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I have watched like 10 videos and never understood but now from you I understood everything, thank you a lot bro you saved my marks
This was very clear. Viewers pls dont skip. This guy teaching is understandable
Really... very super and detailed explanation 🥳🤩🤩
Tq so much sir..love from Assam
Best explaination 👍
Thank you sir
Cleared my doubts..Thanks a lot sir🙏🏼
Thanks for Watching.
This was so helpful. Thankyou so much.
THANK YOU SIR
very excellent, most helpful,thank u sir
Thanks
Thank you Sir....Nice and simple explanation ✌🏻
Thankyou!!!!!
You're welcome!
You did a great job.
Nice🙏
Love u bro
Thank-you sir
Thanks... please share
🙏🙏🙏
Thank you
Thank you for watching.. please share
It is the problem of uvl on simply supported beam of unsymmetrical which is very helpful for clearing the concept. You also must provide the symmetrical uvl on simply supported beam.
Bro for the last part finding bending moment at C, u can just find the area of the parabola from the SFD. Area will be( 2/3xbasexheight). Easiest.
Yes can be done
I didn't get 5.19😢
Me too😭
I got it
Still in doubt?
Please solve the equation of "X" value from SFD diagram.
Why you wrote X value directly it makes little bit confusion
What kind of confusion? If you state here I shall clarify for you.
X= 5.19
It's not written directly.. please check
Great
X and h value how to get?
by using the concept that at maximum BM, sf is zero in case of simply supported beam... and then by applying concept of similar triangles
Thnq bro
Gud
And for Ra wl/6. Rb wl/3
nice brother
best best best
very confussing to understand .but not bad
It depends
To find x sub formula L/ROOT3
You are the hero of comment section
I have watched like 10 videos and never understood but now from you I understood everything, thank you a lot bro you saved my marks
This was very clear. Viewers pls dont skip. This guy teaching is understandable
Really... very super and detailed explanation 🥳🤩🤩
Tq so much sir..love from Assam
Best explaination 👍
Thank you sir
Cleared my doubts..Thanks a lot sir🙏🏼
Thanks for Watching.
This was so helpful. Thankyou so much.
THANK YOU SIR
very excellent, most helpful,thank u sir
Thanks
Thank you Sir....Nice and simple explanation ✌🏻
Thanks
Thankyou!!!!!
You're welcome!
You did a great job.
Thanks
Nice🙏
Love u bro
Thank-you sir
Thanks... please share
🙏🙏🙏
Thank you
Thank you for watching.. please share
It is the problem of uvl on simply supported beam of unsymmetrical which is very helpful for clearing the concept. You also must provide the symmetrical uvl on simply supported beam.
Bro for the last part finding bending moment at C, u can just find the area of the parabola from the SFD. Area will be( 2/3xbasexheight). Easiest.
Yes can be done
I didn't get 5.19😢
Me too😭
I got it
Still in doubt?
Please solve the equation of "X" value from SFD diagram.
Why you wrote X value directly it makes little bit confusion
What kind of confusion? If you state here I shall clarify for you.
X= 5.19
It's not written directly.. please check
Great
Thank you
X and h value how to get?
by using the concept that at maximum BM, sf is zero in case of simply supported beam... and then by applying concept of similar triangles
Thnq bro
Gud
Thanks
And for Ra wl/6. Rb wl/3
nice brother
Thanks
best best best
Thanks
very confussing to understand .but not bad
It depends
To find x sub formula L/ROOT3
You are the hero of comment section