Answer to the quiz : If we take /26 that means 2 bits into the last octet Meaning we can have 4 networks 192.168.1.(00******) 192.168.1.(01******) 192.168.1.(10******) 192.168.1.(11******) Converting to decimal 0/64/128/192 Thank you very much for this lessons
many students are lost in schools just because some teachers make it hard while explaining things in classrooms . thanks so much for making it easy for us. no exaggeration, you are the best.
This is making things soo much easier to understand. Thank you! I see a bunch of answers already but.. 192.168.1.0; 192.168.1.1 - 62; 192.168.1.63 */26 192.168.1.64; 192.168.1.65 - 126; 192.168.1.127 */26 192.168.1.128; 192.168.1.129 - 190; 192.168.1.191 */26 192.168.1.192; 192.168.1.193 - 254; 192.168.1.255 */26
I know I’m years late but why did it go from 62 to 126 I understand it’s usable addresses and the next step on binary but why does it do it to solve the next one?
I´m not a English native speaker but I´m preparing for TOEFL and CCNA 200-301 in this year, with your videos I kill 2 birds with 1 stone. Thank you so much !!!
Jeremy, thank you so much for this course! I passed my exam yesterday and I wouldn't of been able to do it without your help and boson! There is no course like this one! Other courses I have tried in the past do not compare to this one!
I came here randomly searching subnetting explanations. Looked this video and the next one through, and finally I decided to do the whole series from the beginning. The best thing a teacher can hope for is when students ask for more. Great work, Jeremy!
192.168.1.64/26 192.168.1.128/26 192.168.1.192/26 Thank you for your lectures! And congratulations on passing CCNA with a high score. I wish to do the same.
i am not exaggerating but you are the best teacher for networking on youtube. I dont think there is material better than this out there. Even on Udemy which is paid.
I did not watch part 2 yet but I'll just drop my own answers about the quiz based from the learnings I've garnered in your video: CIDR = /26 1. usable addresses = 62 (2^6 = 64 - 2) 2. network address of subnet 1 = 192.168.1.0 broadcast address of subnet 1 = 192.168.1.63 Subnet 1: 192.168.1.0 - 192.168.1.63 .1 (first usable); .62 (last usable) Subnet 2: 192.168.1.64 - 192.168.1.127 Subnet 3: 192.168.1.128 - 192.168.1.191 Subnet 4: 192.168.1.192 - 192.168.1.255
My teacher was an amazing person. He was very kind, well educated, and always stayed late to help students. But you Jeremy, are simply much, much better. This is simply an observation.
I was so lost when I first started this ccna journey, but with every day and every video everything makes so much more sense. Thank you so much for your videos!
This is surreal I'm not new to networking I've actually been self-studying for cybersec cert and now decided to take CCNA to solidify my understanding of networking and this is UNREAL. I have NEVER seen a better explanation on subnetting ever before. Thank you!
I'm omitting the "192.168.1" part for brevity's sake: - Subnet 1: .0/26 - Subnet 2: .64/26 - Subnet 3: .128/26 - Subnet 4: .192/26 I'm guessing it works like this because once the host portion of the address is maxed out it "overflows" into the network prefix, resetting all the host bits to 0 and thereby producing the identifying address of the proceeding subnetwork. This isn't intuitively reflected in the dotted decimal representation of the address because we're grouping by octets/bytes instead of sextets.
Im finally starting the subnetting. It took me longer than what i thought but in the meanwhile i got a new job. Im a server assembler technician and this course is giving me a chance to get an amazing carreer
This is the quiz solution: 1) 192.168.1.0/26, with broadcast address of: 192.168.1.63/26, 2) 192.168.1.64/26, with broadcast address of: 192.168.1.127/26, 3) 192.168.1.128/26, with broadcast address of: 192.168.1.191/26, 4) 192.168.1.192/26, with broadcast address of: 192.168.1.255/26 And thank you very much for your great content!
Jeremy you are just amazing! I´m not a native english speaker but your pronounciation is so great that even I understand every word clearly. I learned more with your videos yet than in 2 years school. Thanks for the free content. I really really appreciate it.
I'm lucky to have been one of the ones who picked up subnetting pretty easily when I was studying for CompTIA Network+, but I can definitely understand how it's a confusing topic for a lot of people. This video is an excellent resource for anyone struggling with it. Thanks for your videos, Jeremy!
I'm very lucky to get a total list of CCNA videos made by Jeremy. Waoo your explaining method is just another level.Anybody who doesn't speak English can just watch your PP (masterfully explained with examples) and understand everything. I had always difficulty to understand default route, Binary base2/base16 and everything that i'm learning day by day, i'm very thankful to you. Thank you sir again for an excellent explanation. I'm keeping learning and hoping to pass my CCNA exam in the next upcoming 2 months.
