0:00:00 Highlights 01:23 Itihaas 01:10 Chapter Flow 01:39 Introduction 01:51 Concept of Force 02:24 Aristotle’s Fallacy 04:37 Galileo - The Law of Inertia 07:18 Newton 11:41 Momentum 14:26 Newton's Second Law of Motion 17:41 Questions Based on Newton's Second Law of Motion 18:48 Newton's Third Law of Motion 21:48 Questions Based on Newton's Third Law of Motion 23:37 Part 2: Applications 23:59 Application 1: Conservation of Momentum 27:18 Questions Based on Conservation of Momentum 27:47 Application 2: Impulse 34:43 Questions Based on Impulse 35:49 What is FBD? 36:24 Application 3: Equilibrium 36:57 Questions Based on Equilibrium 38:35 Application 4: Dynamics 43:03 Part 3: Common Forces in Mechanics 43:18 Common Forces 1: Tension Force 44:39 Questions Based on Tension Force 45:14 Common Forces 2: Spring Force 46:27 Questions Based on Spring Force 46:44 Common Forces 3: Friction 53:44 Common Forces 4: Centripetal Force 56:16 Questions Based on Centripetal Force
00:08 Introduction to Newton's Laws of Motion 02:01 Force is necessary to create motion 06:01 Inertia is resistance to change in state of motion or rest 07:50 Newton's First Law of Motion 11:45 Momentum describes the motion content in a body. 13:37 Force is the rate of change of momentum 17:23 Momentum defined by mass * velocity 19:06 Force and momentum are related in the laws of motion. 22:50 Momentum conservation and its application in isolated systems 24:48 Understanding the conservation of momentum in space 28:05 Understanding momentum and impulse 30:02 Understanding of impulse and momentum concepts 34:04 Understanding the concept of force and momentum in physics 36:11 Understanding Equilibrium in Physics 40:18 Understanding acceleration and force in physics 42:20 Common forces in mechanics and tension force explained 46:12 Understanding static and kinetic friction 47:48 Understanding static friction and its relationship with kinetic friction. 51:18 Understanding friction and force on an accelerating box. 52:56 Summary of Rolling Friction and Centripetal Force 56:19 Circular motion and centripetal force 58:06 The concept of friction and its relation to centripetal force and banking explained 1:02:16 Understanding the formula of PF
bhaiya aapse ek request hein, jabhi bhi kuch important qeuestion ya phir note screen pe aata hein toh thoda sa side hokar screen dekhado please, otherwise great video nice way of teaching
0:00:00 Highlights
01:23 Itihaas
01:10 Chapter Flow
01:39 Introduction
01:51 Concept of Force
02:24 Aristotle’s Fallacy
04:37 Galileo - The Law of Inertia
07:18 Newton
11:41 Momentum
14:26 Newton's Second Law of Motion
17:41 Questions Based on Newton's Second Law of Motion
18:48 Newton's Third Law of Motion
21:48 Questions Based on Newton's Third Law of Motion
23:37 Part 2: Applications
23:59 Application 1: Conservation of Momentum
27:18 Questions Based on Conservation of Momentum
27:47 Application 2: Impulse
34:43 Questions Based on Impulse
35:49 What is FBD?
36:24 Application 3: Equilibrium
36:57 Questions Based on Equilibrium
38:35 Application 4: Dynamics
43:03 Part 3: Common Forces in Mechanics
43:18 Common Forces 1: Tension Force
44:39 Questions Based on Tension Force
45:14 Common Forces 2: Spring Force
46:27 Questions Based on Spring Force
46:44 Common Forces 3: Friction
53:44 Common Forces 4: Centripetal Force
56:16 Questions Based on Centripetal Force
So hardwork :)
❤
🤟
41:52 SIr in the this ques the answer will be F=m(g+a)=20000(10+5)=300000N
Thank you
Ya......I was also kinda confused about that and knew someone in the comments would point this out
🙂 thank you. ..
2023 - 2024 Student Attendance here 👇👇
Yo
Yeah 😊
Why ? Are you a teacher with attendance register ?
