Sir I do believe that there has to be the cubic curve in bmd of portion AC of opposite nature of what you have drawn. As shear force is decreasing from A to C , so the slope of cubic curve in bmd in Portion AC will also decrease . So it will look like an arc of an upward parabola (y²=4ax) lying above the x axis which is just opposite in nature of what u have drawn. Let me know if I am correct or not . Thank you for the detailed solution.
It's a big help to my subj. Thanks sir.
Most welcome James, we are glad this video helped you, keep watching and all the best
The bending moment at a point should be equal in all the cases. But here why it is not..? Is this answer is correct..?
Nice explanation.......thanks sir
Thanks and welcome
Its wrong how can it be correct explanation
Sir I do believe that there has to be the cubic curve in bmd of portion AC of opposite nature of what you have drawn. As shear force is decreasing from A to C , so the slope of cubic curve in bmd in Portion AC will also decrease . So it will look like an arc of an upward parabola (y²=4ax) lying above the x axis which is just opposite in nature of what u have drawn.
Let me know if I am correct or not .
Thank you for the detailed solution.
I think sir took wrong sign convention
nice lecture
The sfd diagram is wrong! Load intensity is increasing so the slope of shear diagram will increase also.
For section DE it will be
32.5(x) -40(x-2)
I think for BMD "+" is under the line.
Tq sir 💯🔥
welcome
SFD and BMD sketch for section AC is wrong. It would be opposite which your have drawn.
For section DE why isn't the length (2-x)?
Just confused about how EB and DE have the same length, x. My exam is on Thursday. Please help you're my only hope
moment is acting at point E so span is divided as DE and EB and both are 2m
section is cut at DE and that distance is "x" and moment will rotate at that point only so no distance for that moment
@@structuralanalysisanddesign Great thank you! I understand