01 - Source Transformations, Part 1 (Engineering Circuits)

แชร์
ฝัง
  • เผยแพร่เมื่อ 26 ธ.ค. 2024

ความคิดเห็น • 75

  • @michaelhopkins5823
    @michaelhopkins5823 3 ปีที่แล้ว +22

    Great explanation! I wish college professors cared enough to teach like you.

  • @juanboy5005
    @juanboy5005 2 หลายเดือนก่อน +2

    What an outstanding explanation!!
    I must say that I'd been searching for deep and convincing justifications about those simple rules we use for source transformations, but most of what I got so far, no matter its origin or language, was too shallow.
    Then I landed here and got exactly what I was looking for. Let me say that it couldn't be any closer to what I wanted to find. AWESOME!!
    I have already subscribed. Thanks!!! (Juan Boy, BS Chemistry, Another Science-Lover).

  • @mabenyjohnson6908
    @mabenyjohnson6908 4 ปีที่แล้ว +3

    This guy is gifted in teaching!

  • @devaschannel3649
    @devaschannel3649 3 ปีที่แล้ว +3

    Thank you sir,love from India🙏

  • @nickcaruso8893
    @nickcaruso8893 4 ปีที่แล้ว +6

    You are a great teacher! Thank you for posting these videos!

  • @saraharar3114
    @saraharar3114 6 ปีที่แล้ว +10

    thank you ,such a perfect teacher

  • @amoritemweember3449
    @amoritemweember3449 4 หลายเดือนก่อน

    I like the way u give us solid understanding of the topics

  • @eldeeb6912
    @eldeeb6912 7 ปีที่แล้ว +14

    U are awesome !! Now i don't need to attend lectures ☺

    • @miguelplaza3104
      @miguelplaza3104 2 หลายเดือนก่อน +1

      how are you today?

    • @eldeeb6912
      @eldeeb6912 2 หลายเดือนก่อน +2

      @@miguelplaza3104
      Well I graduated 3 years ago and am an Application Engineer in a multinational corporation .. Wow I don’t even recall commenting on any TH-cam videos!

    • @miguelplaza3104
      @miguelplaza3104 2 หลายเดือนก่อน +1

      @@eldeeb6912 nice, im still a student a stupid one 😭 fxk this im doing ComE

    • @eldeeb6912
      @eldeeb6912 2 หลายเดือนก่อน

      @@miguelplaza3104 well it’s not an easy journey :( Good luck buddy!

  • @m7mdarwani964
    @m7mdarwani964 3 ปีที่แล้ว +1

    I appreciate your care to give the idea clearly.

  • @xerxesxylophone7188
    @xerxesxylophone7188 8 ปีที่แล้ว +8

    Thank you! You explained this very well!

  • @AkhonaAndile-dm4um
    @AkhonaAndile-dm4um 2 หลายเดือนก่อน

    cantv wait to have money so i can contribute, youre good sir

  • @sonwabomakinana4488
    @sonwabomakinana4488 2 ปีที่แล้ว +1

    Across the entire globe, I'm sure the majority of lecturers ( Profs and Docs) would gain a lot of knowledge in your classes

  • @mercychepkurui5866
    @mercychepkurui5866 2 ปีที่แล้ว +1

    You great teacher indeed,,continue producing more video

  • @abrarzawad2977
    @abrarzawad2977 2 ปีที่แล้ว

    Thanks Thanks Thanks Thanks a lot
    U made it a whole lotta clear

  • @someone6429
    @someone6429 2 ปีที่แล้ว +1

    Why in the last example when he gets rid of the resistances, he removes the resistance for Voltage source if its the parrallel and for the Current source if it is the Series? I didn't clearly get the idea on why that's the case.

  • @boltez6507
    @boltez6507 ปีที่แล้ว +2

    23:17 Absolute truth here

    • @sanch3608
      @sanch3608 หลายเดือนก่อน

      Finally sombody that uses his brain correctly 🫡

  • @ImStian
    @ImStian 3 ปีที่แล้ว +1

    Amazing explanation

  • @aliabdi1680
    @aliabdi1680 7 ปีที่แล้ว +1

    The best explanation I've ever seen :)

  • @ahmadalmooalm7023
    @ahmadalmooalm7023 6 ปีที่แล้ว +2

    ... Your explain is great

  • @nazanwar6469
    @nazanwar6469 6 ปีที่แล้ว +1

    I honestly wish that I have studied with you instead of that stupid uni they have made my life very hard for me...!!! Thanks, man this was very educational and enjoyable for me

  • @lenchoabdulgefar
    @lenchoabdulgefar ปีที่แล้ว

    Thank you ❤❤

  • @gouravchouhan1790
    @gouravchouhan1790 3 ปีที่แล้ว

    Ur a great teacher👍👍

  • @ezzhamdan7399
    @ezzhamdan7399 2 ปีที่แล้ว

    bro , god bless u. amazing explanation.

  • @leosbagoftricks3732
    @leosbagoftricks3732 4 ปีที่แล้ว +1

    You could tell the "black boxes" apart using the following method: The box with the voltage source will get hotter when you sort it, while the current source containing box will cool down. (assuming it's an ideal current source)

  • @ahmadtharwat2670
    @ahmadtharwat2670 6 ปีที่แล้ว +2

    thanx alot u helped me

  • @TheElectromagno
    @TheElectromagno 4 ปีที่แล้ว

    Good explanation. Thank you.

