Free CCNA | Subnetting (Part 2) | Day 14 | CCNA 200-301 Complete Course
ฝัง
- เผยแพร่เมื่อ 11 มิ.ย. 2024
- Free CCNA 200-301 flashcards/Packet Tracer labs for the course: jitl.jp/ccna-files
📖 My CCNA Book: www.manning.com/books/acing-t...
📚Boson ExSim: jitl.jp/ccna-exsim ← the BEST practice exams for CCNA
💻Boson NetSim: jitl.jp/ccna-netsim ← 100+ detailed guided labs for CCNA
💯ExSim + NetSim: jitl.jp/ccna-kit ← get BOTH for a discount!
🥇CCNA Gold Bootcamp: www.flackbox.com/cisco-ccna-c... ← the course I used to get my CCNA (top rated course on the Internet)
Get the course ad-free with bonus quizzes and more on JITL Academy: courses.jeremysitlab.com
This video, day 14 of my free CCNA complete course, continues our look into subnetting. You will learn how to subnet larger networks (Class B).
In this FREE and COMPLETE CCNA 200-301 course you will find lecture videos covering all topics in Cisco official exam topics list, end-of-video quizzes to test your knowledge, flashcards to review, and practice labs to get hands-on experience.
SUPPORT MY CHANNEL
The best way to support my channel is to like, comment, subscribe, and share my videos to help spread the word!
If you can spare to leave a tip, here are some options:
PayPal: paypal.me/jeremysitlabYT
BAT (Basic Attention Token) tips in the Brave browser (www.jeremysitlab.com/brave-br...)
======================
Patreon: / jeremysitlab
======================
Cryptocurrency Addresses
Bitcoin: bc1qxjpza7nx46e8a2rtz6vkcrvxx9mfjnufdrk0jv
Ethereum: 0x08B4325b1B99B05d850A3bfCd4A6620D770cfB64
======================
0:00 Introduction
0:42 Things we'll cover
1:14 Day 13 Quiz Answer
5:20 Subnetting Trick
6:47 Subnetting Practice
10:48 Identify the subnet (network address)
12:49 Number of hosts per subnet (Class C)
14:17 Subnetting Class B Networks
18:09 What prefix length is appropriate?
19:48 Identify the subnet
20:59 Number of hosts per subnet (Class B)
22:00 Quiz 1 (Answers are in the next video)
22:21 Quiz 2
22:37 Quiz 3
22:53 Quiz 4
23:13 Quiz 5
#cisco #CCNA - วิทยาศาสตร์และเทคโนโลยี
ERRATA: At 3:45, the range of subnet 2 is 192.168.1.64 - 192.168.1.127
At 21:00, for a /21 prefix length the number of hosts should be 2046, NOT 2044.
Thanks!
Thanks for pointing it out to me!
@@JeremysITLab pin it please :]
@@LarrySoliman Oops, I thought I did. Thanks!
CANT SEEM TO FIGURE OUT THE BORROWED BIT THING. SO LOST
I passed my CCNA today, and i thank you jeremy for being the best resource to pass it, thank you for your efforts and gifting us with this amazing FREE content.
What did you do to prepare besides this course ? Im at day 14 and i'm hoping this course can get as close as i can to a CCNA, thanks !
I came here randomly searching subnetting explanations. Looked this video and the previous one through, and finally I decided to do the whole series from the beginning. The best thing a teacher can hope for is when students ask for more. Great work, Jeremy!
after watching these subnetting videos for the past week on repeat. im finally starting to understand. yay!
1./23 prefix length
2.172.21.96.0/20
3. 192.168.91.127/26
4. 172.16.64.0 - 172.16.127.255
5. 64 subnets, because of the 6 bits borrowed from the 3rd octate.
keep the good work up bro..thanks
in the 5th its all maths. because we have used prefix /23 before for 500 hosts,logicly, we need to take the step back, and have 500*2=1000. originally we have /16 on our big network, /22-/16=6. 2 in the power of 6 is 64.
@@antonymakesvideos4244 can u tell me how u got/23 when 500 hosts are asked in Q1?
