All Formulas of Electricity: 1) I = Q/t 2) Q = ne 3) V = W/Q 4) V = IR 5) R = Rho x L/A 6)Resistance in Series: Rs = R1 + R2 + R3 7)Resistance in Parallel: 1/Rp = 1/R1 + 1/R2 + 1/R3 (» Reciprocal of R1+R2+R3) 8)H = V × Q i) H = VIt ii) H = I²Rt iii) H = V²t/R 9) P = W/t i) P = VI ii) P = I²R iii) P = V²/R 10) E = P × t S.I. Units: Current ( I ) - Ampere Charge ( Q ) - Coulomb Time ( t ) - Second Potential Difference or Voltage ( V ) - Volt Resistance ( R ) - Ohm Ω Resistivity ( Rho ) - Ohm meter Power ( P ) - Watt Heat = Energy = Work = Joule Measuring Devices: Ammeter / Milli Ammeter - for measuring current (always connected in series) Galvanometer - for measuring small/sensitive currents (we can also get the direction of the current) Voltmeter - for measuring volts (always connected in parallel) Ohm Meter - Measures the resistivity Things to remember: electron charge = (1.6 x 10⁻¹⁹ C) 1kWh= 3.6 × 10⁶J 1Ampere = 1000mA 1 Kilowaat = 1000W 1 Horse Power = 746W i hope this list will help you! ❤ ek free ka like dete jan
h=3cm F=-12cm U=-18cm Now, using Mirror formula 1\u +1/v = 1/f, 1/-18 +1/v =1/f 1/v=1/-12+ 1/18 1/v=-3+2/36 1/v=-1/36 V=-36 Now, m=-v/u m=-(-36)/-18 m=-2 Again, m=h'\h -2=h'/3 -2×3=h' -6=h' h'=-6 Therefore, distance of the image from the mirror is 36cm. Height of the image is 6cm. Now, Answer= -36/-6. Therefore, option (b) is correct Answer. ❤❤❤❤ Please one like for it ❤❤❤ Thanks for 1k likes ♥️♥️♥️♥️♥️
00:04 Rapid revision of the Light chapter 00:41 Understanding reflection and bouncing back of light 02:00 Understanding virtual and direct images 02:39 Understanding lateral inversion and reflection in mirrors 03:59 Understanding of radius of curvature and focal length 05:03 Understanding light behavior in convex and concave mirrors 06:27 Tips and tricks to spot and use tricks in the exam 07:13 Understanding the Positioning Trick 08:51 Understanding Real and Virtual images 09:30 Convex mirror always forms virtual image 10:53 Understanding Convex and Concave Mirrors 11:36 Understanding the positioning of objects in relation to the mirror and lens 12:57 Representation of height using 'm' in Optics with formula v/u 13:39 Understanding Convex Mirror Focal Length 15:02 Understand the formula of magnification. 15:41 Understanding Snell's Law and Refractive Index 17:00 Understanding the movement of light in denser medium 17:38 Understanding the concept of lateral displacement in refraction. 18:52 Understanding Convex and Concave Lenses 19:38 Explaining the rules for optical center and mirror in geometric optics. 21:01 Focus on consistent numbering for easy referencing 21:37 Understanding the placement of lights and objects in relation to focus points 22:57 Understanding optics through lenses and mirrors 23:34 Explanation of lens formula and magnification formula. 24:52 Understanding the changes in formula and power of light. 25:29 Understanding focal length and its numerical value in meters is important for exams. 26:47 Understanding convex lens and screen positioning by hasnain khan can we get 900k for our great science teacher Prashant kirad
Who want 90+ marks in 10th board exam Who want 90+ marks in 10th board exam Who want 90+ marks in 10th board exam Who want 90+ marks in 10th board exam
@@shreyhemavat3298 Yeh jo tum aise comment karkare dal rahe hu kya usse tumhare 90+ aa jayega Jitna time tum comment likhne mein laga rahe ho uthe padhne mein tagaoo toh I am 💯% sure ke tumhare 90 above aayege
@@TatiyaBicchuop Given, focal length =-12cm,v=-18cm ,and heigth of image=3cm after that ,we use to mirror formula ; 1/f=1/v+1/u 1/-12=1/-18+1/u 1/u=1/-12+1/18 1/u=-3+2/36 1/u=-1/36 u=-36 cm m=-v/u m=-(-18)/-36 m=-1/2 m=hi/ho -1/2=3/ho ho=-6cm
Now, according to the mirror formula, we know that: 1/f = 1/v - 1/u Now, by substituting the given data, we get: 1/12 = 1/v - 1/18 Solving for v, we get: v = 36 cm ii) In order to determine the height of an image, we need to use the magnification formula: m = -v/u m = -36/18 = -2 Thus, the image is twice as big as the object but inverted. h' = -2 x 3 cm = -6 cm
A rapid revision of the chapter on light covers key concepts such as reflection, properties of mirrors, and the behavior of light through lenses. It emphasizes important laws, formulas, and practical applications, including how to solve numerical problems. The session aims to clarify complex topics efficiently for Class 10 students. ##### You may be interested in these questions: - [What are the main properties of light?](#related) - [How do concave and convex mirrors differ?](#related) - [What is the significance of the focal length in lenses?](#related) Highlights: 00:04 Light is a significant chapter in physics that involves understanding its properties and behavior. This revision covers essential concepts such as reflection, plane mirrors, and spherical mirrors. -The reflection of light occurs when it bounces off a shiny surface, following specific laws that govern its behavior. Understanding these laws is crucial for solving related numerical problems. -Plane mirrors produce virtual and erect images, and their properties include lateral inversion and equal size of the image compared to the object. This understanding is vital for practical applications. -Spherical mirrors, including concave and convex types, have unique characteristics that affect how they reflect light. Recognizing their differences helps in comprehending various optical phenomena. 04:04 The focal length is the distance from the pole to the focus of a mirror, which plays a crucial role in the behavior of light rays. Understanding properties of concave and convex mirrors helps in predicting how light interacts with them. -Light rays that pass through the focus of a concave mirror will emerge parallel, illustrating the converging nature of these mirrors. This property is essential for understanding image formation. -The center of curvature for both concave and convex mirrors reflects light rays back along the same path. This fundamental property is key for various optical applications. -A practical trick for remembering the image formation positions in concave mirrors involves identifying focal points. This aids in predicting where images will be formed based on the object's location. 