's any worth making a video on.
haha the English section is much more challenging... in America this is a standardized test, so anybody who is taking tough classes can do this pretty easily
For 3rd one If you're going to attempt digital sat Jut put the equation in desmos And put the options give "r" any value which ever point lies on the Line for every value of "r" that's your answer Cause these eq are same they have infinitely many solutions So whichever the value of r is the correct solution (point) will always be on the graph
For the lasr question, you can do it in your calculator. Just plug in both equations and it will give u the two answers for x and y being X=7/2 -3/2 y And y=y, this is the same format as B for the last question but instead of r, y is used in the calculator.
For the first one you don’t even need to do any calculations. -14 is the minimum value y can take once you draw the graph. So at any other x apart from 9, my y value has necessarily got to be higher than -14. And there’s only one option that is larger than -14.
as a turkish student i recommend you to check out 2024-AYT exam we turkish students suffer while our european and american brothers and sisters enjoy their lives
the last one was on june 2023 sat test. took my time. ended up just guessing the answer. nevertheless fortune was on my side that day. eventually scored 780
answer this please , a circle with Centre, C= (h,k) contains point A,B A=(h+1,K+ sq root of 138) and angle ACB is a right angle. find length of arc AB.
Angle ACB is a right angle ,that means the distance(arc) length of AB is equal to 1/4 of the circle which is (pi X r)/2 radius = distance b/n a and c R^2 = (h+1-h)2 + (k+sqrt 138-k)2 R^2= 1^2 + 138 R^2 = 1 + 138 R= sqrt 139 Arc ab= (pi X sqrt 139)/2
The first question after some long algebra i got that a = (175/1000) b=(-315/100) and c=(175/1000) and pluging in this numbers into x=-b/2a (you get 9) and y=-D/4a you get -14 , so the question is that my answer dont add up to any of the possibility that are there but they do give you a D>0 wich means two solutions and the right vertex point so help me
I will be giving the digital sat this august. However, I am at a score range of 650 to 680 in math . I did watch some of your videos for help to solve some of the questions but improved by 70 to 80 points. My main area of weakneeses are in the following topics: Median, quadratics (hard questions such as in this video), sometimes percentages, and functions with transformations. Can you guide me what measures to take in order to get at least 780 or even a perfect score on the maths section. I might give the Digital sat in October again.
is it just me or is the 1st question hard? because I still don't get how John got -12 to be the answer ( I don't understand why a, b, and c are incorrect)
We can estimate where the vertex is, and the question says that there are two solutions. Therefore, we know that the graph must open upwards in order to meet and intersect the x-axis. After expanding vertex form, we can simplify and find the equation for a. The minimum value of a must be 0.0000000001 ( or higher than 1), there it is impossible to attain any other value for the answer.
first response is correct, but in simpler terms, it's because 14 subtracted from any positive number will equal a number greater than -14. Answer choices A and B are both less than -14, so they can't be correct. Answer choice C is -14, which is also incorrect because -14 is not greater than -14. Therefore D is the only possible answer.
Since the “a” must be positive,we should plug in a option which will cause the value of “a” be positive,means the number should be larger than -14 (=>-12) so that their sum will be positive.-12+14=2,which is positive ✅
Hi, I want to buy your course but the thing is that I'm a foreigner ",i have never taken sat before and my math score is 250 and you said your course can help only students who have above 400 points Should I purchase your course If not how can I improve my score ?
Hi, I want to buy your course but the thing is that I'm a foreigner ",i have never taken sat before and my math score is 250 and you said your course can help only students who have above 400 points Should I purchase your course If not how can I improve my
Hey John am currently in the 650-700 range but it look like am no good when it comes to level 4.5-5 questions. Could you advice me on what to do so I can get a perfect score on the math section for the December SAT
I'm also going to take the sat this December, my tip is just to practice. I raised my score from the 500 range to the 750-790 range. Write down whatever type of question you don't know then watch TH-cam or Khan Academy on it then do some ixl.
I'm also presenting December. I hope to improve my scores, you guys have any tips to improve Math Section? I had a 680 on my last sim and I know I can do better.
The vertex was underneath the x-axis and the parabola intersects the x-axis at two points so we know it opens upward, if it opened down it would not intersect the x-axis at all because the vertex is under the x-axis...
