This is one of the teachers or instructors that made students afraid of mathematics. See how he took over 10 minutes to solve a problem that can be solved in less than 1 minute. Students will now think that it is a huge headache to solve such a problem.
That's not the idea. If you solve a problem in 1 minute, nobody will watch it. If the video is at least 8 minutes long then it brings in more revenue because of the ads and that's what YT is going after, of course. More profit to the detriment of YT'ers!
Good god. This is why people hate mathematicians. You literally made the problem ten times harder than it has to be. I am a trained physicist, and I found this excruciating. I can just imagine the middle and high school students watching this.
I’m glad you found a more efficient method! 🔥 💯. It’s all about finding the most suitable representation! 😎 Thanks for your feedback! I appreciate your perspective! 💖💯
@@superacademy247 I think he was saying you have expounded too much when it has simple solution... 1/(2)^3/8 but seriously, 1 over 8th root of 8 is what it is...
Я тоже устал смотреть как разжовывают одни и те же правила, и по два раза переписывают одно и тоже 🤦♂️ Такое ощущение что аФтАр преподает для дебилов имеющих память как у рыбки гуппи 🤦♂️
Since 8 is the same as 2^3, why didn't you do (2)^(-3x(1/8)) ie (2)^(-3/8) ? Which is the same as your answer simplified because 32 = 2^(5/8) and 5/8 - 1 = -3/8 because 1/2 is the same as 2^(-1)
This is only one of the solution.Actually there are seven more roots.So this problem has eight roots,two are real and other six are comlex.This according to fundametal theorem of algebra.
unfortunately, YT pushes these videos to a lot of viewers and it gets lots of views. There's something stupid about the algorithm, not the video. The video is pretty basic but either, that's what people click on or YT recommends these kinds of videos to more people than videos that are a little bit more challenging. They definitely changed something to reward these kinds of videos. I agree, it's click-baity. I don't think this problem came up on a test at Harvard. Sad but this is the reality.
unfortunately, YT pushes these videos to a lot of viewers and it gets lots of views. There's something stupid about the algorithm, not the video. The video is pretty basic but either, that's what people click on or YT recommends these kinds of videos to more people than videos that are a little bit more challenging. They definitely changed something to reward these kinds of videos. I agree, it's click-baity. I don't think this problem came up on a test at Harvard. Sad but this is the reality.
Most of these fancy questions have answers that are just as simple as the questions. The people who can see the simple answers go to Harvard. The people who dream up complicated routines get to be tax collectors in Hyderabad They then steal either three or five eighths off the top before forwarding the rest up the line to New Delhi.
The easier approach is to multiply the denominator and numerator of the expression inside the bracket by 2^5. Then the expression becomes (32/2^8)^(1/8) thus the answer. I have seen another video of yours regarding (1/9)^(1/9). The answer for that would be (3^(7/9))/3 The fact of the matter is that the answer is not any simpler than the question. If the question had 1/5 the answer would be (fifth root of 625)/5. Can do it almost by memory.
Well done. And elegantly typed! And "Wen" is medieval English for "to know." 😂 Come to think of it, a Walther is a hand gun, very effective at point-blank range.
Can't we take (1/8) as 2 to the negative 3 to the (1/8)? Then we multiply the exponents -3(1/8) to get 2^(-3/8)? I saw how you started the problem, and it does work that way, but it is long.
Thanks for sharing your perspective but a negative exponent in the numerator is like a radical denominator. Go a step further to make the exponent on the numerator positive.✅🚀💖💯👍🥰🤩😎
(1/8)^1/8= 1/(((8^1/2)1/2)1/2) =1/((2*(2^1/2)1/2)1/2)=(2.828)^1/2)1/2 the rest can be done using the manual technique for finding the square root. You faied your own test.
I appreciate your method, it's a creative approach to simplify the expression. 🙏Thanks for pointing out the mistake, I'll make sure to review my calculations carefully. 😅💯
Sixteen minutes for this ? You call this a trick! Where is the trick? I think you have also a trick for 1+1 = ? like 1+1 = 1^3+1^4+0^4 because 1^a = 1 and 0^b =0 so etc etc... and your trick can last 18.8 millards years. I'm joking but I stopped the video before I bigbang.