500 hosts. So 2^H -2 >=500, where H is is number of host bits. So we need 9 host bits to have 500 addresses. So out of total 32 bits, we are using 9 hosts bits so remaining network bits will be 32-9 =23. Hence /23. This is how I calculated.
@@SkMariamFathima atleast 500 hosts
I'm so grateful for this opportunity to learn CCNA at my own pace and on my own time. Thank you for making this course available to everyone.
1) 255.255.254.0
2) 172.21.111.201/20 belongs to 172.21.96.0/20 subnet
3) 192.168.91.64 subnet and 192.168.91.127 broadcast
4) subnet is 172.16.64.0 and broadcast 172.16.127.255
5) 172.30.0.0/22 = 64 subnets
Thanks for your excellent videos.
I wanted to seriously thank you for this. This is by far the best introduction I've had to subnetting, especially understanding subnetting versus just solving problems. Thank you for being so practical in your approach.
Thanks Evan, glad to hear that :)
I'm the man who is going to be king of the network admins
Incredibly helpful course! I'm binge watching it (currently on a 14th video) and just wanted to say thank you very much! I'm not planning on taking CCNA exam, I just wanted to learn basics of Networking and your course helped me so SO SO much. Looking forward for your videos and other courses if you're planning them. Best networking teacher!
Thanks so much!
Did you pass?
@@muffinbutton1484 they're not planning to take the exam.
Aloha.......brah...iv been watching neils course and others....lets just say yours are by far, above and beyond anything thats out there ....im grateful for ur time and effort...MAHALO
You are a blessing, believe me when I say that subnetting by far is one of the toughest things to get a grasp on, at least for me. I have watched countless videos from different instructors and you have made it click for me. Truly appreciated all you do.
AGREED!!
Yes but once you get the hang of it it seems simple. Subnetting IPv6 networks is a blast! :)
You kick butt!!! Just found this series and so grateful that it's online. Thanks Jeremy!
I finally starting to get it. Holy moly. It took rewatching you and Neil Anderson multiple times and this time making better notes.
I love your way of deepening the topic understanding through practice problems,quizzes and the like. Thanks a lot!
Thanks J, this requires constant practice, helpful walkthroughs. Always like your guidelines
Thanks Glenn!
Finally, the long awaited video is in...
Thank you very much.
Thank you!
Such a great course! Thanks for putting this together! You're a very good teacher!
Thank you once again Jeremy.
All of us aspiring network engineers appreciate your work!!
Thanks for the series. Foe once, in all my years of training and working in IT, this was explained easily and now seems less daunting.
Thank you, I'm glad to hear that :)
After your videos. i feel i'm an expert in subnettings, you made it so easy to understand and resolve all solutions, thank you so much
This video really had me thinking and using my brain. Learning subnetting is difficult but I get better each time I study. Love that I can go back and watch videos. I found it helpful for me to add tags to the Anki cards corresponding with the video they came from. I have found that this process of tagging allows me to identify the concepts I am struggling. To identify the video I need to watch I browse the deck in Anki and sort by the reviews field. The more reviews there are the less I know that card and can re-watch the day associated with it. Has been incredibly helpful so far.
Thanks James :)
Hi James, thats is such a good idea, where / how do you add tags? My brain hurts after this too haha
Hi, the quiz is always helpful. My answers are
Q1. The prefix we should use is 23. 172.30.0.0/23 first subnet Network
address
Q2. The host 172.21.11.201/20 is belongs to subnet address: 172.21.96.0/20
Q3. The broadcast address of 192.168.91.78/26 is 192.168.91.127/26
Q4. The 2nd subnet address is: 172.16.64.0/18 & Broadcast
address is 172.16.127.255/18
Q5. We can able to make 64 subnets.
Q.5 answer should be 16 subnets
In Q3, how did you get 192.168.91.127/26?
Since prefix is /26, shouldn't we set all host bits after 26th bit to 1 to get the broadcast address?
For me, I got 192.168.91.63, please help
Thank you for another great video with clear, concise explanations!
I am not giving CCNA exam but I am loving these videos as You are explaining it with so much of dedication. Thank you sir
Thanks Bikash :)
Thank you for this content. I've learned a trick to finding which subnet a host address belongs to. For the example you used, I divide the subnet ID by the binary value 217/8=27.125 (we don't care about the decimal value, only the whole number). Then I multiply the whole number by the binary value 27*8=216. Then I replace the subnet ID from the problem with the new subnet ID to get the network range and its home subnetwork. Shout out to Keith Barker for the shortcut.