08:08 Understanding image formation in mirrors is crucial for mastering optics. The nature of the image-whether real or virtual-depends significantly on the object's position relative to the mirror. -The relationship between the object's position and image type is essential. When an object is between the focus and the pole, a virtual and erect image is produced. -Concave mirrors are primarily used to enlarge images, making them valuable in applications like torches and makeup mirrors. Their ability to create real images is also noteworthy. -Conversely, convex mirrors create smaller images and are commonly used in car side mirrors and shaving mirrors. They provide a wider field of view, enhancing safety. 12:11 Understanding the rules of sign convention is essential for solving mirror-related problems in optics. Accurate application of these rules leads to correct calculations of focal length, image distance, and magnification. -The mirror formula, represented as 1/v + 1/u = 1/f, is vital for finding relationships between object distance, image distance, and focal length. This formula relies heavily on correct sign conventions. -Magnification is defined as the ratio of the height of the image to the height of the object. The formula m = -v/u helps determine whether the image is real or virtual. -Refraction describes how light bends when passing from one medium to another. Snell's Law governs this bending, establishing the relationship between angles of incidence and refraction. 16:14 The refractive index of a medium determines how much light bends when passing through it, with higher indices indicating greater bending. Understanding this concept is crucial for studying optics and light behavior. -The difference between rarer and denser media influences light behavior, as light bends towards the normal when moving from a rarer to a denser medium. This principle is essential in optics. -The formula for calculating refractive index is derived from the ratio of the speed of light in air to that in the medium. This relationship highlights the inverse nature of refractive index and light speed. -Understanding lens types, such as convex and concave, is vital for grasping how light focuses or diverges. Their unique properties determine how images are formed in optical systems. 20:16 Light passing through the optical center of a lens travels in a straight line, following three fundamental rules. Understanding these rules is essential for analyzing ray diagrams of convex and concave lenses. -The ray diagram techniques for both convex and concave lenses are similar to those used in mirrors, making the transition easier for learners. It's important to follow the same numbering method in both diagrams. -Understanding the formation of images based on object positions relative to the focal points is crucial. Various cases illustrate how images can be real or virtual depending on the object's location. -The applications of convex and concave lenses differ, with convex lenses used in magnifying glasses and concave lenses in telescopes. Each type serves specific purposes in optics. 24:20 The focal length of a convex lens is always positive, while that of a concave lens is negative. This distinction is crucial for understanding lens power and image formation. -Understanding the sign convention for focal lengths is essential. Convex lenses have positive focal lengths, while concave lenses have negative ones, affecting calculations. -The power of a lens indicates its ability to converge or diverge light. Positive power corresponds to convex lenses, and negative power to concave lenses. -When calculating power using the formula P = 1/f, ensure focal length is in meters. Converting centimeters incorrectly can lead to wrong answers.
Formulas related to reflection of light, => in reflection angle of incidence is equal to angle of relection, magnification = height of image/height of object m=hi/ho wher m is the magnification hi is the height of image ho is the height of object =>also m=-v/u formulaes related to refraction of light, => n =sini/sinr where n is the refractive index i is angle of incidence r angle of refraction =>lens formula 1/f =1/v -1/u =>power of lens,p=1/f(in m ) p=100/f(in cm) =>power of combination of lens P=P1+P2+P3... =>magnification ,m=hi/ho m=v/u => refractive index n21=speed of light in medium one /speed of light in medium 2 n21=v1/v2
For those who want to remember RD AND DR if still confused so:- DR:-Doctor stay away from normal.Doctor doesn't like normal people so he avoid,he only like patient😅 RD:-Just switch it and opposite of away is toward the normal
arey yaar isme pura problem solve krna zaruri nhi hai... concave mirror ho to smjh lena image real and inverted hai wo minus hi rhega and magnification bhi minus hoga kyuki concave mirror h... iske jaise question me zyada dimag mt lagao
Homework: Given: Height of object, h = 3 cm Object distance, u = -18 cm (as the object is in front of the mirror) Focal length, f = -12 cm (as it is a concave mirror) Using the mirror formula, 1/f = 1/u + 1/v, we can find the image distance, v: 1/f = 1/u + 1/v 1/-12 = 1/-18 + 1/v v = -36 cm The negative sign indicates that the image is formed behind the mirror. Now, using the magnification formula, m = -v/u, we can find the height of the image, h': m = -v/u h'/h = -v/u h' = -v/u x h Substituting the values, we get: h' = -(-36)/(-18) x 3 h' = 6 cm Therefore, the distance of the image from the mirror is 36 cm and the height of the image is 6 cm.
