Common ion effect and buffers | Chemistry | Khan Academy

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  • เผยแพร่เมื่อ 24 ธ.ค. 2024

ความคิดเห็น • 77

  • @xky8124
    @xky8124 7 ปีที่แล้ว +11

    Thank you. Really learn more here than lessons.

  • @AngellaBakali-jf6tg
    @AngellaBakali-jf6tg ปีที่แล้ว +3

    Wooow thanks Khan Academy. I have always had troubles in this topic. Now am happy I have followed

  • @harshpatel7323
    @harshpatel7323 8 ปีที่แล้ว +4

    Check this out.
    [anything] = n x 10^(m)
    p[anything] = (n-1).(10-m)
    So in the video,
    Ka= 1.8 x 10^(-5) = [H3O+]
    p[H3O+]= (5-1).(10-2) [don't include negative & round).
    pH= 4.8 ~4.74
    Learned this through a MCAT Kaplan Video, so the credit goes to them! You can use this for anything...so if you're given Ka and need to get the pKa, or the pOH and you know the [OH]. Very handy for fast calculations. You can always to the long-log method for an accurate answer.

  • @musicoswateros449
    @musicoswateros449 4 ปีที่แล้ว +2

    Y'all *demanding* a solution without calculator should really be ashamed not to appreciate the work this man is doing. If you want to know how to approximate the value of pH, that's not something that the chemistry video must necessarily cover. Go search TH-cam for a video on logarithms.

  • @franks8209
    @franks8209 5 ปีที่แล้ว +65

    I swear you and organic chem tutor have the lowest volume videos on youtube.

    • @sychomadman
      @sychomadman 5 ปีที่แล้ว +12

      I guess it depends on the speakers on your device. It's loud on mine.

    • @hindbenyousef134
      @hindbenyousef134 4 ปีที่แล้ว +6

      yess I agreed. But they are the best tutors

    • @almazwyohannes
      @almazwyohannes ปีที่แล้ว +2

      Organic chemistry is the best

  • @harshitaPOF14
    @harshitaPOF14 9 ปีที่แล้ว +6

    thank you so much khan academy! this helped a great deal! :-))

  • @huntersikari
    @huntersikari 8 ปีที่แล้ว +5

    10:56 Can we assume every time that the x is of a very less value?
    THank u for the video!

    • @sayambandyopadhyay
      @sayambandyopadhyay 8 ปีที่แล้ว

      yah +hunter sikari

    • @berezker
      @berezker 8 ปีที่แล้ว +6

      hunter sikari No
      we can only assume x is a small value only when ka < 1
      for example : 1.83x10^-4, we ignore x since the degree of ionization is very small ( less than 5%) and ka < 1
      where as if ka = 6.73x10^3 , we have to include x in the equation since ka > 1 and degree of ionization is greater than 5%

    • @sayambandyopadhyay
      @sayambandyopadhyay 8 ปีที่แล้ว

      That is obviosly idiot

    • @sparshailawadi7129
      @sparshailawadi7129 8 ปีที่แล้ว +11

      Sayam Bandyopadhyay obvious, idiot.*
      Idiot.

    • @sayambandyopadhyay
      @sayambandyopadhyay 8 ปีที่แล้ว

      lol

  • @T-She-Go
    @T-She-Go 7 ปีที่แล้ว +3

    Yaaaas, thank you!

  • @rizzmechanics
    @rizzmechanics ปีที่แล้ว

    Thank you!! never knew it was this easy

  • @jenniferporoye9324
    @jenniferporoye9324 3 ปีที่แล้ว +2

    thank you, this video was so helpful ! :)

  • @naruhinafan100
    @naruhinafan100 7 ปีที่แล้ว +4

    Henderson Hassleback equation will be your friend with these type problems. PH= Pka+log ([conjugate base]/[acid])

    • @devikanair44
      @devikanair44 4 ปีที่แล้ว +1

      when I did CA/A I did NH3/NH4 and got the wrong answer but when I did the reverse got the correct. Anyone know why?

  • @apearson79
    @apearson79 5 ปีที่แล้ว +1

    Excellent, thanks!

  • @ayushsinghbohra4625
    @ayushsinghbohra4625 6 ปีที่แล้ว +1

    Thank you...

  • @siddhantsinha7807
    @siddhantsinha7807 9 ปีที่แล้ว +1

    How can we equate Ka = [CH3COO-][H3O+]/[CH3COOH]
    what I have learnt Is this [CH3COO-][H3O+]/[CH3COOH] = Kh (i.e hydrolysis constant) and Kh = Kw/Ka. And from here we calculate x and then [H3O+] = x. And then pH = - log (x).

