Electric Current and Circuit 1. Ohm's Law: - V = IR (Voltage = Current x Resistance) - I = V/R (Current = Voltage / Resistance) - R = V/I (Resistance = Voltage / Current) 2. Power: - P = VI (Power = Voltage x Current) - P = I^2R (Power = Current^2 x Resistance) - P = V^2/R (Power = Voltage^2 / Resistance) 3. Energy: - E = Pt (Energy = Power x Time) - E = VIt (Energy = Voltage x Current x Time) Resistance and Resistivity 1. Resistivity: - ρ = RA/l (Resistivity = Resistance x Area / Length) 2. Resistance: - R = ρl/A (Resistance = Resistivity x Length / Area) 3. Combination of Resistances: - Series: R_total = R1 + R2 + ... + Rn - Parallel: 1/R_total = 1/R1 + 1/R2 + ... + 1/Rn Electric Potential 1. Electric Potential: - V = W/q (Voltage = Work / Charge) Other Formulas 1. Kilowatt-hour (kWh): - 1 kWh = 1000 Wh = 3.6 x 10^6 J 2. Fuse and Circuit Breaker: - I = V/R (Current = Voltage / Resistance) Units and Conversions 1. Volt (V) 2. Ampere (A) 3. Ohm (Ω) 4. Watt (W) 5. Joule (J) 6. Kilowatt-hour (kWh) likeee😃
welcome everyone and thnks for like[edit] All Formulas of Electricity: 1) I = Q/t 2) Q = ne 3) V = W/Q 4) V = IR 5) R = Rho x L/A 6)Resistance in Series: Rs = R1 + R2 + R3 7)Resistance in Parallel: 1/Rp = 1/R1 + 1/R2 + 1/R3 (» Reciprocal of R1+R2+R3) 8)H = V × Q i) H = VIt ii) H = I²Rt iii) H = V²t/R 9) P = W/t i) P = VI ii) P = I²R iii) P = V²/R 10) E = P × t S.I. Units: Current ( I ) - Ampere Charge ( Q ) - Coulomb Time ( t ) - Second Potential Difference or Voltage ( V ) - Volt Resistance ( R ) - Ohm Ω Resistivity ( Rho ) - Ohm meter Power ( P ) - Watt Heat = Energy = Work = Joule Measuring Devices: Ammeter / Milli Ammeter - for measuring current (always connected in series) Galvanometer - for measuring small/sensitive currents (we can also get the direction of the current) Voltmeter - for measuring volts (always connected in parallel) Ohm Meter - Measures the resistivity Things to remember: electron charge = (1.6 x 10⁻¹⁹ C) 1kWh= 3.6 × 10⁶J 1Ampere = 1000mA 1 Kilowaat = 1000W 1 Horse Power = 746W i hope this list will help you! ❤ ek free ka like dete jana
20:12 Q1 [b] it becomes half Q2 Power=100000W t=1hr Power=100000/1000=100W Total energy consumption= 100 * 1 = 100kwh Cost of energy consumed in one day= 100 * 10 = ₹1000 Cost of energy consumed in 30 days = 1000 * 30 = ₹30000
God bless you guys do hard work and try to get 95+% in your exam! Thanks for 2.2k likes❤ Thanks for 2.4k likes 🗿 Thanks for 2.6k likes 😲 Thanks for 3k likes 👀🔥💀 Thanks for 3.6k likes 🥲
Questions:- Q)1) Solution--- By Ohm's Law, V=IR=> I=V/R So I is inversely proportional to R When R is doubled, I is halved Answer:- b) It becomes half Q)2) Solution--- P=100000W=100KW [1KW=1000W] t=1 hr per day For 30 days, t=30 hrs We know, P=W/t=>W=Pt=>W=100KW×30h=>W=3000KWh Cost- 1KW --> Rs 10 3000KW --> Rs 10×3000=Rs 30000 Answer:- Rs 30000 Plss like the comment if you are satisfied with the answer.....😅😅😅😅😊😊 Thank you everyone for crossing 800 likes ❤️
Question 1: ans b) its becomes half And Question 2: Power = 100,000 Watts (or 100 kW) Time per day = 1 hour Total energy consumption per day = Power x Time = 100 kW x 1 hr = 100 kWh Total energy consumption for 30 days = 100 kWh/day x 30 days = 3000 kWh Cost per kWh = Rs. 10 Total cost for 30 days = Total energy consumption x Cost per kWh = 3000 kWh x Rs. 10/kWh = Rs. 30,000 So, the total cost for 30 days is Rs. 30,000. Here's a breakdown: Power | 100 kW Time per day | 1 hr Energy/day | 100 kWh Energy/30 days | 3000 kWh Cost/kWh | Rs. 10 Total Cost/30 days | Rs. 30,000
Formula: I=Q×T Q=n×e (n= no. of electrons) V=W/Q V=I×R, I=V/R, R=V/I R=pL/A Rnet series= R1+R2+R3… Rnet parallel= 1/R1+1/R2+1/R3.. P=W/T P=V×I P=I²×R P=V²/R E=P×T, P=E/T, T=E/P H=P×T, H = V×R×T, H=I²×R×T S.I units: Current (I)= Ampere Charge (Q)= Colomb Time(t)= second Potential Difference (V)= Volt Resistance (R)= ohm Resistivity (rho)= ohm meter Power(P)= watt Work done= w Values: e={1.6×10-¹⁹} 1KWH = 3.6×10⁶ J 1 Ampere=1000mA 1kilowatt=1000W 1hr= 3600sec Definition: Ammeter: For measuring Current in Series circuit. Volt meter: For measuring Volt in parallel circuit. Ohm's law: The voltage across a resistor is directly proportional to the current flowing through the resistance. Please like this if you feel it is helpful ❤️🙏