Wouldn't the answer to the first question be -14? If you plug in 0 for a, and and then add the terms, you would end up with 0x^2-0x-14, which would result with the answer being -14.
not really. Im taking a-level maths currently in my senior year, and yes I do agree a-level maths is way way more advanced, the exam questions are rarely tricky. Id say just study the syllabus and you'll do great. Sat on the other hand, questions are often tricky, and it feels like I must know the strategies for each type of question.
Wait, in the second question, if you expand (hx+k)(x+j), which is (hx^2+hjx+kx+kj) or (hx^2+hjkx+kj) which makes b = hjk, and since h = 4, kj = -45, b is simply 4*(-45) = -180, which in this case, b/h is -180/4 = 45, is an integer, can someone explain where I got wrong?
In the second question, it was rather easy to calculate b. b=hjk=4*(-45) Which makes option A the correct choice too. So if 2 options seem equally right, will I be given the marks if i choose option A?
isn't it b = hj + k tho? cuz it's hx^2+hjx+kx+kj but hjx+kx doesn't equal hjkx, right? Unless I'm wrong, answer A might be founded upon this mistake. Remember that's there's only ever one right answer to a problem; if another looks correct, something is whack.
The parabola intersects x-axis at 2 points,also it is given that the vertex of that parabola is (9,-14) , so if you draw it on xy-plane it is clear that a should be positive.
The parabola has a vertex positioned under the x-axis so if the it opened upward it would intersect the x-axis ( which it did ) and if opens down then it wouldn't intersect at all - just because the vertex is underneath the x-axis
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Post questions in the comments - Good luck on Saturday everybody 🫡
First Question : DSAT PT 4 - Module 2 - #26 *_(Page 48)_*
satsuite.collegeboard.org/media/pdf/sat-practice-test-4-digital.pdf
Second Question : DSAT PT 4 - Module 1 - #23 *_(Page 38)_*
satsuite.collegeboard.org/media/pdf/sat-practice-test-4-digital.pdf
Third Question : DSAT PT 1 - Module 1 - #26 *_(Page 40)_*
satsuite.collegeboard.org/media/pdf/sat-practice-test-1-digital.pdf
Where are the answers to all these questions? How would i know that i have done correctly?
The answer to the qst question is very time consuming. Instead, we can just say that vertex is the lowest point in a parabola and all other points will have greater value of f(x). Therefore, the answer is -12. Also, it may help in some other question, but you can say a+b+c=f(1)
Ohh
Thanks you, but I don’t get it, how does it help us assume that it is good to say a+b+c=f(1) to answer the question?
@@haziquniverse It doesn't help in this question, But in other questions, it may help
@@haziquniverse
The vertex is at f(9). If f(1) > f(9), the parabola opens upward. Hence, a+b+c > -12.
@@OverclockingCowboy So what you are trying to say is that, since the vertex is the lowest point any value of x will lead to a larger value of f(x) than f(9); So, we can say f(1) will be greater than f(9); we know what both of them are: This helps us say a+b+c > -14
thanks bro i was really struggling with the 1st question
All these questions have simpler and logic way to figure out the solutions efficiently and accurately. The first step is not to calculate but to analyze. For example, the 2nd question, since you've gotten kj=-45, so j=-45/k; and the question said that j is an integer so -45/k is an integer, then 45/k is also an integer.
Yeap, that's the logic I used. I just did the math to demonstrate the math behind the logic.
Took the DSAT today and the last question was similar to your first question in the video. In the test, the question gave the roots to the function and asked for the sum a + b. For anyone wanting to try out the question the coordenates given were (12,0) and (-6,0) and a > 1. Answer is -10
hey i tried to solve this but I'm stuck, can you pls share how you got -10?
@@jayshoney3045 they give you the roots, so reverse factor basically to find b and c. then find a by plugging in roots
@@returntolobby3030 what do you mean by reverse factor?
@@NataliaPodut Hi, I tried to solve this question too, and here is my work process:
When the roots are (12,0) and (-6,0), and a > 1, we know that the factored form of the quadratic function is:
y = a(x-12)(x+6)
When we expand this into the form [ax^2 +bx +c], it is:
y = a(x^2 -6x-72) --> y = ax^2 -6ax -72a
Now here, I am assuming that the question asked for the SMALLEST value of (a+b). Then we can assume that the value of 'a' is 2 (since the smallest value that satisfies a>1 is 2).
a = a = 2
b = -6a = -6*2 = -12
Finally, the values of a+b would be:
2+(-12) = -10
Therefore, the answer is -10.
