Here is newton's fourth law😂 "that every book continues in the state of rest until and unless an external or internal exam appears and the speed of page turning is directly proportional to the syllabus to be covered and the tension in mind remains constant.😂
0:00 Introduction 1:07 Force 3:04 Inertia 6:15 Newton's 1 law 8:43 Momentum 11:56 Impulse 13:20 Question 1 19:12 Newton's 2 law 21:32 Newton's 3 law 23:39 Question 2 33:46 Tension 40:05 Question 3 47:21 Friction 51:50 Angle of friction (Angular Friction) 54:16 Angle of repose 58:45 Question 4 1:02:42 Lift Case "Centripetal force" is not in this video Thank you sir for saving our time and exam and thanks for this amazing video .
i have watched 6 more videos for same chap but at last i came here to understand properly beacause there is no other teacher like abhishek sir. he deserves much better
best way to understand tension force is... imagine ur both hands are tied with rope and stretched in opposite direction with same force... to protect and to resist it u will stretch towards center i.e. away from body
I never thought that someone could teach better than physics wallah. seriously you taught well and we need teachers like you and also the lecture was engaging.thank you !
1:2:25 , first value of f find f/mg= mew, f = 6 put in 4g-f=7a , 40-6=7a , 34=7a, 34/7=a, 4.8=a put value a in eq 1st 5g-T=5a, 50-T=5×4.8, 50-T=24, 50-24= T, 26N=T Thanku💕
First, we'll solve the first equation for T: 5g - T = 5a T = 5g - 5a Now, substitute this expression for T into the second equation: (5g - 5a) - 2g sin(30°) - f = 2a Simplify and rearrange: 5g - 2g sin(30°) - f = 7a g = 9.8 m/s² (acceleration due to gravity) f = 0 (no friction, or friction is negligible) Substitute these values: 5(9.8) - 2(9.8) sin(30°) = 7a 49 - 9.8 = 7a 39.2 = 7a Now, solve for a (acceleration): a = 39.2 / 7 a = 5.6 m/s² Now that we have the acceleration, we can find the tension (T): T = 5g - 5a = 5(9.8) - 5(5.6) = 49 - 28 = 21 N So, the acceleration is approximately 5.6 m/s², and the tension is approximately 21 N.
For those who have problem in finding acceleration in 1:02:25 - find the value of f by using formula f/mg=mew,m is 2kg and value of mew is given.And then it gives f=12N , now put these in eq.2.Answer is acceleration = 5.4 m/s square and tension = 22.8N.
Yaaaaaan Poore saal wamu wamu kiya kutta fadke Aur kal mera midterm exam hai 😂😂😂😂 Usme tho ye nahi lik sakta Tho ab sahu sahu chillaunga paper faadke😂😂😂😂😂
Sir keep it up......👍🏻👍🏻mind blowing on whole TH-cam only u are supporting to school students....rest all other faculties completing a chapter in 10 to 20 hrs🤕
bhai vo questions or concept pe time bhi to utna hi dete h y video sirf revision ke liye use kr skte hai agr kisi new session ko bache ko ye dekhke ye bol diya jaye ki chapter khtm to it is not good even he had covered every topic
I think the correct answer must be: As we know Fs=0.3*mgcos30=5.19 Then, a=4.97 So after putting the value of 'a' the tension will be 25.15 N Waiting for your check sir!
Thanks for it I am doing wrong through I am taking 2G edge mass for finding friction force but after seeing your answer I will know that reaction force is equal to MG cos theta then simply we get the right answer
Where are thsse Motion Intuitive concept of force, Inertia, Newton's first law of motion; momentum and Newton's second law of motion; impulse; Newton's third law of motion. Law of conservation of linear momentum and its applications. Equilibrium of concurrent forces, Static and kinetic friction, laws of friction, rolling friction, lubrication. Dynamics of uniform circular motion: Centripetal force, examples of circular motion (vehicle on a level circular road, vehicle on a banked road).
Tip : Banking of road is not covered in the video but is very important topic and can be asked in school exam because my school teacher gave this topic in 5 marks in both Unit testsand half yearly examination....
