Harvard University Admission Question | Solve For Sqaure root of Iota? | Algeria

[@ubiraceelihimas]

Muito bom, já tinha resplvido

[@gp-ht7ug]

Hello, why didn’t you apply sqrt(i)=sqrt(e^(i*pi))?

[@germanalexandru]

i=(-1 + 2*i + 1)/2=[ (i + 1)^2] / 2
The rest is simple.