Sorry if my explanation isn't that great. I hope it made sense!
thank yo so much!!! @@선-b8x
bros arms are immaculate.
Ong bro 💀
@@CuttingGrass___fr I’d let him put me in a chokehold with those massive pythons 😍😍😍
Do you know any other places to practice these level 5 questions? Also, could you make a quick one about Density? It is a new topic on the DSAT
More hard questions + density are here: www.admissionhackers.com/sms
density was tested on paper SAT as well, will check if there's any worth making a video on.
Density is just mass/volume, usually density and mass is given, or you can just calculate volume with the given numbers
it says its 400$ ;-;
@@JohnSAT
this actually is so helpful thank youuu
Bruh I wish I was born in the US💀
haha the English section is much more challenging... in America this is a standardized test, so anybody who is taking tough classes can do this pretty easily
@@avery8733 nah man he is taking sat so he can go to usa
For 3rd one
If you're going to attempt digital sat
Jut put the equation in desmos
And put the options give "r" any value which ever point lies on the Line for every value of "r" that's your answer
Cause these eq are same they have infinitely many solutions
So whichever the value of r is the correct solution (point) will always be on the graph
For the last example if you plug in a one for each x value you’ll still get the right answer
I gave yesterday’s SAT, the module 2 for maths was particularly challenging but rest of it was pretty easy, expecting above 1500 ;D
What did you get?
whatd u get
whatd you get
how much did u score?
for the last question, you have one equation and one unknown, you will get an r value for each of these x,y coordinates thus all are correct. Thanks
hey john can u post more last min vids before saturday these help out a lotttt
Heyy, how is your preparation going
@@baobei5908 its v good how bout you
For the lasr question, you can do it in your calculator. Just plug in both equations and it will give u the two answers for x and y being
X=7/2 -3/2 y
And y=y, this is the same format as B for the last question but instead of r, y is used in the calculator.
Thank you
i don't understand, how do you plug in both equations if they are the same
1st qs can be simply done by discriminant we will get a>0 so the ans should be the last one❤❤❤❤
For the first one you don’t even need to do any calculations. -14 is the minimum value y can take once you draw the graph. So at any other x apart from 9, my y value has necessarily got to be higher than -14. And there’s only one option that is larger than -14.
You are so right 🧠
I'm not trying to spread negativity... these videos are useful...but.. aren't these questions a bit easy
Yes the SAT is easy, it’s just a matter of knowing how to do them, which is kinda hard because the questions are supposed to trick you
as a turkish student i recommend you to check out 2024-AYT exam we turkish students suffer while our european and american brothers and sisters enjoy their lives
the last one was on june 2023 sat test. took my time. ended up just guessing the answer. nevertheless fortune was on my side that day. eventually scored 780
GG
@@knowbody1bro fr said GG😭😂
@@Omar-rk2jk ?
@@Omar-rk2jk think he meant on math section not overall HAHAH
@@adithyavenkataraghavan299 😅😅🤣🤣🤣
answer this please , a circle with Centre, C= (h,k) contains point A,B A=(h+1,K+ sq root of 138) and angle ACB is a right angle. find length of arc AB.
Angle ACB is a right angle ,that means the distance(arc) length of AB is equal to 1/4 of the circle which is (pi X r)/2
radius = distance b/n a and c
R^2 = (h+1-h)2 + (k+sqrt 138-k)2
R^2= 1^2 + 138
R^2 = 1 + 138
R= sqrt 139
Arc ab= (pi X sqrt 139)/2
for 26 example I offer to use simple values as x=2, y=1
Good luck y'all!
The first question after some long algebra i got that a = (175/1000) b=(-315/100) and c=(175/1000) and pluging in this numbers into x=-b/2a (you get 9) and y=-D/4a you get -14 , so the question is that my answer dont add up to any of the possibility that are there but they do give you a D>0 wich means two solutions and the right vertex point so help me
bruh this is like 8th grade level questions
come to India and have a look at jee you guys will have an existential crisis.
I will be giving the digital sat this august. However, I am at a score range of 650 to 680 in math . I did watch some of your videos for help to solve some of the questions but improved by 70 to 80 points. My main area of weakneeses are in the following topics: Median, quadratics (hard questions such as in this video), sometimes percentages, and functions with transformations. Can you guide me what measures to take in order to get at least 780 or even a perfect score on the maths section. I might give the Digital sat in October again.