Here is the answer i got - 1st subnet: 192.168.1.0 - 192.168.1.63 2nd subnet: 192.168.1.64 - 192.168.1.127 3rd subnet: 192.168.1.128 - 192.168.1.191 4th subnet: 192.168.1.192 - 192.168.1.255 NB: the last IP addresses in each subnet represent their respective broadcast. Thanks Jeremy. Am really enjoying your classes
I Thought I am the only one that do enjoy this guy teaching... so humble to the point that he do explain everything from scratch like he is teaching a 3 years old child... English is so clear and ...... cant explain more... thanks boss
damn...this is just amazing..i am sooooo greatful for you Jeremy, and for this beautiful technology called the Internet...Vincent Cerf and Bob Khan for inventing TCP/IP, Larry Robets and his team for inventing packet switching, and sooooooo many other (BBN folks/ MIT etc) to Michael Faraday who first started harnessing electricity in 1831, and invented the first electric motor with salt water a magnet petrie dish a copper wire suspended in air..getting into I.T made me go ALL way down the rabbithole of how we have come this far..and thank you..here we are in 2022 and im leisurely soaking up this knowledge for FREE...Jeremy I am soo beyond grateful bro, im unemployed depressed, suffered alot in life as a youth, but as soon as i am employed I promise to pay you what u deserve for this man...God bless bro!!! thank u so much for this..u explain it the bestttttttttttttttttttttttttttttttttttttt
Every time I try to watch someone else's lectures I say "no way is this better". Jeremy's lectures have set such a high bar that I often assess them to his content standards. Of course they have never met them.
your the GOAT i watched someone else's explanation of this and couldn't understand it at all. so I said to myself let me go to Jeremy's video of it.. Now its easy for me THANKS!!!!
Here are my answers for the quiz question: 192.168.1.64 /26 192.168.1.128 /26 192.168.1.192 /26 Since the host part is 6 bits (2 to the power 6 equals 64), I used increments of 64 to get the next network address of the remaining subnets; i.e 0 + 64 = 64 64 + 64 = 128 128 + 64 = 192 Thanks :)
@@Reason_over_Dogma Yes that's true but you can also use the remaining 2 bits in the last octet which are the portion of the network Now and convert them from binary into decimal and would give you the same answer or 2n=4 Network or Subnets 00 000000 = 0 /26 0 I 000000 = 64 /26 I 0 000000 = 128 /26 I I 000000 = 192 /26
Took a while and some guidance but I got it! The range for subnet 1 is 192.168.1.0-192.168.1.63 Range for subnet 2 is 192.168.1.64-192.168.1.127 Range for subnet 3 is 192.168.1.128-192.168.1.191 Range for subnet 4 is 192.168.1.192-192.168.1.255
I've struggled with subnetting for so long. It's been one of the subjects I dread going back to and I usually give up half way through because it's so difficult for me to understand. I know this video is just scratching the surface.. but. Thank you for helping me break that cycle.
Mr. Jeremy i am overwhelmed after i heard some comments about the exam started yesterday, please provide us a video about what to really focus on before talking the exam, you are a great teacher and we passing the exam relays on god then you ..... god bless you
I haven't taken the new exam yet so I'm not sure what the most important topics are yet! Look up David Bombal on TH-cam, he took the exam and has some advice about it.
im js in the process of studying for the ccna, day 1 - 13 has been great with amazing explanations I greatly appreciate this course and will make sure the pass the exam by the end of this summer
Hi Jeremy, I just found and watched your Subnetting - Part 1 video. I could never really get a grip on Subnetting but after watching Part 1, I finally understand how it works and can calculate subnets. Thanks a ton and I going to watch Part 2 in just a few minutes. Keep up the good work!
Out of all of the videos I have watched Jeremy can teach a wall how to pass the CCNA. He makes it so easy and simple, this is the best Subnet video I have watched. Have to give credit to Jeremy for passing my CCNA. My only complaint is his book is not completed, if so please tell me and I will buy the other half of it, it is National Treasure. Thank you Jeremy for making, learning a complex skill so simple.
i have seen so many video i have worked with prefixs for long time but never could understand and solve them as simply as you have explained Sir! u r master in teaching and explaining if you thought of tourism to middle east consider Yemen, you have put all your knowledge for free and i well show you the hole country for free also ^_^ anytime you wish thank you from all of my heart greetings from Yemen
No corny analogies. I have done basic class c networking for lans before with no need to subnet but am now studying and learning networking for non ccna certification. After 5 or 6 videos this is the perfect video to tie it all together. Going to subscribe and look at that book!
For anyone reading this and maybe feeling overwhelmed, dont give up, just watch it again, take notes, watch it multiple times a day, while youre at a break, in the train etc. I am a total idiot in math and I was scared of binary and subnetting, but believe me if I could do it, you can too Watch those videos from jeremy, they are very good
I originally got my CCNA in 2010 and it expired. Now I find myself in a situation where I need to recertify and this course has been amazing thus far. Daunting task but thanks to your videos I have confidence I'll get there quickly. Thank you.
I have watched many tutorials on TH-cam rangning from programming frameworks to maths and I have to say, you are the best tutor I've ever come across. Thanks a ton for this course!
Thank you i have seen 10-12 video but your explanation has given the idea about how to break a large network into a small subnet and how to assign the addresses to the host serially. Really satisfied, i did not thought that this lecture will give me that idea what i actually looking for. after watching i understand that you know how to put the information from one brain to another empty brain with clear explanation and you have that capability. Thank You Jeremy.❤❤❤
This is the best subnetting video I've come across, hands down. You show the BEST way to break it down not only to use it, but to understand it completely.