Nice idea. I am just wondering how did you arrive at the binary value of 8.
@@vaitheeshiyer 8 is the block size, or number of unique hosts (0 - 7)
does not work if .17 /27. We have 3 borrowed bits , where the last network bit is 32, so subnet ids go .0 .32 0.64 etc. .17 octate in binary is 0 0 0 1 0 0 0 1, change network bits (5 last bits in this case) to 0 and you get 0 in the whole octate. So .17 /27 belongs to .0 /27. BUT if you use your trick and 17/8=2.125 and then 2x8=16. We have subnet id increment of 32, so .16 /27 cannot be a subnet, because it is within the ip range of .0/27. Nor .16 /27 can be a subnet, because it does not add up in binary calculations.
Where did i mess up ? :P
Hi Jeremy,
I would like to thank you very much for your great lessons. I have learned so much from your lessons.
Thanks a million for giving them for free.
Thank you, I'm glad they're helpful!
your explanation is very clear brother.
Thank you so much for lovely clear lectures Subnetting (Part 1 & 2)
I already understood the basics of binary arithmetic as I have some programming background but this course is really improving my ability to quickly think in binary
man! what great and polished work you have done, thank you very much!!
Hi Jeremy. Thanks for the lesson.
1. /23
2. 172.21.96.0/20
3.192.168.91.127/26
4. using a /18 subnet 172.16.64.0 - 172.16.127.255
5. 64 subnets
the last question I've to take a glance at the last chart in your slide :DDDDD don't know if it's good
Perfect answers! 👍
@@JeremysITLab Hey Jeremy, On quiz 3, How is it .127 in the last octet. I get all the part till finding that 192.168.91.128 is the subnet.
@@bluesparrowlove6846 Late response, but for anyone who might be wondering:
Since each subnet has 64 addresses, including broadcast + network (2^6), the network address of the second subnet (192.168.91.64) counts as an address in the subnet, if that makes sense.
Another way to look at it is how .0 to .63 in subnet 1 is counted as 64 addresses because the network address, 192.168.91.0 is counted the first address.
Hopefully that makes sense! It took me quite a while to understand and I also got this question wrong initially.
Great job Jeremy, keep up the good work.
Day 14 was awesome! Thank you Jeremy!
This channel is getting a spot in my bookmarks… definitely
Thank You Jeremy, really Thank You... Respect to the other videos I saw, You are really the best!!!!!!!
Thanks, Pietro :)
most awaited course ,really really helpfull jeremy's sir, its very very interesting ,at present situation i can't donate you, but surely I will. so I humble request you to please complete this course , Its really helpfull for Us. your way of teaching very lucent also. great course| Thank You very much
Thank you for making these videos!
Jeremy, thank you for making this content.
It's getting hard to grasp! Thanks by the way:)
Hi Jeremy, Thanks for this simple way to find out the subnets and the host range. I was stuck in this video and looked elsewhere but came back later to your video and I understood it quite easily. You are excellent. Thanks. God bless. Hope all is fine in Japan.
Thanks Sanjay, all is fine here, I hope the same for you ;)
Thank for your an excellent presentation.
I love it.
You just made it so easy for me.. Thank you so much.
Thank you for watching!
Eres un buen instructor, buen trabajo Jeremy...!!!
That trick with the last bit borrowed from the host portion is pretty neat lol. Thank you for the great explanation!
Thanks for simplifying the class C network address, still trying to understand the calculations and to memorise all of the subnets and host numbers, very useful video I recommend everyone who is studing CCNA or Network+
Hello ! Thank you for the video!
Thanks for putting this very informative videos out. Is there more videos to come
Thank you so much for the video!
Thank you for these great lectures.
Thanks for watching :)
thank you for this explanation of subnetting. it was clear. for class b number of hosts, i still use 2^n-2; where n = 16 - number of borrowed bit/s
Very important,, good Background, excelent, Thanks a lot
Did anyone else get ring bells in their heads at 10:48 when you realized the trick you can use to get the subnet of the host address ? so easy and simple this men has been God Sent to teach us all !
nice very nice i watch a lot of subnetting and ur video is the best direct to the point u also included the point to point network.