Hi everyone I am from sose dwarka Only due to these helful videos i able to crack sose entrance out of 96000 thoushand student ... Nice ab sir keep it up. I want a video also in whole basic mathematics used in physics . With practice dpp ... I hope you will make
Sir Newton third law of motion ke first questions me 21N ka nahi 24N ka force lagega and Jo aapne momentum wala question bataya hai usme -2-2=+4 nahi -4km/s aayega
Newton's fourth law of motion🤣🤣:- Every book continues to be in state of rest and covered with dust until and unless internal and external exam appears and the speed of the page turning is directly proportional to the syllabus covered and tension in mind remain constant.
" first understand concept then short cut" 24:42 golden rule If we study like that we can crack any exam with ease. I highly appreciate this strategy of yours sir coz not every coaching teacher does this and that is why most of the students find difficulty in solving tricky problems
@@Adarshnotforyou bro one chapter in chem alone takes a week. My basics are shit and i barely pass in maths. On top of that i missed half my classes and have zero notes. I do not go to tutions not coaching classes. I have no clue how i even got sci considering how laid back i am. Regreting my decisions frr.
@@jkn.01 bro... Me relating to you seems to be so concerning... I also don't have any notes as I started 11th very late... Although tomorrow's my last quaterly exam and it's chemistry ☠️ and did you also choose pcm... I did... And getting fucked by it... And because I was constantly getting Ill one time after another.. I missed almost all my classes... Barely passing these exams with one shots .. and still trying to find tuitions..
@@khalidahazarika8748 ohkay........🙂🥲 But I think it's not enough for neet 2023 , u should watch Gaurav Gupta Sir........ Just search one shot of (any chapter u want ) by gaurav gupta sir
@@arunsarrati2606 bro sir ne pehle kahatha na mue = friction(f)/mg(gravitation) aur mue ki value given hai 0.3 aur mg lele 10 put karke aari hai f ki value 3
SIR apse pdhne se phle tk mujhe lgta tha ki main n to class me axcha score kr paungi or n hi neet me😢 pr ab lgta h ki jese aap pdhate ho agr use physics khte h to yes, I can do itt!!
I am too abhishek and today felling blessed to have the same name of you.. Today I fell NEET is halwa with your quality + quantity + your free crash coarse .. Jis chapter ko smjne me mujhe 10 din lge vo apne aur surely tb b nii bol skte usse apne 1 hr. Me Chur chur krr dia thanks a lot sir you r just love Love from up..🔥🔥❤️❤️❤️😝
This video is very helpful for the one who wants to clear his/her concept in less time.. Hats off to your teaching Sir.. May all your hardwork pays off.. 😊💕
I have my +2 1st year examination in 5 days and Abhishek sir helped me a lot .. I watched motion in a plane Motion in a straight line and this chapter for my exam .. hope for the best
Here is newton's fourth law😂 "that every book continues in the state of rest until and unless an external or internal exam appears and the speed of page turning is directly proportional to the syllabus to be covered and the tension in mind remains constant.😂
😂
Dont give them ideas 🤣
@@skydecay69 😑
Damn ... You 😂😂
@@beinghuman_9625 😂
0:00 Introduction
1:07 Force
3:04 Inertia
6:15 Newton's 1 law
8:43 Momentum
11:56 Impulse
13:20 Question 1
19:12 Newton's 2 law
21:32 Newton's 3 law
23:39 Question 2
33:46 Tension
40:05 Question 3
47:21 Friction
51:50 Angle of friction (Angular Friction)
54:16 Angle of repose
58:45 Question 4
1:02:42 Lift Case
"Centripetal force" is not in this video
Thank you sir for saving our time and exam and thanks for this amazing video .
Thanks For Short Cut
Thanks
Tq bhai
Circular motion bhi toh nhi hai
Rolling friction is also absent
Attandance of those before one night of exam😂🙋
👍
🤜🤛
Are these vedio helpful if you haven't studied chapter before??
@@thepseudosphinx Na na na 💀 esa na karna .