00:04 Overview of electricity concepts 00:39 Charge 02:21 Quantization of charge explained 03:02 Understanding current and ammeter 04:32 Understanding work done and potential difference 05:11 Understanding formulas for charge, current, voltage, and work done by charge. 06:30 Understanding basic circuits and components 07:12 Understanding resistance and its unit 08:51 Understanding the significance of resistance in Ohm's Law 09:40 Understanding the relationship between resistance and temperature in electricity 11:03 Understanding voltage and current in parallel circuits 11:46 Calculating total resistance using Ohm's Law 13:25 Heating effect of electric current 14:07 Understanding the concept of resistance and heat generation in electrical circuits 15:29 Understanding the properties of Nichrome material 16:17 Understanding Power in Electricity 17:45 Understanding the concept of kilowatt-hour 18:33 Understanding the importance of conversion in exams 20:03 Understanding the relationship between voltage and current. 20:39 Share and discuss about the lecture topic with friends.
Q1) b It becomes half Reason According to ohm's law I is inversely proportional to R Therefore is R is doubled so the I will decrease causing for V to decrease too , as it is directly proportional to I Q2) Given , P=100000W = 100kW t=1hr/day For 30days t=30hrs We know, Enery= Power×time =100kW×30hrs=3000kWh Therefore cost will be 30000kWh×₹10 =₹30000
hiie every one 1. Ohm's Law: - V = IR (Voltage = Current x Resistance) - I = V/R (Current = Voltage / Resistance) - R = V/I (Resistance = Voltage / Current) 2. Power: - P = VI (Power = Voltage x Current) - P = I^2R (Power = Current^2 x Resistance) - P = V^2/R (Power = Voltage^2 / Resistance) 3. Energy: - E = Pt (Energy = Power x Time) - E = VIt (Energy = Voltage x Current x Time) Resistance and Resistivity 1. Resistivity: - ρ = RA/l (Resistivity = Resistance x Area / Length) 2. Resistance: - R = ρl/A (Resistance = Resistivity x Length / Area) 3. Combination of Resistances: - Series: R_total = R1 + R2 + ... + Rn - Parallel: 1/R_total = 1/R1 + 1/R2 + ... + 1/Rn Electric Potential 1. Electric Potential: - V = W/q (Voltage = Work / Charge) Other Formulas 1. Kilowatt-hour (kWh): - 1 kWh = 1000 Wh = 3.6 x 10^6 J 2. Fuse and Circuit Breaker: - I = V/R (Current = Voltage / Resistance) Units and Conversions 1. Volt (V) 2. Ampere (A) 3. Ohm (Ω) 4. Watt (W) 5. Joule (J) 6. Kilowatt-hour (kWh) i think this will make easy 😇😇
(2) P=100000 w t= 1hr per day Converting power into kilowatt ; 100000/1000= 100kw E= p x t = 100kw x 1hr = 100kwh Cost for 30 days, rate of 10rs per kwh= 100x 30x ₹10 = ₹30000. (Answer)
Here are the key formulas from Class 10 Electricity chapter: *Electricity Formulas* *1. Electric Charge* - Q = ne (Charge = number of electrons × charge of an electron) - Q = It (Charge = current × time) *2. Electric Current* - I = Q/t (Current = charge / time) - I = V/R (Current = voltage / resistance) *3. Resistance* - R = ρL/A (Resistance = resistivity × length / area) - R = V/I (Resistance = voltage / current) *4. Ohm's Law* - V = IR (Voltage = current × resistance) - I = V/R - R = V/I *5. Series Circuit* - R_total = R1 + R2 + ... + Rn (Total resistance = sum of individual resistances) - I = V/R_total *6. Parallel Circuit* - 1/R_total = 1/R1 + 1/R2 + ... + 1/Rn (Reciprocal of total resistance = sum of reciprocals of individual resistances) - V = I × R_total *7. Power* - P = VI (Power = voltage × current) - P = I^2R - P = V^2/R *8. Energy* - E = Pt (Energy = power × time) - E = VIt *9. Heating Effect of Current* - H = I^2Rt (Heat = current^2 × resistance × time) *10. Electric Power and Energy* - 1 kWh = 3.6 × 10^6 J (1 kilowatt-hour = 3.6 megajoules) *Important Constants* - Charge of an electron (e) = 1.6 × 10^-19 C - Resistivity of copper (ρ) = 1.68 × 10^-8 Ωm *Other Key Concepts* - Potential difference (V) - Electromotive force (EMF) - Conductors, Insulators, and Semiconductors - Series and Parallel circuits - Short circuit and Open circuit These formulas and concepts will help you solve problems in the Class 10 Electricity chapter. Would you like additional practice questions or explanations?