I got to this point last Friday the 27th of May and was struggling badly. I was overthinking and doing short cuts. Even went to other videos to get some other pointers. Within the last few days with hours of practicing, I made huge progress and it's simply just writing out the binary numbers. I pretty much used your slides with the tricks as much as the other videos. I also used a lot of paper but for now, it's getting them done. I imagine that if I keep practicing for a few more weeks, my progress will look even greater.
Been doing networking and damn subnetting gave me a hard time, but now I m actually more confidebt taking exams and setting up networks. Big thanks to you Mister!!!
Hello Jeremy, my answers would be subnets#1 192.168.1.0/26 to 192.168.1.63/26 subnets#2 192.168.1.64/26 to 192.168.1.127/26 subnets#3 192.168.1.128/26 to 192.168.1.191/26 subnets#4 192.168.1.192/26 to 192.168.1.255/26 please correct me if I'm wrong :) thank you
Answer of Day-13 Quiz: Subnet 1 - 192.168.1.0 Subnet 2 - 192.168.1.64 Subnet 3 - 192.168.1.128 Subnet 4 - 192.168.1.192 Thank you so much for this amazing video! I really enjoyed Subnetting, that was so hard for me before watching this video. Your hard work and dedication to creating quality content are greatly appreciated. Keep up the fantastic work!
I have done two courses First ITproTV: sucks big time Second: Udemy by Neil: much better than the first one Now this one: by far the best one, so thorough and easy to understand! Wow you are great Jeremy
An easy way to calculate your host bits is (32-x)=host bits. with x = your cidr mask. for example; /25 is 32-25=7 then 2^7=128, 128-2 = 126 usable addresses. This avoids having to write out binary on paper and makes it so you can do it in your head if you memorize the powers of 2.
This is absolutely so easy for you but now I feel smart just for following what you were saying in the video, there are no words to describe how much I respect you, you are unique 🙏
hey i jusy wanted to drop in and say thank you! Because of your sims i was able to really prepare for the icnd2 200-105 and passed the day before the cert apocalypse!
Wow. When I heard about subnetting I thought that its something difficult, but by your video this is much easier to understand than even the routing video.
When it came to networking I loved everything else except for subnetting and that's because for some reason I struggled with it more compared to the rest of the content. Yourself and David Bombal made me understand them better than I ever have. I can confidently subnet networks now and understand WHY I am using that specific address block/CIDR Notation. Thank you.
i am programmer once we had a good teacher on TH-cam named Bucky he was sharing with us free tutorials we all liked him his way of explaining the concepts were better than those in payed videos and also those who teach in the university we suddenly lost his posts we heard that he was payed by big tutorials websites like udemy to stop the free tutorials . i hope u will not stop these stuffs if u hired in companies like these
Subnetting was this easy the whole time?? I read two different CCNA text books and had no idea what the hell I was looking at in the subnetting sections, but this video makes it so simple
Hi Jeremy, First of all thanks for the wonderful videos. The answer of Quiz: Subnet1: 192.168.1.0/26 Subnet2: 192.168.1.64/26 Subnet3: 192.168.1.128/26 Subnet4: 192.168.1.192/26
At 8:30, what does it mean by network address? What is 203.0.113.0 used for? I understand the broadcast address and two additional addresses for the routers but I do not understand the first one.
I wanted to inquire about why we change the borrowed bits to create different subnets within a network while keeping the original bits associated with the network portion the same, regardless of the subnet. What prevents me from modifying any other bits of the network portion, excluding the borrowed bits? I understand that logically, it makes sense to maintain the network portion the same, indicating that the subnet is originally part of this network, or, in other words, we are creating "subnets" of the original network. Also, determining the number of borrowed bits is not a clear-cut process. It makes sense when you start off with a network based on classful addressing (i.e., A, B, and C), because the prefix lengths are predefined. So, when you start subnetting the network, finding the number of borrowed bits is easy - essentially subtracting the original prefix length from the new prefix length. However, what if you start off with an arbitrary network not defined using classful addressing? Let's assume a network address of 172.64.0.0, which is a valid network address for both a /16 and a /24 prefix (I believe), although their broadcast addresses are different. If I give a prefix length of /25, then in the /16 case, there will be 9 borrowed bits, and in the /24 case, we'll have 1 borrowed bit. I wouldn't know this unless these prefix lengths were specified beforehand. So, you can see the dilemma I'm facing, albeit it could always be the case that I haven't understood the underlying concepts properly. 😂 I hope someone can clear my doubts on this topic. Oh, and by the way Jeremy, your course is seriously a godsend for all CCNA aspirants.
Let's use the CIDR = /26 Subnet hopping is 64 First Subnet: 192.168.1.0 - 192.168.1.63 (1-62) Second Subnet: 192.168.1.64 - 192.168.1.127 (65-126) Third Subnet: 192.168.1.128 - 192.168.1.191 (129-190) Fourth Subnet: 192.168.1.192 - 192.168.1.255 (193-254) Thank you very much for the content
Hey jeremy please help me finding why you put at time 17:35 you wrote The remaining addres in the 203.0.113.0/24 address block (203.0.113.4 - 203.0.113.255) are now available to be used in other subnets! why not (203.0.113.3 - 203.0.113.255) are now available to be used in other subnets! Please help and explain why not elaborate!!!