An unnecessarily confusing and convoluted way of Rationalizing The Denominator...! Why not just explain it in a more straight forward way - which I'm pretty sure you know how to do. Sorry dude but this is the kind of thing that makes the average person think that math is really hard (which most of it is! but not this...)
TH-cam gives us freedom to express authority over the topic 🥰. Can't you see the fascinating style I've deployed to rationalize the denominator in an elegant way?
Why is the new expression considered to be "simplified"? The original expression can easily be computed using a calculator. The 16+ minutes you spent simplifying was a waste of time. (1/8)^(1/8) can be written as 2^(-3/8) by inspection.
I personally need this kind of help. I have a hard time not thinking about every step to make sure I understand every single aspect of the problem rather than solving it with a memorized set of rules. I still don't understand this, but I understood the rule set. I will have to look further into why some of the rules are what they are, though. It sucks to have to do it this way, but I cannot make myself turn off and turn out.
Thanks for sharing your perspective on problem-solving. It's great that you're determined to understand the underlying principles! 💯💕💪I hear you! It's definitely challenging to balance speed and understanding. Keep up the hard work! 💪💕🤩
@superacademy247 Oh, far out! I didn't think anyone at the site would pay attention to this comment. I watch your stuff everyday now. I decided a few months ago I was going to polish up my math skills before I started looking for partnering with a university in Europe for a PhD program. I realized very quickly that the memorized rules as an undergraduate were no longer with me. The reason I don't remember them is the reason I try to gain the concepts that create the rules. This also added a year onto my graduation time so those years ago so I stopped thinking, got a tutor, went twice a week, and memorized enough to get through calculous. For me, Algebra was much harder at the introduction stages. Once I knew the reasons to the rules I could speak the language. For the life of me I can't believe I did it now. It was the difference between one Bachelor or two so I figured, "why not?" Regardless, I like your presentations. I ignore the "subscribe" segment, because I already subscribed. I understand you need people to recognize your work so that you can continue to do this. If I can't get caught up, at least to pre-calc, by Spring I'll probably take your full course. My old nemesis time continues to creep up on me though. Thank you for your work! Chadillac
@@superacademy247A long journey to reach just 1/ 8th root of 8.Anybody can reach there by two steps. Again a long tedious journey to reach the final answer . Answer is also not in simpler form. Please cut short the journey.
It is a good review of the rules of exponents. Not an easy way to solve, but a good review none the less! Now if the instructions were solve this using all the known rules of exponents, then this is the way!
To evaluate the expression 1/8^1/8, we need to follow the order of operations (PEMDAS): 1. Exponentiate 8 to the power of 1/8: 8^1/8 = 8^(1/8) 2. Take the reciprocal of the result: 1 / 8^(1/8) Using a calculator or solving algebraically: 8^(1/8) ≈ 1.297379 1 / 1.297379 ≈ 0.77037 So, 1/8^1/8 ≈ 0.77037.
Too short. I think you should use the definition of non-integer exponentiation, i.e. eˣ = Σₙ xⁿ/n! , along with the definition of natural logarithm, i.e. ln(x) = ∫₁ˣ 1/t dt, so that you can rigorously define (1/8)¹ᐟ⁸ and carefully simplify it.
I appreciate your feedback! It's all about finding the most efficient approach for these types of problems.Thanks for your input! I strive to provide multiple perspectives and techniques to help with problem-solving.💯💕🙏
That took way too long then you can do this in two steps first eight is 2 to the 3rd power and then you apply the 8th route to both on top of the bottom and just multiply the exponents which would be 2 to the third power times one over two thirds
I increased the play speed to 2x and it still seemed too slow. You could easily skip many of the steps, because if your viewers don't understand basic stuff they are never going to make it in any exam, let alone Cambridge or Harvard.