Charge Conductor Insulator Numerical Electric potential Potential difference Electric current Electric current Direction of electric current Ohms law Resistance Resistance of a conductor Graph between VAndI Good conductor Good insulator Good resistance Factor affecting of a conductor Domestic electric circuit Advantages of parallel circuit Power
Please provide all the remaining chapters rapid revision as soon as possible as syllabus is almost completed it will be much helpful for last minute revision..😊
1 = It becomes half 2=power=100kw Per day= 1hr Cost =30days=30hrs Rate=10rs per kwh We know that p=w/t So,w=pt 100kw×30 W=3000kwh 1kw=rs10 3000×10 30000❤😅
00:04 Rapid Revision of Electricity 00:39 चार्ज क्या है और इसके प्रकार 02:21 Quantization of charge formula q = n 03:02 Understanding current and its measurement 04:32 Understanding Work Done and Potential Difference in Electricity 05:11 Understanding electrical circuits and formulas. 06:30 Understanding ammeter and voltmeter diagrams 07:12 Understanding resistance and its properties 08:51 Understanding Voltage and Current Graph Slope 09:40 Understanding resistance and temperature relationship 11:03 Voltage remains the same in parallel while current divides. 11:46 Derive total resistance using Ohm's law 13:25 Heating effect of electric current 14:07 Understanding resistances and their proportionality 15:29 Understanding the properties of nichrome material in electrical heaters 16:17 Understanding Power in Electrical terms 17:45 Understanding the concept of kilowatt-hour and its relation to energy consumption. 18:33 Understanding electrical energy consumption and power rating 20:03 Understanding the relationship between voltage and current.
00:04 Rapid Revision of Electricity 00:39 What is Charge and its types 02:21 Quantization of charge formula q = n 03:02 Understanding current and its measurement 04:32 Understanding Work Done and Potential Difference in Electricity 05:11 Understanding electrical circuits and formulas. 06:30 Understanding ammeter and voltmeter diagrams 07:12 Understanding resistance and its properties 08:51 Understanding Voltage and Current Graph Slope 09:40 Understanding resistance and temperature relationship 11:03 Voltage remains the same in parallel while current divides. 11:46 Derive total resistance using Ohm's law 13:25 Heating effect of electric current 14:07 Understanding resistances and their proportionality 15:29 Understanding the properties of nichrome material in electrical heaters 16:17 Understanding Power in Electrical terms 17:45 Understanding the concept of kilowatt-hour and its relation to energy consumption. 18:33 Understanding electrical energy consumption and power rating 20:03 Understanding the relationship between voltage and current. 20:39 Share the video with friends and comment the topic you want a lecture on.
Electric Current and Circuit
1. Ohm's Law:
- V = IR (Voltage = Current x Resistance)
- I = V/R (Current = Voltage / Resistance)
- R = V/I (Resistance = Voltage / Current)
2. Power:
- P = VI (Power = Voltage x Current)
- P = I^2R (Power = Current^2 x Resistance)
- P = V^2/R (Power = Voltage^2 / Resistance)
3. Energy:
- E = Pt (Energy = Power x Time)
- E = VIt (Energy = Voltage x Current x Time)
Resistance and Resistivity
1. Resistivity:
- ρ = RA/l (Resistivity = Resistance x Area / Length)
2. Resistance:
- R = ρl/A (Resistance = Resistivity x Length / Area)
3. Combination of Resistances:
- Series: R_total = R1 + R2 + ... + Rn
- Parallel: 1/R_total = 1/R1 + 1/R2 + ... + 1/Rn
Electric Potential
1. Electric Potential:
- V = W/q (Voltage = Work / Charge)
Other Formulas
1. Kilowatt-hour (kWh):
- 1 kWh = 1000 Wh = 3.6 x 10^6 J
2. Fuse and Circuit Breaker:
- I = V/R (Current = Voltage / Resistance)
Units and Conversions
1. Volt (V)
2. Ampere (A)
3. Ohm (Ω)
4. Watt (W)
5. Joule (J)
6. Kilowatt-hour (kWh)
likeee😃
Thanku
Thank you so much bro ♥
Thanks bro ☺
wow 😅😅
Is this all the formula in this chapter??