@@JeremysITLab I think it should be 203.0.113.4 - 203.0.113.252 . We only have 5 bit at last octet . If we turn all to 1s we would reach 252 not 255. Thans for your excellent videos though. I have learnt a tons. Keep up the goood work.
Just passed my CCNA yesterday thanks to you! I only used this course and Boson NETSIM. Thanks for this Jeremy, this course was amazing. I’ll be making a donation. I’ll be looking forward to the CCNP course.
Thanks Jeremy another great video lesson. Please keep it up! I was about to post the answer but then others comments spoil me, and figure it out my answer was wrong :D But no warries I am not afraid to expose my ignorance, I have to learn and get better.
I'm a noob to all this. I'm taking a network essentials class which brought me to this video. One problem I am trying to answer is how many broadcast domains does a network diagram show. And I thought I knew until I got to around the 19:52 mark in the video and you take away the broadcast address from between the two routers. I have tried to research whether a connection between two routers creates a broadcast domain. The diagram shows the main router with multiple connections, two of which go to two routers. There are no devices between the routers. Any help from anyone would be appreciated.
ERRATA: At 18:27, '203.0.113.0/30' under the diagram should be '203.0.113.0/31'. I copied the slide and forgot to change that network address!
I noticed that mistake. no problem
Watching this right now, also noticed thank you for confirming. also Thank you for the great content helps me a lot.
S
Yeah, we noticed. You taught us well :D
I paused to come and check the comments :P
Subnetting was one of my weakest subjects for years. Now it is one of my strongest. I passed the CCNA yesterday and I am grateful.
was the exam hard?
Message to all learners, please be patient and just be thankful to the great teacher!
Thank you for this comment :)
Answer to the quiz :
If we take /26 that means 2 bits into the last octet
Meaning we can have 4 networks
192.168.1.(00******)
192.168.1.(01******)
192.168.1.(10******)
192.168.1.(11******)
Converting to decimal 0/64/128/192
Thank you very much for this lessons
many students are lost in schools just because some teachers make it hard while explaining things in classrooms .
thanks so much for making it easy for us. no exaggeration, you are the best.
Thank you, so glad to hear you like the videos!
The best thing you can learn in life is the art of finding THE good teacher for each subject. Jeremy for sure is mine for Cisco stuff
This is making things soo much easier to understand. Thank you!
I see a bunch of answers already but..
192.168.1.0; 192.168.1.1 - 62; 192.168.1.63 */26
192.168.1.64; 192.168.1.65 - 126; 192.168.1.127 */26
192.168.1.128; 192.168.1.129 - 190; 192.168.1.191 */26
192.168.1.192; 192.168.1.193 - 254; 192.168.1.255 */26
Perfect answer, well done!
This was helpful, Thanks!
nice man👌
I know I’m years late but why did it go from 62 to 126 I understand it’s usable addresses and the next step on binary but why does it do it to solve the next one?
Never mind I get it
I´m not a English native speaker but I´m preparing for TOEFL and CCNA 200-301 in this year, with your videos I kill 2 birds with 1 stone. Thank you so much !!!
how's the studying going!
Did you pass the exam?
Haha😂
Jeremy, thank you so much for this course! I passed my exam yesterday and I wouldn't of been able to do it without your help and boson! There is no course like this one! Other courses I have tried in the past do not compare to this one!
congs, how long did you take to study the course?
@@mudanchuck I studied it for about 3 months
thanks let me put in the effort too
I came here randomly searching subnetting explanations. Looked this video and the next one through, and finally I decided to do the whole series from the beginning. The best thing a teacher can hope for is when students ask for more. Great work, Jeremy!
192.168.1.64/26
192.168.1.128/26
192.168.1.192/26
Thank you for your lectures! And congratulations on passing CCNA with a high score. I wish to do the same.
Perfect answers! Good luck on your CCNA ;)
i am not exaggerating but you are the best teacher for networking on youtube. I dont think there is material better than this out there. Even on Udemy which is paid.
I did not watch part 2 yet but I'll just drop my own answers about the quiz based from the learnings I've garnered in your video:
CIDR = /26
1. usable addresses = 62 (2^6 = 64 - 2)
2. network address of subnet 1 = 192.168.1.0
broadcast address of subnet 1 = 192.168.1.63
Subnet 1: 192.168.1.0 - 192.168.1.63
.1 (first usable); .62 (last usable)
Subnet 2: 192.168.1.64 - 192.168.1.127
Subnet 3: 192.168.1.128 - 192.168.1.191
Subnet 4: 192.168.1.192 - 192.168.1.255
awesome
right
do subnet 2 - 4 also have their first and last IP address reserved for network and broadcast address?
@@chrographyyes off course
Yes ofcourse like subnet 2 192.168.1.64 first IP & .127 broadcast. similar to Subnets 3 & 4@@chrography
My teacher was an amazing person. He was very kind, well educated, and always stayed late to help students. But you Jeremy, are simply much, much better. This is simply an observation.
I was so lost when I first started this ccna journey, but with every day and every video everything makes so much more sense. Thank you so much for your videos!