Una simplificación tan sencilla que se puede resolver en 2 minutos, este profesor tardó el tiempo que duraba Albert Einstein explicando la solución de cualquier problema relacionado con la astro-fisica. Un estudiante de educación básica hubiera cambiado este video a los 6 minutos. 😮😢
I solved this in my head before watching. It's easy when you see the tricks (I'm a math dummy, tricks are all I have). One to any power is 1, so the problem is to simplify 1/8^(1/8). Multiply numerator and denominator by 8^7/8 to get 8^(7/8) / 8. Subtract the exponents to get the answer, 8^(-1/8). Note that 2^(5/8)/2 is the same as 2^(-3/8), which is the same as 8^(-1/8). Nice scenic tour through lots of properties, though. I kind of like this sort of overcomplication. That bit about subtracting k is a little overcomplicated in itself. Subtracting a constant from like-base numerator and denominator is just dividing each by base^k.
The answer I obtained has more rational denominator than yours in my opinion which is the primary objective of my step by step process. Your answer and mine are the same but the form matters.
@@superacademy247 The denominators in my answer, 8^(-1/8), are one in the base, 8 in the exponent. Your answers were pretty much the same, aren't they? Just trying to learn, and I appreciate your channel. I often find simpler methods, but that makes for a nice learning experience.
You are the best example of how an easy thing can be made tough 👍🏻👍🏻
I aim to make you think deeper! 😎💯Thanks for sharing your perspective! 🙏
@@superacademy247 In a couple of steps 2^(-3/8)
😂 😢😅
@@superacademy247 It seems that you don’t quite understand his sarcastic tone.
This is one of the teachers or instructors that made students afraid of mathematics. See how he took over 10 minutes to solve a problem that can be solved in less than 1 minute. Students will now think that it is a huge headache to solve such a problem.
That's not the idea. If you solve a problem in 1 minute, nobody will watch it. If the video is at least 8 minutes long then it brings in more revenue because of the ads and that's what YT is going after, of course. More profit to the detriment of YT'ers!
Good god. This is why people hate mathematicians. You literally made the problem ten times harder than it has to be. I am a trained physicist, and I found this excruciating. I can just imagine the middle and high school students watching this.
I’m glad you found a more efficient method! 🔥 💯. It’s all about finding the most suitable representation! 😎 Thanks for your feedback! I appreciate your perspective! 💖💯
@@superacademy247 I think he was saying you have expounded too much when it has simple solution... 1/(2)^3/8 but seriously, 1 over 8th root of 8 is what it is...
Я тоже устал смотреть как разжовывают одни и те же правила, и по два раза переписывают одно и тоже 🤦♂️
Такое ощущение что аФтАр преподает для дебилов имеющих память как у рыбки гуппи 🤦♂️
@@KyosukeNanbu-s7c
ちょっと違う!!
It's 1 over the cube root of one eighth.
Today you went South a little bit:
今日は
少し
南部
🙃
@@superacademy247 GOSH, you're a angel! ❤
Since 8 is the same as 2^3, why didn't you do (2)^(-3x(1/8)) ie (2)^(-3/8) ? Which is the same as your answer simplified because 32 = 2^(5/8) and 5/8 - 1 = -3/8 because 1/2 is the same as 2^(-1)
I wonder
One of the characteristis of mathematics is that it makes difficult things easy.
This actually complicates what is easy
Which is why a.) it gets the wrong answer, and b.) shows the guy has missed the whole essence of *all* these Harvard entry japes.
Totally agreed !
Problem can be solved in two steps
It can be solved in one. It's 0.71 by inspection.
No simplificó, cuando debía de hacerlo.
The most stupid way of solving a simple problem.You are testing the patience of the viewers.
Don't worry, you're under professional control.
@@superacademy247 What is that supposed to mean?
This is only one of the solution.Actually there are seven more roots.So this problem has eight roots,two are real and other six are comlex.This according to fundametal theorem of algebra.
unfortunately, YT pushes these videos to a lot of viewers and it gets lots of views. There's something stupid about the algorithm, not the video. The video is pretty basic but either, that's what people click on or YT recommends these kinds of videos to more people than videos that are a little bit more challenging. They definitely changed something to reward these kinds of videos. I agree, it's click-baity. I don't think this problem came up on a test at Harvard. Sad but this is the reality.
2^(-3/8) is more directly
Well done.
😂😂
I did it in my mind.
@@brunodiazdiaz Aren't you special!
The final form is more complex than the given!
1/8 is 2^ minus 3. So LHS is 2^ minus 3/8. which is 2^5/8 /2 on multiplying by 2/2.