welcome everyone and thnks for like[edit]
All Formulas of Electricity:
1) I = Q/t
2) Q = ne
3) V = W/Q
4) V = IR
5) R = Rho x L/A
6)Resistance in Series: Rs = R1 + R2 + R3
7)Resistance in Parallel: 1/Rp = 1/R1 + 1/R2 + 1/R3 (» Reciprocal of R1+R2+R3)
8)H = V × Q
i) H = VIt
ii) H = I²Rt
iii) H = V²t/R
9) P = W/t
i) P = VI
ii) P = I²R
iii) P = V²/R
10) E = P × t
S.I. Units:
Current ( I ) - Ampere
Charge ( Q ) - Coulomb
Time ( t ) - Second
Potential Difference or Voltage ( V ) - Volt
Resistance ( R ) - Ohm Ω
Resistivity ( Rho ) - Ohm meter
Power ( P ) - Watt
Heat = Energy = Work = Joule
Measuring Devices:
Ammeter / Milli Ammeter - for measuring current (always connected in series)
Galvanometer - for measuring small/sensitive currents (we can also get the direction of the current)
Voltmeter - for measuring volts (always connected in parallel)
Ohm Meter - Measures the resistivity
Things to remember:
electron charge = (1.6 x 10⁻¹⁹ C)
1kWh= 3.6 × 10⁶J
1Ampere = 1000mA
1 Kilowaat = 1000W
1 Horse Power = 746W
i hope this list will help you! ❤
ek free ka like dete jana
Woooow dude .... Prashant bhaiya k saath collaboration kar lo
Tum notes banana ... Aur bhaiya lectures le lege 😅
@@anamikariya2083Actually I am currently studying in class 11th😅
@@draxx915 ookkk
Lag hi raha tha
@@anamikariya2083 can i get your insta?
Thank you so much bro..
20:12 Q1 [b] it becomes half
Q2 Power=100000W
t=1hr
Power=100000/1000=100W
Total energy consumption= 100 * 1
= 100kwh
Cost of energy consumed in one day= 100 * 10
= ₹1000
Cost of energy consumed in 30 days = 1000 * 30
= ₹30000
God bless you guys do hard work and try to get 95+% in
your exam!
Thanks for 2.2k likes❤
Thanks for 2.4k likes 🗿
Thanks for 2.6k likes 😲
Thanks for 3k likes 👀🔥💀
Thanks for 3.6k likes 🥲
Ok bhai😅
No pass
Bhai subscribe kar tha hu top me hauvga😢😅.
😂lol 😂
lol
Ja ja nahi milegi bheekh 😂 koi aur tareeka dhoondh
Questions:-
Q)1) Solution---
By Ohm's Law, V=IR=> I=V/R
So I is inversely proportional to R
When R is doubled, I is halved
Answer:- b) It becomes half
Q)2) Solution---
P=100000W=100KW [1KW=1000W]
t=1 hr per day
For 30 days, t=30 hrs
We know, P=W/t=>W=Pt=>W=100KW×30h=>W=3000KWh
Cost- 1KW --> Rs 10
3000KW --> Rs 10×3000=Rs 30000
Answer:- Rs 30000
Plss like the comment if you are satisfied with the answer.....😅😅😅😅😊😊
Thank you everyone for crossing 800 likes ❤️
Yes
I agree with you 💯
Good job brow ❤
Isme se mera aak hi match kar raha kyu ki dusra wala mene abhi acche se practice ni ki hai
Your 2nd answer is wrong
Ek help kar sakta hai kya bro mara plz
vote for carbon and its compounds 😅
EXAM IS NEAR
NOTHING IS CLEAR
NO NEED TO FEAR
PRASHANT BHAIYA IS HERE ❤❤
😂
Kya bat ha bhai😂
gu kha le
th-cam.com/video/UMcd73j2vTo/w-d-xo.html
Jod or wor
1 like=100% in half yearly and board exams❌
Hard work=result✔
MAA KASAM JISNE SUBS--CRIBE NAHI KIYA VOH PAKA EXAMS MEIN FAIL🤣🤣
@@BOSS-GAMING-1123 Abbey tu to sudrai ga nai
@@BOSS-GAMING-1123jese ki tu
😑😐@@BOSS-GAMING-1123😑😐
@@BOSS-GAMING-1123 jo tereko karega vo to paka fail
Question 1: ans b) its becomes half
And Question 2:
Power = 100,000 Watts (or 100 kW)
Time per day = 1 hour
Total energy consumption per day = Power x Time = 100 kW x 1 hr = 100 kWh
Total energy consumption for 30 days = 100 kWh/day x 30 days = 3000 kWh
Cost per kWh = Rs. 10
Total cost for 30 days = Total energy consumption x Cost per kWh
= 3000 kWh x Rs. 10/kWh
= Rs. 30,000
So, the total cost for 30 days is Rs. 30,000.
Here's a breakdown:
Power | 100 kW
Time per day | 1 hr
Energy/day | 100 kWh
Energy/30 days | 3000 kWh
Cost/kWh | Rs. 10
Total Cost/30 days | Rs. 30,000
Good job
😮
Thnks
Time ko sec me nhi karenge🙄
@@tanisharawat712 mera bhi same doubt h
ig kWh h usliye hour me hi rkhenge
I wish all students get 95%+❤
Thank you 👍🏻😊 you too
Thank
Thank you
Thanks ❤
@@Momo_xtheticsswelcome ❤
Formula:
I=Q×T
Q=n×e (n= no. of electrons)
V=W/Q
V=I×R, I=V/R, R=V/I
R=pL/A
Rnet series= R1+R2+R3…
Rnet parallel= 1/R1+1/R2+1/R3..
