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7^(-1/7) is simpler
He must have shares in an ink company
Nah bro you ain’t making it to Harvard 💀Steps:a) (1/7)^(1/7)b) (7^-1)^(1/7)c) 7^(-1/7)Reasoninga) Given expressionb) Using 1/a = a^-1 - corollary of a^-b = 1/(a^b)c) Using (a^b)^c = a^(bc)
It's awful
7^(-1/7) is simpler
He must have shares in an ink company
Nah bro you ain’t making it to Harvard 💀
Steps:
a) (1/7)^(1/7)
b) (7^-1)^(1/7)
c) 7^(-1/7)
Reasoning
a) Given expression
b) Using 1/a = a^-1 - corollary of a^-b = 1/(a^b)
c) Using (a^b)^c = a^(bc)
It's awful