Extremely boring. Writing the same thing over and over every line . It should take more than 30 secobds.
Taking more time even for simple thing to earn, I think.
unfortunately, YT pushes these videos to a lot of viewers and it gets lots of views. There's something stupid about the algorithm, not the video. The video is pretty basic but either, that's what people click on or YT recommends these kinds of videos to more people than videos that are a little bit more challenging. They definitely changed something to reward these kinds of videos. I agree, it's click-baity. I don't think this problem came up on a test at Harvard. Sad but this is the reality.
Возмущалась, но досмотрела😂
This is not tricks, but it is a long journey trip.
It's rationalizing the denominator
Yes . Stupid long vedio for nothing
This could be solved with in only five steps.
Yes, I agree
Damaging the Reputation of Harvard University.
Answer is more complicated than Question ❓
Most of these fancy questions have answers that are just as simple as the questions.
The people who can see the simple answers go to Harvard.
The people who dream up complicated routines get to be tax collectors in Hyderabad They then steal either three or five eighths off the top before forwarding the rest up the line to New Delhi.
you can say that again
The easier approach is to multiply the denominator and numerator of the expression inside the bracket by 2^5. Then the expression becomes (32/2^8)^(1/8) thus the answer.
I have seen another video of yours regarding (1/9)^(1/9). The answer for that would be (3^(7/9))/3
The fact of the matter is that the answer is not any simpler than the question.
If the question had 1/5 the answer would be (fifth root of 625)/5. Can do it almost by memory.
Lot of repeated steps.
To make everyone find it easier to understand
Harvard University Simplification Tricks: (1/8)¹⸍⁸ =?
(1/8)¹⸍⁸ = (1/2)³⸍⁸ = (1/2³⸍⁸)[(2⁵⸍⁸)/(2⁵⸍⁸)] = (2⁵⸍⁸)/[(2³⸍⁸)(2⁵⸍⁸)] = (2⁵⸍⁸)/(2⁸⸍⁸) = (⁸√32)/2
Very simple
(⁸√32)/2 = 1/⁸√8 is most simple and super trivial.
Stupid Harvard that you long solution man but this short
Well done.
And elegantly typed!
And "Wen" is medieval English for "to know." 😂
Come to think of it, a Walther is a hand gun, very effective at point-blank range.
The simplification has yielded a complicated answer.
Not complicated because the denominator is finally rational
Much tooooo long...! 😴
Too long!
{ 1/a=a^-1 }
(1/8)^(1/8)=(2^-3)^(1/8)
{ (a^b)^c=a^(bc) }
(2^-3)^(1/8)=2^(-3/8)
rationalization: { 1-1=0 } { a^(b+c)=a^b*a^c }
2^(-3/8)=2^(1-3/8-1)=2^(5/8)/2 or 32^(1/8)/2
Can't we take (1/8) as 2 to the negative 3 to the (1/8)? Then we multiply the exponents -3(1/8) to get 2^(-3/8)? I saw how you started the problem, and it does work that way, but it is long.
Thanks for sharing your perspective but a negative exponent in the numerator is like a radical denominator. Go a step further to make the exponent on the numerator positive.✅🚀💖💯👍🥰🤩😎
Trivial. 1/8 = 2^-3. 2^-3^1/8 = 2^-3/8. Hardly difficult.
(2^-3) ^ (2^-3) = 2 ^ (-3/8)
Done
Is he amateur of Math? lhs=(2^(-3))^(1/8)=2^(-3/8).
His way is not elegant.
2^-(3/8) in 2 steps
(1/8)^1/8= 1/(((8^1/2)1/2)1/2) =1/((2*(2^1/2)1/2)1/2)=(2.828)^1/2)1/2 the rest can be done using the manual technique for finding the square root. You faied your own test.
I appreciate your method, it's a creative approach to simplify the expression. 🙏Thanks for pointing out the mistake, I'll make sure to review my calculations carefully. 😅💯
Открыл сумочку, достал кошелёк, закрыл сумочку,открыл кошелёк, достал билет, закрыл кошелёк, открыл сумочку, положил кошелёк....
Jajajajaja
You’re a legend!!