    • @ZnNlove
      @ZnNlove 8 ปีที่แล้ว

      i know this is old but another way to get [H3O+] is using:
      [OH-][H3O+] = Kw
      so,
      [H3O+] = Kw/[OH-]
      Kw is constant: 1.01 x 10^-14
      now u can use the -log[H+]

  • @zinetemer1463
    @zinetemer1463 3 ปีที่แล้ว +1

    best explanation

  • @aimanaamir8450
    @aimanaamir8450 4 ปีที่แล้ว

    gless u man saved my grade

  • @siddhantsinha7807
    @siddhantsinha7807 9 ปีที่แล้ว +1

    OK I'm sorry. I was wrong Kh
    = Kw/Ka is in case of hydrolysis of salt. Thanks. For video

  • @abhishekbattula68
    @abhishekbattula68 6 ปีที่แล้ว +3

    Do we have to always assume that x is a very small number?

    • @TicaDexless
      @TicaDexless 6 ปีที่แล้ว +1

      Only a very small amount of a weak acid/base dissociates.

    • @arinaathilah7605
      @arinaathilah7605 5 ปีที่แล้ว

      If initial concentration/ka >100 then we can ignore x

  • @hadeelmassarwa3561
    @hadeelmassarwa3561 10 หลายเดือนก่อน

    Thank you so much sir! I 🥹🥹

  • @carlossjourneythroughlife2647
    @carlossjourneythroughlife2647 6 ปีที่แล้ว

    Thx! Much help

  • @sagarpatel5013
    @sagarpatel5013 9 ปีที่แล้ว

    Thanks!

  • @nidaaa7714
    @nidaaa7714 6 ปีที่แล้ว

    thank you

  • @harshitaagnihotri7613
    @harshitaagnihotri7613 7 ปีที่แล้ว

    thanks...

  • @omarjallow7102
    @omarjallow7102 6 ปีที่แล้ว

    thank for sharing

  • @Labdominals
    @Labdominals 8 ปีที่แล้ว +24

    Why is the volume so low?

  • @GuruprakashAcademy
    @GuruprakashAcademy 8 ปีที่แล้ว

    good

  • @Killia0316
    @Killia0316 2 ปีที่แล้ว

    What if Ka and Kb are not given? How would we find the pH buffer?

  • @parisamkh1
    @parisamkh1 8 ปีที่แล้ว +1

    thank youuuuuuuuuuuuuuuuuuuuuuuuuuu

  • @abeselombelete7052
    @abeselombelete7052 3 ปีที่แล้ว +1

    whose watching after 6years

  • @robincodjoe3222
    @robincodjoe3222 7 ปีที่แล้ว +3

    Why is this not a buffer system ? why didn't we take the -log of the Ka and then the log of the ratio of conjugate base over acid?

    • @naruhinafan100
      @naruhinafan100 7 ปีที่แล้ว +4

      that works too. For example the second problem whose PH was 8.89. You could have use kw/kb to find Ka and then the solution is simply PH = -log(5.56 x 10^10) + log (0.15/0.35) will give you the 8.89 PH he found without having to go through all of those steps . It is good to know the ICE method solution however

  • @asy42699
    @asy42699 ปีที่แล้ว

    not me abusing the Henderson-Hasselbalch equation to get the same answers

  • @marlena4522
    @marlena4522 6 ปีที่แล้ว +2

    You cannot use a calculator on the MCAT. You should show people how to best approximate these values. Example: -log(m x 10^-n) = approx. n - 0.m. So for this video -log (7.7 x 10^ -6) = 6- 0.77 = 5.23

    • @DuraiPrema
      @DuraiPrema ปีที่แล้ว

      Can u explain this elaboratly

  • @Vunami
    @Vunami 7 ปีที่แล้ว

    Arrigato

  • @IshDaFishPickleball
    @IshDaFishPickleball 5 ปีที่แล้ว

    why is the x small??

  • @nasimiqbal2078
    @nasimiqbal2078 6 ปีที่แล้ว

    Please fix the sound

  • @vctrs5630
    @vctrs5630 7 ปีที่แล้ว

    What does happen to Nh4NO3??

    • @dennislup
      @dennislup 6 ปีที่แล้ว

      it makes the concentration of NH4 increase, this is all happing at once

  • @finnb585
    @finnb585 6 ปีที่แล้ว +2

    All your videos are calculate pH, the EASIEST. Why not do an example on calculate strong base conc. if the pH of acetic acid buffer is _____________.

  • @sadafshefa2285
    @sadafshefa2285 6 ปีที่แล้ว +1

    Why is the volume always so low in khanacademy videos?

  • @On99123
    @On99123 3 ปีที่แล้ว

    HKUST anyone?