Go read rules for transformation and median then just do some practice
Did you take the exam? What are your results?
@@amazingjuanpedro99 results aren’t out yet
update?@@Muhammad_Ibrahim864
@@Muhammad_Ibrahim864 how was it?
Thanks for the video! at least now i have less questions to worry about now
thank you
❤❤thanks soo much
THESE ARE 10TH GRADE QUESTIONS HERE IN INDIA
is it just me or is the 1st question hard? because I still don't get how John got -12 to be the answer ( I don't understand why a, b, and c are incorrect)
We can estimate where the vertex is, and the question says that there are two solutions. Therefore, we know that the graph must open upwards in order to meet and intersect the x-axis. After expanding vertex form, we can simplify and find the equation for a. The minimum value of a must be 0.0000000001 ( or higher than 1), there it is impossible to attain any other value for the answer.
first response is correct, but in simpler terms, it's because 14 subtracted from any positive number will equal a number greater than -14. Answer choices A and B are both less than -14, so they can't be correct. Answer choice C is -14, which is also incorrect because -14 is not greater than -14. Therefore D is the only possible answer.
@@abhinavgottipati I understand why a cannot be negative, but why can't it be 0?
@@olaostrowski3894 if a is zero, your equation would be y = 0*(x-h)^2+k or just y=k which is a straight horizontal line.
Since the “a” must be positive,we should plug in a option which will cause the value of “a” be positive,means the number should be larger than -14 (=>-12) so that their sum will be positive.-12+14=2,which is positive ✅
Do we get a rough sheet on the test day of DIGITAL SAT?
As a guy who studies for YOS,these are very easy for me
bro it's America😂😂
@@mikethegamedev ye
I have seen a method including desmos, would that method work always?
Hi mr jon I start the sat new I don't know which book I should give if its possible can you answer to me which book I should use
Thanks
Hi, I want to buy your course but the thing is that I'm a foreigner ",i have never taken sat before and my math score is 250 and you said your course can help only students who have above 400 points
Should I purchase your course
If not how can I improve my score ?
you're the best
As a guy who is preparing for the Korean SAT, im not being sarcastic but I could've solved these in high school grade 2
Hi, I want to buy your course but the thing is that I'm a foreigner ",i have never taken sat before and my math score is 250 and you said your course can help only students who have above 400 points
Should I purchase your course
If not how can I improve my
Thank you
Hey John am currently in the 650-700 range but it look like am no good when it comes to level 4.5-5 questions. Could you advice me on what to do so I can get a perfect score on the math section for the December SAT
I'm also going to take the sat this December, my tip is just to practice. I raised my score from the 500 range to the 750-790 range. Write down whatever type of question you don't know then watch TH-cam or Khan Academy on it then do some ixl.
I'm also presenting December. I hope to improve my scores, you guys have any tips to improve Math Section? I had a 680 on my last sim and I know I can do better.
hi, i never saw any SAT test, but for the "hardest" these look low lvl, is SAT an easy test or something like that?
Easy for the Asians ig
i still couldn't understand why is it 12, an you explain?
do we get a formula sheet for the math section for the PSAT?
I did sat on oct and got 1230, math: 710 and eng :520 i really want to improve ....HELP
JEE ADVANCED laughing in corner!
Yah .. exactly 😂
Thanks
Where is s 6 week class
As a student at IIT Bombay these questions are very easy these types i questions i solved in my school in indian education system 😂
why are they so simple? even a grade 9th student can solve it
because *IT IS* grade 9 in the Asia
@@mikethegamedev no. because it is gifted grade 9 student
i used logic to solve the first one in like 10 seconds
Don’t know what is this but thanks
sat tomorrow I’m cooked
where did you get -18 from on the first question?
@@brandon-qw5eupppppppppppppppp
When making your parabolic formula the two -9s combine to make -18
Where did you get the -18 on 1st question? I’m so confused
2 no. Question is Easyyy though!!!!
There is an easier way to do the first one… realize a should be positive which e limited all the options other than -12
what about 'b'?
@@JohnSATb would also have to be positive?
@@srivallikatkuri8028why does it 'have to be' positive?
Cause a is positive and in vertex form x coordinate subtracted is also negative
@@JohnSATidk guess ur right then I got lucky getting -12
for the first question how did you know a is positive
bc the parabola opens upwards!