All the laws of exponents have been used successfully!!
Thanks for your kind words.🎁🎉🥳🎄🌲
Take log base 2 first, then the equation transforms -3/8
Sorry, you practically did nothing but time wasting
I rationalized the denominator successfully and completely
@@superacademy247And why not simply 8 ^ (-1/8)
Know anybody longer way to solution?
Use the definition of non-integer exponentiation, i.e. eˣ = Σₙ xⁿ/n! , together with the definition of natural logarithm, i.e. ln(x) = ∫₁ˣ 1/t dt.
8 = 2^3
1/8 = 2^(−3). Therfore (1/8)^(1/8) = (2^(−3))^(1/8) = 2^(−3/8)
Sir ! You do not take rest and continue till life
I'm glad you appreciate the effort! 🙏Thanks for the encouragement! 💪
why to do all that ???
To rationalize the denominator completely
@@superacademy247 Completely..? Can it be rationalized partially..? LOL Come on man, do better...
Sixteen minutes for this ? You call this a trick!
Where is the trick?
I think you have also a trick for 1+1 = ?
like 1+1 = 1^3+1^4+0^4 because 1^a = 1 and 0^b =0 so etc etc... and your trick can last 18.8 millards years.
I'm joking but I stopped the video before I bigbang.
😂😂😂he could have spent two hours working out 1+1
Why should rewrite the result of the previous equation again and again 😂
To emphasize
Foolish and unnecessary repeatation
of the same steps
An unnecessarily confusing and convoluted way of Rationalizing The Denominator...! Why not just explain it in a more straight forward way - which I'm pretty sure you know how to do.
Sorry dude but this is the kind of thing that makes the average person think that math is really hard (which most of it is! but not this...)
TH-cam gives us freedom to express authority over the topic 🥰. Can't you see the fascinating style I've deployed to rationalize the denominator in an elegant way?
@@superacademy247 I'm sorry but confusing and unnecessarily complicated is NOT fascinating or elegant.
A lot of unnecessary calculation...
(1/8)^(1/8) = ½^(3/8) = 2^(-3/8) = ½ 2^(5/8) = ½ 32^(1/8).
I just waste 16.5 mins watching all of this while an average Asian kid can solve this problem in 15 secs
1/8=2^(-3) and substitute into eq. => 2^(-3/8) = [2^(3/8)]^(-1) = [8^(1/8)]^(-1) = 1/[8^(1/8)]
Excruciating.
Energy usurping. Brute force!
(1/8)^(1/8)=0.5Surd[32,8]=(Surd[32,8])/2 final answer
Let a=(1/8)^(1/8), so a^8=1/8=2^-3, so a=2^(-3/8)
What a foolish approach.
The simplest answer is 1 over 8 root 8th.
Watch the video and see how we got the answer! 🤯
That was a simple question but you did not simplefy but extended and extended,, Thanx
Thanks for your feedback! 💯🙏It's a Harvard admission problem, so it's meant to be challenging! 💪💪💪
Why is the new expression considered to be "simplified"? The original expression can easily be computed using a calculator. The 16+ minutes you spent simplifying was a waste of time. (1/8)^(1/8) can be written as 2^(-3/8) by inspection.
Question is simpler than answer! You made it different and more complicated!
not simplify , you are rationalizing it , simplify it that means 2^(-3/8)
I appreciate your feedback! I'm trying to show ways to rationalize expressions without calculators.
Sorry. It is not simplicity.
Почему бы просто не возвести в степень числитель и знаменатель? И получить единицу деленную на корень 8 степени из восьми, или 2 в степени -3/8.
I personally need this kind of help. I have a hard time not thinking about every step to make sure I understand every single aspect of the problem rather than solving it with a memorized set of rules. I still don't understand this, but I understood the rule set. I will have to look further into why some of the rules are what they are, though. It sucks to have to do it this way, but I cannot make myself turn off and turn out.
Thanks for sharing your perspective on problem-solving. It's great that you're determined to understand the underlying principles! 💯💕💪I hear you! It's definitely challenging to balance speed and understanding. Keep up the hard work! 💪💕🤩
@superacademy247 Oh, far out!