IT'S A BIG REQUEST SIR!! Please make a video explaining the ch2 of Biology *class 9 Tissues* 🙏🏻 I'll be really grateful to you.. Please make it this week..
h=3cm F=-12cm U=-18cm Now, using Mirror formula 1\u +1/v = 1/f, 1/-18 +1/v =1/f 1/v=1/-12+ 1/18 1/v=-3+2/36 1/v=-1/36 V=-36 Now, m=-v/u m=-(-36)/-18 m=-2 Again, m=h'\h -2=h'/3 -2×3=h' -6=h' h'=-6 Therefore, distance of the image from the mirror is 36cm. Height of the image is 6cm. Now, Answer= -36/-6. Therefore, option (b) is correct Answer.
1Acid is sour Change blue to 🍒 red litmus Change phenophthalein colourless pH is less than 7 (1-6) Give H+ in water Vinger is acetic acid Orange is citric acid Tamarind is tartaric acid Tomato is oxalic Sour milk is lactic acid 🎉.
18:38 Prashant bhaiya write an incorrect symbol because he told us inversaly proportional but he draws the symbol of directly proportion , i know it was happened accidently ...but no problem bhaiya
h=3cm F=-12cm U=-18cm Now, using Mirror formula 1\u +1/v = 1/f, 1/-18 +1/v =1/f 1/v=1/-12+ 1/18 1/v=-3+2/36 1/v=-1/36 V=-36 Now, m=-v/u m=-(-36)/-18 m=-2 Again, m=h'\h -2=h'/3 -2×3=h' -6=h' h'=-6 therefore the correct option is (B). hence the image formed will be real and inverted ....hope the answer is correct
23:20 Bhaiya said concave lens is converging lens But it is Concave lens is diverging lens Convex lens is converging lens! Everyone do mistakes!😀 So many likes!🤗 Thanku dostoo
The answer is ho=3cm f=-12cm u=-18cm Sol:- 1/V=1/f-1/u 1/v= 1/(-12) -1/(-18) On Lcm = -18+12/-216 =-6/-216 From minus to minus cancel The answer will be positive 36 Now height of image m=-V/U =-(36)/-18 From minus to minus cancel =36/18 m=2 m=hi/ho m×ho = hi 2×3 = hi 6=hi
All Formulas of Electricity:
1) I = Q/t
2) Q = ne
3) V = W/Q
4) V = IR
5) R = Rho x L/A
6)Resistance in Series: Rs = R1 + R2 + R3
7)Resistance in Parallel: 1/Rp = 1/R1 + 1/R2 + 1/R3 (» Reciprocal of R1+R2+R3)
8)H = V × Q
i) H = VIt
ii) H = I²Rt
iii) H = V²t/R
9) P = W/t
i) P = VI
ii) P = I²R
iii) P = V²/R
10) E = P × t
S.I. Units:
Current ( I ) - Ampere
Charge ( Q ) - Coulomb
Time ( t ) - Second
Potential Difference or Voltage ( V ) - Volt
Resistance ( R ) - Ohm Ω
Resistivity ( Rho ) - Ohm meter
Power ( P ) - Watt
Heat = Energy = Work = Joule
Measuring Devices:
Ammeter / Milli Ammeter - for measuring current (always connected in series)
Galvanometer - for measuring small/sensitive currents (we can also get the direction of the current)
Voltmeter - for measuring volts (always connected in parallel)
Ohm Meter - Measures the resistivity
Things to remember:
electron charge = (1.6 x 10⁻¹⁹ C)
1kWh= 3.6 × 10⁶J
1Ampere = 1000mA
1 Kilowaat = 1000W
1 Horse Power = 746W
i hope this list will help you! ❤
ek free ka like dete jan
Thnx literally I want this😢
Konse chapter pe comment kar rhe ho
Ye Light hai😂
Thnx ❤
❤❤
Thanks bro
h=3cm
F=-12cm
U=-18cm
Now, using Mirror formula
1\u +1/v = 1/f,
1/-18 +1/v =1/f
1/v=1/-12+ 1/18
1/v=-3+2/36
1/v=-1/36
V=-36
Now,
m=-v/u
m=-(-36)/-18
m=-2
Again,
m=h'\h
-2=h'/3
-2×3=h'
-6=h'
h'=-6
Therefore, distance of the image from the mirror is 36cm.