Ha Teri Ma Ke Liye Aya Hu M Yha Leke Aja Apni Ma Ko
@@Vanshikashivendra-bu1hc kya kara yr bade hoka teacher ban na hai iss liyyaaa😅😅😅
41:58 SIr in the this ques the answer will be F=m(g+a)=20000(10+5)=300000N
how
27:34 ans is 500m/s
How bro? Please tell me
It may be 0.05m/s
0.05 m/s
We have to convert 10 gms into kg right?
27:46 0.05
-10×5/1000
0.05
chiku bhaiya maza a rha ha iss series ma but
we need this series for chemistry also
27:19 answer is A option 0.05 m/sec
00:08 Introduction to Newton's Laws of Motion
02:01 Force is necessary to create motion
06:01 Inertia is resistance to change in state of motion or rest
07:50 Newton's First Law of Motion
11:45 Momentum describes the motion content in a body.
13:37 Force is the rate of change of momentum
17:23 Momentum defined by mass * velocity
19:06 Force and momentum are related in the laws of motion.
22:50 Momentum conservation and its application in isolated systems
24:48 Understanding the conservation of momentum in space
28:05 Understanding momentum and impulse
30:02 Understanding of impulse and momentum concepts
34:04 Understanding the concept of force and momentum in physics
36:11 Understanding Equilibrium in Physics
40:18 Understanding acceleration and force in physics
42:20 Common forces in mechanics and tension force explained
46:12 Understanding static and kinetic friction
47:48 Understanding static friction and its relationship with kinetic friction.
51:18 Understanding friction and force on an accelerating box.
52:56 Summary of Rolling Friction and Centripetal Force
56:19 Circular motion and centripetal force
58:06 The concept of friction and its relation to centripetal force and banking explained
1:02:16 Understanding the formula of PF
53:40 ans - coefficient of sliding friction has dimension of length
41:56 Answer should be 300000, instead of 100000.
27:34 ans is 500m/s
23:30 it should be 150/1000 , sir wrote 150/100 please explain
@@ritishaissrani7356 yup ur right
Ye I also thinking abt it
Then y is the correct answer not in the options?
2024-25 present ✋
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Legends know yai slide 1 month phele 2:55:45 hour wali nlm ki video ki hai😅
Sir plz make one shot of work energy and power
27:45 500
Sir kl mera exam h and this video really helped i am glad i saw this video 😌
Newton ke sar per Apple ki jagah coconut gir Gaya hota to Aaj ham is chapter se Bach jaate😂
Best ever series I found .... Thanku sir .. 😊
All the best sabko kal ke exam ke liye 😅
kuch ni padha😭
@@yoursteel98 me fr
Woww figured out..
@@nvikasni me also fr
Thanks sir really appreciate you complete 5 hour chapter in 1 hours very helpful lecture Thanks again sir 🙏🏻♥️❣️
Get ready for exam on 3-10-23 hzb
Thank you sir for saving for
Our time❤❤
Sirji yh series chem or maths k liye bhi continue kro naa or 12th walo k liye bhi iss series ko continue kro naa ❤
222!
kal school exam vale 👇👇
Thank you sir for this amazing session.......😊😊😊
24:54 😂😂😂😂 sir teaches us in a funny way
Bada udas sa Chand hu mai....🌚
Thanks sir... For making the vdo... ❤
Mg×Vg=Mb×Vb
1kg×5m/s=10×Vb
1×5×1000/(10)=Vb
Vb=500
Can you pls explain how that 1000/(10) is coming?
Neet preparation wale like kre😊
Dude tomorrow is my exam .... Hope could pass phy ...🤞
Sir aap bahut accha padhate hai ese hii hamesha padhate rahiyega 5:43
3h to 1h really legend sir ❣️
doesnt tht mean less info?
@@timetagger-_-6195 when you have very less time and for rev this is just straight up gold
Be ready for tomorrow's exam
Mera to aaj hi hai subah uthkar padh rha hu😶😎
Bro but mra toh re exam hai
Bro but mra toh re exam hai
2024 - 2025 batch comment ⬇️
53:42 c
thanks a lot sir🙏....i couldn't understand this properly in my school but your video helped me a lot😇
Get ready for today's physics exam 🙌😄 25/09/23
@@agrimatripathi7308 jyada acha nhi gaya 😥 first time tha naa aur bilkul new subject tha examination ke liye aage dheere dheere progress ho jayegi.