P=W/T
P=V×I
P=I²×R
P=V²/R
E=P×T, P=E/T, T=E/P
H=P×T, H = V×R×T, H=I²×R×T
S.I units:
Current (I)= Ampere
Charge (Q)= Colomb
Time(t)= second
Potential Difference (V)= Volt
Resistance (R)= ohm
Resistivity (rho)= ohm meter
Power(P)= watt
Work done= w
Values:
e={1.6×10-¹⁹}
1KWH = 3.6×10⁶ J
1 Ampere=1000mA
1kilowatt=1000W
1hr= 3600sec
Definition:
Ammeter: For measuring Current in Series circuit.
Volt meter: For measuring Volt in parallel circuit.
Ohm's law: The voltage across a resistor is directly proportional to the current flowing through the resistance.
Please like this if you feel it is helpful ❤️🙏
Work done ki joule hoti h
Nice bro
1no bhai
Thanks you for this help
1 wala galat hai rev
I = Q/T
00:04 Overview of electricity concepts
00:39 Charge
02:21 Quantization of charge explained
03:02 Understanding current and ammeter
04:32 Understanding work done and potential difference
05:11 Understanding formulas for charge, current, voltage, and work done by charge.
06:30 Understanding basic circuits and components
07:12 Understanding resistance and its unit
08:51 Understanding the significance of resistance in Ohm's Law
09:40 Understanding the relationship between resistance and temperature in electricity
11:03 Understanding voltage and current in parallel circuits
11:46 Calculating total resistance using Ohm's Law
13:25 Heating effect of electric current
14:07 Understanding the concept of resistance and heat generation in electrical circuits
15:29 Understanding the properties of Nichrome material
16:17 Understanding Power in Electricity
17:45 Understanding the concept of kilowatt-hour
18:33 Understanding the importance of conversion in exams
20:03 Understanding the relationship between voltage and current.
20:39 Share and discuss about the lecture topic with friends.
Good luck for all
Tomorrow's exam 💀
😂
Thank You 👽
@@yk_sarkar 💀
Thanks you
Thanks bro
God bless you guys do hard work and try to get 98+% in your exams!
Jo jo like krega bagwan ji uske board's mei 95% above ayee ..!!!!❤
Ok Bhai 10th class may hu 95;
JOJO REFERENCE
Like karne ke baad 95 aajayenge 😂😂
Arra ya bhi ni sis ha
@@Neeraj_king_087
like maangne ka naya tarika. or hai bhai iss comment ko jada series mat lena mai majak kar raha hu.
Q1) b It becomes half
Reason
According to ohm's law
I is inversely proportional to R
Therefore is R is doubled so the I will decrease causing for V to decrease too , as it is directly proportional to I
Q2)
Given ,
P=100000W = 100kW
t=1hr/day
For 30days
t=30hrs
We know,
Enery= Power×time =100kW×30hrs=3000kWh
Therefore cost will be
30000kWh×₹10
=₹30000
This is wrong
Time = Hour
Time = Hour
For 30 days
30x60=1800
@@_its_Rudransh_77bro time already hour me h to change karne ka koi jarurat nhi h isliye direct 30*1 kiya h
Prashant sir is best teacher of science ❤
Prashant sir for 1 like 👍
infinity likes*
bhai stop glazing pls its getting out of hand
Prashant bhaiya is best no one can explain like him
MAA KASAM JISNE SUBS--CRIBE NAHI KIYA VOH PAKA EXAMS MEIN FAIL🤣🤣
@@BOSS-GAMING-1123sudhar ja behan
fail ho jygi
@@BOSS-GAMING-1123 fir bolte hai papa mene padha tha lekin pata nhi kyu fail hogayi
Like or Fail in Maths and Science
hiie every one
1. Ohm's Law:
- V = IR (Voltage = Current x Resistance)
- I = V/R (Current = Voltage / Resistance)
- R = V/I (Resistance = Voltage / Current)
2. Power:
- P = VI (Power = Voltage x Current)
- P = I^2R (Power = Current^2 x Resistance)
- P = V^2/R (Power = Voltage^2 / Resistance)
3. Energy:
- E = Pt (Energy = Power x Time)
- E = VIt (Energy = Voltage x Current x Time)
Resistance and Resistivity
1. Resistivity:
- ρ = RA/l (Resistivity = Resistance x Area / Length)
2. Resistance:
- R = ρl/A (Resistance = Resistivity x Length / Area)
3. Combination of Resistances:
- Series: R_total = R1 + R2 + ... + Rn
- Parallel: 1/R_total = 1/R1 + 1/R2 + ... + 1/Rn
Electric Potential
1. Electric Potential:
- V = W/q (Voltage = Work / Charge)
Other Formulas
1. Kilowatt-hour (kWh):
- 1 kWh = 1000 Wh = 3.6 x 10^6 J
2. Fuse and Circuit Breaker:
- I = V/R (Current = Voltage / Resistance)
Units and Conversions
1. Volt (V)
2. Ampere (A)
3. Ohm (Ω)
4. Watt (W)
5. Joule (J)
6. Kilowatt-hour (kWh)
i think this will make easy 😇😇
0% ego
0% attitude
100% Honest
100% Hardwork
Dil se Salute Prashant Bhaiya 💞💞
@@rumblingpen133 belive
pull your pants when you're done homie
@@nmverse what!