Starting of 11
Anyone from 2024 - 25 batch ? 💀
Hha
Yah
Here I am🖐
Me
Mee
One night before exam here who is watching this in 2023-24
✋kal unit test hai 😢😢
@@funnymoments5258Mera kal half yearly hai physics ka
@@ShashankSingh_45 kitni tayaari Hui bhai fir 😅😅
Ya tum bhi backbencher ho ✌️✌️
Half yearly 😢
@@ShashankSingh_45 me too🙂
15:12 , -2-2 = -4
17:55, cos 45° must be 1/√2 instead of 1/2
exactly
Distance hamesha positive hoti h
Yes
@@Rizzubhai074 distance nahi dundrahe the, momentum dund rahe the
😅😅😅 haa mujhe laga me hii sathiya gai thiii yaha lekin ab pata chala me theek thii thanx for comment 🤗🤗
i have watched 6 more videos for same chap but at last i came here to understand properly beacause there is no other teacher like abhishek sir. he deserves much better
😂
Seems like you sarcasm isn't that bad
is this video not ggod ?
@@Thegigachaddguy
Pw ka naam suna h?
Ashu sir be like: are you sure💀
1 like = pass in exam
2 like = top in exam
Hoi nki
1 unlike to @rohan_adhikary7065 = top in jee
Emotional damage
agaar naai hui naa tu fail hogaa
best way to understand tension force is...
imagine ur both hands are tied with rope and stretched in opposite direction with same force... to protect and to resist it u will stretch towards center i.e. away from body
Great💗
BDSM
@@gamingfever6970🌝🌝🌝🤣
@@gamingfever6970 🤣🤣🤣
😂@@gamingfever6970
I never thought that someone could teach better than physics wallah. seriously you taught well and we need teachers like you and also the lecture was engaging.thank you !
❤
chapri voh JEE NEET ko padhate hain yeh school exam ke liye hai nibbe
@@samarqureshi9429 pw tera baap hai kya jo itna trigger hora
😂😂😂😂😂@@samarqureshi9429
You don't know about aayudh sir😂
47:19 the only teacher who care about student's time on exams ♥️
1:2:25 , first value of f find f/mg= mew, f = 6 put in 4g-f=7a , 40-6=7a , 34=7a, 34/7=a, 4.8=a put value a in eq 1st 5g-T=5a, 50-T=5×4.8, 50-T=24, 50-24= T, 26N=T
Thanku💕
Sir derivation kra rhe hai sari plzz batao
Yes broo😊
@himanshi4313 isme f ki value 6 kyo put kri??? Plss tell
@@avnishkumar4027 isme f ki value 6 kyo put kri?? Plss tell
@@Virat-1840 value sahi se put Karo bhai easy hai
Lets take a second to appreciate his hard work.... Thank You sir for Best lecture 🥰🥰🥰
Halo
First, we'll solve the first equation for T:
5g - T = 5a
T = 5g - 5a
Now, substitute this expression for T into the second equation:
(5g - 5a) - 2g sin(30°) - f = 2a
Simplify and rearrange:
5g - 2g sin(30°) - f = 7a
g = 9.8 m/s² (acceleration due to gravity)
f = 0 (no friction, or friction is negligible)
Substitute these values:
5(9.8) - 2(9.8) sin(30°) = 7a
49 - 9.8 = 7a
39.2 = 7a
Now, solve for a (acceleration):
a = 39.2 / 7
a = 5.6 m/s²
Now that we have the acceleration, we can find the tension (T):
T = 5g - 5a
= 5(9.8) - 5(5.6)
= 49 - 28
= 21 N
So, the acceleration is approximately 5.6 m/s², and the tension is approximately 21 N.
21N nahi 28N
For those who have problem in finding acceleration in 1:02:25 - find the value of f by using formula f/mg=mew,m is 2kg and value of mew is given.And then it gives f=12N , now put these in eq.2.Answer is acceleration = 5.4 m/s square and tension = 22.8N.