I didn't think anyone at the site would pay attention to this comment.
I watch your stuff everyday now.
I decided a few months ago I was going to polish up my math skills before I started looking for partnering with a university in Europe for a PhD program.
I realized very quickly that the memorized rules as an undergraduate were no longer with me.
The reason I don't remember them is the reason I try to gain the concepts that create the rules.
This also added a year onto my graduation time so those years ago so I stopped thinking, got a tutor, went twice a week, and memorized enough to get through calculous.
For me, Algebra was much harder at the introduction stages.
Once I knew the reasons to the rules I could speak the language.
For the life of me I can't believe I did it now.
It was the difference between one Bachelor or two so I figured, "why not?"
Regardless, I like your presentations.
I ignore the "subscribe" segment, because I already subscribed.
I understand you need people to recognize your work so that you can continue to do this.
If I can't get caught up, at least to pre-calc, by Spring I'll probably take your full course.
My old nemesis time continues to creep up on me though.
Thank you for your work!
Chadillac
Thanks you very much for your kind words. I'm humbled.🙏🙏🙏
1/8^(1/8) = 1/2^(3/8) = 2^(-3/8)
Rationalize the denominator
Hmm... How is the ending expression considered a simplification of the starting expression?
Is it simplification or complexification?May I ask.
Rationalization
@@superacademy247A long journey to reach just 1/ 8th root of 8.Anybody can reach there by two steps. Again a long tedious journey to reach the final answer . Answer is also not in simpler form. Please cut short the journey.
It is a good review of the rules of exponents. Not an easy way to solve, but a good review none the less!
Now if the instructions were solve this using all the known rules of exponents, then this is the way!
😂नौ दिन चला अढाई कोस ।
2^(-3/8) 10 -15 sec
These teachers should understand the language of Mathematics with proper understanding.
It’s a demonstration, an unnecessarily lengthy one. There isn’t much useful teaching going on.
Please solve the problem:
x^x+y^y=31
x^y+y^x=17
Have you ever considered changing career ?
(a^n)^(1/n) is not equal to a
exemple with n=2 and a=-5 sqrt(-5²)= 5 not -5
(a^n)^(1/n) = |a|
To evaluate the expression 1/8^1/8, we need to follow the order of operations (PEMDAS):
1. Exponentiate 8 to the power of 1/8: 8^1/8 = 8^(1/8)
2. Take the reciprocal of the result: 1 / 8^(1/8)
Using a calculator or solving algebraically:
8^(1/8) ≈ 1.297379
1 / 1.297379 ≈ 0.77037
So, 1/8^1/8 ≈ 0.77037.
Too short. I think you should use the definition of non-integer exponentiation, i.e. eˣ = Σₙ xⁿ/n! , along with the definition of natural logarithm, i.e. ln(x) = ∫₁ˣ 1/t dt, so that you can rigorously define (1/8)¹ᐟ⁸ and carefully simplify it.
You have complicated a very simple sum.
I appreciate your feedback! It's all about finding the most efficient approach for these types of problems.Thanks for your input! I strive to provide multiple perspectives and techniques to help with problem-solving.💯💕🙏
Some good Algebra Radical/Power demonstrated but student attention span would have been challenged...
(1/8)^(1/8)
= (8^-1)^1/8
=8^(-1/8)
=(2³)^(-1/8)
=2^(-3/8)
When you leave your solution with negative exponent then you've NOT rationalized the denominator. Thanks for sharing your perspective 🥂🔥✅
Это как раз тот случай когда из мухи делают слона...
It's a special case in which an elephant is relegated to rodent class
That took way too long then you can do this in two steps first eight is 2 to the 3rd power and then you apply the 8th route to both on top of the bottom and just multiply the exponents which would be 2 to the third power times one over two thirds
In problems like this, I would give the fast answer, then the long one.
The irony is (and I address the critics) that PROOFS are often much longer.
Good thank you ❤❤❤❤❤❤
You are most welcome! Glad you enjoyed the video! 😁💯💕😎🙏
2^(-3/8)
your method has some value in teaching laws of exponents and radicals .the answer could be (8)^-1/8 but i liked it it is .771105
Thanks 😊🤩🤩🤩
So when he did the m - k and the n - k with k = 2. Was that due to the base number being 2?