Height of the image is 6cm.
Now, Answer= -36/-6.
Therefore, option (b) is correct Answer. ❤❤❤❤
Please one like for it ❤❤❤
Thanks for 1k likes ♥️♥️♥️♥️♥️
thanks bro me solution hi dhundh raha tha
😂😂
Welcome bro ♥️♥️♥️♥️
V = - 36 bro , but it is correct 😂😂
-1/36=1/v
Cross multipy
-v = 36
Because it is concave mirror
00:04 Rapid revision of the Light chapter
00:41 Understanding reflection and bouncing back of light
02:00 Understanding virtual and direct images
02:39 Understanding lateral inversion and reflection in mirrors
03:59 Understanding of radius of curvature and focal length
05:03 Understanding light behavior in convex and concave mirrors
06:27 Tips and tricks to spot and use tricks in the exam
07:13 Understanding the Positioning Trick
08:51 Understanding Real and Virtual images
09:30 Convex mirror always forms virtual image
10:53 Understanding Convex and Concave Mirrors
11:36 Understanding the positioning of objects in relation to the mirror and lens
12:57 Representation of height using 'm' in Optics with formula v/u
13:39 Understanding Convex Mirror Focal Length
15:02 Understand the formula of magnification.
15:41 Understanding Snell's Law and Refractive Index
17:00 Understanding the movement of light in denser medium
17:38 Understanding the concept of lateral displacement in refraction.
18:52 Understanding Convex and Concave Lenses
19:38 Explaining the rules for optical center and mirror in geometric optics.
21:01 Focus on consistent numbering for easy referencing
21:37 Understanding the placement of lights and objects in relation to focus points
22:57 Understanding optics through lenses and mirrors
23:34 Explanation of lens formula and magnification formula.
24:52 Understanding the changes in formula and power of light.
25:29 Understanding focal length and its numerical value in meters is important for exams.
26:47 Understanding convex lens and screen positioning
by hasnain khan
can we get 900k for our great science teacher Prashant kirad
Thanks bro.
Thank you so much😄
Tq❤
❤
Kya mila sale 😂😂
1 like for Prashant Bhaiya and for 100% in Board exams😂😂
Option B is right [ -36, -6 ] 26:38
Option c
@@ShivakshayaSinghha option ç wrong hai
Yeah bhaya Mai i got it answer is option b
@@nbtss_799 tum ho kon aaramb ki ho kya
😊@@ShivakshayaSingh
1 like = 95% 2:51
Bhai agar like kr diya to tu exam krega kya sbka 😪😏
@@MamtaSharma-nh9gkhainaa
Kar rhi nhi aaye tab bataungi
Aur do bar like kiye toh 190% milega kya be 😂😂
I want all students get 100/100 in science exam 2025🎉🎉
Dhanayawaad 😊😊
Thank you 🙏
Thank you 🎉❤❤❤
Thankuuuu❤
❤❤❤
1 like = 95% in bords
are you done with ur bullshit? your guys' comments are annoying af
Who want 90+ marks in 10th board exam
Who want 90+ marks in 10th board exam
Who want 90+ marks in 10th board exam
Who want 90+ marks in 10th board exam
me
mee
Who wants*
95+ MARKS BHAI
@@shreyhemavat3298 Yeh jo tum aise comment karkare dal rahe hu kya usse tumhare 90+ aa jayega
Jitna time tum comment likhne mein laga rahe ho uthe padhne mein tagaoo toh I am 💯% sure ke tumhare 90 above aayege
Human Eye 20 Min Rapid Revision---------Vote Now
Edit: Uploaded!
Rapid revision of human eye 👁️💯❤️
Haa ❤
Rapid revision of human eye
Yess
Yes
27:09 opt b is the answer🎉
Thank you for 870 likes 🍂💫💗
Abe Teri to😡🤬🤬
❤❤❤❤❤❤❤
Jo tumko like karega toh
Like mangne ka accha tarika hai!!!😂😂
Ok thik hai to
8:07 thank you bhaiya mast trick h and the correct answer for the homework question is b(-36, -6)
Yah correct ans is b -36,-6
So the magnification will be negative that is real and inverted
Humlogon ne toh ek hi kitab padhi thi dost par yeh sab tune Kahan se Seekh liya mere bhai😂@@GarvJain-h7n
Ans is 36 and 6
Yeah @@GarvJain-h7n
21:43 dekho
option B is the right answer ( -36,-6)
Bhai mera option c aya
Mera bhi bhai 😅😅@@TatiyaBicchuop
@@TatiyaBicchuop
Given, focal length =-12cm,v=-18cm ,and heigth of image=3cm
after that ,we use to mirror formula ;
1/f=1/v+1/u
1/-12=1/-18+1/u
1/u=1/-12+1/18
1/u=-3+2/36
1/u=-1/36
u=-36 cm
m=-v/u
m=-(-18)/-36
m=-1/2
m=hi/ho
-1/2=3/ho
ho=-6cm
m= -2 not -1/2
Because
m=-v/u
v= -36 , u = -18
v=-(-36)/-18
v=2/-1
v=-2
Bro iss mai v nikalna hai naki u
11:23 In case someone has trouble identifying left and right like I do,
Jo cheez mirror ke saamne hai, woh negative
Jo peeche hai, wo positive
8:07 best trick to remember ray diagrams..... Thanku so much bhaiya..
