From the 38 blocking pairs in C6 to unearthing the digits 8 in C5 and 1 in C3, this solve was laden with wise manipulations! Nicely analyzed and have a beautiful day!
Ah, I thought this was quite easy as there were three obvious pairs right at the opening. But later on, to spot the decisive pair (which for me was a 36) I ended up doing some notations. Nowadays, as one really tries to manage these without, it always feels like a defeat.
I have workmen making a huge row, so can't concentrate much. However, my instant spot from box 8 is that 3 of those numbers form a triple in C6 of box 5, so the box C6 8 cells will also be a triple leaving also a pair in R7 of the box. A couple of C6 solution numbers can be placed from that.
Quite an enjoyable puzzle! Thanks for posting!
From the 38 blocking pairs in C6 to unearthing the digits 8 in C5 and 1 in C3, this solve was laden with wise manipulations! Nicely analyzed and have a beautiful day!
Ah, I thought this was quite easy as there were three obvious pairs right at the opening. But later on, to spot the decisive pair (which for me was a 36) I ended up doing some notations. Nowadays, as one really tries to manage these without, it always feels like a defeat.
One slightly tricky step (4 = row 4 column 7):
47, 54, 75, 44, 53,
74, 45, 65, 64, 35,
25, 15, 34, 39, 69,
31, 42, 41, 46, 96,
62 (hidden pair in column 1),
12, 51, 73, 61, 52,
58, 77, 92, 56, 66,
71, 78, 99, 98, 67,
68, 88, 72, 23, 81,
22, 83, 21, 19, 18,
89, 79, 29, 14, 24,
17, 27, 13, 86, 76.
I have workmen making a huge row, so can't concentrate much. However, my instant spot from box 8 is that 3 of those numbers form a triple in C6 of box 5, so the box C6 8 cells will also be a triple leaving also a pair in R7 of the box. A couple of C6 solution numbers can be placed from that.