Lekin isse to f ki value 6N aa rahi 🙄
@@ankitavishwakarma9284haa vahi
@@ankitavishwakarma9284 put the value of mew in F, you will get a=5.6 and then T=22N
bro aapka 12N kaise aara hai mera toh 6N aara
I think a=6.54 and tension is 18N
Any neet aspirant is here?🙃
present
No
Yes
Present
I'm here 😂🤚
Legends are watching this video one day before their exam on 2x 😂😂
A Bright Future is waiting for you Sir,keep calm and keep making amazing one shots like this...lots of love from Northeast ❤️
sir .....i am very much sure that this channel is going to be next revolution for students ❤
Thank You dear for your words,
For other Chapters
'Chapter name ke sath Abhishek Sahu ' likhkar Search 🔎 karein🥳...... Visit playlist section.
Very good educational video
Sir next chapter fluids
First revolution kiska hai
@@Abhisheksahusir don't worry sir a time will come when you get top rank1 search
Who studying one night before exam 🌚 give attendance ☠️
Yaaaaaan
Poore saal wamu wamu kiya kutta fadke
Aur kal mera midterm exam hai 😂😂😂😂
Usme tho ye nahi lik sakta
Tho ab sahu sahu chillaunga paper faadke😂😂😂😂😂
😂😂😂
Sir keep it up......👍🏻👍🏻mind blowing on whole TH-cam only u are supporting to school students....rest all other faculties completing a chapter in 10 to 20 hrs🤕
bhai vo questions or concept pe time bhi to utna hi dete h
y video sirf revision ke liye use kr skte hai
agr kisi new session ko bache ko ye dekhke ye bol diya jaye ki chapter khtm to it is not good even he had covered every topic
Attendance for the students studying in the early morning of the exam day😂
you are the best teacher for the school going students .. baki sab channels pe toh jee neet ki badi badi videos padi hai ... thnk u 😘
Vahi to jab tak base nahi hoga tab Tak jee ke baare me sochna hi bekar hai
Sir literally in just 1hr I understood full chapter great explaination and nic examples ⚡🔥
14:04 sir how did you put the value of cos 45 as 1/2 .....
My answer is -2√2 kgm/s ???
Please let me know 🙏
got the same answer
Part 1 ka bhi -4 aayega
Yes you are right
sir nei by mistake cos 45 ko 1/2 likh diya its 1/√2
18:07 value of cos 45 and sin 45 is 1/√2
Yes
Yes
Any Kvians? Who have tomorrow physics exam??
Yes bhay
🗿🙏🏼
Yes bro
Yep but abhi 2 din badh hai from 39 gtc
Haa bhai !!
Kal hi hai ; 😂😂
From KV Mughalsarai
17:58 the value for cos45° is 1/√2 and not 1/2
exactky
@@ekanshkatoch1097 Bro it's exactly 😆😆😆 not exactky
@@technical.robo.7454 ik,jaldi me likhdia tha bhai
@@technical.robo.7454 🙄jaldi mei likh diya hoga usne
I think the correct answer must be:
As we know
Fs=0.3*mgcos30=5.19
Then, a=4.97
So after putting the value of 'a' the tension will be 25.15 N
Waiting for your check sir!
Thanks for it I am doing wrong through I am taking 2G edge mass for finding friction force but after seeing your answer I will know that reaction force is equal to MG cos theta then simply we get the right answer
Mine answer is also the same
Mine same
@@nishpvlog2619 yep!
@@koindominus9697 that’s good 😊
sir i wants all chapters like this from you !! amazing explaination & energtic lecture .
sure ! you can get it
Where are thsse Motion
Intuitive concept of force, Inertia, Newton's first law of motion; momentum and
Newton's second law of motion; impulse; Newton's third law of motion. Law of conservation
of linear momentum and its applications. Equilibrium of concurrent forces, Static and kinetic
friction, laws of friction, rolling friction, lubrication. Dynamics of uniform circular motion:
Centripetal force, examples of circular motion (vehicle on a level circular road, vehicle on a
banked road).
Bhai one shot dusra dekh le 😂
Force on 3 block by 2 block = total mass pushed by 2 block/Total mass * total force
= 3kg + 4kg/10 kg *30 N
=21 N
10:00 - 10:15 best example of momentum ever.❤
Addd
Sir elastic collision vala sum wrong h because sin45° and cos45° ke value 1/✓2 hote h respectively .