Thank you, I'm glad you like it :)
Thank you for this course!
Thanks for watching :)
Great. THANKS! Very helpful!!!
They don't give us calculators on the exam so one thing I highly recommend memorizing is the values of adding powers of two. Memorize 128+64+32+16 and all combinations thereof. It's not hard to calculate but you cannot get stuck crunching binary on the CCNA when you barely have any time to spend on a question.
I like yours video ,great help from your videos.
Thx Jeremy for the video
LOL!!! I've been doing math this whole time to find the broadcast address and next subnet when i could have just watched this video for that subnetting trick! Thanks Jeremy
Thanks you just made subnetting easy for me
Thanks, glad to hear that :)
Yes, for part 3, I noticed that I had made a mistake. ;)
Thanks
Excellent videos help me a lot
Thanks jeremy brother
Ok, everything is clear..thank you so much!
Thank you :)
a life saver thank you a lot
Thank you for your help
Great job!
Using logarithms is a quick way to solve for the prefix length needed to achieve x amount of subnets.
For example, when you have a /16 network and you require 500 subnets you would do the following:
1. Take the Logarithm with base 2 of 500 which is 8.97.
2. Round up the answer which give you 9.
3. Add it to the original network length, which gives you 25 (16 + 9).
Interesting!
@@JeremysITLab Thanks! Also, thank you for the great content! Your series for CCNA is the most beginner-friendly I have found so far. You really have a natural ability to teach.
Thank you, sir. your video is really very helpful.
Thanks Jeremy
You are SOOO GOOOOOOD at what you do, Thank you for everything you're doing and then some!
Great Jeremy!!
Thanks Ibrahim!
Amazing tips.
That one trick is the best trick. It's all you need to subnet in your head.
Question 1) 172.30.0.0/23
Question 2) 172.21.96.0/20
Question 3) 192.168.91.127/26
Question 4) 172.16.64.0 - 172.16.127.255
Question 5) (/18) 64 subnets
Thanks for all you doing, it's amazing!
Thank you
The Goat!
You are always awesome ❤️
Thank you :)
Cannot really thank you enough for this great explanation. As said in french :" Chapeau a vous".
I'm following both yourself and Imran Rafei and he started subnetting at a very early stage - day 3. I was still uncomfortable with subnetting, especially class A and B even after watching 2 or 3 times.
At that time, i then tried following Astrit Krisniki who made things a little clearer.
But the way you resolve the problem, especially finding network id & broadcast id for any given network is really painless now. For it would be very cumbersome if we tried to addup the value to get to the next block address, especially with class B & A.👍
Thanks for your comment, I'm glad to hear it :)
Thank you!!!
Hi Jeremy! Love your work man! You're one of a kind! Keep up the good work!
Can you tell us roughly how many more videos need to be uploaded to complete this course please?
I think it will be a maximum of 50 days in total. I hope to increase the speed of making videos and finish the series by the end of this year, if possible.
Suggesting we change the variables in the formula to avoid confusion
2 ^ y
where y = borrowed network bits
borrowed from right to left
2 ^ x - 2
where x = borrowed hosts bits
borrowed from left to right
Another great video thanks!
Thanks, Will!
Great video
wow this is so fascinating, thank u
Thank you! :)
thanks for this amazing vidio
becoming a subnetting-ninja after this.
You are the best.
best subnetting explanation ever
Thank you, Saif!
Thank you so much, Jeremy. I want to become a network engineer too
hello jeremy and thanks for the course again . Is the MAC address needed outside of the LAN? ??
Thank you for the great video.
Thanks Khanh :)
I thank you very much,
Thank you so much sir for this valuble explain ❤❤ now I can understand this . Wish you all the best . Again Thankyou so much😍😍
great videos !!!!
good class ..loved it
Thank you :)
Dude you should make your own website where CCNA, CCNP and CCIE courses are available. Everyone will buy.
I'd love to! But first I have to make the CCNP and CCIE courses ;)
Thanks for the great content
I am going through all of your videos for CCNA
IT's a great video