Can you find area of the Blue Circle? | (Fun Geometry Problem) |

[@santiagoarosam430]

Radio dell cuadrante =10 ---> Radio del semicírculo =10/2=5 ---> Uniendo centros y puntos de tangencia: (5+r)²-(5-r)²=(10-r)²-r² ---> r=5/2---> 25π/4 .
Gracias y saludos

[@MathandEngineering]

Perfect sir, thanks

[@marioalb9726]

A = ¼πR² = 78,5 m² --> R=9,9975 cm
r₁ = ½R = 49,975m
Pytagorean theorem, twice:
(R-r)²-r² = (r₁+r)²-(r₁-r)²
R²-2Rr+r²-r² = (r₁² +2r₁r+r²)-(r₁²-2r₁r+r²)
R²-2Rr = 4r₁r
(2R+4r₁)r = R²
(20 + 20)r ≈ 100
r ≈ 5/2 = 2,500634 m
A = πr² = 19,645 m² ( Solved √ )

[@MathandEngineering]

Thanks friend, it's Excellent 👍