This is surreal I'm not new to networking I've actually been self-studying for cybersec cert and now decided to take CCNA to solidify my understanding of networking and this is UNREAL. I have NEVER seen a better explanation on subnetting ever before. Thank you!
I'm omitting the "192.168.1" part for brevity's sake:
- Subnet 1: .0/26
- Subnet 2: .64/26
- Subnet 3: .128/26
- Subnet 4: .192/26
I'm guessing it works like this because once the host portion of the address is maxed out it "overflows" into the network prefix, resetting all the host bits to 0 and thereby producing the identifying address of the proceeding subnetwork. This isn't intuitively reflected in the dotted decimal representation of the address because we're grouping by octets/bytes instead of sextets.
Im finally starting the subnetting. It took me longer than what i thought but in the meanwhile i got a new job. Im a server assembler technician and this course is giving me a chance to get an amazing carreer
This is the quiz solution:
1) 192.168.1.0/26, with broadcast address of: 192.168.1.63/26,
2) 192.168.1.64/26, with broadcast address of: 192.168.1.127/26,
3) 192.168.1.128/26, with broadcast address of: 192.168.1.191/26,
4) 192.168.1.192/26, with broadcast address of: 192.168.1.255/26
And thank you very much for your great content!
This is amazing never had I ever understood the concept so clearly. Thank you so much for providing such an amazing course.
Great, I'm glad to hear that :)
Jeremy you are just amazing! I´m not a native english speaker but your pronounciation is so great that even I understand every word clearly. I learned more with your videos yet than in 2 years school. Thanks for the free content. I really really appreciate it.
subnet2 : 192.168.1.64/26
subnet3: 192.168.1.128/26
subnet4: 192.168.1.192/26
thanks for hard working you are doing.
I'm lucky to have been one of the ones who picked up subnetting pretty easily when I was studying for CompTIA Network+, but I can definitely understand how it's a confusing topic for a lot of people. This video is an excellent resource for anyone struggling with it. Thanks for your videos, Jeremy!
Thanks Jeremy this subnetting video helped a lot
Thanks so much for the tip! Sorry for the late reply, I just noticed this comment now. I appreciate your support :)
I'm very lucky to get a total list of CCNA videos made by Jeremy. Waoo your explaining method is just another level.Anybody who doesn't speak English can just watch your PP (masterfully explained with examples) and understand everything. I had always difficulty to understand default route, Binary base2/base16 and everything that i'm learning day by day, i'm very thankful to you. Thank you sir again for an excellent explanation. I'm keeping learning and hoping to pass my CCNA exam in the next upcoming 2 months.
Here is the answer i got -
1st subnet: 192.168.1.0 - 192.168.1.63
2nd subnet: 192.168.1.64 - 192.168.1.127
3rd subnet: 192.168.1.128 - 192.168.1.191
4th subnet: 192.168.1.192 - 192.168.1.255
NB: the last IP addresses in each subnet represent their respective broadcast.
Thanks Jeremy. Am really enjoying your classes
I Thought I am the only one that do enjoy this guy teaching... so humble to the point that he do explain everything from scratch like he is teaching a 3 years old child... English is so clear and ...... cant explain more... thanks boss
damn...this is just amazing..i am sooooo greatful for you Jeremy, and for this beautiful technology called the Internet...Vincent Cerf and Bob Khan for inventing TCP/IP, Larry Robets and his team for inventing packet switching, and sooooooo many other (BBN folks/ MIT etc) to Michael Faraday who first started harnessing electricity in 1831, and invented the first electric motor with salt water a magnet petrie dish a copper wire suspended in air..getting into I.T made me go ALL way down the rabbithole of how we have come this far..and thank you..here we are in 2022 and im leisurely soaking up this knowledge for FREE...Jeremy I am soo beyond grateful bro, im unemployed depressed, suffered alot in life as a youth, but as soon as i am employed I promise to pay you what u deserve for this man...God bless bro!!! thank u so much for this..u explain it the bestttttttttttttttttttttttttttttttttttttt
Every time I try to watch someone else's lectures I say "no way is this better". Jeremy's lectures have set such a high bar that I often assess them to his content standards. Of course they have never met them.
Thanks Iman :)
your the GOAT i watched someone else's explanation of this and couldn't understand it at all. so I said to myself let me go to Jeremy's video of it.. Now its easy for me THANKS!!!!
Here are my answers for the quiz question:
192.168.1.64 /26
192.168.1.128 /26
192.168.1.192 /26
Since the host part is 6 bits (2 to the power 6 equals 64), I used increments of 64 to get the next network address of the remaining subnets; i.e
0 + 64 = 64
64 + 64 = 128
128 + 64 = 192
Thanks :)
Perfect!
Thank you for explaining your answer. I had a hard time figuring this out.
@@Reason_over_Dogma Yes that's true but you can also use the remaining 2 bits in the last octet which are the portion of the network Now and convert them from binary into decimal and would give you the same answer or 2n=4 Network or Subnets
00 000000 = 0 /26
0 I 000000 = 64 /26
I 0 000000 = 128 /26
I I 000000 = 192 /26
@@pucka_ak47 thanks for the tip. I ended up passing the CCNA last year. I figured it out thankfully. Wasnt easy for me
@@Reason_over_Dogma congrats... it's not easy for anyone i think...