I was finding like this channel from many days, finally I get this channel, Thanku so much for this wonderful explanation❤❤❤
24:54 that moon part 😂😂😂😂
Earth part 55:15
Except the types of frictional force , all other topics had been taught to me when I was in 9th standard. 😂
Respect button for sir❤❤
Sir... a rocket with a lift of mass....in this question answer is 300000 as F-200000=100000
F =300000 or 3 ×10⁵
Jisaka kal exam hai like kare❤❤❤😅😂😂😂
bhaiya aapse ek request hein, jabhi bhi kuch important qeuestion ya phir note screen pe aata hein toh thoda sa side hokar screen dekhado please, otherwise great video nice way of teaching
Sir work power energy or rotational motion kab aaega
Kal exam hai
Aaj exam hai mera😅😂
Hehe
@@Itsabhishek1144 hello
27:22= recoiling of gun
-m2v2/m1
M= (10/1000)
+1×5/10/1000
500 answer
Hi
SIR I CAN VERY EASILY UNDERSTAND THIS CHAPTER FIRST TIME😅🔥🔥🔥
Sir please make vedio on work energy and power
Yes
Thank you sir it really helps me
on 0.25 x i was able to notice that pen dropped faster than duster (till it was in frame ofc)
are toh its not a perfect world na... Duster may have faced a little more air resistance than the pen
aerodynamic
@@Affantm yeah.... Can be the reason.... Drag stuff, aerodynamic stuff.
Thank you bhaiya 😌😌
Better understanding......
chiku bhaiya please also make one shot of ch work power and energy and rotational motion because tomorrow is my physics exam😢😢😢
Haa kal mera bhi exam hai😅😅😅😅😅😅😅😅
Ha mera bhi kal paper hai
kaisa gya ?😁😅@@beast_the
Thank you sir 🙏🙏
does any one have the pdf of this chapter please
24:52
29:48
55:08
27:42 ans 500m/s
Thanks you sir watching this 2days before exam ❤❤
Thanks bhaiyaaa🎉
Is this video for jee level
Please give me answer
4:18 there in 0.25x you can see pen fall early😅
@@KrishnaGoyal-g9z yes bro
thats because air resistance was greater on the duster due to greater surface area
27:43 Answer is 500m/s
thank you sir
Thank you so
You are grateful teacher
Ànd savings for our it really helps me
21:52 how????
Plz correct
Very well explained sir💯✨
Sir 27:40 wala answer -ve me ayega
43:51 I must unseen it
Thankyou so much sir
It's very helpful of us
Ur the best sir❤❤❤🌈🌈✨✨
Thank u chiku bhaiya ❤
Hi
Last wale v ke formulae yaad karna padega?
24:00 moon part 😂
43:48 sir kya bandar banaya hai 💀
@@Futuristic699 Mai bhi ye hi dekh rha Tha
(A) Inertia of motion
Sir you are speech less sir i always appreciate you😊
Sir your study style is very amazing
43:45 Bandar 😂😂😂
ans is 500m/s
thank you for this amazing session sir!
Bro Mera -500m/s aaya
Thanks sir
Kon kon ye video january mai dekh raha h 😂
@@ashmitadhikari9212 😅
Work energy vala chapter kab aayega sir?
25:08 😅
Sir please momentum physics explain kijiye na
Sir esa kuch Karo ki 1video me sare ch khtm ho jae 😂😅
I am in class 9th🤫 I see for my preodic test 🤔In my school conceot teach highlevel 🫣🤭 ❤Thanks❤
doubt remainig:- résistance and inertia relations ?
Chiku sir Pls teach us deviation tooo
Like if you want derivation guys
41:52 sir yha pe 3×10⁵ ayega
Pass ❤
27:18 a) 0.05 m/s
Answer is 500m/s ready question carefully
@@ravigaming9345 how can you explain pelej
18:35
41:53 answer will be 300,000N
Rdfsfs7gs8heg8sg8dg8dg8dosgosgosgiagai😮🎉😅❤😊🎉😅🎉😮😮😂😮❤😮❤😮😅🎉🎉😊😢😊😊😂😂😮😮❤😅😅😂😊😢😢😅😮❤😮❤😮🎉😅🎉
Sir plss make video of ch work energy and power because we have exam on 25th
Thanku bhaiya 😭
Jee or normal 11th?
41:56 Answer should be 300000
Kal paper h or aaj padhne aaya h😂😂