Kisi aur teacher ka trick bataen
@@k-poplover6612 kiska?
@@kashishsharmayt kajal devali
LearnwithVY channel par ye tricks pehle se hai
@@Alokchaudhary8430-n1g Yes
26:40 the correct answer is b) -36,-6❤
Write answer
@@Rupadsul *Right
26:42 (b) -36,-6
Wrong d is correct
@@NationalPlayer-f8fno b is only Correct
Yaar c is correct
@kalpanadas7247 d is correct u can google
C is the correct one study well guys..
Now, according to the mirror formula, we know that:
1/f = 1/v - 1/u
Now, by substituting the given data, we get:
1/12 = 1/v - 1/18
Solving for v, we get:
v = 36 cm
ii)
In order to determine the height of an image, we need to use the magnification formula:
m = -v/u
m = -36/18 = -2
Thus, the image is twice as big as the object but inverted.
h' = -2 x 3 cm = -6 cm
Bhai answer glt hai tmhara q ki yahan u negative me hoga q ye concave mirror hai
U=-18
Formula itself wrong bhai
1/f=1/v+1/u
f=-12cm
u=-18cm
-1/12=1/v-1/18
=v=-36
hi/ho=-v/u
hi/3=-(-36)/-18
hi/3=-36/18
hi=-6
so correct ans is b
Bhai mirror m (+) ata h
Our lens m(-) ataha h
Jo like nhi kiya woh fail ( Don't take risk)⚠️ like karo unlimited marks pao 😊
Agr tu final boards mai 99% nhi laya to tu gay hai 💀
Mtb ek like karo aur apni puri mahanat ki baand Baja do🤣
Chal baa pass hi kab tha
Bahi phela he fail ho reha hee😢
Bhai ek baat pr dhyan de dena ki kitabo pr dhull lag jane se kahaniyan khatam nhi ho jatii 🗿
7:22 remarkable trick 👍
26:42 option (b) is correct both will be negative
Option B is always correct and whoever likes this video will get 92% in boards 2024-25🎉🎉💯💯💯
@@rudduxd6266 It's B
It's B
A rapid revision of the chapter on light covers key concepts such as reflection, properties of mirrors, and the behavior of light through lenses. It emphasizes important laws, formulas, and practical applications, including how to solve numerical problems. The session aims to clarify complex topics efficiently for Class 10 students.
##### You may be interested in these questions:
- [What are the main properties of light?](#related)
- [How do concave and convex mirrors differ?](#related)
- [What is the significance of the focal length in lenses?](#related)
Highlights:
00:04 Light is a significant chapter in physics that involves understanding its properties and behavior. This revision covers essential concepts such as reflection, plane mirrors, and spherical mirrors.
-The reflection of light occurs when it bounces off a shiny surface, following specific laws that govern its behavior. Understanding these laws is crucial for solving related numerical problems.
-Plane mirrors produce virtual and erect images, and their properties include lateral inversion and equal size of the image compared to the object. This understanding is vital for practical applications.
-Spherical mirrors, including concave and convex types, have unique characteristics that affect how they reflect light. Recognizing their differences helps in comprehending various optical phenomena.
04:04 The focal length is the distance from the pole to the focus of a mirror, which plays a crucial role in the behavior of light rays. Understanding properties of concave and convex mirrors helps in predicting how light interacts with them.
-Light rays that pass through the focus of a concave mirror will emerge parallel, illustrating the converging nature of these mirrors. This property is essential for understanding image formation.
-The center of curvature for both concave and convex mirrors reflects light rays back along the same path. This fundamental property is key for various optical applications.
-A practical trick for remembering the image formation positions in concave mirrors involves identifying focal points. This aids in predicting where images will be formed based on the object's location.
08:08 Understanding image formation in mirrors is crucial for mastering optics. The nature of the image-whether real or virtual-depends significantly on the object's position relative to the mirror.
-The relationship between the object's position and image type is essential. When an object is between the focus and the pole, a virtual and erect image is produced.
-Concave mirrors are primarily used to enlarge images, making them valuable in applications like torches and makeup mirrors. Their ability to create real images is also noteworthy.
-Conversely, convex mirrors create smaller images and are commonly used in car side mirrors and shaving mirrors. They provide a wider field of view, enhancing safety.
12:11 Understanding the rules of sign convention is essential for solving mirror-related problems in optics. Accurate application of these rules leads to correct calculations of focal length, image distance, and magnification.
-The mirror formula, represented as 1/v + 1/u = 1/f, is vital for finding relationships between object distance, image distance, and focal length. This formula relies heavily on correct sign conventions.
-Magnification is defined as the ratio of the height of the image to the height of the object. The formula m = -v/u helps determine whether the image is real or virtual.
-Refraction describes how light bends when passing from one medium to another. Snell's Law governs this bending, establishing the relationship between angles of incidence and refraction.