The vertex was underneath the x-axis and the parabola intersects the x-axis at two points so we know it opens upward, if it opened down it would not intersect the x-axis at all because the vertex is under the x-axis...
SAT 문제가 한국 중학교 수학 문제 수준이두나...
Is there anything changed in DSAT ? In terms of questions content.
Section two is adjusted based on skill and you have desmos the whole time. That's the main stuff
can we take our own calculators in the SAT exam for aug 26 digital sat?
yes, you should
For question 1, how did you get 18?
By completing square method
Because of the identity used as a^2 -2ab + b^2
(x)^2 -2(x)(9)+(9)^2
X^2 -18x +81
How tf are those considered hard? A 9th grader could solve them in less then like 10mins....
These were easy questions according to me
Isnt this just barely scratch the level of 10th grade? Atleast in asia
sir i think answer of last question is delta rather than beta
please confirm it
thx
Wouldn't the answer to the first question be -14? If you plug in 0 for a, and and then add the terms, you would end up with 0x^2-0x-14, which would result with the answer being -14.
a cannot be zero cuz then x^2 will also be a zero, which can never be the case cuz its quadratic
Also does not give us 2 intersections with the x-axis
isn't 81a - 18a = 63a :DD 2:01
you forgot to add the extra a
im not getting a 800 half the time coz i make 1 silly mistake
can u make some videos like this ???
More coming up
if this is SAT paper, then ICSE students could easily go the top universities in the US without any efforts lol
the sat is an English based test the math is relatively easy
not really. Im taking a-level maths currently in my senior year, and yes I do agree a-level maths is way way more advanced, the exam questions are rarely tricky. Id say just study the syllabus and you'll do great. Sat on the other hand, questions are often tricky, and it feels like I must know the strategies for each type of question.
I'm cooked.
Americans have it ez
lucky fellows
dawg wtf are these questions
These are mid question for my country (with due respect)
You said we were not going to plug it in but you did it anyways :(
Liar...
sat isnt hard
I'm nervous abt taking it on Oct 7
@@FuelSuccess-mw9ju how did it went
@@mikethegamedev It was great ig Ill get my result in 14 days but even if I dont get the result I'm hoping for.I will retake it.
@@mikethegamedev I got a 1100 I'll retake it after some time
Sorry to flex , but with an asian origin , these questions are nothing 🙂 We used to solve this in class 9 may be 🙂 .
wait....2:12.....how can it be D) when the answer is C)?
wait but if k and j could be 9,5,15,3,45,1 then technically b could be 4, -4, 12, -12, 44 or -44. All of these could be divided by 4 tho.
right, but b could also be 5,6,7, etc.
The question is asking for "MUST BE TRUE", so there can't be any exceptions.
It feels like you’re doing the math for yourself. You were going so fast. Like what????
These are hard?
Wait, in the second question, if you expand (hx+k)(x+j), which is (hx^2+hjx+kx+kj) or (hx^2+hjkx+kj) which makes b = hjk, and since h = 4, kj = -45, b is simply 4*(-45) = -180, which in this case, b/h is -180/4 = 45, is an integer, can someone explain where I got wrong?
b=hj+k not hjk
when u said "or" it should be hx^2 + (hj+k)x + kj
In the second question, it was rather easy to calculate b. b=hjk=4*(-45) Which makes option A the correct choice too.
So if 2 options seem equally right, will I be given the marks if i choose option A?
isn't it b = hj + k tho? cuz it's hx^2+hjx+kx+kj but hjx+kx doesn't equal hjkx, right? Unless I'm wrong, answer A might be founded upon this mistake.
Remember that's there's only ever one right answer to a problem; if another looks correct, something is whack.
@@BeckBond You are so right. Thank you! It was really helpful and kind of you
@@rehmatkaurmann1285 yaaaa welcome!! Best of luck on the test!!!!
@@BeckBond thank you. I wish you the best too
twas hard
after this video my Asian genes came out
for the first question how did you know a is positive
The parabola opens upwards. That's why the value of a had to be positive
The parabola intersects x-axis at 2 points,also it is given that the vertex of that parabola is (9,-14) , so if you draw it on xy-plane it is clear that a should be positive.
The parabola has a vertex positioned under the x-axis so if the it opened upward it would intersect the x-axis ( which it did ) and if opens down then it wouldn't intersect at all - just because the vertex is underneath the x-axis
bro dk what is a parabola and how a graph works💀💀💀☠