Took a while and some guidance but I got it!
The range for subnet 1 is 192.168.1.0-192.168.1.63
Range for subnet 2 is 192.168.1.64-192.168.1.127
Range for subnet 3 is 192.168.1.128-192.168.1.191
Range for subnet 4 is 192.168.1.192-192.168.1.255
Usable addresses:
Sub1. 192.168.1.0/26: 192.168.1.1 => 192.168.1.62
Sub2. 192.168.1.64/26: 192.168.1.64 => 192.168.1.126
Sub3. 192.168.1.128/26: 192.168.1.129 => 192.168.1.190
Sub4. 192.168.1.192/26: 192.168.1.193 => 192.168.1.254
Thank you so much Jeremy.
I've struggled with subnetting for so long. It's been one of the subjects I dread going back to and I usually give up half way through because it's so difficult for me to understand. I know this video is just scratching the surface.. but. Thank you for helping me break that cycle.
I hope it helps!
Mr. Jeremy i am overwhelmed after i heard some comments about the exam started yesterday, please provide us a video about what to really focus on before talking the exam, you are a great teacher and we passing the exam relays on god then you ..... god bless you
I haven't taken the new exam yet so I'm not sure what the most important topics are yet! Look up David Bombal on TH-cam, he took the exam and has some advice about it.
im js in the process of studying for the ccna, day 1 - 13 has been great with amazing explanations I greatly appreciate this course and will make sure the pass the exam by the end of this summer
Hi Jeremy,
I just found and watched your Subnetting - Part 1 video.
I could never really get a grip on Subnetting but after watching Part 1, I finally understand how it works and can calculate subnets.
Thanks a ton and I going to watch Part 2 in just a few minutes.
Keep up the good work!
Out of all of the videos I have watched Jeremy can teach a wall how to pass the CCNA. He makes it so easy and simple, this is the best Subnet video I have watched. Have to give credit to Jeremy for passing my CCNA. My only complaint is his book is not completed, if so please tell me and I will buy the other half of it, it is National Treasure. Thank you Jeremy for making, learning a complex skill so simple.
Thanks!
Thanks for the tip! :)
i have seen so many video i have worked with prefixs for long time but never could understand and solve them as simply as you have explained Sir! u r master in teaching and explaining
if you thought of tourism to middle east consider Yemen, you have put all your knowledge for free and i well show you the hole country for free also ^_^ anytime you wish
thank you from all of my heart
greetings from Yemen
No corny analogies. I have done basic class c networking for lans before with no need to subnet but am now studying and learning networking for non ccna certification. After 5 or 6 videos this is the perfect video to tie it all together. Going to subscribe and look at that book!
Very clear and direct explanation on why we need to use subnetting to avoid wasting IP addresses.
Thanks, glad to hear it :)
For anyone reading this and maybe feeling overwhelmed, dont give up, just watch it again, take notes, watch it multiple times a day, while youre at a break, in the train etc. I am a total idiot in math and I was scared of binary and subnetting, but believe me if I could do it, you can too
Watch those videos from jeremy, they are very good
I originally got my CCNA in 2010 and it expired. Now I find myself in a situation where I need to recertify and this course has been amazing thus far. Daunting task but thanks to your videos I have confidence I'll get there quickly. Thank you.
how did it go?
@@NoName-ui5ou I passed last September!
@@scroofio congrats!
I have watched many tutorials on TH-cam rangning from programming frameworks to maths and I have to say, you are the best tutor I've ever come across. Thanks a ton for this course!
subnet 2: 192.168.1.64/26
subnet 3: 192.168.1.128/26
subnet 4: 192.168.1.192/26
Perfect!
Thank you i have seen 10-12 video but your explanation has given the idea about how to break a large network into a small subnet and how to assign the addresses to the host serially. Really satisfied, i did not thought that this lecture will give me that idea what i actually looking for. after watching i understand that you know how to put the information from one brain to another empty brain with clear explanation and you have that capability. Thank You Jeremy.❤❤❤
I love the series so far. I am on day 13 and am looking forward to completing this course. Commenting this on every video for the algorithm.
This is the best subnetting video I've come across, hands down. You show the BEST way to break it down not only to use it, but to understand it completely.
Your explanation is so clear and simple to understand.This online course is the best till now.Thank you!
Thank you so much!
I got to this point last Friday the 27th of May and was struggling badly. I was overthinking and doing short cuts. Even went to other videos to get some other pointers. Within the last few days with hours of practicing, I made huge progress and it's simply just writing out the binary numbers. I pretty much used your slides with the tricks as much as the other videos. I also used a lot of paper but for now, it's getting them done. I imagine that if I keep practicing for a few more weeks, my progress will look even greater.
Been doing networking and damn subnetting gave me a hard time, but now I m actually more confidebt taking exams and setting up networks. Big thanks to you Mister!!!
