Kirchhoff's Voltage Law
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- เผยแพร่เมื่อ 3 ม.ค. 2012
- Introduces Kirchhoff's Voltage Law.
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i like this guy, simple and straight to the point
Thank you very much, i watched lots of other videos but didnt really understand why the sum of the voltage was equal to zero but now i do! so thank you again.
wow! really amazed by how you simplify difficult concept that I was struggling to understand with, excellent job.
But as @master1906 says, we can do it in that way also since we are going from a higher potential to a lower potential so while going away from higher to lower there should be a (-ve) sign and again from lower to higher there should be a (+ve) sign. So the equation for the first loop stands as,
-4V-1V-5V+10V=0
Just for a better understanding...
thx for ur detailed explanation!! you make it's much easy to understand:)
Mathematically, you can label voltages either as you suggest or as I do in the video; either way will lead to the correct solution. I use the convention that I do because it agrees with the way Ohm's Law is usually applied, which becomes more important when working with resistor circuits.
damn it, if only I had discovered this channel a months ago...
Thanks so much! I finally understand this!
explained very well...
Superb Video! Finally got the concept. :)
the good thing about the signs is that as long as you are consistently wrong you will still get the right answer.
Your video is appreciated
If you imagine you walking on the circuit board it is the sign that you leave on that you add or subtract from your total voltage
that was a nice video man....thanks
Thanks man!!!it helps alot!!!!
and you explain it very beautifully, thanks but plz answer my question, anyone..
I think the high and low potential has nothing to do with the magnitudes of the voltages...he basicly means the conventinal (excuse my speling) flow of current from posetive to negetive since posetive is at higher potential than negetive we have the posetive values,it changes from the 5v to the 10v its from negetive to posetive now it goes froma lower potential to a higher potential hence the negetive sign.....thanks for the question it made me understand even more....hope this helps.
Those are voltage drops. When current flows through a resistor, there is a drop in voltage and he just wrote those values near the resistors.
What i had trouble with was calculating the voltage drop across each resistor because every example i could find already has the voltage drop labeled which is quite frustrating cuz all you have to say for this video is Vin=Vout
Thank you so much
Excellent
Thank you very much......☺
If you want to use that convention, then I think you should add 'delta' in it, to signify a change/drop in potential. Otherwise it becomes very confusing if you are using that information for something else.
thank you!!
thank you very much
can someone explain to me the plus and minus thingies? are those rectangles supposed to be resistances or something ? I m confused :"D
For any new viewer, the rectangle boxes means resistor, internationally used outside of US.
I have a question, in the very first example he gave, if he switched the signs of the power source, wouldn't he get 20V?
So in the beginning you said from higher potential to low it is positive right? Then how come when your 5V is not negative when it is from low to high?
thanks !
You could give a little bit more insight, but it was a good video.
I don't understand how the 3V drop has a different sign than the other drops.
I disagree with this. If there is a voltage drop, then there should be a (-) sign next to the voltage. And a gain in voltage at the end of the circuit should be (+) so it still adds up to zero, but it is now logically correct.
Are we supposed to imagine something is there for the 6V or is that just the voltage drop between 4V and the source?
the main battery has a voltage of 10V. what if we take those batteries in the first closed path whose sum is not equal to (-10), what then?
for example, what if we have
5 + 2 +6 - 10
what to do now?
Please sumone explain to me why is that -3V up there? and not +3V
Because he chose that, it either gives it a voltage drop or a voltage rise. It could be a component that gives a voltage rise.
thanks
I am having problem solving a question..
Will you help with it @Darryl
Are you Ty Burrell?
i get the formula and stuff, but what i still don't understand is why if it doesn't add up? what if i have a 12V battery, a 5V bulb and a 10V motor, what happens then, did i just prove the law wrong?
+Olam Nomah No, you didn't prove the law wrong, you just proved you built and insufficient circuit. The law never changes. It's even applied as a Physics Law, which stamps it as it always works, no matter how you change the variables.
Your battery and motor will use less voltage in the circuit. the bulb would use 4 volts and the motor would use 8 volts of power in the circuit.
Isn't it backwards? I thought going form a lower potential to higher potential is negative.
It depends on how you see it, both cases are right. However, when computing you have to be consistent if you read it as a rise or a drop.
why's it -3V and not 3V?
+Abrar Rahman Just invert polarity
can u explain more???
It means current's direction is the opposite, just change the arrow going into the battery
That's not possible.
But good job on the video nevertheless.
OMG!! guys just see👉 Kirchhoff spelling 😱😱😱
You're not Sal...
why do his resistors have voltages? resistance is measured in ohms dont listen to this guy if your trying to learn about kirchoff's laws this will just confuse you and youll get it wrong
Mathematically correct but practically ignorant. I realize you are illustrating the voltage values that total to match input but will anybody ever see a negative series voltage in a circuit? Have you got a battery stuck in there?
Nothing wrong with having negative voltages in a series circuit. Contrary to what many people believe, I tell my students that the +/- signs across a resistor actually represent the placement of the +/- terminals of a dc voltmeter across it. Not knowing the actual direction of the current flow through a resistor one is thus free to connect the voltmeter either way. An analog voltmeter would not be able to display a negative reading but a digital voltmeter would have no problem doing so.
Feminists: He said pink is an ugly color! Patriarchy.... blah blah loool
your voice was giving me a headache