first of all, thank for your helpful video. And i have a question, i read from a book that :"we are not allowed to change dependent sources", can you clarify it for me, please!
Can anyone tell me why he put -51Vx and from where he got vx basically? Cuz in the mesh i sum the -7.5 ,+9 and -51 but as a voltages but he took it as -51Vx.
Two thumbs up for recapping the pens constantly, very pleasing to the ears.
The last part should be -70.5 and not -80.5. Hence -1.5/-70.5 and the answer would be 0.0213 A or 21.3 mA. Great video anyways :D
7 years later and still quality material here
loved the tips, thank you so much for sharing this dear
Learnt this concept in few minutes because of your video.
Best video in TH-cam ... For source transformation.... Thanks sir....love from India...
Very end 2nd to last line is supposed to be -70.5i = -1.5. then i = .0213
Thank you a lot for this effort
Literally a lifesaver in circuits 1. TYSM!
Thankyou for this video. This rescued my exam. :)
This was very helpful, thank you.
Awesome video thank U very much ☺️
Thank you professor! this was really good!
very helpful video.... thanks for uploading sir...
first of all, thank for your helpful video. And i have a question, i read from a book that :"we are not allowed to change dependent sources", can you clarify it for me, please!
Thanks for this! Super helpful
Awesome video to understand what source transformation is. It really helped me. Just one mistake is the last part as the other's said. Thank you!
Can anyone tell me why he put -51Vx and from where he got vx basically? Cuz in the mesh i sum the -7.5 ,+9 and -51 but as a voltages but he took it as -51Vx.
IN EX.1 cant I add the voltage sources together since they're series aiding? so V=IR, 48=12700I, I = 3.8mA?...
Thank you so much!