Thanks! Best of luck on the exam ;)
Hello Jeremy,
my answers would be
subnets#1 192.168.1.0/26 to 192.168.1.63/26
subnets#2 192.168.1.64/26 to 192.168.1.127/26
subnets#3 192.168.1.128/26 to 192.168.1.191/26
subnets#4 192.168.1.192/26 to 192.168.1.255/26
please correct me if I'm wrong :)
thank you
Answer of Day-13 Quiz:
Subnet 1 - 192.168.1.0
Subnet 2 - 192.168.1.64
Subnet 3 - 192.168.1.128
Subnet 4 - 192.168.1.192
Thank you so much for this amazing video! I really enjoyed Subnetting, that was so hard for me before watching this video. Your hard work and dedication to creating quality content are greatly appreciated. Keep up the fantastic work!
I have done two courses
First ITproTV: sucks big time
Second: Udemy by Neil: much better than the first one
Now this one: by far the best one, so thorough and easy to understand!
Wow you are great Jeremy
create four subnets from 192.168.1 /24
1=192.168.1.0 /26
2=192.168.1.64 /26
3=192.168.1.128 /26
4=192.168.1.192 /26
2^6-2=62 usable address
i dont understand , why not just use /24 ?
An easy way to calculate your host bits is (32-x)=host bits. with x = your cidr mask. for example; /25 is 32-25=7 then 2^7=128, 128-2 = 126 usable addresses. This avoids having to write out binary on paper and makes it so you can do it in your head if you memorize the powers of 2.
This is absolutely so easy for you but now I feel smart just for following what you were saying in the video, there are no words to describe how much I respect you, you are unique 🙏
Thank you! It wasn't easy when I first studied it ;)
hey i jusy wanted to drop in and say thank you! Because of your sims i was able to really prepare for the icnd2 200-105 and passed the day before the cert apocalypse!
Awesome! Congratulations on making it in time!
You are a legend, Jeremy. Thank you for everything you've done with the CCNA videos (and other certification classes).
This is the best subnetting video I have ever watched & I have watched a lot. Neil explains it well too but you do it best.
Subnet 2: 192.168.1.1
Subnet 3: 192.168.1.2
Subnet 4: 192.168.1.3
Thank you for your lessons!
So this is why in one task we had these kinds of IPs. I've been enlightened.
Thank you for the amazing course.
Each subnet = 64 IP Addresses (including network and broadcast) with notation of '/26'.
Subnet 1: 192.168.1.0 - 192.168.1.63
Subnet 2: 192.168.1.64 - 192.168.1.127
Subnet 3: 192.168.1.128 - 192.168.1.191
Subnet 4: 192.168.1.192 - 192.168.1.255
Wow. When I heard about subnetting I thought that its something difficult, but by your video this is much easier to understand than even the routing video.
When it came to networking I loved everything else except for subnetting and that's because for some reason I struggled with it more compared to the rest of the content. Yourself and David Bombal made me understand them better than I ever have. I can confidently subnet networks now and understand WHY I am using that specific address block/CIDR Notation. Thank you.
Thank you, glad to hear that :)
Ummm, actually it's an 8p8c connector, sweaty 😘
@@garrylarry4865 Ayo what the heck? 🤨
i am programmer once we had a good teacher on TH-cam named Bucky he was sharing with us free tutorials we all liked him his way of explaining the concepts were better than those in payed videos and also those who teach in the university we suddenly lost his posts we heard that he was payed by big tutorials websites like udemy to stop the free tutorials . i hope u will not stop these stuffs if u hired in companies like these
I work as a network engineer, and I'm happy making these videos for free in my spare time. Don't worry, I don't plan to stop!
Yeahhh!!!, Bucky from the newboston :) This guy is just excellent and easy to understand ;)
@@JeremysITLab Thanks for saying this.
Thanks dear teacher
Subnetting was this easy the whole time?? I read two different CCNA text books and had no idea what the hell I was looking at in the subnetting sections, but this video makes it so simple
Thanks @JeremysITLab, I was able to figure out the answer with your hint. I understand how you teach.
this is the first time i know we can use /31 for point to point connection, thanks Jeremy
Yep, most modern network devices should be able to support /31!
You explain everything so effortlessly Jeremy. Thanks!!!!!!!!
Hi Jeremy, First of all thanks for the wonderful videos.
The answer of Quiz:
Subnet1:
192.168.1.0/26
Subnet2:
192.168.1.64/26
Subnet3:
192.168.1.128/26
Subnet4:
192.168.1.192/26
At 8:30, what does it mean by network address? What is 203.0.113.0 used for? I understand the broadcast address and two additional addresses for the routers but I do not understand the first one.
The best tutor for CCNA 200 - 301
Thanks Ibrahim!
Glad to finally be back on track with this training. Horrible 2 weeks were I couldn't dedicate time to study and learn and I feel I forgot everything
Take your time to catch up, no rush!
you are the men..Incredible this was driving me crazy now a lot clear..thank you.
Thanks for your comment, glad to help!
Thanks Jeremy for all the effort you put into these videos. You are amazing!
Thank you Joyce!
Still here. This was also easier to understand than my book was. Not sure how you do it, but you're very good at explaining things.