@@nmverse blud after saying this 🗿
100% roaster
(2) P=100000 w
t= 1hr per day
Converting power into kilowatt ; 100000/1000= 100kw
E= p x t
= 100kw x 1hr
= 100kwh
Cost for 30 days, rate of 10rs per kwh=
100x 30x ₹10 = ₹30000. (Answer)
Metals and non metal rapid revision 👍🏻
th-cam.com/video/UMcd73j2vTo/w-d-xo.html
13:17 Rnet = 2ohm
Current (I) = 1Ampere
Ques 1 20:14
Ans:b)
Ques 2 20:19
Ans:30,000 KWh
bro its 30000 rs not KWh
May it's because v is directly proportional to IR😅
@@MohammedDaniyal-ex3pw YA U R RIGHT
it is right ans b) and 30,000 Rs
th-cam.com/video/UMcd73j2vTo/w-d-xo.html
20:33
Given‚
p= 100000w
t= 1×30= 30 hrs
P=100000/1000
=100kw
P=w×t
So‚therefore
100×30
=3000kwh
But‚ 1kwh= 10rs
So‚
3000×10
=30‚000rs
Bhai mere bhi same answer aa raha hai ❤🎉
🎉❤
30 days ka rate nikalana hai bhai 30 hours ka nahi wrong hai aapka answer I think 😮
@@DivyaGupta-x4qbut bro per day to 1 hour hai na AC... To 30 days ke according 30 hours hi hoga...
So yhi answer correct hai✅
Here are the key formulas from Class 10 Electricity chapter:
*Electricity Formulas*
*1. Electric Charge*
- Q = ne (Charge = number of electrons × charge of an electron)
- Q = It (Charge = current × time)
*2. Electric Current*
- I = Q/t (Current = charge / time)
- I = V/R (Current = voltage / resistance)
*3. Resistance*
- R = ρL/A (Resistance = resistivity × length / area)
- R = V/I (Resistance = voltage / current)
*4. Ohm's Law*
- V = IR (Voltage = current × resistance)
- I = V/R
- R = V/I
*5. Series Circuit*
- R_total = R1 + R2 + ... + Rn (Total resistance = sum of individual resistances)
- I = V/R_total
*6. Parallel Circuit*
- 1/R_total = 1/R1 + 1/R2 + ... + 1/Rn (Reciprocal of total resistance = sum of reciprocals of individual resistances)
- V = I × R_total
*7. Power*
- P = VI (Power = voltage × current)
- P = I^2R
- P = V^2/R
*8. Energy*
- E = Pt (Energy = power × time)
- E = VIt
*9. Heating Effect of Current*
- H = I^2Rt (Heat = current^2 × resistance × time)
*10. Electric Power and Energy*
- 1 kWh = 3.6 × 10^6 J (1 kilowatt-hour = 3.6 megajoules)
*Important Constants*
- Charge of an electron (e) = 1.6 × 10^-19 C
- Resistivity of copper (ρ) = 1.68 × 10^-8 Ωm
*Other Key Concepts*
- Potential difference (V)
- Electromotive force (EMF)
- Conductors, Insulators, and Semiconductors
- Series and Parallel circuits
- Short circuit and Open circuit
These formulas and concepts will help you solve problems in the Class 10 Electricity chapter.
Would you like additional practice questions or explanations?