17:55 sir but cos 45 1/√2 hai, waha pe aapne galti se 1/2 kar diya hai
Abhishek Sahu sir is life saver for schooling students ❤️ 🙏 all concepts covered in 1hr
Kudos to those watching this one day before exam...
thnx
I have 3 more ch to do till tomorrow 8 am
Thnx tho
Lol 😹😂😹 mera exam kl hai aur mujhe 4 chapter abhi krne hai 😁 #dhinth
ONE SHOT PRO EVER IN PHYSICS....SALUTE TO YOUR TEACHING SIR....✌🏻
Best bhai yeh Banda 1 raat phle ke liye🎉😂❤
😂
17:55 Lekin sir cos 45° ki value 1/√2 hoti hai apne 1/2 likha hai 😢
Force applied on 3rd by 2nd is 21N by formula , btw great video on TH-cam, thank you so much sir
How explain me
Attend physics class before one night of half yearly exam 😅😂
Correct from where are u
😄😄
Delhi
🙌😂 💯
and that night is today for me
5g-2gsin30-f=5a+2a
5*10-2*10*1/2-0.2*10 =7a
50-10-6=7a
36=7a
a=36/7
=5.14
FIND TENSION
5*10-T=5*5.14
T= 24.30
Bro f kesa nikala ??
Bhai f kese aya?
@@dudeprajapati5329 f=u/mg se u=0.3 and m =2 kg
Thanks bro @@GuddiSingh-wj7lw
Thnks bhai😊
Inky ponky Donkey
Who is here before Half Yearly...😂😂
~2024🎉
One of the best teacher who takes less time to give more knowledge 👍
What is the value of (a)
came i n the last question
a=1.4m/s and T=43N maybe
HW:- a=5.71
T=21.45......Thankyou sir for this wonderful lecture🥰♥
hi wht did u take the value for friction there?
@@gogetsm f=uN
And N = mg.cos30
@HuAnG guanheng Use the formula Tan theta = fsmax/R,, so R would be mg( 2*10) and tan(30) =1/ root3, then calculate it further
Hello how to calculate tension?
@@royal07musics you have to put the value of acceleration in any of the equation given
Tip : Banking of road is not covered in the video but is very important topic and can be asked in school exam because my school teacher gave this topic in 5 marks in both Unit testsand half yearly examination....
Ata nhi hoga inko
Last night before exams but thanks a lot sir . Everything is clear now. Now I am moving to the chap 6 from your playlist . Thanks a lot💕💕
Pass ho gayi behen? Pehli baar padha tha yeh chapter aise?
Sir you will be the upcoming god of physics 😅 .lots of love from Chhattisgarh
Kal exam hai , aaj syllabus shuru karra hu🥲. Pass ho jau bas
Pass hue?
15:25 sir 1st case mein momentum -4 nhi aaega?
Homework question answer is Acceleration is 17.4m/s^2 and Tension is 37 N.
Kaise kiya muje smja do pls
@@kalpana6366 bheja fray ki raysipy
I am kidding
@@technical.robo.7454 😂😂
26N
Kaise kiya please bata do bhen
Hi everyone I am from sose dwarka
Only due to these helful videos i able to crack sose entrance out of 96000 thoushand student ...
Nice ab sir keep it up.
I want a video also in whole basic mathematics used in physics . With practice dpp ... I hope you will make
Nice video btw cos45=1/√2 so ans will be -2√2 kg m/s
Ye
Class was nice but there's a correction! 15:27 pr sir ne cos45• ki value galti se 1/2 Li h it should have been 1/√2…
Yeh I was also thinking about that
on which time we have power to learn anything ???
answer====last day before the exam
Sir I sure that this channel one day will cross 10 million subscribers....💗
Thank you ❤️
Just Today.....I am searching this a lot and finally this is here❤️🙂☺️
Hello Kashish,
For other Chapters
'Chapter name ke sath Abhishek Sahu ' likhkar Search 🔎 karein🥳...... Visit playlist section.