  • @studentnice8733
    @studentnice8733 8 ปีที่แล้ว +1

    Plz also translate ur lectures into urdu...........
    advance thanks :-)

    • @Kencan254
      @Kencan254 7 ปีที่แล้ว +1

      These videos are meant for MCAT preparation, an exam tested in English. Go look for videos in your language else.

  • @Kencan254
    @Kencan254 7 ปีที่แล้ว +1

    These are AAMC approved videos and given that use of calculator is not permitted in the exam, is it the time you showed your viewers how to solve these problems WITHOUT a calculator?

  • @aarons.1349
    @aarons.1349 4 ปีที่แล้ว

    Marry me professor

  • @jiminpark3865
    @jiminpark3865 4 ปีที่แล้ว

    chemistry sucks but thx for the video anyway

  • @icentvesalvanelisan3823
    @icentvesalvanelisan3823 3 ปีที่แล้ว

    If ye then be risen with Christ, seek those things which are above, where Christ sitteth on the right hand of God. Set your affection on things above, not on things on the earth. For ye are dead, and your life is hid with Christ in God. When Christ, who is our life, shall appear, then shall ye also appear with him in glory. Mortify therefore your members which are upon the earth; fornication, uncleanness, inordinate affection, evil concupiscence, and covetousness, which is idolatry: For which things' sake the wrath of God cometh on the children of disobedience: In the which ye also walked some time, when ye lived in them. But now ye also put off all these; anger, wrath, malice, blasphemy, filthy communication out of your mouth. Lie not one to another, seeing that ye have put off the old man with his deeds; And have put on the new man, which is renewed in knowledge after the image of him that created him: Where there is neither Greek nor Jew, circumcision nor uncircumcision, Barbarian, Scythian, bond nor free: but Christ is all, and in all. Put on therefore, as the elect of God, holy and beloved, bowels of mercies, kindness, humbleness of mind, meekness, longsuffering; Forbearing one another, and forgiving one another, if any man have a quarrel against any: even as Christ forgave you, so also do ye. And above all these things put on charity, which is the bond of perfectness. And let the peace of God rule in your hearts, to the which also ye are called in one body; and be ye thankful. Let the word of Christ dwell in you richly in all wisdom; teaching and admonishing one another in psalms and hymns and spiritual songs, singing with grace in your hearts to the Lord. And whatsoever ye do in word or deed, do all in the name of the Lord Jesus, giving thanks to God and the Father by him. Wives, submit yourselves unto your own husbands, as it is fit in the Lord. Husbands, love your wives, and be not bitter against them. Children, obey your parents in all things: for this is well pleasing unto the Lord. Fathers, provoke not your children to anger, lest they be discouraged. Servants, obey in all things your masters according to the flesh; not with eyeservice, as menpleasers; but in singleness of heart, fearing God: And whatsoever ye do, do it heartily, as to the Lord, and not unto men; Knowing that of the Lord ye shall receive the reward of the inheritance: for ye serve the Lord Christ. But he that doeth wrong shall receive for the wrong which he hath done: and there is no respect of persons.
    Colossians 3 KJV
    bible.com/bible/1/col.3.0.KJV

  • @iqraurooj6516
    @iqraurooj6516 7 ปีที่แล้ว

    Am i the only one who dint get this lecture??

    • @elainew.5301
      @elainew.5301 6 ปีที่แล้ว +1

      There are a lot of terms that you have to learn before watching this video. Maybe you are confused because you don't know the definition of some of the terms (le Chatlier's principle, equilibrium, shift, etc.)

  • @parthranawat5748
    @parthranawat5748 8 ปีที่แล้ว

    how can pH be greater than 7???

    • @orange7142
      @orange7142 8 ปีที่แล้ว

      +Parth Ranawat pH is a measure of how acidic/basic water is. The range goes from 0 - 14, with 7 being neutral. pHs of less than 7 indicate acidity, whereas a pH of greater than 7 indicates a base. Got this from google.

    • @sayambandyopadhyay
      @sayambandyopadhyay 8 ปีที่แล้ว +2

      Wtf??

    • @xky8124
      @xky8124 7 ปีที่แล้ว

      Of cause, otherwise why do we have pH up to 14?

  • @ronixmacroom5300
    @ronixmacroom5300 7 ปีที่แล้ว

    rubbish

  • @1nonlyvii
    @1nonlyvii ปีที่แล้ว

    Thank you so so so muchhh , I have my chemistry exam tomorrow ( 6 units included ) & you're being a lifesaver rn. 🤍

  • @IdokoTestimony
    @IdokoTestimony 4 หลายเดือนก่อน

    Thank you so much