  • @abdirahmanali7230
    @abdirahmanali7230 8 ปีที่แล้ว

    Superb explanation. Thank you

  • @tarzenvai8333
    @tarzenvai8333 3 ปีที่แล้ว

    thank you sir ,,, you are the best

  • @vakhariyajay2224
    @vakhariyajay2224 3 ปีที่แล้ว

    Thank you very much. You are a genius.

  • @karim5199
    @karim5199 4 ปีที่แล้ว

    thanks your explanation it's very good

  • @f140299792
    @f140299792 7 ปีที่แล้ว +1

    thanks for your explanation ! that is what i need

    • @MathAndScience
      @MathAndScience  7 ปีที่แล้ว

      I really appreciate it!
      Get our Free App and View all Lessons!
      www.MathTutorApp.com

  • @merazulhaque2412
    @merazulhaque2412 6 ปีที่แล้ว +1

    Thank you Sir....u r awesome

  • @donroussey7595
    @donroussey7595 7 ปีที่แล้ว +1

    Confused. Why can't V source and I source be the same? Battery,p.s etc provide V and I right? PLUS why do you want to transform in the first place? What application in electronics is this for? Possibly a switched p.s? The high frequency chopped p.s.?

    • @kr3wdog06
      @kr3wdog06 6 ปีที่แล้ว +3

      I believe source transformations help simplify the circuit as well as allow you the ability to use one equation in the end to solve for equivalence. It might have a better purpose deeper in circuits. I know some of the info and earlier circuits is merely an introduction. But I believe it's just another way to simplify circuits to get the equivalent resistance etc...

  • @martinmendiolamm
    @martinmendiolamm 8 ปีที่แล้ว +3

    My friend liked your explanation since his professor appears to be clueless at times.

    • @abromchris7670
      @abromchris7670 6 ปีที่แล้ว

      I always feel clueless while my professor is teaching this subject

  • @yuhangdu5626
    @yuhangdu5626 3 ปีที่แล้ว

    thank you very much

  • @pradeepprakash7105
    @pradeepprakash7105 5 ปีที่แล้ว

    At 13:07 pls explain more clearly
    Few amps of current is through resistor and some current through short circuit . But you are telling that total amps will flow through short circuit. Doesn't it violate KCL??

    • @NoOne-ky1er
      @NoOne-ky1er 4 ปีที่แล้ว +1

      No,
      Current chooses the least resistive path.
      But path of short circuit has zero resistance. That's Why all current will flow through it.

    • @pradeepprakash7105
      @pradeepprakash7105 4 ปีที่แล้ว +1

      @@NoOne-ky1er thank you

  • @the_emmo
    @the_emmo 8 ปีที่แล้ว +1

    Excellent explanation. Thanks (:

  • @carlosaragon5446
    @carlosaragon5446 4 ปีที่แล้ว

    thank you... you are awesome

  • @amirnazarian8952
    @amirnazarian8952 4 ปีที่แล้ว

    i wish i could have pay the courses but unfortunately i can't due to "us" banking sanctions under my country (Iran)
    so i should just continue with Ur videos in youtube
    thank you for everything !

  • @AricDaNinja
    @AricDaNinja 8 ปีที่แล้ว

    Great job. Thanks.

  • @travislarrat3439
    @travislarrat3439 4 ปีที่แล้ว

    Awesome

  • @V2Guerrero
    @V2Guerrero 3 ปีที่แล้ว

    Never said why though, teach the specifics please. Only saying it’s just ohm’s law. I get it, but explanation always helps.

  • @Gchoice-channel
    @Gchoice-channel 2 ปีที่แล้ว

    You are blessed in Jesus name 🙏🙏🙏

  • @sheralikhtk5200
    @sheralikhtk5200 5 ปีที่แล้ว +1

    I wish I knew about u before

  • @hloesilen
    @hloesilen 6 ปีที่แล้ว

    Thank you!!!!!

  • @boufahjamalek2204
    @boufahjamalek2204 8 ปีที่แล้ว

    ur the best :) thank you :)

  • @abromchris7670
    @abromchris7670 6 ปีที่แล้ว

    how to buy your lessons

    • @MathAndScience
      @MathAndScience  6 ปีที่แล้ว

      Hi, you can get them all by visiting: www.mathtutordvd.com. Thank you!

  • @robertlake2753
    @robertlake2753 6 ปีที่แล้ว +1

    Need help on an EE problem? Type: 'Circuit Solver' by Phasor Systems on Google Play.

  • @cowboycannon5476
    @cowboycannon5476 9 หลายเดือนก่อน

    🐐

  • @Nolimitscomedy
    @Nolimitscomedy 6 ปีที่แล้ว +58

    Thank you for not being Indian

  • @Michael-vb3se
    @Michael-vb3se 6 ปีที่แล้ว

    Please help

  • @irfanoktenoglu4658
    @irfanoktenoglu4658 ปีที่แล้ว

    you sound a lot like joe rogan man thats crazy

  • @joelmwape832
    @joelmwape832 4 ปีที่แล้ว

    Sir I need your help please add me

  • @yogeshwaridahiwale8367
    @yogeshwaridahiwale8367 6 ปีที่แล้ว +1

    Please hindi me sir

    • @Michael-vb3se
      @Michael-vb3se 6 ปีที่แล้ว +1

      Go to an Indian channel sir