@@Abhisheksahusir ok sir
@@Abhisheksahusir sir you are best teacher ever ❤❤❤❤❤❤
Nice explanation sir 😘
@@Abhisheksahusir MECHANICAL ADVANTAGE AUR PSEUDO FORCE
Sir Newton third law of motion ke first questions me 21N ka nahi 24N ka force lagega and Jo aapne momentum wala question bataya hai usme -2-2=+4 nahi -4km/s aayega
best teacher for physics among others..❤❤❤❤
a= 4.44 m/s²
f=8.88N
Tention= 27.8N
Its 25.15 N here!!
Did you find out frictional force??
@@Familychannel_ mera bhi T=25.15 aaya h
t=19:08 value of cos45 is 1/√2
Therefore the final answer becomes 2√2
You are correct but the final answer would be 4/√2
@@fungro06 how
@@fungro06 sorry sorry actually both are same thing
Yeah even my answer is coming 2root2.
How is 4root2 ?
@@fungro06 ans minus. Me ayga na
Impulse is the applied force on the object in the short period
Newton's fourth law of motion🤣🤣:-
Every book continues to be in state of rest and covered with dust until and unless internal and external exam appears and the speed of the page turning is directly proportional to the syllabus covered and tension in mind remain constant.
Yrr kl exam h mera half yearly or muza kuch nhi aata ...darr lg rha h muza bht kl ka liye ...🥹🥹
Exam kesa tha
@@LijaAnsari hard bht hard 10 no. Bhi nhi aayga ...muza lgaa toh
@@LijaAnsari koi nhi tum padho ...fir btana kse gya exam tumhara m toh padhi nhi thii bilkul bhi isliye acha nhi gya ....🥲🥲
@@LijaAnsari best hi jayga ...🙌🙌 Bs padh lo ...
@@ChhaviPal-g3o mehnat to har rahe hen
Sir Your the best teacher for physics after watching your videos I felt that physics is quite interesting😀
" first understand concept then short cut" 24:42 golden rule
If we study like that we can crack any exam with ease. I highly appreciate this strategy of yours sir coz not every coaching teacher does this and that is why most of the students find difficulty in solving tricky problems
I have my half yearly examination tomorrow and I'm watching it today . Wish us luck 🤞🙏🏻
How'd it go?
Mine is in a week and I have barely completed half of syllabus. Guess we failing mid terms 💀💗.
@@jkn.01 in a week ? ☠️ Naah that's plenty of time you have in your hands 💀
@@Adarshnotforyou bro one chapter in chem alone takes a week. My basics are shit and i barely pass in maths. On top of that i missed half my classes and have zero notes. I do not go to tutions not coaching classes. I have no clue how i even got sci considering how laid back i am. Regreting my decisions frr.
@@jkn.01 bro... Me relating to you seems to be so concerning... I also don't have any notes as I started 11th very late... Although tomorrow's my last quaterly exam and it's chemistry ☠️ and did you also choose pcm... I did... And getting fucked by it... And because I was constantly getting Ill one time after another.. I missed almost all my classes... Barely passing these exams with one shots .. and still trying to find tuitions..
Is it complete for neet 2023? 🙂 Please reply someone
Idk too but i m still watching 🙂
@@khalidahazarika8748 ohkay........🙂🥲 But I think it's not enough for neet 2023 , u should watch Gaurav Gupta Sir........ Just search one shot of (any chapter u want ) by gaurav gupta sir
a=4.972m/s^2, T=25.140N
This is the best one shot i have ever seen
acceleration=5.10[since f=4.242]
Tension=24.5
F ki value kaisa aae plz explane bro .
@@arunsarrati2606 bro sir ne pehle kahatha na mue = friction(f)/mg(gravitation)
aur mue ki value given hai 0.3 aur mg lele 10 put karke aari hai f ki value 3
@@arunsarrati2606 since f =uN
(u =0.3,N =2gcos30)
F=0.3x2x 9.8 x√3/2(on solving this you get frictional force)
@@priyavrathakheda2121 if we will solve this we will get 5.0 something but your f was 4.242
@@khyatisri4587 yeah sorry there was some calculation error
Sir tomorrow is my half yearly and your one shot videoss are helping me too much for my revision💥💥
Same
Which school
@Krish Garg city
how was your exm ?? Was this video helpful ??