16:14 The refractive index of a medium determines how much light bends when passing through it, with higher indices indicating greater bending. Understanding this concept is crucial for studying optics and light behavior.
-The difference between rarer and denser media influences light behavior, as light bends towards the normal when moving from a rarer to a denser medium. This principle is essential in optics.
-The formula for calculating refractive index is derived from the ratio of the speed of light in air to that in the medium. This relationship highlights the inverse nature of refractive index and light speed.
-Understanding lens types, such as convex and concave, is vital for grasping how light focuses or diverges. Their unique properties determine how images are formed in optical systems.
20:16 Light passing through the optical center of a lens travels in a straight line, following three fundamental rules. Understanding these rules is essential for analyzing ray diagrams of convex and concave lenses.
-The ray diagram techniques for both convex and concave lenses are similar to those used in mirrors, making the transition easier for learners. It's important to follow the same numbering method in both diagrams.
-Understanding the formation of images based on object positions relative to the focal points is crucial. Various cases illustrate how images can be real or virtual depending on the object's location.
-The applications of convex and concave lenses differ, with convex lenses used in magnifying glasses and concave lenses in telescopes. Each type serves specific purposes in optics.
24:20 The focal length of a convex lens is always positive, while that of a concave lens is negative. This distinction is crucial for understanding lens power and image formation.
-Understanding the sign convention for focal lengths is essential. Convex lenses have positive focal lengths, while concave lenses have negative ones, affecting calculations.
-The power of a lens indicates its ability to converge or diverge light. Positive power corresponds to convex lenses, and negative power to concave lenses.
-When calculating power using the formula P = 1/f, ensure focal length is in meters. Converting centimeters incorrectly can lead to wrong answers.
Hi
26:40
H=3cm
F=12cm
U=18cm
1/V+1/u=1/f
1/v = -1/12 - (-1/18)
Lcm=36
1/v = -3/36+2/36
1/v = -1/36
V=-36
M=-36/18
M=-2
M=-h/h
-2=h/3
h=-6
Opt b is correct ans 😊
Thank you ❤
❤
😮
Thanks
Like karoge to 95 %+
Vote for urgent need for class 10th
Physics ch 2 - human eye and colourful world 🔥
Chemistry ch -2 acid,base and salt
This week my exam please sir 😊
Apne batch nhi liya h kyy??
Nhi@@Harshff804
Haaa
7:37 damnnn bhaiyaaa lit 🔥🔥 love the trick 🗣️
Sahi mei ❤️🔥🗣️
Also give tricks for biology diagrams
Hiii ayushiii
Hii dev
@@SriramPattanayak7 hiii
7:13 salute hai bhaiya aapko🫡 kya mast trick batai hai👍
Acids , base and salt rapid revision 👍🏻
Sahi bola
Ha
Thanks bhaiya for the trick 8:00😊
Next chapter control and coordination plz 🥺
And thqu for giving ur full effort ❤️💫
Yea vote
Hii
Uploaded
@@IntrovertMee-03 yes watched 👍
0:50 The simplest way to learn NCERT:
N- NUTRITION
C- CIRCULATION
E- EXCRETION
R- RESPIRATION
T- TRANSPORTATION
PLS LIKE 😊😊
Vote for Urgent need for class 9th ----
Biology ch 2 - tissues
Physics ch- Force and laws of motion 🔥🤌
Next week is my exam ... Plz ASAP🥲
😢
Yes boss
th-cam.com/video/ccNmX3zcbss/w-d-xo.htmlsi=jAnkz0LbCjfffi90
Ye lo tissue ch
@@ronakrawal07tissue ch th-cam.com/video/ccNmX3zcbss/w-d-xo.htmlsi=jAnkz0LbCjfffi90
@@khushilohiya8346th-cam.com/video/ccNmX3zcbss/w-d-xo.htmlsi=jAnkz0LbCjfffi90
Tissue ch
15:10 - Refraction
Formulas related to reflection of light,
=> in reflection angle of incidence is equal to angle of relection,
magnification = height of image/height of object
m=hi/ho
wher m is the magnification
hi is the height of image
ho is the height of object
=>also m=-v/u
formulaes related to refraction of light,
=> n =sini/sinr
where n is the refractive index
i is angle of incidence
r angle of refraction
=>lens formula
1/f =1/v -1/u
=>power of lens,p=1/f(in m )
p=100/f(in cm)
=>power of combination of lens
P=P1+P2+P3...
=>magnification ,m=hi/ho
m=v/u
=> refractive index n21=speed of light in medium one /speed of light in medium 2
n21=v1/v2
Ho kaun aap
Bade intelligent lagte ho Sare formula yaad hain
For those who want to remember RD AND DR if still confused so:-
DR:-Doctor stay away from normal.Doctor doesn't like normal people so he avoid,he only like patient😅
RD:-Just switch it and opposite of away is toward the normal
Thank you bhaiya ❤️
Homework:
27:09------> -36,-6 (option B)
bhai solution btao ge ek barr
@@gurtejsingh2549
Bilkul..
Height of object=3cm.(Given)
F= -12 (Given)
u= -18
v= ?