He is the best bhaiya 😊😊❤❤❤❤❤❤and best teacher 😊❤ who agree😊😊❤❤
May all of you get 95+ ✨
Meanwhile legends were watching this masterpiece on the exam day 👀
@@Shubham-uy7fi Yoo 🤟😂🤣
@@Shubham-uy7fi Ji ho gye h khatam 🥲
@@Shubham-uy7fi My real name is Jivika Kashyap Rajput and My nickname is Tanu Kashyap Rajput ✨🙌
@@Shubham-uy7fi Jivika means Roti kmane ki Ruchi or jeevan ,,,,Tanu means Delicate , Patla , Minute
@@Shubham-uy7fi Science 😀
Bhaiya please bring cased based questions.... Vote for this
.. 😢
The first question answer is b) it becomes half and the second question answer is 3,00,000
I think it's 30000 not 300000❤
Yes@@Techmastershorts-p9j
Second is 30000😊
Here,
P = 100 kW
T=1×30=30h
Rate of current= 10rs
So. the total cost of current is 100×30×10 = 30000/
Are bhayyooo wo 30 nhi 720 hona chahie
Hrs me cnvrt krna he use
Wahi wahi
@@AmeyKeni-z8ubro time per day kitta use hota hai woh given hai so correct hai ans bhai ka
Bhai uska ans sahi
hai apna recheck kro
Sahi he👍🏻
20:15 Option (B)
20:32 answer :- ₹ 30,000
Boards Ki Kasam Jisne Like Nhi Kiya Woh Pakka Fail Honge !! 😂
(Don't Take Risk) 💢
Gali dene wala bottom 😂
Agar acha nhi likh sakte toh please bura bhi mt likha kro kisi ke liye
@@Sigma-tk4vy here
@@NikhilKumar-z3b4m chalna...dekh toh le comment kya kiya hai usme
@@NikhilKumar-z3b4m shi baat hai bhai
Sir/Bhai ne right time par video dali 😊
Ha kal hi exam h mera
Ha mera 1min baad hi h
Vote for Ch-3 Metals and Non Metals now
Bhaiya we request ch-3 next ❤
1:47 true ufff😩🫶🏻
Hi
Charge
Current
Potential
Potential difference
Circuit
Omh Lay's
Ty bhai
20:08 B
Like or fail
Boards ki kasam jisne subscribe nhi kiya wo exam me fail ho jayega ☠️ 💀
Thank you so much bhaiya❤❤❤❤
Love you from Uttarakhand ❤❤❤
20:14 Q1 b) It becomes half
20:24 Q2 Ans = 30000 Rs
Thank you so much bhaiya. You are the best teacher for Science.....❤
2nd is 30000
@@sgplays8622 Thank you, typing mistake ho gyi thi
@@troll_faceedits-s3e np
Boards ki kasam jisnei like or subscribe nahi kiya vo pakka fail mei joh bhi bolti hu sachi mei sach hota h don't take risk 😮
Bhaiya app repid revision karake Mera sara topic clear kar diya I like ur pattern
Use in teaching 🙏🙏🙏🙏🙏🙏🙏🙏🙏
Vote for Metal and non metal
Board ki kasam jisne like nhi kiya vo fail🫵⚠️⚠️
Jo dusro ko fail krna chahta hai sabse pehle to vahi fail ho
Like ke liye kuchh bhi kar sakte**
Hehe abhay le liya abb bol
Boards ki kasm jo subscribe nhi karega vo exam mai fail😅
1 LIKE =98.9% IN BOARD😊(DON'T TAKE RISK)❤
😢😢😢
All teachers are best but Prashant sir is very very very very very best teacher
Who reads this comment will get 95% in boards 🎉
12:35 r(net)= 2ohm
12:35 current remains the same in both
Jisko next chapter METALS AND NON-METALS chahiye please like karo -------->
20:13 answers:
Q1 = it becomes half [ I=V/R]
Q2 = ₹ 30,000 [ 3000kWh × ₹10]
Hii
Very nice information ❤
Bhaiya in 0:59 the definition of semiconductor and insulator are opposite . It is wrong.
Sir ne jo bola wo sunayee naii diya kya behra hai kya.
Bhaag yahaan se..
Shi me bhara hi 😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂😂
Thank you bhaiya ji mee iss chapter kelia besabri se intezar kar raha ta 🙏😊
Bhaiya please upload the chapter Atoms and molecules class 9th 👍🏻
Guys please vote for atoms and molecules 👍🏻
12:40
R net = 2ohm
Current = 1Ampere
Hay❤
DON'T DIE BEFORE YOUR DEATH
Charge
Conductor
Insulator
Numerical
Electric potential
Potential difference
Electric current
Electric current
Direction of electric current
Ohms law
Resistance
Resistance of a conductor
Graph between VAndI
Good conductor
Good insulator
Good resistance
Factor affecting of a conductor
Domestic electric circuit
Advantages of parallel circuit
Power
😅
@@Monika-if9up😅
Bhai topper hai kya 😂
@@DeepakSingh-y2t6j nahi bhai like de Dena bs like ka liya likha 😂
@@Pranks_girl ok
like kar diya ho okay 👍
1st answer will be current becomes half because
V=IR
V/I=R
THEREFORE, R is inverse proportion to I, I becomes half
You and your team is god of science, thanks for mentor us ..
❤
@@woodworkingRSK 11th/12th science teachers be like:- kya karu fir job chodh du 💀
Use of magnetic current bhi pls bhaiya as it's coming in half yearly
20:13 a) it doubles
Q. 30000rs
P×t= energy
P should be in kwh
100×1= 100
Cost for 30 days = 100×30×10= 30000
It becomes half inversely proportional
Please provide all the remaining chapters rapid revision as soon as possible as syllabus is almost completed it will be much helpful for last minute revision..😊
Prashant bhaiya ko best teacher and best motivational speaker manne wale like kare 👍
Bhaiyaa ne aj josh meter bhul gye
20:06 (b) It becomes half
20:18 Answer:- 30,000 Rs.
Respect button for Prashant bhaiya❤❤⬇️⬇️⬇️
1 like 99 in board no risk
Ans-1-It becomes half
Ans-2- 30 day cost = ₹30000
if the resistance of a conductor doubles, what happens to the current for the same applied voltage?
