00:03 Air resistance slows down fast-moving objects more than slow-moving objects 01:22 Object without air resistance follows symmetrical parabolic path. 02:32 Projectiles with air resistance have unique motion and acceleration characteristics. 03:44 Projectile faces air resistance, leading to terminal velocity. 04:59 Acceleration graph helps understand velocity changes. 06:17 Terminal velocity is when the velocity of a falling object remains constant. 07:28 Terminal velocity is reached when the buoyant force balances out the force of gravity. 08:47 Parachutes affect terminal velocity by increasing air resistance
Can you please tell, that in the 8:11 when the skydiver opens the parachute, does the negative acceleration(i.e. when there is a straight line downwards in a vs. t graph) mean the skydiver goes upwards?
The skydiver definitely does NOT go upwards. The upward acceleration just means the velocity vector is being changed in the upward direction, which means the very large downward velocity is less large BUT STILL DOWNWARD
Hello my question is this, Taking the air resistance into account,the acceleration of a free falling body can be described approximately by a(v)=g-av^2. Here g is the gravity acceleration and a a constant. Determine the velocity v(t) of the body that is released from rest. Thank you!
@@AndyMasley Hi Andy, thank you for the reply. I was hopping to treat the rocket as a projectile as for I got the exit velocity from the thrust, would it still not work? I guess for my problem, I need to take in altitude and other forces on the rocket. Anyway thank you again for answering.
Hii, thank you for the explanation, it cleared up a lot of things to me!! Just a question, to calculate the velocity of the fall with air resistance, which formula should i use? You kinda explained it but i’m a bit confused, sorry
It's not possible to calculate the velocity without calculus. You can estimate the velocity by estimating the slope at any point on the position-time graph
Hi Andy, Thank you so much for creating this video. It made understanding air resistance easy! When considering air resistance in the movement of a paper airplane (knowing the force of the thrust, distance traveled and time traveled) would it be possible to graph and equation with the information I mentioned to show how the paper airplane would have moved in the absence of air resistance like your graph of the ball in the video?
@@AndyMasley Thank you so much for this insight. I am doing my IA about paper airplanes and I'm hoping to make the math worth it. This video and your response have been so useful in understanding the physics behind it!!
Shouldn't air resistance also depend on the mass of the object? So I guess if we take mass into account, should it be... F_air = km(v)^2? where k is a constant.
It depends on multiple factors yeah. The general shape of the air resistance graph stays the same for different masses, the specific numbers on the axes change but IB doesn't get that specific
I tried to calculate the angle and velocity, but i was unable to, even by using this farside.ph.utexas.edu/teaching/336k/lectures/node29.html Those are correct answers in the book: 39,180 yards (35,830 m) 70.27 sec 44,510 yards (40,700 m) 89.42 sec 45,960 yards (42,030 m) 98.6 sec How they were calculated? With air ressistance?
As a parent, I can't thank you enough for such a clear explanation of concepts ! God bless you
You are a saviour I can't express how clear these videos are!!
What a fabulous explanation. Thank you so much! You taught the concept in such a simple and lucid manner.
FOR THE FIRST TJME IN MY LIFE,I UNDERSTOOD THIS
Let's gooooo
This is such a good video I hope u feel rlly good knowing you've helped ppl
I do thank you, and comments like this help!
You are the Greatest of ALL TIME!
00:03 Air resistance slows down fast-moving objects more than slow-moving objects
01:22 Object without air resistance follows symmetrical parabolic path.
02:32 Projectiles with air resistance have unique motion and acceleration characteristics.
03:44 Projectile faces air resistance, leading to terminal velocity.
04:59 Acceleration graph helps understand velocity changes.
06:17 Terminal velocity is when the velocity of a falling object remains constant.
07:28 Terminal velocity is reached when the buoyant force balances out the force of gravity.
08:47 Parachutes affect terminal velocity by increasing air resistance
THANK YOU SO MUCH FOR THIS VIDEO. THIS REALLY HELPED ME TO UNDERSTAND! HOW CAN I DONATE TO YOU?
A like & subscribe is great!!
Can you please tell, that in the 8:11 when the skydiver opens the parachute, does the negative acceleration(i.e. when there is a straight line downwards in a vs. t graph) mean the skydiver goes upwards?
The skydiver definitely does NOT go upwards. The upward acceleration just means the velocity vector is being changed in the upward direction, which means the very large downward velocity is less large BUT STILL DOWNWARD
Very interesting analysis!!!
Thank you very much for making the concept so easy, sir.
thank you so much, this helped a lot you should really do edexcel A LEVEL physics topics!!!
What happens to time of flight in air drag case when compare to when its absent... Increases or decreases
Hello my question is this,
Taking the air resistance into account,the acceleration of a free falling body can be described approximately by a(v)=g-av^2.
Here g is the gravity acceleration and a a constant.
Determine the velocity v(t) of the body that is released from rest.
Thank you!
Amazing explanation, thank you!
Hi Andy
I want to know if this can be applied to a rocket trajectory and could this be done on excel?
@@AndyMasley Hi Andy, thank you for the reply. I was hopping to treat the rocket as a projectile as for I got the exit velocity from the thrust, would it still not work? I guess for my problem, I need to take in altitude and other forces on the rocket. Anyway thank you again for answering.
so what will the graphs look like for the x direction
It would be 0 for the two examples at the end because there is no acceleration or velocity in the x direction.
i love you so much ❤️❤️❤️❤️
The explanation was pretty clear but I'm afraid I didn't understand anything.
Drat!
i think i have found my saving grace.
Hii, thank you for the explanation, it cleared up a lot of things to me!! Just a question, to calculate the velocity of the fall with air resistance, which formula should i use? You kinda explained it but i’m a bit confused, sorry
It's not possible to calculate the velocity without calculus. You can estimate the velocity by estimating the slope at any point on the position-time graph
Hi Andy,
Thank you so much for creating this video. It made understanding air resistance easy!
When considering air resistance in the movement of a paper airplane (knowing the force of the thrust, distance traveled and time traveled) would it be possible to graph and equation with the information I mentioned to show how the paper airplane would have moved in the absence of air resistance like your graph of the ball in the video?
@@AndyMasley Thank you so much for this insight. I am doing my IA about paper airplanes and I'm hoping to make the math worth it. This video and your response have been so useful in understanding the physics behind it!!
Shouldn't air resistance also depend on the mass of the object? So I guess if we take mass into account, should it be... F_air = km(v)^2? where k is a constant.
It depends on multiple factors yeah. The general shape of the air resistance graph stays the same for different masses, the specific numbers on the axes change but IB doesn't get that specific
@@AndyMasley Okay, thanks for the time and info.
It help me lot
thanks mate
thank you
I tried to calculate the angle and velocity, but i was unable to, even by using this
farside.ph.utexas.edu/teaching/336k/lectures/node29.html
Those are correct answers in the book:
39,180 yards (35,830 m) 70.27 sec
44,510 yards (40,700 m) 89.42 sec
45,960 yards (42,030 m) 98.6 sec
How they were calculated? With air ressistance?
Hello. Please can you make a vedio about safety parabola in projectile motion💌
didn't know kermit did physics
bye bye 2.1