Height of image= ?
..
Mirror formula --> 1/f=1/v+1/u
-1/12 = 1/v - 1/18
1/v = -1/36
v= -36.
m=-v/u
= 36/(-18)
= -2.
m= height of image/ height of object
-2= height of image/ 3(given)
Height of image= -2×3
= -6.
Answers------> -36,-6(option B)
Hope it helped 👍🏻
arey yaar isme pura problem solve krna zaruri nhi hai... concave mirror ho to smjh lena image real and inverted hai wo minus hi rhega and magnification bhi minus hoga kyuki concave mirror h... iske jaise question me zyada dimag mt lagao
@@Shiva14_sj thanks
Love you Prashant bhaiya ❤
Vote for Control and Coordination ❤
(Please Bhaiya yeh chapter revise kara do)
Ha bhaiya 😢😢🎉
November ma kon dekh rha h 27:12
Us
Me 😎
👍👍
hii
November me 27:12 kaha se aaya hai comment karna 😅😅😅😅😂😂😂😂😂😂😂
December mai kon kon dekh raha hai 😭
Pre boards arree guys😭👍
Me
Half yearly 💀🙂
@@AaradhyaSahu-kv9pn hnm😭
@@MamtaSharma-c5y my science exam is tomorrow 🙂
@@AaradhyaSahu-kv9pn all the best 👍😭
Thank u ❤ for this❤❤
Hlo
Homework:
Given:
Height of object, h = 3 cm
Object distance, u = -18 cm (as the object is in front of the mirror)
Focal length, f = -12 cm (as it is a concave mirror)
Using the mirror formula, 1/f = 1/u + 1/v, we can find the image distance, v:
1/f = 1/u + 1/v
1/-12 = 1/-18 + 1/v
v = -36 cm
The negative sign indicates that the image is formed behind the mirror.
Now, using the magnification formula, m = -v/u, we can find the height of the image, h':
m = -v/u
h'/h = -v/u
h' = -v/u x h
Substituting the values, we get:
h' = -(-36)/(-18) x 3
h' = 6 cm
Therefore, the distance of the image from the mirror is 36 cm and the height of the image is 6 cm.
v=-36
m=-2
hi=-6
Option (b) is ✔✅
☺☺🤘🏻🤘🏻
F is negative -12
U is negative -18
H is 3
Then v is +36
M is -v/u
-36/-18=2
Option (b) is correct answer
Control coordination rapid revision
26:42 (a) option is correct 💯💯💯💯💯💯💯💯💯💯
Please bring rapid revesion of
Acid base and salts 😢
Control and coordination 😮
1 like = 99 in boards
27:09 optin b isthe correct answer 😊😊
7:56 words are not enough to thank youuu😭😭😭 mujhe ye bilkul nh yaad ho rha tha bilkul nahi ab ikdm bdhiya se yaad ho jayga
Thank you so much 🥺🥺🥺❤️❤️❤️
Hii
@@JwhshsNwnsbshsh yes?
@@Zoya.imroz_ tum 10 th me ho
@@akhandbharat1989 hn
@@Zoya.imroz_ 24-25 mai
One like 👍 for Prashant bhaiya and comment for digraj sir
done both
Hy bhaiya
27:11 option b -36,-6
7:45 kya trick hai bhai 👏🏻👏🏻 SUPERB 🔥🔥🔥
EXAM IS NEAR
NOTHING IS CLEAR
NO NEED TO FEAR
WHEN PRASHANT
BHAIYA IS HERE ❤❤
Sir ka mu melele jake
Jo mera comment like nhi kiya to wo fail exam me
Tu thodi bkl hai kya
Hi
Ye fake hote h mehnat karo bahut aache percentage aaye ge
@@Apekshagupta.123 nhi depend on bless
Abe chal ...ye sb kuch n hota pdhne Aya h to pdhle 😏
2:19 🕶️ dark
Horror
❤❤❤
Sir what a trick you have taught , i properly understand
26:38 option B is correct sir
Prashant bhaya❤ you are the best teacher in the world❤
Acid, base and salt rapid revision
Yes😢
IT'S A BIG REQUEST SIR!!
Please make a video explaining the ch2 of Biology *class 9 Tissues* 🙏🏻 I'll be really grateful to you.. Please make it this week..
Pleaseeeeee🙏🏻🙏🏻🙏🏻🙏🏻
I too want this.. Please Prashant sir
Yes sir please make a video , Tissue
Think like= brick>wall> hous
Cell>tissue>organe>Body
-36,-6 (b)
Galat hai bhai😂
Concave mirror image always virtuel and erect means positive
1 like 👍 = 90+% in board exam
What is the sum of 909and9865688544
And then subtract17839055
Hello 🎉
7:25--100% of the problem solved 🎉😊
Thank you very much prasant bhaiya itne saare topics ko short revision se padha de rahe..itne easy way se padhane k liye thank you 😊
Very Helpful in times of exam❤
THANKYOUSMMM BHAIYAA LUV U YAAR BOHOT HELPFULL THA
27:10 B is the right answer ❤
Love From Assam 🙂🩷🩷🩷🩷🩷🩷🩷🩷
bro assamr pora
❤
❤
@@Miss_Nikii_kashyap broo assam 💝💝
Assam seba
h=3cm
F=-12cm
U=-18cm
Now, using Mirror formula
1\u +1/v = 1/f,
1/-18 +1/v =1/f
1/v=1/-12+ 1/18
1/v=-3+2/36
1/v=-1/36
V=-36
Now,
m=-v/u
m=-(-36)/-18
m=-2
Again,
m=h'\h
-2=h'/3
-2×3=h'
-6=h'
h'=-6
Therefore, distance of the image from the mirror is 36cm.
