Fun puzzle indeed. Very different path for me, starting everything from block 8's quadruple 3458 in the middle and top rows leaving a 19 pair in the bottom, the 179 triple in the left column of that chute leaving the 6 in row 6. The 1 with this arrangement was always in r4c6 in block 5 allowing to place the 2 and the 5 on the right side of block 2. Pretty solid construction to finish the puzzle with relative ease. Thanks for posting. Good show. Your path was so different as to creating a whole different word for me :)
Using the 19 pairs in C4 to generate several 6s in the grid helped with the solve! Long sequences of unknowns as per R8 early on were also helpful (here, a 6 in C9 manifested)! Great work to be celebrated - an enjoyable trio of solves this day!
par(4,8) en 6a col y tercia (1,5,9) en el Sector 8 ent (7,4)=5; único lugar (6,4)=6 (3,5)=6; tercia(1,7,9) en 4a col (8,8)=5 (3,6)=2 (1,6)=5 (3,7)=5 (2,2)=5 formándose la tercia (2,5,8) en 5a col dentro del Sector 5 ent (4,6)=1; par(1,9) en 5a col, cuat(1,3,7,9) en 1a fila; cuat(1,2,7,9) en 2a fila; tercia(2,4,7) en 9a fila; cuat (3,4,6,8) en 8a fila ent (8,9)=6 (7,2)=6; cuat(1,2,4,7) en el Sector 9; (7,1)=9 (2,1)=7 (3,4)=7 (3,8)=8 (4,8)=6; par (3,4) en 3a fila ent (3,9)=1 (3,2)=9 (1,2)=1 (1,5)=9 (2,4)=1 (9,5)=1 (9,4)=9 (2,9)=2 (2,8)=9 (1,7)=7 (1,8)=3 (5,8)=1 (5,7)=8 (4,7)=4 (6,8)=7 (6,9)=3 (7,9)=7
Thanks for the fun puzzle!
Thanks Sir. Very kind of you Sir
Fun puzzle indeed. Very different path for me, starting everything from block 8's quadruple 3458 in the middle and top rows leaving a 19 pair in the bottom, the 179 triple in the left column of that chute leaving the 6 in row 6. The 1 with this arrangement was always in r4c6 in block 5 allowing to place the 2 and the 5 on the right side of block 2. Pretty solid construction to finish the puzzle with relative ease. Thanks for posting. Good show. Your path was so different as to creating a whole different word for me :)
Using the 19 pairs in C4 to generate several 6s in the grid helped with the solve! Long sequences of unknowns as per R8 early on were also helpful (here, a 6 in C9 manifested)! Great work to be celebrated - an enjoyable trio of solves this day!
Philip thanks you for posting this 3rd Sudoku.
You're welcome
NF: Numb Fingers Niels from doing 3 puzzles/day.
😁
Ah, a symmetrical puzzle. So pleasing on the eye (75 = row 7 column 5):
75, 74, 88, 22, 89,
72, 71, 76, 86, 21,
34, 18, 17, 35, 64,
48, 37, 16, 36, 46,
38, 28, 29, 39, 12,
24, 15, 32, 95, 94,
69, 79, 58, 77, 47,
68, 57, 42, 93, 45,
41, 82, 81, 33, 31,
65, 55, 63, 62, 73,
98, 78, 92, 53, 52.
I couldn't find any " fun" in this puzzle.Would you kindly enlighten me about the fun
Perhaps our ideas of fun just don't align.
@@NMalteC Dear Sir, honestly speaking,I am not clear as yet.Without getting offended,( no offence meant, Sir) oblige me to make me to understand, Sir
I can't and I won't. I find some sudokus more fun to solve than others. I seriously don't see why that's a mystery
par(4,8) en 6a col y tercia (1,5,9) en el Sector 8 ent (7,4)=5; único lugar (6,4)=6 (3,5)=6; tercia(1,7,9) en 4a col (8,8)=5 (3,6)=2 (1,6)=5 (3,7)=5 (2,2)=5 formándose la tercia (2,5,8) en 5a col dentro del Sector 5 ent (4,6)=1; par(1,9) en 5a col, cuat(1,3,7,9) en 1a fila; cuat(1,2,7,9) en 2a fila; tercia(2,4,7) en 9a fila; cuat (3,4,6,8) en 8a fila ent (8,9)=6 (7,2)=6; cuat(1,2,4,7) en el Sector 9; (7,1)=9 (2,1)=7 (3,4)=7 (3,8)=8 (4,8)=6; par (3,4) en 3a fila ent (3,9)=1 (3,2)=9 (1,2)=1 (1,5)=9 (2,4)=1 (9,5)=1 (9,4)=9 (2,9)=2 (2,8)=9 (1,7)=7 (1,8)=3 (5,8)=1 (5,7)=8 (4,7)=4 (6,8)=7 (6,9)=3 (7,9)=7