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Muito bom, já tinha resplvido
Hello, why didn’t you apply sqrt(i)=sqrt(e^(i*pi))?
i=(-1 + 2*i + 1)/2=[ (i + 1)^2] / 2 The rest is simple.
Muito bom, já tinha resplvido
Hello, why didn’t you apply sqrt(i)=sqrt(e^(i*pi))?
i=(-1 + 2*i + 1)/2=[ (i + 1)^2] / 2
The rest is simple.