You're using [H3O+] and [Cl-] etc., in other words, the concentrations of these molecules. As it turns out, HCl is a strong acid, so you get very little HCl and very much H3O+ and Cl-, which means large values divided by a small value, which equals a large total value (10^7). You can't check the calculation because the values for the concentrations weren't given here, Jay just told you that it comes down to 10^7.
Okay, No one has answered my real question- Around 3:15 you "used your Ka expression to get 10^7. How in the hell did you get that? I'll double check my calculator to see if there's a button to divide H30+ and Cl- by HCl...........yep, not seeing it. Am I just stupid? how do you get that value?
robbie magnuson They are just numbers that are already discovered. For any given problem, the concentrations will either be given to you or will be findable, by giving you the pH. In that case you would just plug in the value for the concentration
it's the molarity of H30+Cl- by HCl.... (moles of solute per litre of solution..) if u replace these values in the equation ull get 10^7 as the ka value... moreover ka value is always given in the last page of your text book.
I am with Robbie on this one. Where did he get the 10^7????? Is there a chart with values for H3O+ and HCl somewhere?
yes, the values are usually given
it's already a constant value, blaze :)
You're using [H3O+] and [Cl-] etc., in other words, the concentrations of these molecules. As it turns out, HCl is a strong acid, so you get very little HCl and very much H3O+ and Cl-, which means large values divided by a small value, which equals a large total value (10^7). You can't check the calculation because the values for the concentrations weren't given here, Jay just told you that it comes down to 10^7.
Guys I need help, please:
Acetic acid is added to water until the ph value reaches 4. What is the total concentration of the added acetic acid?
Okay, No one has answered my real question- Around 3:15 you "used your Ka expression to get 10^7. How in the hell did you get that? I'll double check my calculator to see if there's a button to divide H30+ and Cl- by HCl...........yep, not seeing it. Am I just stupid? how do you get that value?
robbie magnuson They are just numbers that are already discovered. For any given problem, the concentrations will either be given to you or will be findable, by giving you the pH. In that case you would just plug in the value for the concentration
it's the molarity of H30+Cl- by HCl.... (moles of solute per litre of solution..) if u replace these values in the equation ull get 10^7 as the ka value... moreover ka value is always given in the last page of your text book.
i dont understand the Ka expression so its [products] over [HA] but what is [HA]???????
an acid H is the hydrogen part
well A can be Cl or even SO4
No HA Is just a notation for weak acid
Very helpful sir.. thanks
Thank you sir