(b) It becomes half
Why
1 = It becomes half
2=power=100kw
Per day= 1hr
Cost =30days=30hrs
Rate=10rs per kwh
We know that p=w/t
So,w=pt
100kw×30
W=3000kwh
1kw=rs10
3000×10
30000❤😅
Wrong hai 72000000 ayega
Time travell 6:42
1:46 universal truth💀
Maa kasam jisne like nhi kiya vo exam me fail ho jayga 😂😂
Bhai ese ese Kasam n de 😢
Bhai tu bhi exam me fail ho jaega
@@RinaSingh-y9p 😔
@@SanjuktaBehera-w9v me 2 subject me hogya 😭
Ispe jitne like aayega tu utne baap ka 💀
Exam is near
Nothing is clear
No need to fear
When prashant bhaiya is here
👏
Question1- Ans (b)
Question 2 -Ans Rs30,000😊
East or west prashant bhaiya best maj aa gaye bhaiya litrally kab se is vid ka wait kr rha tha
Yuppp !! U are right I'm also waiting for this video.....☺️
@@Kamakshisharma576 YEH I TOPPED IN MY SCIENCE EXAM BECUSE OF BHAIYA
@@AadyadeepSharmacongrates dear☺️👀💛
God bless you guys do hard work and try to get 99%
In your exam
Bhai apka exam kb hai
1 Subscribe =95% don't take risk orna fail 😂😂
00:04 Rapid Revision of Electricity
00:39 चार्ज क्या है और इसके प्रकार
02:21 Quantization of charge formula q = n
03:02 Understanding current and its measurement
04:32 Understanding Work Done and Potential Difference in Electricity
05:11 Understanding electrical circuits and formulas.
06:30 Understanding ammeter and voltmeter diagrams
07:12 Understanding resistance and its properties
08:51 Understanding Voltage and Current Graph Slope
09:40 Understanding resistance and temperature relationship
11:03 Voltage remains the same in parallel while current divides.
11:46 Derive total resistance using Ohm's law
13:25 Heating effect of electric current
14:07 Understanding resistances and their proportionality
15:29 Understanding the properties of nichrome material in electrical heaters
16:17 Understanding Power in Electrical terms
17:45 Understanding the concept of kilowatt-hour and its relation to energy consumption.
18:33 Understanding electrical energy consumption and power rating
20:03 Understanding the relationship between voltage and current.
Kon kon November me dekh rhe ho 😂
Hii
My bad luck😢
Hi
Hii 😊
Mee also
I wish you all got 95 % marks ❤❤🎉🎉
00:04 Rapid Revision of Electricity
00:39 What is Charge and its types
02:21 Quantization of charge formula q = n
03:02 Understanding current and its measurement
04:32 Understanding Work Done and Potential Difference in Electricity
05:11 Understanding electrical circuits and formulas.
06:30 Understanding ammeter and voltmeter diagrams
07:12 Understanding resistance and its properties
08:51 Understanding Voltage and Current Graph Slope
09:40 Understanding resistance and temperature relationship
11:03 Voltage remains the same in parallel while current divides.
11:46 Derive total resistance using Ohm's law
13:25 Heating effect of electric current
14:07 Understanding resistances and their proportionality
15:29 Understanding the properties of nichrome material in electrical heaters
16:17 Understanding Power in Electrical terms
17:45 Understanding the concept of kilowatt-hour and its relation to energy consumption.
18:33 Understanding electrical energy consumption and power rating
20:03 Understanding the relationship between voltage and current.
20:39 Share the video with friends and comment the topic you want a lecture on.
1 like = 95% ❌
1 hour daily=95%✅
kal kiska exam hai
20:15 b is right
Bhayiya yar 9th class ke bhi to kuch rapid revision Lao 25 ko exam hai
Same
Same
Same bhai
Tum bhi kisi vidhya bharti school se ho ???
Mera kal hi hai bhai😅
TQ so much sir I need this chapter 😊🙏🏻😀
💖💖💖💖💖💖💖
H.W
Q1 (b) It becomes half
Q2 30,000 Rs.
Boards ki kasam jisne subscribe nhi Kiya wo exam me Fail 😂😂 (Don't Take Risk) 💀☠️
Tarimaa ka ▓▓▓██░░░░░░░░░█ tera baap dera kya number board me
Chup
@@10thGrader-so3ngkise bol ra bhai
Bag
Bhai mara to new
❤❤❤❤❤ thank u bhaiya❤❤❤❤❤❤
11:03 derivation
bhaiya please magnetic effect of electric current
bhaiya please because we have that for half yearly exam please bhaiya
🙏🙏🙏🙏
3-4 din mai aa jayaga
@@Rajeev_meenatab tak exam aa jayega
Board ki Kasam jisne subscribe nahi Kiya board fail 😂🎉😢
I pray 🥺🥺🥺 to all will be pass atleast 95 , 96 percent😭😭😭😭
Best of luck to all 👍🏻👍🏻👍🏻👍🏻👍🏻👍🏻👍🏻👍🏻👍🏻👍🏻
1 like = 95%+
1 subscribe and 1 like = 99% ❤❤❤😂😂
11:31Ra