Height of the image is 6cm.
Now, Answer= -36/-6.
Therefore, option (b) is correct Answer.
You are only the teacher of science whick I like so much and u are the best explainer with tricks 😊❤
7:37 bhaiya really I love this trick 💗
Hi gm miss you
❤❤❤
My atetude all things ❤❤
Bhaiya this video helped me a lot thank you again.. You're the one who makes me understand everything in a very easy way.. ☺
Lecture starts at 0:40
ThanxXx You saved my 39.696969 Seconds...
Pucha
1Acid is sour
Change blue to 🍒 red litmus
Change phenophthalein colourless
pH is less than 7 (1-6)
Give H+ in water
Vinger is acetic acid
Orange is citric acid
Tamarind is tartaric acid
Tomato is oxalic
Sour milk is lactic acid 🎉.
1 like for prashant bhaiya
1 like kya Prashant bhaiya ke liye toh jitne like kre utne km h
mere ghr pr jitne phone h utne phone se like kr denge
Nice lecture jaldi dekh lo sab ❤😊 let's crack it together 😊 All the very best all of you ❤🫡🎉
All the best you also
@@mdaksam2032 thank you bro 🙏
Thanks for rivision ✍️🙏🏻
18:38 Prashant bhaiya write an incorrect symbol because he told us inversaly proportional but he draws the symbol of directly proportion , i know it was happened accidently ...but no problem bhaiya
December ma kon dekh rha hai 4:26
Thanks Bhaiya aapki videos se bohot help multi h 😊
h=3cm
F=-12cm
U=-18cm
Now, using Mirror formula
1\u +1/v = 1/f,
1/-18 +1/v =1/f
1/v=1/-12+ 1/18
1/v=-3+2/36
1/v=-1/36
V=-36
Now,
m=-v/u
m=-(-36)/-18
m=-2
Again,
m=h'\h
-2=h'/3
-2×3=h'
-6=h'
h'=-6
therefore the correct option is (B).
hence the image formed will be real and inverted ....hope the answer is correct
Thanks
You are genius bro ...............
Actually I can't understand the question but understand your answer 😂😂😹🤧
Waaah 🎉🎉🎉 bhaiya waah 🎉 17:20
Kon December me dekh rha h 2024 pre board me😢
Main
Main bhi ✋🏻🫡
Mee
answer is option = (B) thank you sir for your help
That"beta" is so cute😊😊☺️ yeh sunte hi apnapan sa ho jata hai
sir babut aachi trick batai thankyou so much sir ❤😊😊😊😊😊😊😊
HELPED ME SO MUCH THANKYOU PRASHANT BHAIYA!!!!!!!
27:10 answer is b -36,-6
by the way I like trick but I already lean how to make ray diagrams
Great thing for before exams preparation 😊😊
23:20 Bhaiya said concave lens is converging lens
But it is
Concave lens is diverging lens
Convex lens is converging lens!
Everyone do mistakes!😀
So many likes!🤗 Thanku dostoo
December....❤🎉
Vote for urgent need class 9th “Tissues ” (Biology )❤......
Force and laws of motion (physics )✨ please bhaiya 🙏 September 2 is my exam 🙏😥😥.........
hi 👋🏻♥️
The answer is
ho=3cm
f=-12cm
u=-18cm
Sol:- 1/V=1/f-1/u
1/v= 1/(-12) -1/(-18)
On Lcm
= -18+12/-216
=-6/-216
From minus to minus cancel
The answer will be positive 36
Now height of image
m=-V/U
=-(36)/-18
From minus to minus cancel
=36/18
m=2
m=hi/ho
m×ho = hi
2×3 = hi
6=hi
TYSM BRO
It's wrong
1/v +1/u =1/f
Therefore
1/v+ 1/-18=1/-12
1/v-1/18=1/-12
1/v=1/-12+1/18
Then calculate
@@jadumanibehera2121 its right you are doing wrong there is direct formula that is 1/v-1/u=1/f therefore 1/v=1/f-1/u
Option B 27:09
10th me 99% lane wlae like kare
Mein lane wali hun
60 wale ❤
Like Karne se aa jata tab toh sare toppers padhayi chhodkar like thokte 😂😂😂
90+ wale like kare 23:09
rapid revision of human eye❤❤❤😊
1 like uu give 90 + in 10th board exan🩷❤️🎉🎉🎊⭐
Exam's are near
Don't fear 😨
Because Prashant Bhai is here
To clear
↓↓↓
(Please give like ❤)