Thank you very much you saved my life. I was going through some mesh analysts videos on TH-cam and I was confused why are they solving the second voltage source with negative sign and I was sure they were solving it wrong. Now you made everything clear to me. ❤
In agreement w/ the equations. And I like how you did that and that was helpful. However, it is not in agreement w/ four methods I checked in numerics for current. I have I1 = 3.2308, I2 = 3.5385. Confirmed Simulation LtSpice, Falstad simulator, algebraic systems of eq. by elimination confirmed by ChatGTP check, Reduced Row Echelon Format Matrix TI-84 Plus CE. What I do not understand is precisely how systems of eq. are related. I know to put the coefficients in there but not really how they are multiplied. Until I take Lin. Alg.
Are you saying that a circuit still flows, in both of 2 mesh circuits, even if the opposite polarity is stronger voltage? Both sources are connected together, not separate power sources.
Through any branch in a circuit, there is only one resulting current, but if there are two sources, that current is the result of the effects of each of the sources. e.g., if the effect of source one results in 2 amps and the effect of source two results in -1.5 amps, then the total current will be 0.5 amps.
The correct answers are 3.23A for I1 and 3.54A for I2. Because you want proof of these answers. 7*3.23 - 3*3.54 = 11.99V and -3*3.23 + 5*3.54 = 8.01V. Your answers give for the second equation -3*4.38 +5*6.23 = 18.01V. This should be 8V and not 18V. You filled in the wrong voltage for the second equation. You also use a rather strange form of Cramers rule for I2.
Thank you very much you saved my life. I was going through some mesh analysts videos on TH-cam and I was confused why are they solving the second voltage source with negative sign and I was sure they were solving it wrong. Now you made everything clear to me. ❤
So glad it was helpful!
In agreement w/ the equations. And I like how you did that and that was helpful. However, it is not in agreement w/ four methods I checked in numerics for current. I have I1 = 3.2308, I2 = 3.5385. Confirmed Simulation LtSpice, Falstad simulator, algebraic systems of eq. by elimination confirmed by ChatGTP check, Reduced Row Echelon Format Matrix TI-84 Plus CE. What I do not understand is precisely how systems of eq. are related. I know to put the coefficients in there but not really how they are multiplied. Until I take Lin. Alg.
I also got the same result. My guess is there was an error in his solving the system of equations. The video is still excellent nonetheless!
that's what I got also.
You are the man 👊
Are you saying that a circuit still flows, in both of 2 mesh circuits, even if the opposite polarity is stronger voltage? Both sources are connected together, not separate power sources.
Through any branch in a circuit, there is only one resulting current, but if there are two sources, that current is the result of the effects of each of the sources. e.g., if the effect of source one results in 2 amps and the effect of source two results in -1.5 amps, then the total current will be 0.5 amps.
I was thinking it should be -12+I14+I13-1I3
18 should be 8
i thought this was really good
Thanks!
The correct answers are 3.23A for I1 and 3.54A for I2.
Because you want proof of these answers. 7*3.23 - 3*3.54 = 11.99V and -3*3.23 + 5*3.54 = 8.01V. Your answers give for the second equation -3*4.38 +5*6.23 = 18.01V. This should be 8V and not 18V. You filled in the wrong voltage for the second equation. You also use a rather strange form of Cramers rule for I2.
Simulate that result.
you glossed over the most important part. was liking it until then
What's the most important part?