Sir mujhe bhut easily samajh aa gaya. Thank you so much for your efforts 😊😊
Please keep making videos
Thanks dear sir ji for your support 🙏🙏🙏 you are best teacher in TH-cam channel for mine 😊😊😊
Sir, at 18:00 the value of cos 45° is 1/√2......but you have taken 1/2 😊..
Homework: 1) Acceleration= 4.28 approx.
2) Tension= 28.60 approx.
What is f value
How?
f will be umgcos30?....or umg?
@@kanak-7971 yes
@@ChaganVlogger29 u=f/R
R=2gcos30°
u=0.3(given)
f=uR= 0.3 x 2gcos30°
Attandance of those before one night of exam😂😂😂😂😂😂😂😂😂😂😂😂😂 😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂
Cbse?
@@Krity_anand_1yes 😊
Nice explanation sir ❤️❤️❤️
Numerical bilkul smjh nhi aye 😅
Jaise he numerical aya skip kar do😅
Best of luck all the students who is preparing for exam 😊😊
Sir , in 15:19 in the equation how did u get 0.2 x 10 - 0.2 x 10 ??? anyways good teaching sir helped a lot
200g converted into 0.2kg
Bro 200g is converted into kg which is 0.2 kg
SIR apse pdhne se phle tk mujhe lgta tha ki main n to class me axcha score kr paungi or n hi neet me😢 pr ab lgta h ki jese aap pdhate ho agr use physics khte h to yes, I can do itt!!
I am too abhishek and today felling blessed to have the same name of you..
Today I fell NEET is halwa with your quality + quantity + your free crash coarse ..
Jis chapter ko smjne me mujhe 10 din lge vo apne aur surely tb b nii bol skte usse apne 1 hr. Me
Chur chur krr dia thanks a lot sir you r just love
Love from up..🔥🔥❤️❤️❤️😝
1:02:30
Not sure but
Acceleration=4.97
I got 4.85 its almost same
@@SAHIL-gl5wfand mine 4.28 😂
Kal kiska kiska exam h 😂
Mai ra
😂😂
Kal physics ka exam hai class 11 😅😂😂
mera😢
Parso hai bhai
I'm Amazed! VERY ETHICAL ❤
I saw ur vdo today itself sir ❤️nd now I'm gonna study physics frm here only 💜 coz of uh i understood each nd every concept thank uh soo much sir 💜
Fnet = ma
5g------------T = 5a----eqn1
2gsin30-- T = 2a-----eqn2
eq 1 subtracted by eqn 2
3g sin30 = 3a ( g=10,,,,, sin30 = 1/2 )
3*10*1/2 =3a
30*1/2 = 3a
15 = 3a
15/3 = a
5ms square = a
put a in eq 1
5g--T=5a
5*10--T =5*5
50--T = 25
T = 5
Where is F .. in equation 2
This video is very helpful for the one who wants to clear his/her concept in less time.. Hats off to your teaching Sir.. May all your hardwork pays off.. 😊💕
Numericals nikal jaate h kyaa iss video ke baad??
@@sawanahlawat3544 cbse level yes
Sir acc is 4.85m/sec² and tension is 24.25N
I have my exam in 9 hrs studying 12 at night , wish me the best 💫💫
Same😂
Who is here to see this video only for passing in exam😅😅
Attendance for those who watch video last night before exam 😅
17:56 cos 451/√2 aata hai na ?
Please can someone tell me the proper answer
Sir 17:13 cos 45 ki value galat li h 😅
1:02:19 Tension force = 25.14N
How you get the f ?
F is cofficient of u which is 0.3
I have my +2 1st year examination in 5 days and Abhishek sir helped me a lot .. I watched motion in a plane
Motion in a straight line and this chapter for my exam .. hope for the best
How did it go?
Sir I have doubt.. 3 kg ka fbd bnay to uska mass 3 hona chaiye na 2 kese hua... Ti -3×2 hona chaiye na
T1 -3g =3×3 hona chaiye..
Obviously the best teacher....providing us with the best content and to the point explanation 👌 😊