Thanks John, glad to hear it :)
I use this subnetting table to calculate network ID, host ID range, usable hosts and broadcast ID:
Network ID Subnet Mask Host ID Range Usable Host ID’s Broadcast ID
192.168.1.0 /26 192.168.1.1 - 192.168.1.62 62 192.168.1.63
192.168.1.64 /26 192.168.1.65 - 192.168.1.126 62 192.168.1.127
192.168.1.128 /26 192.168.1.129 - 192.168.1.190 62 192.168.1.191
192.168.1.192 /26 192.168.1.193 - 192.168.1.254 62 192.168.1.255
Subnetting explained step by step precisely, thank you very much 👏
solved*
And thank you so much for doing this series, I will definitely donate to you when I pass.
I wanted to inquire about why we change the borrowed bits to create different subnets within a network while keeping the original bits associated with the network portion the same, regardless of the subnet. What prevents me from modifying any other bits of the network portion, excluding the borrowed bits? I understand that logically, it makes sense to maintain the network portion the same, indicating that the subnet is originally part of this network, or, in other words, we are creating "subnets" of the original network.
Also, determining the number of borrowed bits is not a clear-cut process. It makes sense when you start off with a network based on classful addressing (i.e., A, B, and C), because the prefix lengths are predefined. So, when you start subnetting the network, finding the number of borrowed bits is easy - essentially subtracting the original prefix length from the new prefix length. However, what if you start off with an arbitrary network not defined using classful addressing?
Let's assume a network address of 172.64.0.0, which is a valid network address for both a /16 and a /24 prefix (I believe), although their broadcast addresses are different. If I give a prefix length of /25, then in the /16 case, there will be 9 borrowed bits, and in the /24 case, we'll have 1 borrowed bit. I wouldn't know this unless these prefix lengths were specified beforehand. So, you can see the dilemma I'm facing, albeit it could always be the case that I haven't understood the underlying concepts properly. 😂
I hope someone can clear my doubts on this topic.
Oh, and by the way Jeremy, your course is seriously a godsend for all CCNA aspirants.
Let's use the CIDR = /26
Subnet hopping is 64
First Subnet: 192.168.1.0 - 192.168.1.63
(1-62)
Second Subnet: 192.168.1.64 - 192.168.1.127
(65-126)
Third Subnet: 192.168.1.128 - 192.168.1.191
(129-190)
Fourth Subnet: 192.168.1.192 - 192.168.1.255
(193-254)
Thank you very much for the content
This is brilliant, wish I had started a year ago. Thank you very much J, keep up the good work.
Thank you :)
Hi! Your course arrived in Brazil! Congrats on the excellent content and didactics. Looking forward to the CCNP course! Hug
verdde
very glad to have acheived my comptia trifecta before tackling ccna... dont think i could do it without
It's the first time I heard that the /31 prefix can be used. For point-to-point networks companies and ISPs still use the /30
Greatful to get these CCNA videos as I begin studying for CCNA
دمت گرم ... بد گیر کرده بودم توش :)))💛💛
Hey jeremy please help me finding why you put at time 17:35
you wrote The remaining addres in the 203.0.113.0/24 address block (203.0.113.4 - 203.0.113.255) are now available to be used in other subnets!
why not (203.0.113.3 - 203.0.113.255) are now available to be used in other subnets!
Please help and explain why not elaborate!!!
Because we used the 203.0.113.0/30 subnet, which includes 203.0.113.0 to 203.0.113.3. Therefore 203.0.113.4 - 203.0.113.255 remain.
@@JeremysITLab I think it should be 203.0.113.4 - 203.0.113.252 . We only have 5 bit at last octet . If we turn all to 1s we would reach 252 not 255. Thans for your excellent videos though. I have learnt a tons. Keep up the goood work.
Thank you so much for providing free CCNA courses. Power!!!
Just passed my CCNA yesterday thanks to you! I only used this course and Boson NETSIM. Thanks for this Jeremy, this course was amazing. I’ll be making a donation. I’ll be looking forward to the CCNP course.
I just started the CCNA course too using Jeremy's videos. Please is the Boson Netsim free?
Literally, your tutoring is fascinating and understandable and i love following you through all of your videos.
Thank you :)
Thanks Jeremy another great video lesson. Please keep it up! I was about to post the answer but then others comments spoil me, and figure it out my answer was wrong :D But no warries I am not afraid to expose my ignorance, I have to learn and get better.
I like your attitude! Keep up the good work ;)
Hi all. Sorry Jeremy at min 23:22 you say 45 host ip + 2 (network and broadcat)=47, but do not mis 1 ip for interface of router (for each ntw)?
Actually, the router is a host too. A host is any device with an IP address!
I'm a noob to all this. I'm taking a network essentials class which brought me to this video. One problem I am trying to answer is how many broadcast domains does a network diagram show. And I thought I knew until I got to around the 19:52 mark in the video and you take away the broadcast address from between the two routers. I have tried to research whether a connection between two routers creates a broadcast domain. The diagram shows the main router with multiple connections, two of which go to two routers. There are no devices between the routers. Any help from anyone would be appreciated.
Your main gold for these videos, is succeed. I fully understand subnetting thank you
hey jeremy, its an easy way to learn subneting. thank you
You can sometimes use the network address, there is work ongoing to enable and standardize it's use.
Man, you are helping these concepts to be easy to learn for beginners like me! Thank you thank you!
Glad to hear that, thanks :)
Thank you for every video you made to help us understand the CCNA course