Newton's Second Law - IB Physics

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  • เผยแพร่เมื่อ 3 ม.ค. 2025

ความคิดเห็น • 15

  • @shamelsinha1626
    @shamelsinha1626 4 ปีที่แล้ว +22

    You are so underrated. Your vids are much more comprehensive and concise than StudyNova and Chris Donney. Keep up the amazing work!

  • @kokoxo_
    @kokoxo_ 2 ปีที่แล้ว +5

    you are literally the only reason i pass. u make me feel like i can actually understand physics and that i'm not stupid. Thank youuuuu!!

    • @AndyMasley
      @AndyMasley  2 ปีที่แล้ว +2

      So so wonderful to get feedback like this, thank you!

  • @aneeqanadeem8953
    @aneeqanadeem8953 4 ปีที่แล้ว +12

    Thanks for giving us such amazing lectures.

  • @abhinavsingh9790
    @abhinavsingh9790 ปีที่แล้ว +1

    Today as a new physics student this is video is SO USEFUL THANK YOU SIR

  • @NM-gg3hs
    @NM-gg3hs 2 ปีที่แล้ว +2

    Mr Andy, in IB, is Newtons Second Law F net=rate of change of momentum?

    • @AndyMasley
      @AndyMasley  2 ปีที่แล้ว

      Yes! Because Ft = change in momentum, if you divide both sides by time you get F = (change in momentum)/t

  • @speedysenu4183
    @speedysenu4183 2 ปีที่แล้ว +1

    Hello sir! I really liked your video on this topic, but I would have 1 question. Why doesn't the m*a here 5:52 have a negative sign in front of it? The acceleration vector is opposite of what we consider the positive direction.

    • @aryansh_
      @aryansh_ ปีที่แล้ว

      He did a mistake of placing a negative sign in front of frictional force .

  • @zerrickbarlow1862
    @zerrickbarlow1862 2 ปีที่แล้ว

    Its my understanding that IB physics starts with many motion scenarios ignoring friction. At what point does the curriculum start to include friction in the scenarios?

  • @EkinAdaÇalıkStudent
    @EkinAdaÇalıkStudent ปีที่แล้ว +1

    you suddenly made everything so easy...

  • @antonissak6297
    @antonissak6297 ปีที่แล้ว

    this one was a real banger

  • @salmaabdelraheam2773
    @salmaabdelraheam2773 2 ปีที่แล้ว

    hello thank you so much! i have a question in the last car example, do we usually not consider the applied force from the engine when the question states Air resistance is negligible?

    • @RohanChakk
      @RohanChakk ปีที่แล้ว

      I thought the same thing 😅, but I think since it was originally traveling at 30 m/s (a constant velocity) then the net force = 0?

  • @AlexandroGiovanni
    @AlexandroGiovanni 3 ปีที่แล้ว

    Thank you dayum