Appallingly longwinded and why leave it as (2^(5/8))/2 which is not simplified when you can reduce it to 2^(-3/8)?
The objective is to rationalize the denominator
The eighth root of 1 is 1 but also -1.
Wouldn’t it be 1/2^(3/8) or 2^(-3/8)? or 1/[8^(1/8)]
For repeating the same n times, the comment is "it gives rise to" .Unnecessary repetitions.
Waste of time. Waste of phone battery. Nobody use in daily life.
😂You make me feel like laugh. You're hilarious 😆
Simplification is very lengthy with repetition which would have been avoided .
I increased the play speed to 2x and it still seemed too slow. You could easily skip many of the steps, because if your viewers don't understand basic stuff they are never going to make it in any exam, let alone Cambridge or Harvard.
x^8=2^-3=>x=2^-3/8.ans
=(2^-3)^(1/8)=2^(-3/8)
You could solve this much easier and faster using exponents as verses roots.
I appreciate the suggestion! There are often multiple ways to approach a problem! 😎
ნერვებზე მომშლელია ასე დაწვრილებით წერა, პირველკლასელი ხომ არ უყურებს ?
Почему вы так долго решаете?Устно 2^-³/⁸,не хотите так,преобразуйте,как хотите,но не так долго.
It's long because it's a crash course for newbies
@@superacademy247or for idiots?
There are so many repetitions in the steps! Harvard applicants are supposed to be more intelligent than the host likes to project!
Una simplificación tan sencilla que se puede resolver en 2 minutos, este profesor tardó el tiempo que duraba Albert Einstein explicando la solución de cualquier problema relacionado con la astro-fisica. Un estudiante de educación básica hubiera cambiado este video a los 6 minutos. 😮😢
too much trouble for such a minor problem 8^(1/8) = 1/(8^(1/8)) and 1/(8^(1/8)) = 1/2^(3/8) and 1/2^(3/8) = 2^(-3/8)
r u really from harvard university......i don't belive.....
You've earned the two marks for that question, now have you got time for the rest of the exam?
I dont get that k equaling 2 why two ?
The 8th root of +1 can be */-1. But because you are using surds I will forgive you.
This is like walking around the refrigerator.
was this the lesson of how to make simple tasks complicated? .. must have missed that class in school
its 2^-3/8 OR 1/2^3/8
It's after midnight... I couldn't sleep... I watched this over and over repeating of numbers.... chrrrr chrrrr zzzzzz.....
Ans = 2^(-3/8)
Wrost method, poor understanding of this guy....he has complicated everything, lucky we can ignore him
I've rationalized the denominator completely
complicate meth od
(1/8) ^ (1/8)
= ^8√ (1/8)
= ^(2*2*2) √(1/8)
= √√√(1 / 8)
= 1 / (√√√8)
= 1 / ( 2^(1/4) * 2^(1/8) )
= 1 / ( 2^(3/8))
= 2^(-3/8)
янадзвичайно довге поясненя з багаторазовим повторенням того самого.
Este man da mucha vuelta
I solved this in my head before watching. It's easy when you see the tricks (I'm a math dummy, tricks are all I have).
One to any power is 1, so the problem is to simplify 1/8^(1/8).
Multiply numerator and denominator by 8^7/8 to get 8^(7/8) / 8. Subtract the exponents to get the answer, 8^(-1/8).
Note that 2^(5/8)/2 is the same as 2^(-3/8), which is the same as 8^(-1/8).
Nice scenic tour through lots of properties, though. I kind of like this sort of overcomplication.
That bit about subtracting k is a little overcomplicated in itself. Subtracting a constant from like-base numerator and denominator is just dividing each by base^k.
The answer I obtained has more rational denominator than yours in my opinion which is the primary objective of my step by step process. Your answer and mine are the same but the form matters.
@@superacademy247 The denominators in my answer, 8^(-1/8), are one in the base, 8 in the exponent. Your answers were pretty much the same, aren't they?
Just trying to learn, and I appreciate your channel. I often find simpler methods, but that makes for a nice learning experience.
Friend such problems can be solved with the help of logarithms if not using calculators.